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USMLE Step 1 · United States

USMLE Step 1 respiratory system questions

45 original USMLE Step 1-style questions on respiratory system, each with the correct answer, an explanation, why the other options are wrong and the educational objective. Solve them in the quiz or read them below, grouped by section.

Questions45 with answers
Sections8
Options per question5
Time≈ 68 min
USMLE Step 1 Respiratory system: practice quizPick an answer to see the correct option and the explanation at once. Your best score is saved in this browser.

Lung Development & Pediatric Pathology

4 questions
1

A woman at 31 weeks' gestation presents in preterm labor and receives a course of betamethasone. Delivery occurs 48 hours later. The infant, a male weighing 1,500 g, develops tachypnea, grunting, and subcostal retractions within 2 hours of birth. Chest x-ray shows diffuse fine granular opacities with air bronchograms bilaterally. A sample of amniotic fluid obtained before delivery had been sent for analysis. Which of the following amniotic fluid findings would have best predicted this infant's respiratory course?

  1. APositive foam stability (shake) test
  2. BPresence of phosphatidylglycerol with lecithin/sphingomyelin ratio of 3.0
  3. CElevated alpha-fetoprotein concentration
  4. DLecithin/sphingomyelin ratio of 1.2
  5. ELecithin/sphingomyelin ratio of 2.5
Show answer
Answer: D. Lecithin/sphingomyelin ratio of 1.2

An L/S ratio below 2.0 indicates insufficient pulmonary surfactant and predicts a high risk of neonatal respiratory distress syndrome (RDS), which is caused by type II pneumocyte immaturity and inadequate lecithin (phosphatidylcholine) production. Surfactant lowers alveolar surface tension; its deficiency leads to progressive atelectasis, diffuse alveolar damage, and the granular ground-glass appearance with air bronchograms seen on chest x-ray. An L/S ratio ≥2.0 generally indicates fetal lung maturity and low RDS risk. Phosphatidylglycerol appears later in gestation and its presence further supports maturity, the opposite of this infant's clinical picture.

  • A. A positive shake (foam stability) test indicates adequate surfactant and predicts fetal lung maturity, not RDS.
  • B. Phosphatidylglycerol presence with an L/S ratio of 3.0 reflects mature lungs and would predict a benign respiratory course.
  • C. Elevated amniotic alpha-fetoprotein suggests a neural tube defect or abdominal wall defect, not lung immaturity.
  • E. An L/S ratio of 2.5 indicates fetal lung maturity and predicts a low risk of RDS, not the course described.
Educational objective: An amniotic fluid lecithin/sphingomyelin ratio below 2.0 indicates fetal lung immaturity and predicts neonatal respiratory distress syndrome from surfactant deficiency.
2

A full-term female newborn develops severe respiratory distress and cyanosis within minutes of birth. Examination shows a scaphoid abdomen and absent breath sounds on the left side with heart sounds heard best in the right chest. Chest x-ray shows loops of bowel in the left hemithorax with mediastinal shift to the right. Which of the following best explains the underlying cause of this infant's respiratory insufficiency?

  1. APremature closure of the ductus arteriosus in utero, leading to right ventricular hypertrophy
  2. BFailure of the tracheoesophageal septum to divide the foregut, causing abnormal communication between the trachea and esophagus
  3. CDelayed closure of the pleuroperitoneal membrane allowing abdominal viscera to herniate into the thorax, compressing the developing lung and reducing bronchial branching
  4. DAbnormal migration of neural crest cells into the distal colon, causing functional bowel obstruction
  5. EFailure of the bulbus cordis and truncus arteriosus to septate, producing a single arterial outflow tract
Show answer
Answer: C. Delayed closure of the pleuroperitoneal membrane allowing abdominal viscera to herniate into the thorax, compressing the developing lung and reducing bronchial branching

Congenital diaphragmatic hernia, most commonly a left-sided posterolateral (Bochdalek) defect, results from failure of the pleuroperitoneal membrane to close, allowing abdominal organs to herniate into the thoracic cavity early in development. The herniated viscera occupy space normally available for lung growth, mechanically compressing the ipsilateral (and often contralateral) developing lung bud and impairing bronchial branching and alveolarization. This produces pulmonary hypoplasia, the key determinant of postnatal respiratory failure and mortality. The mediastinal shift and bowel-filled hemithorax on imaging are classic findings.

  • A. Premature ductal closure causes fetal heart failure and hydrops, not pulmonary hypoplasia from mechanical compression.
  • B. This describes tracheoesophageal fistula, which presents with feeding-related choking and polyhydramnios, not a scaphoid abdomen with bowel in the thorax.
  • D. This describes the pathogenesis of Hirschsprung disease, unrelated to diaphragmatic development or lung hypoplasia.
  • E. This describes truncus arteriosus, a conotruncal cardiac defect unrelated to diaphragmatic herniation.
Educational objective: Congenital diaphragmatic hernia results from failed pleuroperitoneal membrane fusion, allowing abdominal contents to herniate into the thorax and cause pulmonary hypoplasia via compression of the developing lung.
3

A male infant born at 26 weeks' gestation weighing 800 g required mechanical ventilation with high fraction of inspired oxygen for severe respiratory distress syndrome. At 34 weeks postmenstrual age, he remains oxygen-dependent with persistent tachypnea and crackles on auscultation. Chest x-ray shows diffuse haziness with small cystic areas bilaterally. Which of the following best describes the primary mechanism underlying this infant's chronic lung disease?

  1. AAspiration of meconium causing chemical pneumonitis and surfactant inactivation
  2. BDeficient alpha-1 antitrypsin activity leading to unopposed neutrophil elastase action on alveolar walls
  3. COxygen free radical injury and barotrauma causing arrested alveolar development and impaired septation
  4. DCongenital absence of pulmonary lymphatics leading to interstitial fluid accumulation
  5. EAutoimmune destruction of type II pneumocytes by maternally transferred antibodies
Show answer
Answer: C. Oxygen free radical injury and barotrauma causing arrested alveolar development and impaired septation

Bronchopulmonary dysplasia (BPD) results from prolonged exposure of the immature lung to supplemental oxygen and mechanical ventilation (barotrauma/volutrauma) in premature infants. Reactive oxygen species overwhelm the infant's limited antioxidant defenses, triggering inflammation and injury to the developing alveoli and airways. This disrupts normal alveolarization and septation, producing fewer, larger, simplified alveoli and the characteristic patchy, cystic changes on imaging. BPD is diagnosed clinically as oxygen requirement persisting beyond 28 days of life or to 36 weeks postmenstrual age.

  • A. Meconium aspiration syndrome occurs in term or post-term infants from in utero meconium passage, not from prolonged ventilation in a preterm infant.
  • B. Alpha-1 antitrypsin deficiency causes early-onset emphysema in adults, not neonatal chronic lung disease from oxygen therapy.
  • D. Congenital pulmonary lymphangiectasia is a distinct, rare developmental disorder, not the mechanism of ventilator/oxygen-induced lung injury.
  • E. BPD is not an antibody-mediated autoimmune process; it results from oxidative and mechanical injury, not maternal antibody transfer.
Educational objective: Bronchopulmonary dysplasia results from oxygen free radical injury and barotrauma in premature lungs, arresting normal alveolar septation and development.
4

A full-term female newborn develops copious drooling, coughing, and cyanosis with her first attempted feeding. The pregnancy was complicated by polyhydramnios. On examination, a feeding tube passed through the mouth meets resistance and coils back after advancing approximately 10 cm. Abdominal x-ray shows a normal gas pattern with air present in the stomach and bowel. Which of the following is the most likely diagnosis?

  1. ALaryngotracheoesophageal cleft
  2. BH-type tracheoesophageal fistula without atresia
  3. CEsophageal atresia with distal tracheoesophageal fistula
  4. DIsolated esophageal atresia without fistula
  5. EEsophageal atresia with proximal tracheoesophageal fistula
Show answer
Answer: C. Esophageal atresia with distal tracheoesophageal fistula

The most common type of tracheoesophageal anomaly (about 85% of cases) is esophageal atresia with a distal tracheoesophageal fistula connecting the trachea to the distal esophageal segment. The blind proximal esophageal pouch explains the inability to pass a feeding tube and the choking, drooling, and cyanosis with feeding attempts, while polyhydramnios results from the fetus's inability to swallow amniotic fluid in utero. Air is seen in the stomach and bowel because the distal fistula allows air from the trachea to enter the GI tract, distinguishing it from isolated atresia, which shows a gasless abdomen.

  • A. Laryngotracheoesophageal cleft is a rare separate anomaly causing aspiration with feeds but does not produce the coiled feeding tube finding of a blind esophageal pouch.
  • B. H-type fistula without atresia allows a feeding tube to pass normally into the stomach, which is inconsistent with the resistance described.
  • D. Isolated esophageal atresia without a fistula would produce the same tube-coiling finding but a gasless abdomen, since no air can reach the distal bowel.
  • E. Proximal fistula with distal atresia is rare and would still produce a gasless abdomen because the distal esophagus is blind-ending with no tracheal communication.
Educational objective: The most common tracheoesophageal anomaly is esophageal atresia with a distal fistula, causing a blind proximal pouch (inability to pass a feeding tube, polyhydramnios) with air still reaching the stomach via the fistula.

Pulmonary Mechanics & Gas Exchange Physiology

4 questions
5

A 68-year-old man with a history of pulmonary embolism 3 days ago has persistent dyspnea. His respiratory rate is 26/min and oxygen saturation is 90% on room air. Arterial blood gas on room air at sea level shows: pH 7.46, PaCO2 30 mm Hg, PaO2 65 mm Hg. Which of the following best characterizes the mechanism of this patient's hypoxemia? (Assume barometric pressure 760 mm Hg, FiO2 0.21, respiratory quotient 0.8.)

  1. AIncreased A-a gradient due to ventilation-perfusion mismatch
  2. BNormal A-a gradient due to diffusion-limited gas exchange at rest
  3. CIncreased A-a gradient due to right-to-left intracardiac shunt present since birth
  4. DNormal A-a gradient due to decreased inspired oxygen tension
  5. ENormal A-a gradient due to alveolar hypoventilation
Show answer
Answer: A. Increased A-a gradient due to ventilation-perfusion mismatch

The alveolar gas equation gives PAO2 = FiO2 × (Patm − PH2O) − (PaCO2/R) = 0.21 × (760 − 47) − (30/0.8) ≈ 150 − 37.5 ≈ 112 mm Hg. The A-a gradient is PAO2 − PaO2 ≈ 112 − 65 = 47 mm Hg, markedly elevated above the normal range (roughly 10–15 mm Hg, age-adjusted). Pulmonary embolism obstructs blood flow to ventilated alveoli, creating areas of high V/Q ratio alongside reflex redistribution of flow to other regions, producing overall V/Q mismatch, which widens the A-a gradient because gas exchange becomes inefficient despite adequate ventilation. The patient is also hyperventilating (low PaCO2), which is a compensatory response to hypoxemia and anxiety, not the cause of his hypoxemia.

  • B. Diffusion limitation classically causes hypoxemia only during exercise, not at rest, and would still produce an elevated, not normal, A-a gradient.
  • C. A congenital right-to-left shunt would have presented much earlier in life and is not suggested by this acute presentation after pulmonary embolism.
  • D. Decreased inspired oxygen tension (e.g., high altitude) causes hypoxemia with a normal A-a gradient, not an elevated one as calculated here.
  • E. Pure hypoventilation would show an elevated PaCO2 and a normal A-a gradient; this patient has a low PaCO2 and a markedly elevated gradient.
Educational objective: An elevated A-a gradient indicates V/Q mismatch or shunt as the cause of hypoxemia, as seen in pulmonary embolism, whereas a normal A-a gradient points to hypoventilation or low inspired oxygen.
6

A 30-year-old man is exercising vigorously. Compared to resting muscle, his exercising skeletal muscle shows increased local temperature, increased PCO2, and decreased pH. A blood sample from the venous drainage of this muscle shows a rightward shift of the oxygen-hemoglobin dissociation curve compared to resting conditions. Which of the following best explains the molecular mechanism of this shift?

  1. AIncreased carbon dioxide directly competes with oxygen for binding at the heme iron, independent of hemoglobin conformation
  2. BIncreased hydrogen ion binding to hemoglobin stabilizes the deoxygenated (taut) conformation, decreasing hemoglobin's affinity for oxygen
  3. CDecreased pH increases hemoglobin's affinity for 2,3-BPG at the alpha-globin chains, enhancing oxygen loading
  4. DIncreased 2,3-BPG binds to the oxygenated (relaxed) hemoglobin conformation, increasing oxygen affinity
  5. EIncreased temperature increases the number of hemoglobin binding sites available for oxygen
Show answer
Answer: B. Increased hydrogen ion binding to hemoglobin stabilizes the deoxygenated (taut) conformation, decreasing hemoglobin's affinity for oxygen

The Bohr effect describes how increased H+ (from increased CO2 and lactic acid production during exercise) binds to specific residues on hemoglobin, favoring and stabilizing the deoxygenated taut (T) conformation over the oxygenated relaxed (R) conformation. The T state has lower affinity for oxygen, shifting the dissociation curve to the right and promoting oxygen unloading at the tissue level where it is metabolically needed. Increased temperature and 2,3-BPG act through related allosteric mechanisms that also favor the T state and rightward shift. This is physiologically advantageous because actively metabolizing tissue needs more oxygen delivered exactly where CO2 and acid are being produced.

  • A. Carbon dioxide affects oxygen binding mainly through carbamino formation and pH-driven conformational change, not by directly competing with oxygen at the heme iron.
  • C. 2,3-BPG binds the beta-globin chains, not the alpha chains, and its effect is to decrease, not enhance, oxygen affinity.
  • D. 2,3-BPG binds preferentially to the deoxygenated (taut) form, not the oxygenated form, and decreases, not increases, oxygen affinity.
  • E. Increased temperature does not change the number of binding sites; it decreases hemoglobin's oxygen affinity by promoting the taut conformation.
Educational objective: Increased H+, CO2, and temperature stabilize the deoxygenated taut conformation of hemoglobin, decreasing oxygen affinity and shifting the dissociation curve rightward to favor oxygen unloading in metabolically active tissue.
7

A 45-year-old man develops left lower lobe atelectasis after abdominal surgery. Pulmonary blood flow to the atelectatic segment decreases despite the absence of any thrombus or vascular obstruction. Which of the following best explains the mechanism responsible for this redistribution of blood flow?

  1. ADecreased alveolar PCO2 directly triggers smooth muscle contraction in pulmonary arterioles
  2. BIncreased alveolar nitric oxide release constricts pulmonary arterioles in the hypoxic segment
  3. CLocal accumulation of prostacyclin in hypoxic alveoli promotes vasoconstriction of adjacent arterioles
  4. DSympathetic nervous system activation selectively vasodilates pulmonary vessels in well-ventilated lung regions
  5. EAlveolar hypoxia causes contraction of vascular smooth muscle in pulmonary arterioles supplying the poorly ventilated region
Show answer
Answer: E. Alveolar hypoxia causes contraction of vascular smooth muscle in pulmonary arterioles supplying the poorly ventilated region

Hypoxic pulmonary vasoconstriction is a unique, local, non-neural response in which alveolar hypoxia causes contraction of pulmonary vascular smooth muscle in the arterioles supplying that specific region. This diverts blood flow away from poorly ventilated alveoli (as in atelectasis) toward better-ventilated regions, optimizing overall ventilation-perfusion matching. The mechanism involves hypoxia-induced inhibition of oxygen-sensitive potassium channels in pulmonary vascular smooth muscle, leading to membrane depolarization, calcium influx, and contraction. This response is the opposite of the vasodilation that hypoxia produces in most other systemic vascular beds.

  • A. It is alveolar hypoxia, not hypocapnia, that is the primary trigger for pulmonary vasoconstriction in this setting.
  • B. Nitric oxide is a vasodilator, not a vasoconstrictor, and its release is generally decreased, not increased, in hypoxic lung regions.
  • C. Prostacyclin is a vasodilator produced by endothelium and would oppose, not promote, vasoconstriction.
  • D. Hypoxic pulmonary vasoconstriction is a local, intrinsic smooth muscle response independent of systemic sympathetic innervation.
Educational objective: Hypoxic pulmonary vasoconstriction diverts blood flow away from poorly ventilated alveolar regions by direct, local contraction of pulmonary arteriolar smooth muscle in response to alveolar hypoxia, optimizing V/Q matching.
8

A healthy 28-year-old man is standing upright and undergoes measurement of pulmonary arterial, venous, and alveolar pressures at different lung regions. In the middle lung zone, blood flow is determined by the pressure gradient between the pulmonary artery and the alveoli, while pulmonary venous pressure has little effect on flow. Which pressure relationship best characterizes this zone?

  1. AAlveolar pressure exceeds pulmonary venous pressure, which exceeds pulmonary arterial pressure
  2. BPulmonary arterial pressure exceeds pulmonary venous pressure, which exceeds alveolar pressure
  3. CPulmonary arterial pressure exceeds alveolar pressure, which exceeds pulmonary venous pressure
  4. DAlveolar pressure exceeds pulmonary arterial pressure, which exceeds pulmonary venous pressure
  5. EPulmonary venous pressure exceeds pulmonary arterial pressure, which exceeds alveolar pressure
Show answer
Answer: C. Pulmonary arterial pressure exceeds alveolar pressure, which exceeds pulmonary venous pressure

West zone 2 occurs in the mid-lung and is characterized by pulmonary arterial pressure exceeding alveolar pressure, which in turn exceeds pulmonary venous pressure. Because alveolar pressure is higher than venous pressure, flow is governed by the arterial-to-alveolar pressure gradient rather than the usual arterial-to-venous gradient, and venous pressure changes do not affect flow (a Starling resistor effect). This contrasts with zone 1 (alveolar pressure exceeds both vascular pressures, causing no flow, seen in hypovolemia or positive-pressure ventilation) and zone 3 (arterial and venous pressures both exceed alveolar pressure, so flow depends on the normal arteriovenous gradient, as at the lung bases).

  • A. This relationship does not correspond to any physiologic West zone.
  • B. This arterial > venous > alveolar relationship defines zone 3 (lung base), where flow is governed by the normal arteriovenous gradient.
  • D. This defines zone 1 (lung apex under low cardiac output or positive pressure ventilation), where alveolar pressure exceeds both vascular pressures and flow ceases.
  • E. Venous pressure does not normally exceed arterial pressure in the upright lung.
Educational objective: In West zone 2, pulmonary arterial pressure exceeds alveolar pressure, which exceeds venous pressure, so blood flow depends on the arterial-alveolar gradient rather than venous pressure.
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Acid-Base & Ventilatory Control

3 questions
9

A 45-year-old man undergoes an experimental protocol in which his arterial PCO2 is increased while his arterial PO2 and pH are held constant by controlled infusion, and separately his arterial PO2 is decreased to 55 mm Hg while PCO2 is held constant. Measurement of ventilation shows a brisk increase in both conditions, but the increase in PCO2 alone produces a much larger and faster ventilatory response than the decrease in PO2 alone. Which mechanism best explains the predominant stimulus accounting for the larger response?

  1. AIncreased carbon dioxide directly stimulates peripheral chemoreceptors in the carotid bodies independent of pH
  2. BDecreased oxygen tension increases cerebrospinal fluid bicarbonate, stimulating medullary chemoreceptors
  3. CIncreased carbon dioxide is detected by carotid body glomus cells via inhibition of calcium channels
  4. DDecreased oxygen directly depolarizes central chemoreceptors in the medulla
  5. ECarbon dioxide diffuses into the cerebrospinal fluid and is hydrated to form carbonic acid, which dissociates and lowers local pH, stimulating central chemoreceptors
Show answer
Answer: E. Carbon dioxide diffuses into the cerebrospinal fluid and is hydrated to form carbonic acid, which dissociates and lowers local pH, stimulating central chemoreceptors

CO2 crosses the blood-brain barrier easily and enters the cerebrospinal fluid, where carbonic anhydrase catalyzes its hydration to carbonic acid, which dissociates into H+ and bicarbonate. The resulting fall in CSF pH stimulates central chemoreceptors on the ventral medulla, producing a rapid and robust increase in ventilation; this is the dominant drive for minute-to-minute ventilatory control under normal conditions. Peripheral chemoreceptors (carotid and aortic bodies) respond primarily to hypoxemia (PO2 less than approximately 60 mm Hg) and contribute only a minor component of the CO2 response. Central chemoreceptors do not directly sense oxygen, which is why hypoxic drive is a comparatively weaker and slower stimulus.

  • A. CO2's main ventilatory effect is mediated through central chemoreceptors via CSF pH, not through a pH-independent peripheral carotid body mechanism.
  • B. Hypoxia does not raise CSF bicarbonate as its stimulatory mechanism; hypoxic sensing occurs in peripheral carotid bodies through different ion channel mechanisms.
  • C. Carotid body hypoxia sensing (not CO2 sensing) involves inhibition of oxygen-sensitive potassium channels in glomus cells, not calcium channel effects from CO2.
  • D. Central chemoreceptors are not directly sensitive to oxygen tension; hypoxia is sensed mainly by peripheral carotid body chemoreceptors.
Educational objective: Central chemoreceptors respond to CO2-induced changes in CSF pH and provide the dominant, fast ventilatory drive, while peripheral chemoreceptors primarily sense hypoxemia and contribute a smaller component of CO2-driven ventilation.
10

A 68-year-old man with a 50-pack-year smoking history and long-standing chronic obstructive pulmonary disease is brought to the emergency department with worsening dyspnea. Baseline arterial blood gas on room air at home (per his records) shows PCO2 58 mm Hg and PO2 52 mm Hg. In the emergency department, he is placed on a non-rebreather mask delivering 100% oxygen. Over the next hour he becomes increasingly somnolent and difficult to arouse. Which mechanism most directly explains his worsening mental status?

  1. AHigh supplemental oxygen precipitates bronchospasm, increasing dead space ventilation
  2. BHigh supplemental oxygen causes acute pulmonary edema that impairs alveolar ventilation
  3. CHigh supplemental oxygen directly suppresses the medullary respiratory center through oxygen toxicity
  4. DHigh supplemental oxygen increases cerebral blood flow, causing cerebral edema and altered mental status
  5. EHigh supplemental oxygen abolishes hypoxic stimulation of peripheral chemoreceptors, reducing ventilatory drive and causing CO2 retention
Show answer
Answer: E. High supplemental oxygen abolishes hypoxic stimulation of peripheral chemoreceptors, reducing ventilatory drive and causing CO2 retention

In patients with chronic CO2 retention, central chemoreceptors become relatively desensitized to CO2 over time, and ventilation becomes more dependent on hypoxic stimulation of peripheral chemoreceptors in the carotid bodies. Administering high-concentration supplemental oxygen eliminates this hypoxic drive, reducing minute ventilation and causing progressive CO2 retention (hypercapnia) and worsening respiratory acidosis, which manifests clinically as somnolence or CO2 narcosis. Additional contributing mechanisms include worsening ventilation-perfusion mismatch (reversal of hypoxic vasoconstriction) and the Haldane effect, but blunting of hypoxic ventilatory drive is the classically tested mechanism. Oxygen should be titrated carefully in chronic CO2 retainers to a target saturation around 88-92% rather than withheld entirely.

  • A. High-flow oxygen is not known to precipitate bronchospasm as the mechanism of hypercapnic somnolence in this scenario.
  • B. Oxygen-induced acute pulmonary edema is not a recognized mechanism of hypercapnia in this setting.
  • C. Oxygen toxicity from acute high-concentration therapy causing direct medullary suppression is not the mechanism of this phenomenon.
  • D. Hyperoxia typically decreases, not increases, cerebral blood flow, and this is not the mechanism of CO2 narcosis.
Educational objective: In chronic CO2 retainers, high-concentration supplemental oxygen can blunt hypoxic drive at peripheral chemoreceptors, reducing ventilation and causing dangerous CO2 retention and CO2 narcosis.
11

A 32-year-old man travels from sea level to a mountain village at 4,300 meters elevation for a two-week trek. Upon arrival, he hyperventilates in response to lower inspired oxygen tension. After one week at this altitude, his arterial blood gas shows pH 7.42, PCO2 28 mm Hg, and HCO3- 18 mEq/L. Which mechanism best accounts for the renal response that has occurred by this time point?

  1. AIncreased renal ammonium excretion to generate new bicarbonate and correct the primary metabolic acidosis
  2. BIncreased renal hydrogen ion secretion in the collecting duct to compensate for the primary respiratory alkalosis
  3. CDecreased renal carbonic anhydrase activity leading to increased bicarbonate reabsorption
  4. DDecreased renal bicarbonate reabsorption and increased bicarbonate excretion to compensate for the primary respiratory alkalosis
  5. EIncreased aldosterone-mediated sodium reabsorption leading to increased renal bicarbonate generation
Show answer
Answer: D. Decreased renal bicarbonate reabsorption and increased bicarbonate excretion to compensate for the primary respiratory alkalosis

At high altitude, the hypoxia-driven hyperventilation (via peripheral chemoreceptor stimulation) causes a primary respiratory alkalosis, with low PCO2 and a compensatory rise in pH. Over several days, the kidneys compensate by decreasing bicarbonate reabsorption in the proximal tubule and increasing bicarbonate excretion in the urine, lowering plasma bicarbonate toward normal and returning pH closer to 7.40. This renal compensation is slower than the respiratory response (taking days) but allows sustained hyperventilation and improved oxygen-carrying capacity without severe alkalemia, an important part of acclimatization along with increased 2,3-BPG and erythropoietin-driven erythropoiesis.

  • A. This describes compensation for a primary metabolic acidosis, which is the opposite of the alkalosis present here.
  • B. Increased hydrogen secretion would raise, not lower, plasma bicarbonate, which is the opposite of the renal response seen in respiratory alkalosis.
  • C. Decreased carbonic anhydrase activity and increased bicarbonate reabsorption would raise plasma bicarbonate, opposite to what occurs in appropriate renal compensation for alkalosis.
  • E. Aldosterone-driven bicarbonate generation is not the primary mechanism of renal compensation for high-altitude respiratory alkalosis.
Educational objective: Renal compensation for the respiratory alkalosis of high-altitude acclimatization involves decreased bicarbonate reabsorption and increased urinary bicarbonate excretion, normalizing pH over several days.

Obstructive Lung Disease

10 questions
12

A 59-year-old man with a 35-pack-year smoking history presents with a productive cough producing thick sputum that has occurred on most days for the past 3 months, recurring for the second consecutive year. He denies hemoptysis or significant weight loss. Physical examination reveals scattered wheezes and rhonchi bilaterally. A bronchial biopsy obtained during a prior evaluation is reviewed and shows marked thickening of the mucus-secreting gland layer relative to total bronchial wall thickness. Which finding most directly supports the diagnosis suggested by this biopsy? Reference: Reid index (gland layer thickness / total bronchial wall thickness) greater than 0.4 is considered elevated.

  1. AGranulomas with central caseous necrosis
  2. BLoss of alveolar septa with permanent airspace enlargement
  3. CReid index of 0.3
  4. DCurschmann spirals and Charcot-Leyden crystals in sputum
  5. EReid index of 0.6
Show answer
Answer: E. Reid index of 0.6

Chronic bronchitis is a clinical diagnosis defined by a productive cough for at least 3 months in 2 consecutive years, and its histologic correlate is hypertrophy and hyperplasia of the submucosal mucus-secreting glands in the bronchial wall, quantified by the Reid index. A Reid index greater than 0.4 (here, 0.6) confirms the glandular hyperplasia characteristic of chronic bronchitis, reflecting the chronic irritation and mucus hypersecretion driven by cigarette smoke exposure. This contrasts with emphysema, whose hallmark is destruction of alveolar walls, and with asthma, whose sputum shows eosinophilic markers such as Curschmann spirals and Charcot-Leyden crystals.

  • A. Caseating granulomas suggest tuberculosis or fungal infection, not chronic bronchitis.
  • B. This describes the pathology of emphysema, not chronic bronchitis.
  • C. A Reid index of 0.3 falls within the normal range and would not support the diagnosis of chronic bronchitis.
  • D. These findings are characteristic of asthma (eosinophilic airway inflammation), not chronic bronchitis.
Educational objective: Chronic bronchitis is diagnosed clinically by productive cough for 3 months in 2 consecutive years and is histologically confirmed by an elevated Reid index (mucous gland hyperplasia) greater than 0.4.
13

A 61-year-old man with a 40-pack-year smoking history presents with progressive dyspnea and a chronic productive cough. Chest CT shows destruction of lung parenchyma concentrated in the upper lobes, with relative sparing of the lower lobes. The lower lobes, when affected in a different patient population, show diffuse destruction involving the entire acinus uniformly from the respiratory bronchiole to the alveoli. Which of the following best explains why this patient's disease pattern predominates in the upper lobes?

  1. AGravity-dependent perfusion delivers more circulating neutrophil elastase inhibitor to the lower lobes
  2. BInhaled particulates and neutrophil-derived proteases accumulate preferentially in proximal respiratory bronchioles of the upper lung zones
  3. CAlpha-1-antitrypsin is synthesized locally in lower lobe alveolar macrophages, protecting them selectively
  4. DUpper lobes receive disproportionately higher ventilation relative to perfusion, concentrating reactive oxygen species
  5. EUpper lobes have a higher ratio of type I to type II pneumocytes, increasing susceptibility to oxidative injury
Show answer
Answer: B. Inhaled particulates and neutrophil-derived proteases accumulate preferentially in proximal respiratory bronchioles of the upper lung zones

Centriacinar (centrilobular) emphysema, the pattern seen in smokers, predominantly affects the upper lobes because inhaled cigarette smoke particulates and the resulting neutrophil and macrophage infiltration are concentrated in the respiratory bronchioles, the proximal part of the acinus. Neutrophil elastase released by these inflammatory cells destroys the walls of the respiratory bronchioles and adjacent alveoli while sparing the distal alveolar ducts and sacs. This contrasts with panacinar emphysema in alpha-1-antitrypsin deficiency, which uniformly destroys the entire acinus and predominates in the lower lobes because unopposed elastase activity is not anatomically restricted. The distribution difference reflects where the inciting insult (smoke deposition) versus the underlying defect (systemic antiprotease deficiency) exerts its effect.

  • A. Perfusion gradients do not determine antiprotease delivery or emphysema distribution; the mechanism is proximal acinar inflammation from inhaled smoke.
  • C. Alpha-1-antitrypsin is synthesized in the liver, not locally by lower lobe macrophages.
  • D. Ventilation-perfusion ratios do not account for the specific centriacinar distribution pattern seen in smoking-related emphysema.
  • E. Pneumocyte type ratios do not differ significantly by lobe in a way that explains emphysema distribution.
Educational objective: Smoking-related emphysema is centriacinar and upper lobe-predominant because inhaled particulates and neutrophil elastase damage the proximal acinus, whereas alpha-1-antitrypsin deficiency causes panacinar, lower lobe-predominant emphysema from unopposed elastase activity throughout the entire acinus.
14

A 34-year-old nonsmoking woman presents with progressive dyspnea on exertion. Pulmonary function tests show an obstructive pattern with decreased FEV1/FVC ratio. She also has a history of neonatal jaundice and current mildly elevated liver transaminases, and liver biopsy reveals periodic acid-Schiff-positive, diastase-resistant globules within periportal hepatocytes. Genetic testing reveals a PiZZ genotype. Which of the following best explains the combined pulmonary and hepatic findings in this patient?

  1. AA mutant transporter protein fails to export chloride ions, causing thick secretions that obstruct both bile ducts and bronchioles
  2. BChronic hepatic inflammation releases circulating elastase that directly destroys alveolar walls over time
  3. CExcess copper deposition in the liver and lung parenchyma triggers fibrosis in both organs
  4. DAutoantibodies against hepatocyte and type II pneumocyte surfaces cause combined organ damage
  5. EA misfolded protease inhibitor accumulates within hepatocytes and fails to reach the circulation, causing hepatocyte injury and unchecked neutrophil elastase activity in the lung
Show answer
Answer: E. A misfolded protease inhibitor accumulates within hepatocytes and fails to reach the circulation, causing hepatocyte injury and unchecked neutrophil elastase activity in the lung

Alpha-1-antitrypsin (A1AT) is synthesized by hepatocytes and normally inhibits neutrophil elastase in the lung. The Z allele produces a misfolded A1AT protein that polymerizes and accumulates within the endoplasmic reticulum of hepatocytes, forming PAS-positive, diastase-resistant globules and causing hepatocyte injury that can progress to cirrhosis. Because the mutant protein cannot be properly secreted, serum and alveolar A1AT levels are low, leaving neutrophil elastase unopposed in the lung and causing panacinar emphysema, especially in the lower lobes. The PiZZ genotype represents homozygosity for the Z allele and carries the highest risk of both severe emphysema and liver disease. This is a classic example of a gain-of-function toxic accumulation causing one organ's pathology and a loss-of-function deficiency causing another's.

  • A. This describes the CFTR mutation of cystic fibrosis, not alpha-1-antitrypsin deficiency.
  • B. The liver does not release elastase; hepatic injury results from intracellular protein accumulation, not elastase secretion.
  • C. This describes Wilson disease, not alpha-1-antitrypsin deficiency.
  • D. There is no autoantibody-mediated mechanism in alpha-1-antitrypsin deficiency.
Educational objective: In PiZZ alpha-1-antitrypsin deficiency, misfolded protein accumulates in hepatocytes causing liver cirrhosis, while the resulting low circulating A1AT leaves neutrophil elastase unchecked in the lung, causing panacinar emphysema.
15

A 16-year-old boy with known asthma develops acute wheezing and chest tightness within minutes of exposure to a cat. He is treated and improves, but 6 hours later he develops a second episode of wheezing and dyspnea without re-exposure to the allergen. Bronchoalveolar lavage performed during this second episode would most likely show predominance of which of the following cell types compared to the initial episode?

  1. ACD8+ cytotoxic T lymphocytes
  2. BPlasma cells
  3. CEosinophils
  4. DNatural killer cells
  5. ENeutrophils
Show answer
Answer: C. Eosinophils

Asthma exacerbations following allergen exposure classically occur in two phases. The early phase occurs within minutes and results from allergen cross-linking IgE bound to mast cells, triggering degranulation and release of preformed histamine and leukotrienes, causing immediate bronchospasm. The late phase occurs 4 to 8 hours later and is driven by recruitment of eosinophils, along with Th2 lymphocytes and basophils, which release major basic protein, eosinophil cationic protein, and additional leukotrienes (especially LTC4, LTD4, LTE4), causing sustained bronchoconstriction, mucus hypersecretion, and airway edema. Repeated late-phase inflammation over time contributes to airway remodeling in chronic asthma. Inhaled corticosteroids primarily target this eosinophilic late-phase inflammation.

  • A. CD8+ cytotoxic T lymphocytes are more associated with viral infections and are not the predominant late-phase effector cell in allergic asthma.
  • B. Plasma cells are not characteristically recruited during the late-phase response; IgE is produced earlier by sensitized B cells.
  • D. Natural killer cells are not the predominant effector cell recruited in the late-phase asthmatic response.
  • E. Neutrophils are more characteristic of bacterial infection or severe status asthmaticus, not the typical allergic late-phase response.
Educational objective: The early phase of an asthma exacerbation is mediated by IgE-activated mast cell degranulation, while the late phase 4 to 8 hours later is driven by eosinophilic airway inflammation.
16

A 24-year-old woman with asthma uses an inhaler during an acute episode of wheezing, after which her symptoms rapidly improve. The medication acts on a Gs-coupled receptor on bronchial smooth muscle cells. Activation of this receptor leads to bronchodilation through which of the following downstream mechanisms?

  1. AInhibition of phosphodiesterase-4 directly prevents degradation of cyclic GMP in airway smooth muscle
  2. BBlockade of leukotriene receptors on bronchial smooth muscle prevents cysteinyl leukotriene-mediated contraction
  3. CInhibition of acetylcholine release at postganglionic parasympathetic nerve terminals reduces muscarinic receptor stimulation
  4. DIncreased phospholipase C activity raises intracellular IP3 and diacylglycerol, releasing calcium from the sarcoplasmic reticulum
  5. EIncreased adenylyl cyclase activity raises intracellular cAMP, which activates protein kinase A and promotes myosin light-chain phosphatase activity and smooth muscle relaxation
Show answer
Answer: E. Increased adenylyl cyclase activity raises intracellular cAMP, which activates protein kinase A and promotes myosin light-chain phosphatase activity and smooth muscle relaxation

Albuterol is a short-acting beta-2 adrenergic receptor agonist. Beta-2 receptors are coupled to Gs proteins, and their activation stimulates adenylyl cyclase to convert ATP to cyclic AMP. Increased intracellular cAMP activates protein kinase A, which phosphorylates and inhibits myosin light-chain kinase while promoting myosin light-chain phosphatase activity, ultimately lowering intracellular calcium sensitivity and causing bronchial smooth muscle relaxation. This mechanism provides rapid relief of bronchospasm in acute asthma exacerbations. Beta-2 agonists also decrease mast cell mediator release, though their primary therapeutic effect is direct bronchial smooth muscle relaxation.

  • A. Beta-2 agonists increase cAMP via adenylyl cyclase, not cGMP via phosphodiesterase inhibition; phosphodiesterase-4 inhibitors like roflumilast act through a different pathway.
  • B. This describes the mechanism of leukotriene receptor antagonists such as montelukast, not beta-2 agonists.
  • C. Albuterol does not act presynaptically on cholinergic nerve terminals; that mechanism describes anticholinergics like ipratropium acting postsynaptically, not beta agonists.
  • D. This describes Gq-coupled receptor signaling such as that of muscarinic M3 or alpha-1 receptors, which promotes smooth muscle contraction, not relaxation.
Educational objective: Beta-2 agonists like albuterol bronchodilate by stimulating Gs-coupled receptors to increase cAMP, activating protein kinase A and relaxing bronchial smooth muscle.
17

A 45-year-old woman with moderate persistent asthma has been using an inhaled fluticasone inhaler twice daily for the past 3 months. She now presents with white, curd-like plaques on her tongue and buccal mucosa that scrape off easily, revealing an erythematous base. Which of the following counseling points would most effectively have prevented this complication?

  1. ASwitch to a systemic oral corticosteroid taken once daily instead of an inhaled form
  2. BUse a short-acting beta-agonist before the corticosteroid to open the airways first
  3. CAvoid using the inhaler within 2 hours of brushing teeth
  4. DTake the inhaled corticosteroid with food to reduce local mucosal exposure
  5. ERinse the mouth with water and spit after each inhaler use
Show answer
Answer: E. Rinse the mouth with water and spit after each inhaler use

This patient has oral candidiasis (thrush), a well-recognized local adverse effect of inhaled corticosteroids such as fluticasone. Corticosteroid deposition in the oropharynx suppresses local mucosal immune defenses and promotes overgrowth of Candida albicans. Rinsing the mouth with water and spitting it out immediately after each inhaler use removes residual drug from the oropharyngeal mucosa and significantly reduces the risk of candidiasis. Using a spacer device with metered-dose inhalers also reduces oropharyngeal deposition. This simple behavioral measure is standard counseling given to all patients prescribed inhaled corticosteroids.

  • A. Switching to systemic corticosteroids would increase systemic adverse effects and is not an appropriate substitution for an inhaled form to prevent a local adverse effect.
  • B. Using a beta-agonist first does not reduce oropharyngeal corticosteroid deposition or candidiasis risk.
  • C. Timing relative to tooth brushing has no established role in preventing corticosteroid-associated oral candidiasis.
  • D. Inhaled corticosteroids act locally in the airway; taking them with food does not reduce oropharyngeal deposition or candidiasis risk.
Educational objective: Rinsing the mouth and spitting after inhaled corticosteroid use prevents oropharyngeal candidiasis by removing residual drug that would otherwise suppress local mucosal defenses.
18

A 38-year-old woman with chronic sinusitis and nasal polyps develops wheezing, chest tightness, and rhinorrhea within an hour of taking ibuprofen for a headache. She reports similar reactions to aspirin in the past. This reaction is attributed to a shift in arachidonic acid metabolism toward the lipoxygenase pathway. A medication that blocks the receptor for the key mediators of this pathway would be most effective for long-term control. Which of the following is the mechanism of this medication?

  1. ABlockade of histamine H1 receptors on bronchial smooth muscle
  2. BInhibition of cyclooxygenase-2 to reduce prostaglandin synthesis selectively
  3. CInhibition of phosphodiesterase-4 to increase intracellular cAMP in inflammatory cells
  4. DAntagonism of cysteinyl leukotriene type 1 receptors on bronchial smooth muscle and inflammatory cells
  5. EInhibition of mast cell degranulation by stabilizing mast cell membranes
Show answer
Answer: D. Antagonism of cysteinyl leukotriene type 1 receptors on bronchial smooth muscle and inflammatory cells

This patient has aspirin-exacerbated respiratory disease (Samter triad: asthma, nasal polyps, and aspirin/NSAID sensitivity). COX inhibition by aspirin or NSAIDs shunts arachidonic acid metabolism toward the 5-lipoxygenase pathway, markedly increasing production of cysteinyl leukotrienes (LTC4, LTD4, LTE4), which cause bronchoconstriction, mucus secretion, and vascular permeability. Montelukast is a leukotriene receptor antagonist that selectively blocks the cysteinyl leukotriene type 1 (CysLT1) receptor, preventing these mediators from exerting their effects and providing effective prophylaxis in this condition. Zileuton, an alternative agent, instead inhibits 5-lipoxygenase directly to prevent leukotriene synthesis.

  • A. H1 receptor blockade targets histamine-mediated allergic symptoms, not leukotriene-mediated bronchoconstriction in this condition.
  • B. Further COX-2 inhibition would not help and may still precipitate symptoms in aspirin-sensitive patients since the problem is excess leukotriene production, not insufficient COX inhibition.
  • C. This describes phosphodiesterase-4 inhibitors like roflumilast, used in COPD, not leukotriene receptor antagonists.
  • E. This describes mast cell stabilizers like cromolyn, which act upstream of leukotriene release rather than blocking the leukotriene receptor.
Educational objective: In aspirin-exacerbated respiratory disease, COX inhibition shunts arachidonic acid toward leukotriene overproduction; montelukast blocks the CysLT1 receptor to prevent leukotriene-mediated bronchoconstriction.
19

A 29-year-old man with a history of recurrent childhood pulmonary infections and chronic sinusitis presents with a persistent cough productive of large volumes of foul-smelling purulent sputum, occasionally with streaks of blood. Chest CT shows irregular dilation of bronchi with bronchial wall thickening extending to the lung periphery. Sweat chloride testing is normal. Histologic examination of the affected bronchi would most likely reveal which of the following?

  1. ANon-caseating granulomas with multinucleated giant cells in a lymphatic distribution
  2. BEosinophilic mucin plugs with Charcot-Leyden crystals and fungal hyphae invading the bronchial wall
  3. CDestruction of bronchial walls with chronic inflammatory infiltrate and replacement of normal respiratory epithelium by fibrosis
  4. DDiffuse alveolar damage with hyaline membrane formation
  5. EGranulomatous inflammation with caseating necrosis and Langhans giant cells
Show answer
Answer: C. Destruction of bronchial walls with chronic inflammatory infiltrate and replacement of normal respiratory epithelium by fibrosis

Bronchiectasis is permanent dilation of bronchi and bronchioles caused by chronic inflammation and destruction of the muscular and elastic components of the bronchial wall, most often from recurrent or severe infection. Causes include cystic fibrosis, recurrent bacterial infections, primary ciliary dyskinesia, and immunodeficiency. Histologically, the airway wall shows chronic inflammatory infiltrate, destruction of the normal bronchial architecture, and fibrous scarring that replaces the respiratory epithelium, with marked bronchial dilation apparent on imaging. This patient's normal sweat chloride makes cystic fibrosis unlikely, pointing toward another cause of recurrent infection such as primary ciliary dyskinesia, but the underlying histologic destruction and fibrosis pattern is shared across all causes of bronchiectasis.

  • A. Non-caseating granulomas in a lymphatic distribution are characteristic of sarcoidosis.
  • B. This describes allergic bronchopulmonary aspergillosis with fungal invasion, which can cause bronchiectasis but is not the general histologic finding and this patient lacks eosinophilic/allergic features described here.
  • D. Diffuse alveolar damage with hyaline membranes describes acute respiratory distress syndrome, not bronchiectasis.
  • E. Caseating granulomas with Langhans giant cells are characteristic of tuberculosis, not simple bronchiectasis.
Educational objective: Bronchiectasis results from chronic infection or inflammation causing irreversible destruction and fibrotic replacement of the bronchial wall, with causes including cystic fibrosis, recurrent infections, and immune or ciliary defects.
20

A 6-month-old girl presents with failure to thrive, frequent oily, foul-smelling stools, and recurrent respiratory infections with Pseudomonas aeruginosa isolated on sputum culture. Her parents report that she tastes salty when kissed. Genetic testing reveals a deletion of a phenylalanine residue at position 508 of a chloride channel protein, causing the protein to be misfolded and degraded before reaching the cell membrane. Which of the following is the most appropriate confirmatory test for this diagnosis?

  1. ASerum immunoreactive trypsinogen level
  2. BNasal potential difference measurement
  3. CSerum alpha-1-antitrypsin level
  4. DPilocarpine iontophoresis sweat chloride test
  5. EFecal elastase level
Show answer
Answer: D. Pilocarpine iontophoresis sweat chloride test

This infant has classic features of cystic fibrosis, caused here by the ΔF508 mutation, the most common CFTR mutation, which results in a misfolded chloride channel protein that is degraded by the proteasome before reaching the apical membrane of epithelial cells. Loss of functional CFTR impairs chloride (and secondarily sodium and water) transport, producing thick, dehydrated secretions in the lungs and pancreas and abnormally high chloride concentration in sweat due to defective chloride reabsorption in sweat ducts. The pilocarpine iontophoresis sweat chloride test is the gold-standard confirmatory diagnostic test, with a sweat chloride concentration greater than 60 mEq/L on two occasions being diagnostic. Newborn screening measures immunoreactive trypsinogen, but an elevated level only prompts further testing and is not itself confirmatory.

  • A. Immunoreactive trypsinogen is used for newborn screening, not confirmatory diagnosis; it can be elevated in other neonatal conditions as well.
  • B. Nasal potential difference can support the diagnosis in equivocal cases but is not the standard first-line confirmatory test.
  • C. Alpha-1-antitrypsin level evaluates for a different genetic disease causing emphysema and liver disease, unrelated to this presentation.
  • E. Fecal elastase assesses pancreatic exocrine function and supports a diagnosis of pancreatic insufficiency but does not confirm cystic fibrosis itself.
Educational objective: The ΔF508 CFTR mutation causes a misfolded chloride channel that is degraded before reaching the membrane, and the diagnosis of cystic fibrosis is confirmed with an elevated sweat chloride concentration on pilocarpine iontophoresis testing.
21

A 58-year-old man with a 40-pack-year smoking history undergoes pulmonary function testing for progressive dyspnea on exertion. Results show: FEV1 = 1.8 L (55% predicted), FVC = 3.2 L (78% predicted), FEV1/FVC = 56% (predicted > 70%), and total lung capacity = 7.8 L (increased). Which of the following best describes this spirometric pattern?

  1. ANormal spirometry with low effort
  2. BMixed obstructive-restrictive pattern
  3. CRestrictive pattern with normal diffusion capacity
  4. DRestrictive pattern with reduced lung volumes
  5. EObstructive pattern with air trapping
Show answer
Answer: E. Obstructive pattern with air trapping

A reduced FEV1/FVC ratio below the predicted lower limit (here 56%, well under the ~70% threshold) indicates airflow obstruction, since expiratory flow is disproportionately reduced relative to total volume exhaled. The increased total lung capacity reflects air trapping from small airway collapse and loss of elastic recoil, classic for emphysema/COPD. In restrictive disease, both FEV1 and FVC fall proportionally, keeping the FEV1/FVC ratio normal or increased, and total lung capacity is reduced rather than increased. This patient's smoking history and hyperinflation support an obstructive process.

  • A. The abnormal FEV1/FVC ratio and increased TLC indicate true pathology, not poor effort.
  • B. There is no evidence of a superimposed restrictive component such as reduced TLC.
  • C. Restrictive patterns show decreased TLC, and diffusion capacity is not assessed by this data.
  • D. Restrictive disease would show reduced, not increased, total lung capacity.
Educational objective: A decreased FEV1/FVC ratio defines an obstructive ventilatory pattern, whereas a normal or increased ratio with reduced lung volumes defines a restrictive pattern.

Restrictive Lung Disease

3 questions
22

A 34-year-old African American woman presents with dry cough, exertional dyspnea, and erythema nodosum on her shins. Chest x-ray shows bilateral hilar lymphadenopathy. Serum calcium is 11.4 mg/dL (reference 8.4-10.2), and serum ACE level is elevated. Lung biopsy shows noncaseating granulomas composed of epithelioid histiocytes and multinucleated giant cells. Which of the following mechanisms best explains this patient's hypercalcemia?

  1. AEctopic parathyroid hormone production by epithelioid histiocytes
  2. BGranulomas secrete parathyroid hormone-related peptide into the systemic circulation
  3. CActivated macrophages within granulomas convert 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D
  4. DOsteolytic bone metastases releasing calcium from the skeleton
  5. EDecreased renal calcium excretion due to granulomatous interstitial nephritis
Show answer
Answer: C. Activated macrophages within granulomas convert 25-hydroxyvitamin D to 1,25-dihydroxyvitamin D

In sarcoidosis, activated macrophages within noncaseating granulomas express 1-alpha-hydroxylase, which converts 25-hydroxyvitamin D into the active form, 1,25-dihydroxyvitamin D (calcitriol), independent of renal and parathyroid regulation. Calcitriol increases intestinal calcium absorption and bone resorption, leading to hypercalcemia and hypercalciuria. This mechanism explains why hypercalcemia in sarcoidosis can worsen with sun exposure or vitamin D supplementation and improves with glucocorticoid therapy, which suppresses macrophage activity. ACE elevation reflects granuloma burden but does not cause hypercalcemia.

  • A. Granulomas do not produce parathyroid hormone; sarcoidosis-related hypercalcemia is PTH-independent and typically suppresses endogenous PTH.
  • B. PTHrP-mediated hypercalcemia is characteristic of certain malignancies (e.g., squamous cell lung cancer), not sarcoidosis.
  • D. There is no evidence of malignancy or bone metastases in this presentation.
  • E. While sarcoidosis can cause nephrocalcinosis, decreased renal excretion is not the primary mechanism of hypercalcemia here.
Educational objective: Hypercalcemia in sarcoidosis results from macrophage 1-alpha-hydroxylase activity converting vitamin D to its active form within granulomas.
23

A 61-year-old man who worked for 25 years sandblasting metal surfaces in a manufacturing plant presents with progressive dyspnea and a chronic cough. Chest x-ray shows multiple small nodular opacities in the upper lung zones with calcification of the hilar lymph nodes in a peripheral ring-like pattern. Pulmonary function tests show a restrictive pattern. Which of the following is the most likely diagnosis?

  1. ABerylliosis
  2. BHypersensitivity pneumonitis
  3. CCoal worker's pneumoconiosis
  4. DAsbestosis
  5. ESilicosis
Show answer
Answer: E. Silicosis

Silicosis results from chronic inhalation of crystalline silica particles, common in sandblasting, mining, and quarrying. It characteristically produces upper lobe-predominant nodular opacities and eggshell calcification of hilar lymph nodes, a peripheral rim of calcification around enlarged nodes, which is highly specific for this disease. Silica particles are toxic to macrophages, causing cell death and release of inflammatory mediators that promote fibrosis, and silicosis also increases susceptibility to tuberculosis by impairing macrophage function. Coal worker's pneumoconiosis and asbestosis have different radiographic patterns and occupational exposures.

  • A. Berylliosis resembles sarcoidosis with noncaseating granulomas, not eggshell calcification, and is linked to aerospace or electronics exposure.
  • B. Hypersensitivity pneumonitis follows organic antigen exposure, not mineral dust, and does not cause eggshell calcification.
  • C. Coal worker's pneumoconiosis causes diffuse small nodular opacities but not the eggshell calcification seen with silica exposure.
  • D. Asbestosis typically causes lower lobe-predominant fibrosis with pleural plaques, not eggshell calcification or sandblasting exposure.
Educational objective: Eggshell calcification of hilar lymph nodes on chest imaging is a classic finding of silicosis from occupational silica dust exposure.
24

A 70-year-old retired shipyard worker with a 30-year history of asbestos exposure presents with progressive dyspnea, dull chest pain, and weight loss. CT shows diffuse, irregular thickening and nodularity of the pleura with a small pleural effusion, without a discrete lung mass. Pleural biopsy shows a malignant tumor composed of cells with both epithelioid and spindle-cell (sarcomatoid) components. Immunohistochemistry is positive for calretinin and WT-1. Which of the following is the most likely diagnosis?

  1. AMalignant mesothelioma
  2. BSmall cell lung carcinoma
  3. CMetastatic renal cell carcinoma
  4. DBronchogenic adenocarcinoma with pleural metastasis
  5. ESquamous cell carcinoma of the lung
Show answer
Answer: A. Malignant mesothelioma

Malignant mesothelioma arises from the mesothelial lining of the pleura and is strongly associated with asbestos exposure, with a long latency period often exceeding 20-40 years. It characteristically presents with diffuse pleural thickening, nodularity, and effusion rather than a discrete parenchymal mass, and the biphasic epithelioid-sarcomatoid histology with positive calretinin and WT-1 immunostaining is diagnostic, distinguishing it from pulmonary adenocarcinoma, which stains positive for TTF-1 and napsin A. Asbestos exposure also increases the risk of bronchogenic carcinoma, and the combination of smoking with asbestos exposure synergistically raises this risk, but the diffuse pleural pattern and immunoprofile here point to mesothelioma.

  • B. Small cell carcinoma arises centrally and shows small cells with scant cytoplasm and neuroendocrine markers, not this biphasic pattern.
  • C. Renal cell carcinoma metastases would show clear cell or papillary histology and a renal primary, not calretinin/WT-1 positive biphasic tumor.
  • D. Adenocarcinoma would typically show a discrete pulmonary mass and stain positive for TTF-1, not calretinin and WT-1.
  • E. Squamous cell carcinoma usually presents as a central lung mass with keratinization on histology, not diffuse pleural disease.
Educational objective: Malignant mesothelioma, linked to asbestos exposure, shows biphasic epithelioid-sarcomatoid histology and positive calretinin/WT-1 staining, distinguishing it from metastatic pulmonary adenocarcinoma.

Pulmonary Vascular Disease

6 questions
25

A 58-year-old woman is brought to the emergency department because of sudden-onset shortness of breath and right-sided chest pain that worsens with inspiration. She underwent total knee replacement 10 days ago and has been immobile since. She has a history of breast cancer treated with tamoxifen. Temperature is 99.9°F (37.7°C), pulse is 118/min, respirations are 26/min, and blood pressure is 108/72 mm Hg. Pulse oximetry shows 89% on room air. The right calf is swollen and tender compared with the left. Lung auscultation is unremarkable. Which of the following is the most likely diagnosis?

  1. AAcute pulmonary embolism
  2. BSpontaneous pneumothorax
  3. CCommunity-acquired pneumonia
  4. DAcute exacerbation of asthma
  5. EAcute myocardial infarction
Show answer
Answer: A. Acute pulmonary embolism

This patient has multiple components of Virchow's triad: venous stasis from recent immobilization after surgery, hypercoagulability from malignancy and tamoxifen use, and likely endothelial injury from surgery, placing her at high risk for deep venous thrombosis and pulmonary embolism. The combination of sudden dyspnea, pleuritic chest pain, tachycardia, hypoxemia, and a swollen tender calf (suggesting DVT as the embolic source) is the classic presentation of acute PE. Lung auscultation is often normal or shows only mild findings in PE, unlike pneumonia or asthma. The clinical probability here (recent surgery, immobilization, malignancy, unilateral leg swelling) strongly favors thromboembolism over the other diagnoses.

  • B. Pneumothorax classically causes unilateral absent breath sounds and hyperresonance, not present in this patient.
  • C. Pneumonia typically presents with productive cough, fever, and focal consolidation on exam, which are absent here.
  • D. Asthma exacerbation presents with wheezing and a history of reactive airway disease, not reflected in this vignette.
  • E. MI would more likely present with substernal chest pressure and ECG/enzyme changes rather than pleuritic pain and unilateral leg swelling.
Educational objective: Virchow's triad (stasis, hypercoagulability, endothelial injury) predisposes to DVT/PE, which classically presents with sudden dyspnea, pleuritic chest pain, tachycardia, and hypoxemia.
26

A 24-year-old man is admitted after a motorcycle accident with a closed, comminuted fracture of the right femoral shaft, which is treated with intramedullary nailing. Thirty-six hours later, he develops acute confusion, dyspnea, and a petechial rash over the chest, axillae, and conjunctivae. Oxygen saturation is 88% on room air. Platelet count is 98,000/mm³. Which of the following best explains the pulmonary findings in this patient?

  1. AImmune complex deposition in the alveolar capillary basement membrane
  2. BDirect bacterial invasion of the pulmonary capillary endothelium
  3. CActivation of the extrinsic coagulation cascade by tissue thromboplastin
  4. DParadoxical embolization through a patent foramen ovale
  5. EMechanical capillary obstruction and toxic injury from free fatty acids
Show answer
Answer: E. Mechanical capillary obstruction and toxic injury from free fatty acids

Fat embolism syndrome classically follows long bone or pelvic fractures, presenting with the triad of respiratory distress, neurologic changes, and petechial rash, typically 24-72 hours after injury. Marrow fat is released into the venous circulation and travels to the pulmonary capillaries, causing both mechanical obstruction and local toxic injury as fat is hydrolyzed into free fatty acids by lipase, damaging capillary endothelium and inducing an inflammatory response. This produces capillary leak, alveolar hemorrhage, and the characteristic petechiae from microvascular occlusion and thrombocytopenia. The timing and petechial rash distinguish this from pulmonary thromboembolism, which presents acutely and without rash.

  • A. Immune complex-mediated lung injury is not the mechanism in fat embolism syndrome.
  • B. There is no evidence of infection such as fever with positive cultures; this is a sterile inflammatory process.
  • C. Disseminated intravascular coagulation can complicate severe trauma but does not primarily explain the fat-induced capillary injury.
  • D. Paradoxical embolism requires a right-to-left shunt and typically presents with systemic arterial occlusion, not this petechial rash pattern.
Educational objective: Fat embolism syndrome after long bone fracture causes respiratory distress, confusion, and petechiae through mechanical capillary obstruction and toxic endothelial injury by free fatty acids released from marrow fat.
27

A 32-year-old woman, gravida 2 para 1, develops sudden severe dyspnea, hypotension, and altered mental status immediately after a difficult vaginal delivery complicated by prolonged labor. Within minutes she becomes unresponsive and begins to seize. She then has profuse vaginal bleeding that does not clot. Blood pressure is 70/40 mm Hg, pulse is 140/min, and oxygen saturation is 78% on room air. Laboratory studies show platelets of 42,000/mm³, fibrinogen of 60 mg/dL (reference 200-400 mg/dL), and markedly prolonged prothrombin time. Which of the following is the most likely diagnosis?

  1. APeripartum cardiomyopathy
  2. BEclampsia
  3. CPostpartum hemorrhage from uterine atony
  4. DAmniotic fluid embolism
  5. EAcute pulmonary thromboembolism
Show answer
Answer: D. Amniotic fluid embolism

Amniotic fluid embolism is a peripartum catastrophe characterized by sudden cardiovascular collapse, respiratory failure, altered mental status or seizures, and disseminated intravascular coagulation, typically occurring during labor, delivery, or shortly after. Entry of amniotic fluid and fetal debris into the maternal circulation triggers a massive systemic inflammatory and anaphylactoid-like response, activating coagulation and causing profound DIC with hypofibrinogenemia and thrombocytopenia, as seen in this patient's labs. The rapid, dramatic onset with hypoxemia, hypotension, seizure, and consumptive coagulopathy distinguishes it from isolated postpartum hemorrhage or cardiomyopathy. Diagnosis is clinical, as there is no confirmatory laboratory test.

  • A. Peripartum cardiomyopathy develops over days to months postpartum with gradual heart failure symptoms, not this abrupt collapse.
  • B. Eclampsia presents with hypertension and seizures but does not typically cause this degree of hypoxemia and DIC immediately after delivery.
  • C. Uterine atony causes hemorrhage but does not explain the preceding respiratory failure, seizure, and consumptive coagulopathy.
  • E. Pulmonary thromboembolism causes hypoxemia and hypotension but does not explain the seizure and severe consumptive coagulopathy pattern.
Educational objective: Amniotic fluid embolism presents peripartum with sudden hypoxemia, hypotension, altered mental status, and disseminated intravascular coagulation from maternal exposure to amniotic fluid and fetal antigens.
28

A 29-year-old woman presents with progressive exertional dyspnea and fatigue over 8 months. She has no history of lung or connective tissue disease. Examination reveals a loud pulmonic component of the second heart sound and a left parasternal heave. Right heart catheterization shows a mean pulmonary artery pressure of 38 mmHg with normal pulmonary capillary wedge pressure. Lung biopsy shows concentric intimal fibrosis and plexiform lesions of small pulmonary arteries. Genetic testing reveals a mutation in a gene encoding a receptor in the transforming growth factor-beta superfamily. Loss of function of this receptor most directly leads to which of the following in pulmonary vascular smooth muscle and endothelial cells?

  1. AIncreased nitric oxide synthase activity causing vasodilation
  2. BEnhanced prostacyclin synthesis promoting vascular remodeling regression
  3. CDecreased endothelin-1 production reducing vasoconstriction
  4. DUnchecked proliferation due to loss of growth-inhibitory signaling
  5. EReduced potassium channel expression causing hyperpolarization
Show answer
Answer: D. Unchecked proliferation due to loss of growth-inhibitory signaling

This patient has heritable pulmonary arterial hypertension due to a BMPR2 mutation, the most common genetic cause of familial PAH. BMPR2 normally signals through the TGF-beta superfamily pathway to inhibit proliferation of pulmonary vascular smooth muscle and endothelial cells. Loss-of-function mutations in BMPR2 remove this growth-inhibitory signal, leading to uncontrolled proliferation, vascular remodeling, medial hypertrophy, and the pathognomonic plexiform lesions seen on biopsy. This results in progressively elevated pulmonary vascular resistance and right ventricular pressure overload, producing the loud P2 and parasternal heave on exam, with a normal wedge pressure confirming a precapillary (arterial) process rather than left heart disease.

  • A. BMPR2 loss does not increase nitric oxide synthase activity; endothelial dysfunction in PAH actually reduces nitric oxide bioavailability.
  • B. Prostacyclin synthesis is reduced in PAH, promoting vasoconstriction and remodeling rather than its regression.
  • C. Endothelin-1 is typically increased, not decreased, in pulmonary arterial hypertension, contributing to vasoconstriction.
  • E. Potassium channel dysfunction in PAH leads to membrane depolarization and vasoconstriction, not hyperpolarization.
Educational objective: BMPR2 mutations cause heritable pulmonary arterial hypertension by removing TGF-beta superfamily growth inhibition, leading to vascular smooth muscle and endothelial proliferation and plexiform lesion formation.
29

A 67-year-old man with a 45-pack-year smoking history and long-standing chronic obstructive pulmonary disease presents with increasing lower extremity edema and abdominal distension over the past 3 months. He has no chest pain. Examination shows jugular venous distension, a parasternal heave, hepatomegaly with hepatojugular reflux, and pitting edema to the knees bilaterally. Lungs show diffuse expiratory wheezes and decreased breath sounds. Echocardiography shows right ventricular hypertrophy and dilation with preserved left ventricular ejection fraction. Which of the following best explains the mechanism underlying this patient's cardiac findings?

  1. AAutoimmune-mediated destruction of the pulmonary vascular endothelium
  2. BChronic alveolar hypoxia causing pulmonary arterial vasoconstriction and increased right ventricular afterload
  3. CDirect toxic effect of cigarette smoke on right ventricular myocytes
  4. DChronic bronchial artery to pulmonary artery shunting increasing right ventricular preload
  5. ELeft ventricular diastolic dysfunction causing retrograde pulmonary venous hypertension
Show answer
Answer: B. Chronic alveolar hypoxia causing pulmonary arterial vasoconstriction and increased right ventricular afterload

Cor pulmonale is right ventricular hypertrophy, dilation, and eventual failure resulting from a primary lung disorder, most commonly COPD. Chronic alveolar hypoxia in COPD triggers hypoxic pulmonary vasoconstriction, a normally adaptive mechanism that becomes pathologic when sustained and diffuse, leading to chronically elevated pulmonary vascular resistance and pulmonary arterial pressure. This increases right ventricular afterload, causing right ventricular hypertrophy and, eventually, dilation and failure with systemic venous congestion (jugular venous distension, hepatomegaly, peripheral edema). The preserved left ventricular ejection fraction confirms that the right heart failure is secondary to pulmonary disease rather than left heart pathology.

  • A. Cor pulmonale from COPD is a hypoxia-driven vascular and mechanical process, not an autoimmune endothelial process.
  • C. Cigarette smoke primarily damages lung parenchyma and airways; it does not directly cause right ventricular myocyte toxicity in cor pulmonale.
  • D. Bronchial-pulmonary shunting is not the mechanism of cor pulmonale and does not explain the elevated pulmonary vascular resistance.
  • E. Preserved ejection fraction without evidence of left heart disease argues against left ventricular diastolic dysfunction as the cause.
Educational objective: Cor pulmonale results from chronic lung disease causing hypoxic pulmonary vasoconstriction, which raises pulmonary vascular resistance and right ventricular afterload, leading to right ventricular hypertrophy and failure.
30

A 50-year-old man is diagnosed with acute pulmonary embolism and started on intravenous unfractionated heparin, with warfarin added on day 1 and overlapped until therapeutic anticoagulation is achieved, at which point heparin is discontinued. Which of the following correctly describes the mechanisms of action and corresponding monitoring tests for these two drugs?

  1. AHeparin activates antithrombin III, monitored by PTT; warfarin inhibits vitamin K epoxide reductase, monitored by PT/INR
  2. BHeparin directly inhibits factor Xa, monitored by PT/INR; warfarin activates protein C, monitored by PTT
  3. CHeparin inhibits vitamin K epoxide reductase, monitored by PT/INR; warfarin activates antithrombin III, monitored by PTT
  4. DHeparin activates antithrombin III, monitored by PT/INR; warfarin inhibits antithrombin III, monitored by PTT
  5. EHeparin inhibits platelet aggregation, monitored by bleeding time; warfarin activates antithrombin III, monitored by PTT
Show answer
Answer: A. Heparin activates antithrombin III, monitored by PTT; warfarin inhibits vitamin K epoxide reductase, monitored by PT/INR

Unfractionated heparin binds to and activates antithrombin III, which then inactivates thrombin (factor IIa) and factor Xa; its anticoagulant effect is monitored using the partial thromboplastin time (PTT), with the dose titrated to a therapeutic range. Warfarin inhibits vitamin K epoxide reductase, blocking the gamma-carboxylation and activation of vitamin K-dependent clotting factors II, VII, IX, and X (and proteins C and S); its effect is monitored using the prothrombin time, reported as the international normalized ratio (PT/INR). Heparin and warfarin are overlapped initially because warfarin transiently depletes protein C before fully reducing procoagulant factors, creating a brief hypercoagulable window; heparin is continued until the INR is therapeutic to prevent this paradoxical thrombosis risk.

  • B. Heparin does not directly inhibit factor Xa (that describes agents like fondaparinux or direct Xa inhibitors), and warfarin does not activate protein C as its therapeutic mechanism.
  • C. This reverses the mechanisms and monitoring tests of heparin and warfarin.
  • D. Warfarin inhibits synthesis of vitamin K-dependent factors, not antithrombin III, and PT/INR, not PTT, is used for warfarin monitoring.
  • E. Heparin's primary anticoagulant mechanism is antithrombin activation, not platelet inhibition, and bleeding time is not used to monitor heparin.
Educational objective: Heparin activates antithrombin III and is monitored by PTT, while warfarin inhibits vitamin K epoxide reductase and is monitored by PT/INR; the two are overlapped in PE treatment because warfarin transiently causes a hypercoagulable state via protein C depletion.

Pleural Disease & Mediastinum

5 questions
31

A 62-year-old man with a history of congestive heart failure and recently diagnosed squamous cell lung carcinoma presents with worsening dyspnea. A thoracentesis is performed, yielding straw-colored fluid. Serum total protein is 7.2 g/dL, serum lactate dehydrogenase (LDH) is 180 U/L, pleural fluid total protein is 4.5 g/dL, and pleural fluid LDH is 260 U/L. Which of the following best characterizes this pleural effusion according to Light's criteria?

  1. ATransudate, because the pleural fluid to serum protein ratio is less than 0.5
  2. BExudate, because the pleural fluid to serum LDH ratio is less than 0.6
  3. CIndeterminate, because only one of the three Light's criteria is met
  4. DExudate, because the pleural fluid to serum protein ratio exceeds 0.5
  5. ETransudate, because the pleural fluid LDH is less than two-thirds the upper limit of normal serum LDH
Show answer
Answer: D. Exudate, because the pleural fluid to serum protein ratio exceeds 0.5

Light's criteria classify a pleural effusion as exudative if any one of the following is present: pleural fluid to serum protein ratio greater than 0.5, pleural fluid to serum LDH ratio greater than 0.6, or pleural fluid LDH greater than two-thirds the upper limit of normal serum LDH. In this patient, the pleural fluid to serum protein ratio is 4.5/7.2 = 0.625, which exceeds 0.5, meeting criteria for an exudate on this basis alone; only one criterion needs to be met to classify the effusion as exudative. This is consistent with a malignant effusion from his lung carcinoma, since exudates result from increased capillary permeability or impaired lymphatic drainage, in contrast to transudates caused by increased hydrostatic or decreased oncotic pressure as in isolated heart failure.

  • A. The calculated protein ratio of 0.625 exceeds 0.5, meeting criteria for an exudate, not a transudate.
  • B. The pleural fluid to serum LDH ratio here is 260/180 = 1.44, which is greater than 0.6, also supporting exudate, not contradicting it via this reasoning, making this statement's criterion value incorrect.
  • C. Only one of Light's three criteria needs to be met to classify an effusion as exudative; this effusion meets at least one (and here, more than one) criterion, so it is a definitive exudate, not indeterminate.
  • E. This statement inverts the criterion; an LDH less than two-thirds the upper limit of normal would support a transudate, but the protein ratio alone already confirms an exudate.
Educational objective: An effusion is exudative by Light's criteria if it meets any one of three thresholds: pleural/serum protein ratio >0.5, pleural/serum LDH ratio >0.6, or pleural fluid LDH exceeding two-thirds the upper limit of normal serum LDH.
32

A 19-year-old man who is 6 ft 4 in (193 cm) tall and weighs 135 lb (61 kg) presents with sudden-onset right-sided chest pain and dyspnea that began while he was sitting in class. He has no history of trauma or lung disease and does not smoke. Vital signs are temperature 98.6°F (37°C), blood pressure 122/78 mmHg, pulse 98/min, respirations 22/min, and oxygen saturation 94% on room air. Examination shows decreased breath sounds and hyperresonance to percussion over the right hemithorax, with the trachea midline. Chest x-ray shows a visceral pleural line with absence of lung markings peripheral to it on the right side. Which of the following best explains this patient's condition?

  1. ARupture of a bronchogenic cyst into the pleural space
  2. BRupture of an apical subpleural bleb
  3. CLaceration of the parietal pleura by a fractured rib
  4. DTransdiaphragmatic passage of air from a perforated viscus
  5. EErosion of the visceral pleura by a necrotic tumor
Show answer
Answer: B. Rupture of an apical subpleural bleb

Primary spontaneous pneumothorax occurs classically in tall, thin young men due to rupture of apical subpleural blebs, which are small air-filled sacs thought to arise from increased mechanical stress and reduced perfusion at the lung apex. Air leaks from the alveolus into the pleural space, collapsing the lung and causing ipsilateral hyperresonance and decreased breath sounds with a midline trachea (simple, not tension, pneumothorax). Risk factors include smoking, male sex, and a tall, thin body habitus (Marfan-like thoracic configuration). This differs from secondary spontaneous pneumothorax, which occurs in patients with underlying lung disease such as COPD or cystic lung disease.

  • A. Bronchogenic cysts are rare congenital lesions and not the typical cause in this demographic.
  • C. No trauma history is given, and rib fracture is a cause of traumatic, not spontaneous, pneumothorax.
  • D. There is no abdominal pathology or peritoneal signs suggesting a perforated viscus.
  • E. There is no evidence of malignancy in this young patient with an acute, isolated event.
Educational objective: Primary spontaneous pneumothorax in tall, thin young men typically results from rupture of apical subpleural blebs.
33

A 24-year-old man is brought to the emergency department after a motor vehicle collision. He is in severe respiratory distress. Blood pressure is 82/50 mmHg, pulse is 128/min, and oxygen saturation is 85% on room air. Examination shows distended neck veins, tracheal deviation to the left, and absent breath sounds with hyperresonance over the right hemithorax. Which of the following is the most appropriate immediate next step in management?

  1. APortable chest x-ray to confirm the diagnosis
  2. BEmergent intubation and mechanical ventilation
  3. CChest CT scan with intravenous contrast
  4. DNeedle decompression of the right second intercostal space
  5. EPericardiocentesis
Show answer
Answer: D. Needle decompression of the right second intercostal space

This patient has tension pneumothorax, a clinical diagnosis based on respiratory distress, hypotension, tracheal deviation away from the affected side, distended neck veins, and ipsilateral absent breath sounds with hyperresonance. It is a life-threatening emergency caused by accumulating pleural air that compresses the lung and shifts the mediastinum, kinking the vena cava and reducing venous return, which causes obstructive shock. Immediate needle decompression at the second intercostal space, midclavicular line, converts the tension pneumothorax to a simple one and must precede imaging. Definitive management with chest tube thoracostomy follows decompression.

  • A. Imaging delays life-saving treatment in a patient with a clinical diagnosis and hemodynamic instability.
  • B. Positive pressure ventilation can worsen tension pneumothorax before decompression and does not address the underlying problem.
  • C. CT delays treatment and is contraindicated in an unstable patient; it is not the immediate step.
  • E. The findings indicate pneumothorax, not cardiac tamponade, which would show muffled heart sounds and no tracheal deviation.
Educational objective: Tension pneumothorax is a clinical diagnosis requiring immediate needle decompression before imaging or other interventions.
34

A 58-year-old man is hospitalized with fever and productive cough for 5 days. Temperature is 102.5°F (39.2°C), blood pressure is 110/70 mmHg, and pulse is 102/min. Chest x-ray shows right lower lobe consolidation with a moderate pleural effusion. Thoracentesis yields turbid yellow fluid with the following values: pH 7.10, glucose 32 mg/dL, lactate dehydrogenase 1200 U/L (serum LDH 180 U/L), and white blood cell count 45,000/mm³ with 90% neutrophils. Gram stain and culture of the fluid grow Streptococcus pneumoniae. Which of the following is the most likely diagnosis?

  1. AEmpyema
  2. BMalignant pleural effusion
  3. CChylothorax
  4. DHemothorax
  5. ETransudative effusion from heart failure
Show answer
Answer: A. Empyema

Empyema is frank pus or grossly infected fluid in the pleural space, diagnosed by pleural fluid with low pH (<7.20), low glucose (<60 mg/dL), high LDH, a markedly elevated neutrophil-predominant white cell count, and a positive Gram stain or culture, as seen here following untreated or inadequately treated bacterial pneumonia. The low pH and glucose reflect high metabolic activity of neutrophils and bacteria consuming glucose and producing acid. These findings meet Light's criteria for an exudate and indicate the need for tube thoracostomy drainage in addition to antibiotics, since antibiotics alone are insufficient once frank pus has formed. Untreated empyema can progress to a fibrothorax with a thickened pleural rind.

  • B. Malignant effusions are typically exudative with a positive cytology, not a positive bacterial culture with markedly low pH and glucose.
  • C. Chylothorax shows milky fluid with high triglycerides, not purulent fluid with positive bacterial culture.
  • D. Hemothorax is diagnosed by a pleural fluid hematocrit at least half of peripheral blood hematocrit, not by positive bacterial culture.
  • E. Heart failure produces a transudate with normal pH, normal glucose, low LDH, and a negative culture.
Educational objective: Empyema is defined by pleural fluid with low pH, low glucose, high LDH, and a positive Gram stain or culture, requiring drainage.
35

A 67-year-old man with a 30-year history of occupational asbestos exposure as a shipyard pipefitter presents with progressive dyspnea and right-sided chest pain. Chest CT shows diffuse, nodular thickening of the right pleura encasing the lung, without a clear primary mass elsewhere. Pleural biopsy shows atypical cells with papillary and tubular architecture. To distinguish this from metastatic pulmonary adenocarcinoma involving the pleura, which of the following immunohistochemical marker combinations is most useful?

  1. AS-100 and HMB-45 positive
  2. BCEA and Ber-EP4 positive, calretinin negative
  3. CCytokeratin 7 positive, cytokeratin 20 negative
  4. DTTF-1 positive, napsin A positive
  5. ECalretinin and WT-1 positive, CEA negative
Show answer
Answer: E. Calretinin and WT-1 positive, CEA negative

Malignant mesothelioma characteristically stains positive for calretinin, WT-1, and cytokeratin 5/6, and is negative for carcinoembryonic antigen (CEA), while metastatic pulmonary adenocarcinoma shows the opposite pattern (CEA and Ber-EP4 positive, calretinin negative). This immunophenotypic panel is essential because mesothelioma and adenocarcinoma can appear histologically similar, including papillary architecture, but have very different prognoses and treatments. Mesothelioma arises from mesothelial cells lining the pleura and is strongly associated with asbestos exposure after a long latency period. TTF-1 and napsin A are markers of pulmonary adenocarcinoma, not mesothelioma.

  • A. S-100 and HMB-45 are melanoma markers and are not relevant to this differential.
  • B. This CEA/Ber-EP4-positive, calretinin-negative pattern is characteristic of adenocarcinoma, not mesothelioma.
  • C. CK7+/CK20- is a nonspecific pattern seen in many adenocarcinomas including lung, and does not distinguish mesothelioma from adenocarcinoma.
  • D. TTF-1 and napsin A positivity indicates pulmonary adenocarcinoma, not mesothelioma.
Educational objective: Mesothelioma is calretinin and WT-1 positive and CEA negative, the opposite pattern of metastatic pulmonary adenocarcinoma.

Infectious Pulmonary Disease

10 questions
36

A 54-year-old man presents with fever, chills, and a cough productive of rust-colored sputum for 2 days. Temperature is 103°F (39.4°C), blood pressure is 118/76 mmHg, pulse is 108/min, and respirations are 26/min. Examination shows dullness to percussion and bronchial breath sounds over the right lower lung field. Chest x-ray shows dense consolidation of the entire right lower lobe with air bronchograms. Sputum Gram stain shows gram-positive, lancet-shaped diplococci surrounded by a capsule. Which of the following is the most likely causative organism?

  1. AStaphylococcus aureus
  2. BKlebsiella pneumoniae
  3. CHaemophilus influenzae
  4. DMycoplasma pneumoniae
  5. EStreptococcus pneumoniae
Show answer
Answer: E. Streptococcus pneumoniae

Streptococcus pneumoniae is the most common cause of community-acquired typical (lobar) pneumonia, characteristically presenting with acute fever, productive rust-colored or blood-tinged sputum, and lobar consolidation on imaging. Its polysaccharide capsule is the main virulence factor, enabling evasion of phagocytosis, and is the target of pneumococcal vaccines. The Gram stain finding of gram-positive, lancet-shaped (pointed) diplococci in pairs is classic and distinguishes it from other gram-positive cocci. Lobar consolidation reflects alveolar filling with fibrin-rich exudate that spreads contiguously through the lobe via the pores of Kohn.

  • A. Staphylococcus aureus appears as gram-positive cocci in clusters, not lancet-shaped diplococci in pairs.
  • B. Klebsiella causes lobar pneumonia with currant jelly sputum in alcoholics but appears as a gram-negative encapsulated rod, not a gram-positive diplococcus.
  • C. Haemophilus influenzae is a small gram-negative coccobacillus, not a gram-positive diplococcus.
  • D. Mycoplasma is a gram-indeterminate organism lacking a cell wall and causes an atypical, interstitial pattern, not lobar consolidation.
Educational objective: Streptococcus pneumoniae, identified by gram-positive lancet-shaped diplococci, is the leading cause of typical lobar pneumonia.
37

A 17-year-old boy presents with a 1-week history of low-grade fever, malaise, and a persistent dry cough. Temperature is 100.8°F (38.2°C), blood pressure is 112/70 mmHg, and pulse is 88/min. Lung auscultation is unremarkable despite the symptoms. Chest x-ray shows diffuse, patchy interstitial infiltrates bilaterally, more severe than expected from the physical examination findings. Laboratory studies show mild anemia, and a peripheral blood smear shows red blood cell agglutination at room temperature that resolves with warming. Which of the following best explains this patient's anemia?

  1. AAutoantibodies against erythropoietin receptors suppressing marrow production
  2. BMicroangiopathic hemolysis from fibrin deposition in small vessels
  3. CDirect bacterial invasion and lysis of red blood cells
  4. DIgM antibodies against red blood cell I antigen causing complement-mediated hemolysis
  5. EIgG antibodies against the Rh antigen causing extravascular hemolysis
Show answer
Answer: D. IgM antibodies against red blood cell I antigen causing complement-mediated hemolysis

Mycoplasma pneumoniae infection triggers production of IgM autoantibodies directed against the I antigen on red blood cells; these cold agglutinins bind erythrocytes at low temperatures in peripheral circulation and fix complement, causing intravascular hemolysis and agglutination that reverses with warming. This is thought to result from cross-reactivity or polyclonal B-cell activation following infection and classically accompanies the atypical, interstitial pneumonia pattern with a dry cough and exam findings milder than the chest x-ray suggests. Mycoplasma lacks a cell wall, so it cannot be seen on Gram stain, and it is diagnosed serologically or by PCR. The clinical mismatch between radiographic severity and mild examination findings is a classic clue to atypical pneumonia.

  • A. Autoantibodies to erythropoietin receptors are not a recognized mechanism of Mycoplasma-associated anemia.
  • B. There is no evidence of schistocytes, thrombocytopenia, or organ ischemia to suggest a microangiopathic process.
  • C. Mycoplasma does not directly invade or lyse erythrocytes; its hemolysis is immune-mediated.
  • E. This describes warm autoimmune hemolytic anemia, which is IgG-mediated and not typically cold-reactive or linked to Mycoplasma.
Educational objective: Mycoplasma pneumoniae induces IgM cold agglutinins against the I antigen, causing complement-mediated hemolytic anemia.
38

A 62-year-old man returns from a business trip and stayed in a hotel with a large decorative fountain. He now presents with high fever, confusion, and watery diarrhea for 2 days. Temperature is 103.5°F (39.7°C), blood pressure is 100/64 mmHg, and pulse is 110/min. Chest x-ray shows patchy consolidation in the right lower lobe. Laboratory studies show serum sodium 128 mEq/L and mildly elevated liver transaminases. Sputum Gram stain shows numerous neutrophils but no organisms are visualized. Which of the following is most likely to establish the diagnosis?

  1. ASputum culture on blood agar
  2. BSerum galactomannan assay
  3. CCold agglutinin titer
  4. DUrinary antigen test
  5. ESputum Giemsa stain
Show answer
Answer: D. Urinary antigen test

Legionella pneumophila is a gram-negative intracellular organism that stains poorly with standard Gram stain, requiring silver stain or special culture media (buffered charcoal yeast extract agar) for direct visualization. The Legionella urinary antigen test is the most rapid and widely used diagnostic method in clinical practice, detecting a serogroup 1 antigen with high sensitivity and specificity, and remains positive even after antibiotics are started. The clinical picture of severe pneumonia with extrapulmonary features, including hyponatremia, gastrointestinal symptoms, confusion, and elevated liver enzymes, strongly suggests Legionella, which is acquired from contaminated water sources such as air conditioning systems, hot tubs, or fountains rather than person-to-person transmission.

  • A. Legionella grows only on specialized buffered charcoal yeast extract agar, not standard blood agar.
  • B. Galactomannan is a marker for invasive aspergillosis, not Legionella infection.
  • C. Cold agglutinins are associated with Mycoplasma pneumoniae, not Legionella.
  • E. Giemsa stain is used for organisms such as Pneumocystis or blood parasites, not Legionella.
Educational objective: Legionella pneumonia, linked to contaminated water sources and extrapulmonary findings like hyponatremia, is best diagnosed by urinary antigen testing.
39

A 56-year-old man with a 20-year history of chronic alcohol use disorder is brought to the emergency department after being found disoriented at home. Temperature is 102.9°F (39.4°C), blood pressure is 96/60 mmHg, and pulse is 118/min. He has a cough productive of thick, blood-tinged, gelatinous sputum. Chest x-ray shows dense consolidation of the right upper lobe with a visible air-fluid level suggestive of cavitation. Sputum culture grows a mucoid, lactose-fermenting gram-negative rod. Which of the following virulence factors is most responsible for the mucoid appearance of this organism's colonies and sputum?

  1. AExotoxin A
  2. BPyocyanin pigment production
  3. CLipooligosaccharide endotoxin
  4. DThick polysaccharide capsule
  5. EIgA protease
Show answer
Answer: D. Thick polysaccharide capsule

Klebsiella pneumoniae possesses a thick polysaccharide capsule that confers the characteristic mucoid colony morphology on culture and produces the thick, viscous, currant jelly sputum seen clinically. This capsule also impairs phagocytosis and contributes to the organism's virulence and propensity to cause necrotizing lobar pneumonia with cavitation, classically affecting the upper lobes in patients with alcohol use disorder or diabetes mellitus who have impaired airway protective reflexes and aspiration risk. The gelatinous, blood-tinged sputum results from capsule material mixed with necrotic lung tissue and blood. Klebsiella is a lactose-fermenting gram-negative rod of the Enterobacteriaceae family.

  • A. Exotoxin A is a virulence factor of Pseudomonas aeruginosa, not Klebsiella.
  • B. Pyocyanin is a blue-green pigment produced by Pseudomonas aeruginosa, not Klebsiella.
  • C. While Klebsiella has lipopolysaccharide (endotoxin) contributing to systemic illness, it is not responsible for the mucoid colony or sputum appearance.
  • E. IgA protease is a virulence factor of mucosal pathogens like Streptococcus pneumoniae and Haemophilus influenzae, not primarily responsible for Klebsiella's mucoid appearance.
Educational objective: Klebsiella pneumoniae's thick polysaccharide capsule produces the classic mucoid, currant jelly sputum in alcoholic patients with necrotizing lobar pneumonia.
40

A 34-year-old man with HIV infection is found to have a CD4+ T-lymphocyte count of 150/mm³ (reference >500) on routine follow-up. He is asymptomatic and currently takes no medications. His viral load is 45,000 copies/mL. To prevent an opportunistic pulmonary infection characterized by bilateral ground-glass opacities and foamy alveolar exudates on biopsy, which of the following is the most appropriate next step in management?

  1. AStart voriconazole
  2. BStart azithromycin
  3. CStart trimethoprim-sulfamethoxazole
  4. DStart isoniazid and pyridoxine
  5. EStart fluconazole
Show answer
Answer: C. Start trimethoprim-sulfamethoxazole

Patients with HIV and a CD4+ count below 200/mm³ are at high risk for Pneumocystis jirovecii pneumonia and require prophylaxis with trimethoprim-sulfamethoxazole, which inhibits sequential steps in folate synthesis (dihydropteroate synthase and dihydrofolate reductase) in the organism. P. jirovecii pneumonia classically presents with bilateral ground-glass opacities on imaging and disc-shaped yeast forms seen with silver stain of alveolar exudate. Prophylaxis is continued until the CD4+ count rises above 200/mm³ for at least 3 months on antiretroviral therapy. TMP-SMX also provides prophylaxis against Toxoplasma gondii and some bacterial infections.

  • A. Voriconazole targets Aspergillus and other molds, not Pneumocystis jirovecii.
  • B. Azithromycin is used for Mycobacterium avium complex prophylaxis, indicated at CD4+ counts below 50/mm³.
  • D. Isoniazid with pyridoxine is used for latent tuberculosis treatment, not Pneumocystis prophylaxis, and requires a positive PPD/IGRA first.
  • E. Fluconazole is not recommended for routine primary prophylaxis against endemic fungal infections in HIV in current guidelines.
Educational objective: HIV-infected patients with a CD4+ count below 200/mm³ should receive trimethoprim-sulfamethoxazole prophylaxis against Pneumocystis jirovecii pneumonia.
41

A 27-year-old woman who emigrated from the Philippines 2 years ago undergoes a routine health screening. She has no symptoms and received the BCG vaccine as a child. A tuberculin skin test shows 14 mm of induration at 48 hours. An interferon-gamma release assay (IGRA) is positive. Chest radiograph is normal. Which of the following best explains the cellular mechanism responsible for the central necrosis seen in tuberculous granulomas?

  1. ADirect cytotoxic effect of mycobacterial exotoxin on epithelial cells
  2. BActivated macrophages killing mycobacteria via reactive oxygen species and lysosomal enzymes
  3. CIgE-mediated mast cell degranulation surrounding infected tissue
  4. DNeutrophil elastase-mediated proteolysis of lung parenchyma
  5. EComplement-mediated lysis of infected macrophages
Show answer
Answer: B. Activated macrophages killing mycobacteria via reactive oxygen species and lysosomal enzymes

Caseating granulomas in tuberculosis form when CD4+ T helper 1 cells activate macrophages via interferon-gamma, causing the macrophages to try to kill intracellular Mycobacterium tuberculosis using reactive oxygen species and lysosomal enzymes; this process also damages surrounding host tissue, producing the characteristic central caseous necrosis. The IGRA result being positive in this patient confirms sensitization to M. tuberculosis antigens (not cross-reactive with BCG, unlike the skin test), indicating latent infection rather than active disease given the normal chest radiograph and absence of symptoms. A positive IGRA with no symptoms and normal imaging is managed as latent TB. M. tuberculosis has no classic exotoxin; its pathogenesis depends on an intracellular immune-mediated response rather than direct toxin damage.

  • A. Mycobacterium tuberculosis does not produce an exotoxin; tissue damage results from the host immune response.
  • C. Tuberculosis granuloma formation is a cell-mediated (Th1) response, not an IgE-mediated hypersensitivity reaction.
  • D. Neutrophils are not the primary effector cells in granulomatous caseous necrosis; macrophages and T cells predominate.
  • E. Granuloma necrosis is driven by activated macrophages, not complement-mediated lysis.
Educational objective: Caseating necrosis in tuberculous granulomas results from macrophage-mediated killing of mycobacteria via a Th1-driven, cell-mediated immune response that also damages host tissue.
42

A 58-year-old man with a history of latent tuberculosis diagnosed 10 years ago begins treatment with infliximab for rheumatoid arthritis. Eight months later, he develops low-grade fever, night sweats, and a chronic productive cough with blood-streaked sputum. Chest CT shows a thick-walled cavity in the right upper lobe apex. Which of the following best explains the apical localization of this lesion?

  1. ARelatively higher tissue oxygen tension favoring growth of an obligate aerobe
  2. BGreater ventilation-perfusion ratio producing increased airway turbulence
  3. CHigher density of alveolar macrophages in the apical segments
  4. DDecreased lymphatic drainage in the lung apex compared to the base
  5. EReduced mucociliary clearance in upper lobe bronchi
Show answer
Answer: A. Relatively higher tissue oxygen tension favoring growth of an obligate aerobe

Mycobacterium tuberculosis is an obligate aerobe, and the lung apices have the highest oxygen tension relative to perfusion of any lung region, favoring reactivation and bacillary proliferation there. TNF-alpha, produced by activated macrophages, is essential for maintaining granuloma integrity and containing latent infection; infliximab blocks TNF-alpha, increasing the risk of reactivation of latent tuberculosis, as occurred in this patient. Reactivation classically produces a fibrocaseous cavitary lesion in the apical and posterior segments of the upper lobes due to this relatively high oxygen tension. While apical regions do have a high ventilation-perfusion ratio, this reflects relatively low blood flow (and hence oxygen delivery) relative to ventilation, which is precisely what raises local oxygen tension.

  • B. The ventilation-perfusion mismatch in the apex is relevant because it raises oxygen tension, not because it causes turbulence.
  • C. Macrophage density is not higher in the apex; oxygen tension is the key determinant of mycobacterial growth there.
  • D. Lymphatic drainage differences are not the established explanation for apical localization of reactivation tuberculosis.
  • E. Mucociliary clearance is not regionally reduced in the upper lobes; this is not the mechanism for apical TB reactivation.
Educational objective: Reactivation tuberculosis characteristically localizes to the lung apices because the high regional oxygen tension favors growth of the obligate aerobe Mycobacterium tuberculosis.
43

A 45-year-old man presents with fever, dry cough, and chest pain 2 weeks after exploring caves in Ohio that contained large amounts of bat guano. His temperature is 101.3°F (38.5°C). Chest radiograph shows bilateral hilar lymphadenopathy with patchy infiltrates. A lung biopsy is obtained. Which of the following histologic findings would most strongly support the diagnosis of this patient's infection?

  1. ABroad-based budding yeast forms 8-15 micrometers in diameter
  2. BSeptate hyphae branching at acute angles invading blood vessels
  3. CMacrophages containing numerous small oval yeast forms 2-4 micrometers in diameter
  4. DSpherules filled with endospores within granulomatous inflammation
  5. EEncapsulated yeast with narrow-based budding highlighted by mucicarmine stain
Show answer
Answer: C. Macrophages containing numerous small oval yeast forms 2-4 micrometers in diameter

Histoplasma capsulatum is found in soil contaminated with bird or bat droppings in the Ohio and Mississippi River valleys, and infection follows inhalation of microconidia. On histology within infected macrophages, it appears as small, oval, intracellular budding yeasts measuring 2-4 micrometers in diameter, often described as resembling a 'dot' inside macrophages on silver or Giemsa stains. The acute pulmonary presentation with hilar lymphadenopathy after cave exploration (a classic exposure history) supports this diagnosis. Treatment of moderate to severe disease is with amphotericin B, followed by itraconazole.

  • A. Broad-based budding yeasts are characteristic of Blastomyces dermatitidis, found in the Midwest and Southeast but not specifically linked to cave/bat exposure.
  • B. Septate hyphae with acute-angle branching describe Aspergillus, typically causing invasive disease in immunocompromised hosts.
  • D. Spherules with endospores are characteristic of Coccidioides immitis, associated with Southwest US exposure, not this presentation.
  • E. Encapsulated yeast with narrow-based budding describes Cryptococcus neoformans, associated with bird droppings (not bat guano caves) and more classically causing meningitis.
Educational objective: Histoplasma capsulatum, acquired from bird or bat droppings in the Ohio/Mississippi River valleys, appears as small intracellular oval yeasts within macrophages on histology.
44

A 38-year-old construction worker develops fever, cough, and diffuse joint pain 10 days after working on a site in Bakersfield, California, in the San Joaquin Valley. He also notes tender red nodules on his shins. Chest radiograph shows a right lower lobe infiltrate with ipsilateral hilar adenopathy. A lung biopsy shows large, thick-walled round structures containing numerous small round particles surrounded by granulomatous inflammation. Which of the following is the most likely causal organism?

  1. ACoccidioides immitis
  2. BParacoccidioides brasiliensis
  3. CCryptococcus neoformans
  4. DHistoplasma capsulatum
  5. EBlastomyces dermatitidis
Show answer
Answer: A. Coccidioides immitis

Coccidioides immitis is endemic to the deserts of the Southwestern United States, including California's San Joaquin Valley (hence the nickname 'Valley fever'), and causes an acute pulmonary illness that may be accompanied by erythema nodosum and arthralgias ('desert rheumatism'). In tissue, the organism forms large, thick-walled spherules filled with endospores, which is diagnostic on histology. Infection occurs after inhalation of arthroconidia from disturbed soil, as occurs with construction or excavation work. Most cases are self-limited in immunocompetent hosts, but disseminated disease can occur in immunosuppressed patients or certain ethnic groups.

  • B. Paracoccidioides brasiliensis causes a similar spherule-forming disease but is endemic to Latin America, not the Southwestern United States.
  • C. Cryptococcus neoformans produces narrow-based budding encapsulated yeast, not spherules, and is not linked to this geographic exposure.
  • D. Histoplasma capsulatum produces small intracellular budding yeasts, not spherules, and is linked to river valley bird/bat droppings exposure, not Southwest desert soil.
  • E. Blastomyces dermatitidis produces broad-based budding yeasts, not spherules with endospores.
Educational objective: Coccidioides immitis, endemic to the Southwestern US, forms thick-walled spherules containing endospores in tissue and classically causes erythema nodosum and arthralgias with pulmonary infection.
45

A 29-year-old woman with a long-standing history of asthma presents with worsening wheezing, low-grade fever, and productive cough with thick brownish mucus plugs. Serum total IgE is markedly elevated at 1200 IU/mL (reference <100), and serum precipitins against Aspergillus fumigatus are positive. Chest CT shows central bronchiectasis with mucoid impaction in the upper lobes. Skin testing shows an immediate wheal-and-flare reaction to Aspergillus antigen. Which of the following best describes the underlying pathophysiology of this patient's condition?

  1. ADirect angioinvasive fungal growth with vascular thrombosis and tissue infarction
  2. BFungal colonization of a pre-existing pulmonary cavity without hyphal tissue invasion
  3. CIgG-mediated complement activation causing immune complex deposition in alveolar capillaries
  4. DType I and type III hypersensitivity reactions to colonizing Aspergillus antigens without tissue invasion
  5. EType IV cell-mediated hypersensitivity granulomatous reaction to inhaled fungal spores
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Answer: D. Type I and type III hypersensitivity reactions to colonizing Aspergillus antigens without tissue invasion

This patient's presentation is classic for allergic bronchopulmonary aspergillosis (ABPA), which occurs in patients with asthma or cystic fibrosis and results from a combined type I (IgE-mediated, immediate hypersensitivity) and type III (IgG-mediated immune complex) hypersensitivity response to Aspergillus fumigatus colonizing the airways, without actual invasion of lung tissue by the fungus. Elevated total IgE, positive Aspergillus-specific IgE and IgG precipitins, and central bronchiectasis with mucoid impaction support this diagnosis. This contrasts with invasive aspergillosis, which involves angioinvasive septate hyphae with acute-angle branching in immunocompromised hosts, and aspergilloma, which is a fungus ball colonizing a pre-existing cavity (such as from prior tuberculosis) without hypersensitivity or invasion.

  • A. This describes invasive aspergillosis, which occurs in immunocompromised patients, not the hypersensitivity-driven disease in this asthmatic patient.
  • B. This describes an aspergilloma, which would not produce this degree of hypersensitivity (elevated IgE, precipitins) or bronchospasm.
  • C. While type III immune complex mechanisms do contribute to ABPA, isolated IgG-complement deposition does not account for the elevated IgE and immediate skin reactivity seen here.
  • E. ABPA is primarily type I and III hypersensitivity, not a type IV granulomatous reaction.
Educational objective: Allergic bronchopulmonary aspergillosis results from type I and type III hypersensitivity reactions to airway-colonizing Aspergillus fumigatus in patients with asthma or cystic fibrosis, without fungal tissue invasion.

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