Log in
Chemistry · Chapter 15. Hydrocarbons

Qualitative reactions for alkynes

A qualitative test for alkynes using ammoniacal silver oxide solution allows the detection of hydrocarbons with a triple bond at the end of the chain. The process is based on the substitution of the acidic hydrogen atom at the terminal carbon atom, forming a characteristic insoluble precipitate.

General formulaCnH2n-2 (corresponds to both alkynes and alkadienes)
Reagent[Ag(NH3)2]OH — ammoniacal silver oxide solution (Tollens' reagent)
TargetTerminal alkynes (triple bond at the end of the chain)
ExceptionsAlkadienes and alkynes with an internal bond (e.g., but-2-yne) do not react
3 min readFor medical studentsUpdated 09/24/2026
Material prepared by WhiteCoat Pro editorial team based on platform study guidesReviewed by medical editor: Aulov A. A., general practitioner · 09/24/2026

Molecular formula analysis

When studying hydrocarbons, it is important to correctly interpret their molecular formula. The general formula $\text{C}_n\text{H}_{2n-2}$ indicates a high degree of unsaturation of the molecule. Two main classes of aliphatic compounds fall under this formula:

  • Alkynes (compounds with one triple bond).
  • Alkadienes (compounds with two double bonds).

For example, the formula $\text{C}_4\text{H}_6$ can belong to either diene hydrocarbons or isomeric alkynes (but-1-yne or but-2-yne). To accurately determine the structure of an unknown substance, specific qualitative reactions are used to differentiate these classes and their isomers.

Specificity of ammoniacal silver oxide solution

To identify hydrocarbons, an ammoniacal silver oxide solution is used — the complex compound $\text{[Ag(NH}_3)_2\text{]OH}$, also known as Tollens' reagent. The interaction with this reagent is a strictly specific qualitative test for terminal alkynes.

Terminal alkynes are hydrocarbons in which the triple bond is located at the very end of the carbon chain. The key chemical feature of such molecules is the presence of an acidic hydrogen atom ($\equiv\!\text{C}-\text{H}$ fragment). Due to the high electronegativity of the carbon atom in sp-hybridization, the bond between carbon and hydrogen is strongly polarized, allowing the hydrogen atom to be replaced by a metal ion (in this case, silver).

It is important to remember that:

  1. Alkadienes do not enter into this reaction because they lack a triple bond and the corresponding acidic hydrogen atoms.
  2. Alkynes with a triple bond in the middle of the chain (internal alkynes, e.g., but-2-yne) are also inert towards Tollens' reagent, since the carbon atoms forming the triple bond lack hydrogen atoms.
Test your knowledge on this topicTasks from the "Chemistry" course bank — instant answers and explanations.

Reaction mechanism using but-1-yne as an example

Let us examine the process using the hydrocarbon of composition $\text{C}_4\text{H}_6$, which gives a positive test with $\text{[Ag(NH}_3)_2\text{]OH}$. Based on the properties of the reagent, the target substance is but-1-yne, which has the structural formula $\text{CH}\equiv\text{C}-\text{CH}_2-\text{CH}_3$.

When ammoniacal silver oxide solution is added to but-1-yne, a metallation reaction occurs, resulting in the synthesis of silver acetylide. The visual sign confirming the reaction is the precipitation of a solid ($\downarrow$).

The reaction equation is as follows: $\text{CH}\equiv\text{C}-\text{CH}_2-\text{CH}_3 + \text{[Ag(NH}_3)_2\text{]OH} \rightarrow \text{Ag}-\text{C}\equiv\text{C}-\text{CH}_2-\text{CH}_3 \downarrow + 2\text{NH}_3 + \text{H}_2\text{O}$

During the reaction, the complex compound breaks down, free ammonia and water are released, and the silver atom firmly binds to the terminal carbon.

Briefly: answers to topical questions

What color of precipitate is formed during the reaction of terminal alkynes with ammoniacal silver oxide solution?

The color of the precipitate is not specified in the provided sources; a silver acetylide precipitate is formed.

How to memorize

Terminal means "at the edge". Tollens' reagent "hooks" only onto the terminal acidic hydrogen. If the triple bond is hidden inside the chain (like in but-2-yne), there is no "hook" — no reaction will occur.

Class and exam questions

Why does but-2-yne not react with ammoniacal silver oxide solution?

In but-2-yne, the triple bond is located in the middle of the carbon chain. The carbon atoms forming this bond do not have acidic hydrogen atoms (≡C-H) that could be substituted by a silver ion.

How to distinguish an alkyne from an alkadiene with the same molecular formula?

Using a qualitative test with ammoniacal silver oxide solution. The terminal alkyne will react to form a silver acetylide precipitate, whereas the alkadiene will not react with this reagent.

What is the visual sign of a qualitative test for terminal alkynes?

Formation of an insoluble precipitate. For example, the reaction of but-1-yne produces a silver acetylide precipitate (Ag-C≡C-CH2-CH3).

Something unclear? Ask the AIThe AI tutor has read the material on "Qualitative reactions of alkynes" and will explain it in simple terms.

What else to study on this topic

  • Structural isomerism of hydrocarbons with the general formula CnH2n-2
  • The nature of the acidity of the terminal hydrogen atom in alkynes
  • Structure and chemical properties of alkkadienes
  • Features of the chemical behavior of but-2-yne

Master the entire topic in the "Chemistry" course

This is a summary. The course covers everything tested in classes and exams.

  • Complete study guide on "Qualitative reactions of alkynes" and 3,009 other subject pages
  • Assignments and quizzes after every topic — just like in a colloquium
  • AI tutor answers questions on the topic anytime
  • 95 video lessons for the subject

Other topics in "Chapter 15. Hydrocarbons"

The entire section "Chapter 15. Hydrocarbons"

Prepared by WhiteCoat Pro faculty in accordance with the medical school curriculum. For educational purposes only.