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USMLE Step 1 · United States

USMLE Step 1 Cardiovascular system questions

49 original USMLE Step 1-style questions on cardiovascular system, each with the correct answer, an explanation, why the other options are wrong and the educational objective. Solve them in the quiz or read them below, grouped by section.

Questions49 with answers
Sections9
Options per question5
Time≈ 74 min
USMLE Step 1 Cardiovascular system: practice quizPick an answer to see the correct option and the explanation at once. Your best score is saved in this browser.

Cardiovascular physiology

5 questions
1

A 24-year-old healthy man participates in a study of venous return. A tourniquet previously placed on his lower limbs is released, causing a sudden increase in venous return to the heart. Left ventricular end-diastolic volume increases from 120 mL to 150 mL over the next several beats. Which of the following best explains the resulting change in stroke volume?

  1. AIncreased heart rate shortens diastolic filling time and increases contractility
  2. BDecreased wall tension reduces myocardial oxygen demand
  3. CIncreased sympathetic stimulation increases phospholamban phosphorylation
  4. DIncreased afterload increases the force generated during isovolumic contraction
  5. EIncreased sarcomere length increases the number of actin-myosin cross-bridges and calcium sensitivity of troponin C
Show answer
Answer: E. Increased sarcomere length increases the number of actin-myosin cross-bridges and calcium sensitivity of troponin C

The Frank-Starling mechanism describes how increased ventricular filling (preload) stretches cardiac sarcomeres toward their optimal length, increasing the number of actin-myosin cross-bridge interactions and increasing the calcium sensitivity of troponin C. This length-dependent activation increases the force of contraction and stroke volume without requiring a change in contractility, heart rate, or neurohormonal input. This intrinsic mechanism allows the heart to match output to venous return beat-to-beat.

  • A. Heart rate is not stated to change in this scenario; the mechanism described is preload-dependent, not rate-dependent.
  • B. This describes a consequence of the law of Laplace, not the mechanism by which stroke volume increases with preload.
  • C. No sympathetic activation is described; the effect is intrinsic to the myocardium, independent of autonomic input.
  • D. Afterload refers to resistance against ejection, not the stimulus described, which is increased venous return (preload).
Educational objective: The Frank-Starling mechanism increases stroke volume via length-dependent increases in myofilament calcium sensitivity and cross-bridge formation when preload increases.
2

A 35-year-old man is brought to the emergency department after a motor vehicle collision with a lacerated spleen. His blood pressure is 82/50 mm Hg, heart rate is 128/min, and skin is cool and clammy. Compared to baseline, which of the following best describes the change in afferent signaling from the carotid sinus and its immediate downstream effect on efferent autonomic output?

  1. AIncreased firing of aortic arch afferents directly stimulates adrenal medullary catecholamine release
  2. BDecreased firing of carotid sinus afferents reduces inhibition of the vasomotor center, increasing sympathetic outflow
  3. CIncreased firing of carotid sinus afferents increases inhibition of the vasomotor center, increasing sympathetic outflow
  4. DDecreased firing of carotid sinus afferents increases vagal efferent output to the sinoatrial node
  5. EDecreased firing of carotid sinus afferents decreases tonic inhibition of the nucleus ambiguus, increasing parasympathetic tone
Show answer
Answer: B. Decreased firing of carotid sinus afferents reduces inhibition of the vasomotor center, increasing sympathetic outflow

Hemorrhage lowers arterial pressure, reducing stretch on carotid sinus and aortic arch baroreceptors and decreasing their afferent firing rate to the nucleus tractus solitarius. Normally, baroreceptor afferents tonically inhibit the rostral ventrolateral medulla (vasomotor center) and excite the cardioinhibitory (vagal) centers; reduced firing removes this inhibition, so sympathetic outflow increases and vagal tone to the heart decreases. The net effect is tachycardia, increased contractility, and peripheral vasoconstriction to restore blood pressure. This reflex has a short latency and is the primary rapid compensatory mechanism in acute blood loss.

  • A. Baroreceptor afferents act centrally on the medulla, not by direct stimulation of the adrenal medulla.
  • C. Firing increases, not decreases, inhibition only when pressure rises; this is the opposite of what occurs in hypotension from hemorrhage.
  • D. Decreased afferent firing reduces, not increases, vagal efferent output, contributing to tachycardia rather than bradycardia.
  • E. Decreased afferent firing decreases parasympathetic tone and increases sympathetic tone, not the reverse.
Educational objective: Hypotension reduces baroreceptor afferent firing, disinhibiting the vasomotor center and increasing sympathetic outflow while reducing vagal tone, producing reflex tachycardia and vasoconstriction.
3

A 58-year-old man undergoes right heart catheterization for evaluation of dyspnea. His oxygen consumption is measured at 250 mL/min. Arterial oxygen content is 20 mL O2/dL and mixed venous (pulmonary artery) oxygen content is 15 mL O2/dL. Using the Fick principle, what is his cardiac output in L/min?

  1. A5.0
  2. B10.0
  3. C2.5
  4. D50.0
  5. E1.25
Show answer
Answer: A. 5.0

The Fick principle states that cardiac output equals oxygen consumption divided by the arteriovenous oxygen content difference: CO = VO2 / (CaO2 − CvO2). The AV O2 difference is 20 − 15 = 5 mL O2/dL, which must be converted to mL O2/L of blood (×10) to match the units of VO2, giving 50 mL O2/L. CO = 250 mL/min ÷ 50 mL/L = 5.0 L/min. This method is used clinically to measure cardiac output when thermodilution is unavailable or when shunts are suspected.

  • B. This would require an AV O2 difference of 2.5 mL O2/dL, which is not given in the vignette.
  • C. This results from failing to convert the AV O2 difference from mL/dL to mL/L before dividing.
  • D. This value results from not converting dL to L at all, producing a tenfold overestimate error in the wrong direction.
  • E. This results from a unit conversion error that overestimates the AV O2 difference.
Educational objective: Cardiac output by the Fick principle equals oxygen consumption divided by the arteriovenous oxygen content difference (converted to consistent volume units).
4

Two patients undergo bedside examination of the jugular venous pulse. Patient A has a loud diastolic murmur best heard at the left lower sternal border with an opening snap, and her jugular venous waveform shows an unusually tall deflection just before each carotid upstroke. Patient B has an irregularly irregular pulse with no discernible organized atrial contraction on telemetry, and his jugular venous waveform lacks this same deflection entirely. Which of the following best explains the waveform findings in both patients?

  1. AThe deflection reflects closure of the pulmonic valve in Patient A and its absence reflects pulmonary hypertension in Patient B
  2. BThe deflection reflects passive atrial filling during ventricular systole in Patient A and its absence reflects complete heart block in Patient B
  3. CThe deflection reflects rapid ventricular filling in early diastole in Patient A and its absence reflects decreased venous return in Patient B
  4. DThe deflection reflects right atrial contraction against a stenotic tricuspid valve in Patient A and its absence reflects lack of coordinated atrial contraction in atrial fibrillation in Patient B
  5. EThe deflection reflects right ventricular isovolumic contraction in Patient A and its absence reflects tricuspid regurgitation in Patient B
Show answer
Answer: D. The deflection reflects right atrial contraction against a stenotic tricuspid valve in Patient A and its absence reflects lack of coordinated atrial contraction in atrial fibrillation in Patient B

The a wave of the jugular venous pulse corresponds to right atrial contraction. In tricuspid stenosis, the right atrium contracts against a fixed, narrowed orifice, generating a markedly elevated resistance and producing a giant a wave. In atrial fibrillation, there is no organized, coordinated atrial contraction, so no a wave is generated at all, regardless of tricuspid valve function. Recognizing these waveform patterns helps localize valvular and rhythm pathology at the bedside without invasive monitoring.

  • A. Pulmonic valve closure corresponds to the second heart sound, not a jugular venous waveform component.
  • B. The a wave reflects active atrial contraction, not passive filling, and complete heart block produces intermittent giant 'cannon' a waves, not absent a waves.
  • C. Rapid ventricular filling corresponds to the y descent, not the a wave, and decreased venous return does not eliminate the a wave.
  • E. Isovolumic contraction is a ventricular, not atrial, event and does not correspond to the a wave; tricuspid regurgitation produces a prominent systolic c-v wave, not loss of the a wave specifically from atrial fibrillation.
Educational objective: The jugular a wave represents right atrial contraction; it becomes giant when the atrium contracts against a stenotic tricuspid valve and disappears when atrial contraction is absent, as in atrial fibrillation.
5

A researcher records transmembrane potentials from isolated sinoatrial node cells and isolated ventricular myocytes. The sinoatrial node cells show a slow, spontaneous depolarization during diastole that is absent in the ventricular myocytes, which instead maintain a stable resting potential until stimulated. Which of the following ion currents is primarily responsible for this spontaneous diastolic depolarization in sinoatrial node cells?

  1. ADelayed rectifier K+ current (IK) responsible for repolarization
  2. BFunny current (If), a mixed Na+/K+ inward current activated by hyperpolarization
  3. CFast voltage-gated Na+ current (INa) activated at threshold potential
  4. DInward rectifier K+ current (IK1) that stabilizes resting membrane potential
  5. EL-type Ca2+ current (ICa-L) responsible for the plateau phase
Show answer
Answer: B. Funny current (If), a mixed Na+/K+ inward current activated by hyperpolarization

Pacemaker cells of the sinoatrial node lack a true resting potential and instead exhibit automaticity driven by phase 4 spontaneous depolarization. As the membrane potential becomes maximally negative after repolarization, hyperpolarization-activated cyclic nucleotide-gated (HCN) channels open, producing the funny current (If), a slow mixed Na+/K+ inward current that gradually depolarizes the cell toward threshold. Once threshold is reached, T-type and then L-type calcium channels open to generate the upstroke, since sinoatrial node cells lack significant fast Na+ channel activity. Ventricular myocytes express IK1, which keeps the resting potential stable and prevents spontaneous depolarization, explaining the absence of automaticity in these cells.

  • A. The delayed rectifier current mediates repolarization (phase 3), not spontaneous depolarization.
  • C. Fast Na+ current drives the rapid upstroke (phase 0) of ventricular action potentials and is largely absent/inactivated in nodal cells; it does not drive diastolic depolarization.
  • D. IK1 maintains a stable resting potential in ventricular myocytes and is largely absent in nodal cells, which is why nodal cells, not ventricular cells, show automaticity.
  • E. L-type calcium current contributes to the upstroke (phase 0) of the pacemaker action potential after threshold, not the initial slow diastolic depolarization.
Educational objective: Spontaneous diastolic depolarization (automaticity) in sinoatrial node pacemaker cells is driven by the hyperpolarization-activated funny current (If) through HCN channels.

Vascular pathology & atherosclerosis

10 questions
6

A 54-year-old man with hypertension and a 30-pack-year smoking history undergoes carotid endarterectomy. Histologic examination of the excised plaque shows lipid-laden macrophages within the intima, along with extracellular lipid, smooth muscle cells, and a fibrous cap. Which of the following best describes the mechanism by which the macrophages in this lesion accumulate lipid?

  1. AHydrolysis of circulating triglycerides by endothelial lipoprotein lipase with local fatty acid uptake
  2. BReceptor-mediated uptake of native LDL via the LDL receptor with normal feedback downregulation
  3. CUnregulated uptake of oxidized LDL via scavenger receptors on macrophages
  4. DPhagocytosis of ruptured erythrocytes within the vessel wall following microhemorrhage
  5. EActive secretion of VLDL particles by activated macrophages into the subendothelial space
Show answer
Answer: C. Unregulated uptake of oxidized LDL via scavenger receptors on macrophages

Endothelial injury from risk factors such as hypertension and smoking increases permeability to LDL, which accumulates in the intima and becomes oxidized and modified. Macrophages recognize oxidized LDL through scavenger receptors (such as CD36 and SR-A), which, unlike the native LDL receptor, are not subject to negative feedback downregulation as intracellular cholesterol rises. This leads to unregulated lipid uptake, transforming macrophages into cholesterol-laden foam cells, the hallmark of both early fatty streaks and more advanced atherosclerotic plaques. Foam cell death and lipid release contribute to the necrotic lipid core of advanced lesions.

  • A. Lipoprotein lipase acts on triglyceride-rich lipoproteins in capillaries for tissue fatty acid delivery, not on macrophage foam cell formation in the arterial intima.
  • B. The native LDL receptor pathway is tightly regulated by feedback downregulation and does not lead to the unchecked lipid accumulation seen in foam cells.
  • D. Microhemorrhage with erythrophagocytosis can contribute iron and hemoglobin-derived pigment to advanced plaques but is not the primary mechanism of foam cell formation.
  • E. Macrophages take up lipid rather than secrete VLDL; VLDL is produced by hepatocytes, not macrophages.
Educational objective: Foam cells form when macrophages take up oxidized LDL via scavenger receptors, a pathway that lacks the negative feedback regulation of the native LDL receptor.
7

A 61-year-old man is evaluated for cardiovascular risk. He has a blood pressure of 148/92 mm Hg, fasting LDL of 165 mg/dL, HDL of 38 mg/dL, and fasting glucose of 92 mg/dL. He has smoked one pack of cigarettes daily for 35 years. His father died of myocardial infarction at age 58. His body mass index is 31 kg/m2 and he reports a sedentary lifestyle. Which of the following is the strongest independent, non-modifiable risk factor for atherosclerotic cardiovascular disease in this patient?

  1. AElevated low-density lipoprotein cholesterol
  2. BCigarette smoking
  3. CHypertension
  4. DObesity with sedentary lifestyle
  5. EFamily history of premature coronary artery disease
Show answer
Answer: E. Family history of premature coronary artery disease

A family history of premature coronary artery disease, defined as myocardial infarction or sudden cardiac death in a first-degree male relative before age 55 (or female relative before age 65), is a major independent risk factor for atherosclerosis that cannot be modified. While elevated LDL, smoking, and hypertension are also major independent risk factors, they are modifiable through lifestyle change or pharmacotherapy. Obesity and sedentary lifestyle are contributory risk factors but are considered less independently predictive and are also modifiable. Recognizing non-modifiable risk factors is important for risk stratification even though clinical management focuses on the modifiable ones.

  • A. Elevated LDL is a major independent risk factor but is modifiable with statins and lifestyle changes.
  • B. Smoking is a major independent risk factor but is fully modifiable through cessation.
  • C. Hypertension is a major independent risk factor but is modifiable with antihypertensive therapy and lifestyle change.
  • D. Obesity and sedentary lifestyle are contributory, modifiable risk factors rather than major independent, non-modifiable ones.
Educational objective: Family history of premature coronary artery disease is a major independent but non-modifiable risk factor for atherosclerosis, distinct from modifiable risk factors like LDL, smoking, and hypertension.
8

A 70-year-old man with a 50-pack-year smoking history undergoes ultrasound screening that reveals a 4.8-cm fusiform dilation of the abdominal aorta below the level of the renal arteries. He is asymptomatic. Which of the following best explains the underlying mechanism responsible for this finding?

  1. AImmune complex deposition in the vasa vasorum causing transmural necrotizing inflammation
  2. BInherited defect in fibrillin-1 leading to abnormal transforming growth factor-beta signaling and cystic medial degeneration
  3. CIncreased matrix metalloproteinase activity degrading elastin and smooth muscle loss in the media, weakened by atherosclerotic plaque and reduced vasa vasorum perfusion
  4. DAutoantibody-mediated granulomatous destruction of the elastic lamina with giant cell infiltration
  5. ECongenital bicuspid remodeling of the aortic root extending into the infrarenal segment
Show answer
Answer: C. Increased matrix metalloproteinase activity degrading elastin and smooth muscle loss in the media, weakened by atherosclerotic plaque and reduced vasa vasorum perfusion

Abdominal aortic aneurysms below the renal arteries are most commonly caused by atherosclerosis, which impairs diffusion of oxygen and nutrients from the lumen and compresses the vasa vasorum, causing medial ischemia. This triggers increased matrix metalloproteinase activity from inflammatory cells, degrading elastin and collagen and causing loss of smooth muscle cells, which weakens the media and allows the vessel to dilate. The infrarenal aorta is especially vulnerable because it has fewer vasa vasorum and relies more on luminal diffusion than the thoracic aorta. This mechanism differs from the genetic connective tissue defects seen in Marfan syndrome or the vasculitic mechanisms of autoimmune arteritides.

  • A. Immune complex-mediated transmural necrotizing inflammation describes polyarteritis nodosa.
  • B. Fibrillin-1 mutations and TGF-beta dysregulation cause Marfan-associated aortic root and ascending aortic disease, not typical infrarenal atherosclerotic AAA.
  • D. Granulomatous giant cell destruction describes temporal arteritis, not atherosclerotic AAA.
  • E. Bicuspid aortic valve is associated with ascending aortic dilation, not infrarenal abdominal aneurysms.
Educational objective: Atherosclerosis-related medial ischemia and matrix metalloproteinase-mediated elastin degradation are the principal mechanism of infrarenal abdominal aortic aneurysm.
9

A 24-year-old man with a tall, thin body habitus, long fingers, and a history of lens dislocation presents to the emergency department with sudden, severe, tearing chest pain that radiates to his back between the scapulae. Blood pressure is 160/95 mmHg in the right arm and 120/80 mmHg in the left arm. A chest CT with contrast reveals a false lumen in the ascending aorta. Which of the following is the most likely diagnosis?

  1. APulmonary embolism
  2. BST-elevation myocardial infarction
  3. CAortic dissection
  4. DEsophageal rupture
  5. EAcute pericarditis
Show answer
Answer: C. Aortic dissection

This patient has classic features of Marfan syndrome (tall stature, arachnodactyly, lens dislocation) caused by a fibrillin-1 mutation, which leads to cystic medial necrosis of the aortic wall through impaired structural support and dysregulated TGF-beta signaling. This predisposes to aortic dissection, presenting as sudden tearing chest pain radiating to the back with a pulse or blood pressure discrepancy between limbs, caused by a tear in the intima allowing blood to dissect through the weakened media and create a false lumen. Diagnosis is confirmed by CT angiography or transesophageal echocardiography showing an intimal flap. Emergency surgical repair is required for ascending (Stanford type A) dissections.

  • A. Pulmonary embolism causes pleuritic chest pain and dyspnea, not a tearing quality radiating to the back with an aortic false lumen.
  • B. MI typically causes pressure-like substernal pain with ECG changes and troponin elevation, not tearing pain with blood pressure differential between arms.
  • D. Esophageal rupture typically follows vomiting and causes mediastinitis, not a false lumen within the aortic wall.
  • E. Pericarditis causes sharp pain that worsens with lying down and improves with sitting forward, with a friction rub, not a false lumen on imaging.
Educational objective: Marfan syndrome-associated cystic medial necrosis predisposes to aortic dissection, presenting as tearing chest pain radiating to the back with unequal blood pressures between limbs.
10

A 26-year-old woman of Japanese descent presents with a 6-month history of fatigue, low-grade fevers, and arm pain with exertion. She has decreased radial and brachial pulses on the left side, with a blood pressure of 150/90 mmHg in the right arm and unmeasurable blood pressure in the left arm. An arm bruit is heard. Erythrocyte sedimentation rate is 80 mm/hr (reference range: 0-20 mm/hr). CT angiography shows thickening and narrowing of the aortic arch and its proximal branches. Which of the following is the most likely diagnosis?

  1. AGiant cell arteritis
  2. BKawasaki disease
  3. CPolyarteritis nodosa
  4. DTakayasu arteritis
  5. EBuerger disease
Show answer
Answer: D. Takayasu arteritis

Takayasu arteritis is a granulomatous large-vessel vasculitis that classically affects young Asian women, involving the aortic arch and its major branches. It presents with constitutional symptoms, elevated inflammatory markers, and weak or absent pulses in the upper extremities ('pulseless disease'), along with asymmetric blood pressures and bruits. Vessel wall thickening and stenosis are seen on imaging, and histology shows granulomatous inflammation of the media with giant cells. Treatment is with corticosteroids, and surgical bypass may be needed for critical stenosis.

  • A. Giant cell arteritis affects the temporal and other cranial branches of the carotid artery in patients over 50 years old, not the aortic arch in young women.
  • B. Kawasaki disease is a childhood vasculitis affecting coronary arteries, not the aortic arch in adults.
  • C. Polyarteritis nodosa is a medium-vessel vasculitis affecting renal and visceral arteries, not the aortic arch, and typically occurs in middle-aged adults.
  • E. Buerger disease affects small and medium distal arteries of the extremities in smokers, causing digital ischemia, not aortic arch involvement.
Educational objective: Takayasu arteritis is a granulomatous large-vessel vasculitis of the aortic arch and its branches that classically affects young Asian women, causing weak upper extremity pulses and elevated ESR.
11

A 68-year-old woman presents with a 3-week history of unilateral throbbing headache, scalp tenderness, and pain in her jaw muscles when chewing that resolves with rest. She also reports stiffness and aching in her shoulders and hips. Erythrocyte sedimentation rate is 95 mm/hr (reference range: 0-20 mm/hr). If left untreated, this patient is at greatest risk for which of the following complications?

  1. ADigital gangrene
  2. BHemorrhagic stroke
  3. CIrreversible monocular vision loss
  4. DMesenteric ischemia and bowel infarction
  5. ERenal artery stenosis with hypertension
Show answer
Answer: C. Irreversible monocular vision loss

This patient has giant cell (temporal) arteritis, a granulomatous vasculitis of medium and large arteries, classically the branches of the carotid artery, occurring in patients over 50 years old and associated with polymyalgia rheumatica (proximal muscle stiffness and elevated ESR). Jaw claudication occurs due to ischemia of the masseter muscles. The most feared complication is irreversible monocular blindness due to occlusion of the ophthalmic or posterior ciliary arteries causing ischemic optic neuropathy, which is why high-dose corticosteroids are started immediately on clinical suspicion, even before temporal artery biopsy confirmation.

  • A. Digital gangrene is characteristic of Buerger disease or severe Raynaud phenomenon, not giant cell arteritis.
  • B. Hemorrhagic stroke is not a characteristic complication of giant cell arteritis, which causes ischemic rather than hemorrhagic vascular events.
  • D. Mesenteric ischemia is a feature of polyarteritis nodosa, which affects medium-sized visceral arteries.
  • E. Renal artery involvement and hypertension are more characteristic of Takayasu arteritis or polyarteritis nodosa, not giant cell arteritis.
Educational objective: Giant cell arteritis can cause irreversible monocular blindness from ophthalmic artery occlusion, so corticosteroids should be started immediately on clinical suspicion to prevent vision loss.
12

A 45-year-old man presents with fever, weight loss, abdominal pain, and a new onset of foot drop. He has a history of chronic hepatitis B infection. Examination reveals livedo reticularis on both legs and multiple tender subcutaneous nodules along the lower extremities. Blood pressure is 165/100 mmHg. Serum creatinine is 2.1 mg/dL (reference range: 0.6-1.2 mg/dL). Mesenteric angiography shows multiple small aneurysms alternating with areas of stenosis. Which of the following is the most likely diagnosis?

  1. APolyarteritis nodosa
  2. BGranulomatosis with polyangiitis
  3. CKawasaki disease
  4. DMicroscopic polyangiitis
  5. ETakayasu arteritis
Show answer
Answer: A. Polyarteritis nodosa

Polyarteritis nodosa is a necrotizing vasculitis of medium-sized muscular arteries that spares the pulmonary circulation and classically presents with constitutional symptoms, renal involvement (hypertension and renal insufficiency from arterial narrowing), mononeuritis multiplex (such as foot drop from vasa nervorum ischemia), livedo reticularis, and subcutaneous nodules. It is associated with chronic hepatitis B infection, with immune complex deposition causing transmural necrotizing inflammation of the arterial wall. Angiography classically shows a 'string of pearls' pattern caused by alternating aneurysmal dilation and stenosis. Treatment involves corticosteroids and cyclophosphamide, with antiviral therapy for HBV-associated cases.

  • B. Granulomatosis with polyangiitis involves the upper and lower respiratory tract and kidneys with c-ANCA positivity, not medium-vessel aneurysms associated with hepatitis B.
  • C. Kawasaki disease occurs in children and classically affects the coronary arteries, not adult visceral medium-sized arteries.
  • D. Microscopic polyangiitis is a small-vessel vasculitis typically associated with p-ANCA and lung involvement, not medium-vessel aneurysms or hepatitis B.
  • E. Takayasu arteritis affects the aortic arch and large branches in young women, not medium-sized visceral arteries with a string-of-pearls pattern.
Educational objective: Polyarteritis nodosa is a hepatitis B-associated necrotizing vasculitis of medium-sized arteries producing a string-of-pearls pattern on angiography and multisystem ischemic findings.
13

A 3-year-old boy presents with 6 days of fever, bilateral nonexudative conjunctivitis, a diffuse erythematous rash, cracked lips, and a strawberry tongue. Examination reveals bilateral cervical lymphadenopathy and peeling of the skin on his fingertips. Echocardiography shows dilation of the left coronary artery. Which of the following combinations of drugs is the most appropriate treatment for this patient?

  1. AOral prednisone and low-molecular-weight heparin
  2. BIntravenous methylprednisolone and cyclophosphamide
  3. CIntravenous corticosteroids and warfarin
  4. DIntravenous immunoglobulin and high-dose aspirin
  5. EIntravenous immunoglobulin and clopidogrel
Show answer
Answer: D. Intravenous immunoglobulin and high-dose aspirin

Kawasaki disease is a medium-vessel vasculitis of early childhood presenting with prolonged fever, conjunctivitis, oral mucosal changes, rash, cervical lymphadenopathy, and extremity changes (edema, erythema, and later desquamation), with the most serious complication being coronary artery aneurysm formation. First-line treatment is intravenous immunoglobulin, which reduces systemic inflammation and the risk of coronary artery aneurysms, combined with high-dose aspirin for its anti-inflammatory effect during the acute febrile phase. Aspirin is later continued at a lower, antiplatelet dose until coronary abnormalities resolve. Aspirin use in a child is an exception to the usual contraindication due to the risk of Reye syndrome, because the benefit in Kawasaki disease outweighs this risk.

  • A. Oral prednisone and heparin are not standard first-line therapy for Kawasaki disease.
  • B. Cyclophosphamide is used for severe systemic vasculitides like granulomatosis with polyangiitis, not Kawasaki disease.
  • C. Corticosteroids are not first-line therapy for Kawasaki disease, and warfarin is not standard initial treatment.
  • E. Clopidogrel is not the standard antiplatelet agent paired with IVIG in Kawasaki disease; aspirin is used instead.
Educational objective: Kawasaki disease is treated with IVIG plus high-dose aspirin to reduce systemic inflammation and the risk of coronary artery aneurysms.
14

A 34-year-old man with a 15-year history of smoking one and a half packs of cigarettes daily presents with severe pain and cyanosis of the tips of two fingers on his right hand. He also reports intermittent claudication of the feet. Examination shows ulceration at the tip of the right index finger and decreased pulses in the distal upper and lower extremities bilaterally, with normal proximal pulses. There is no family history of autoimmune disease, and antinuclear antibody testing is negative. Which of the following is the most likely diagnosis?

  1. ASystemic sclerosis
  2. BThromboangiitis obliterans
  3. CAtherosclerotic peripheral artery disease
  4. DAntiphospholipid syndrome
  5. EPolyarteritis nodosa
Show answer
Answer: B. Thromboangiitis obliterans

Thromboangiitis obliterans (Buerger disease) is a segmental, nonatherosclerotic, inflammatory vasculitis of small and medium-sized arteries and veins of the distal extremities, occurring almost exclusively in heavy smokers, typically young to middle-aged men. It presents with distal extremity ischemia, including digital ulceration, cyanosis, and claudication, with normal proximal pulses because the disease spares large vessels. Pathogenesis involves direct endothelial damage and hypersensitivity to tobacco components, causing segmental thrombosing vasculitis with sparing of the vessel wall's internal elastic lamina. Smoking cessation is essential and often leads to improvement.

  • A. Systemic sclerosis causes skin thickening and often positive ANA/anti-centromere or anti-Scl-70 antibodies, which are absent here.
  • C. Atherosclerotic PAD typically affects older patients with proximal large and medium vessel involvement and risk factors like diabetes and hyperlipidemia, not isolated distal small-vessel disease in a young heavy smoker.
  • D. Antiphospholipid syndrome causes recurrent thrombosis and is associated with lupus anticoagulant or anticardiolipin antibodies, not a smoking-related distal vasculitis.
  • E. Polyarteritis nodosa affects medium-sized visceral arteries with systemic symptoms and renal involvement, not isolated digital ischemia in a smoker.
Educational objective: Thromboangiitis obliterans (Buerger disease) is a smoking-related segmental vasculitis of small and medium distal extremity vessels causing digital ischemia and ulceration in young smokers.
15

A 29-year-old woman reports that her fingers turn white, then blue, then red when exposed to cold temperatures, with associated numbness and discomfort that resolves within 20 minutes of warming. She has no other medical conditions, and examination between episodes is normal, including normal nail-fold capillaries. Her symptoms are most directly caused by which of the following mechanisms?

  1. AFibrointimal proliferation and obliteration of digital arterioles secondary to autoantibody-mediated vascular injury
  2. BExaggerated reversible vasospasm of digital arterioles in response to cold or emotional stress
  3. CImmune complex deposition causing necrotizing inflammation of digital arteries
  4. DAtherosclerotic plaque rupture with thrombus formation in digital arteries
  5. EIrreversible thrombotic occlusion of distal digital arteries due to endothelial injury from tobacco use
Show answer
Answer: B. Exaggerated reversible vasospasm of digital arterioles in response to cold or emotional stress

Primary Raynaud phenomenon results from exaggerated, reversible vasospasm of the digital arterioles triggered by cold exposure or emotional stress, without any underlying structural vascular disease; it typically occurs in young women and is not associated with tissue damage or abnormal nail-fold capillaries. This contrasts with secondary Raynaud phenomenon, which occurs in the setting of an underlying connective tissue disease such as systemic sclerosis, where structural changes like fibrointimal proliferation of the vessel wall occur and can lead to digital ulceration and abnormal nail-fold capillary findings. The normal examination and capillaries in this patient support a primary, purely functional vasospastic mechanism rather than an underlying structural disease.

  • A. Fibrointimal proliferation with vessel wall thickening describes secondary Raynaud phenomenon from an underlying connective tissue disease, not primary Raynaud phenomenon.
  • C. Immune complex-mediated necrotizing inflammation describes a vasculitic process, not the reversible vasospasm of Raynaud phenomenon.
  • D. Atherosclerotic plaque rupture is not relevant to a young woman with normal vessels and reversible, cold-triggered symptoms.
  • E. Irreversible thrombotic occlusion describes Buerger disease, not the reversible, episodic nature of this patient's symptoms.
Educational objective: Primary Raynaud phenomenon is caused by reversible vasospasm of digital arterioles without underlying structural vascular disease, distinguishing it from secondary Raynaud phenomenon associated with connective tissue disease.
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Hypertension & lipid pharmacology

7 questions
16

A 27-year-old woman is found to have a blood pressure of 162/104 mm Hg on a routine visit, confirmed on repeat measurement. She has no family history of hypertension and takes no medications. Physical examination reveals a continuous abdominal bruit heard just lateral to the midline above the umbilicus. Serum creatinine is 0.9 mg/dL and serum potassium is 3.3 mEq/L. Renal duplex ultrasonography shows a "string of beads" appearance of the right renal artery. Which of the following is the most likely underlying cause of her hypertension?

  1. APheochromocytoma of the adrenal medulla
  2. BPrimary aldosteronism from an adrenal adenoma
  3. CAtherosclerotic plaque at the renal artery origin
  4. DFibromuscular dysplasia of the renal artery
  5. EEssential hypertension with renal arteriolosclerosis
Show answer
Answer: D. Fibromuscular dysplasia of the renal artery

Fibromuscular dysplasia (FMD) is a nonatherosclerotic, noninflammatory arteriopathy that classically affects the renal arteries of young women, producing alternating areas of medial thinning and fibrous ridges that create the "string of beads" angiographic appearance. Renal artery stenosis from FMD activates the renin-angiotensin-aldosterone system, causing secondary hypertension with hypokalemia from secondary hyperaldosteronism, as seen in this patient. An abdominal bruit in a young, otherwise healthy patient strongly suggests renovascular disease. Atherosclerotic renal artery stenosis typically affects older patients with vascular risk factors and involves the proximal artery, not the characteristic beaded pattern.

  • A. Pheochromocytoma presents with episodic headache, palpitations, and diaphoresis, not a renal artery bruit.
  • B. Primary aldosteronism causes hypokalemic hypertension but would not produce an abdominal bruit or the beaded renal artery appearance.
  • C. Atherosclerotic stenosis typically occurs in older patients with risk factors such as diabetes or smoking, not a young healthy woman.
  • E. Essential hypertension would not explain the abdominal bruit or the characteristic imaging finding in a young patient.
Educational objective: Fibromuscular dysplasia is a key cause of secondary hypertension in young women, producing a "string of beads" appearance on renal angiography due to alternating medial fibrosis and thinning.
17

A 58-year-old man started lisinopril 3 weeks ago for hypertension. He now reports a persistent dry cough that began about 1 week after starting the medication. He has no fever, sputum production, or chest pain, and his lungs are clear to auscultation. Which of the following mechanisms best explains this adverse effect?

  1. AAccumulation of angiotensin I in bronchial tissue
  2. BDirect bronchoconstriction from angiotensin II blockade
  3. CHypersensitivity pneumonitis with eosinophilic infiltration
  4. DIncreased aldosterone-mediated airway inflammation
  5. EDecreased degradation of bradykinin in the lungs
Show answer
Answer: E. Decreased degradation of bradykinin in the lungs

ACE (kininase II) normally degrades bradykinin; ACE inhibitors block this degradation, leading to bradykinin accumulation in the respiratory tract, which stimulates sensory nerve fibers and causes a dry, nonproductive cough in up to 10-20% of patients. The same bradykinin accumulation can cause angioedema of the lips, tongue, and face, a more serious adverse effect requiring immediate discontinuation of the drug. This cough typically resolves within days of stopping the ACE inhibitor and does not recur with angiotensin receptor blockers, which do not affect bradykinin metabolism.

  • A. Angiotensin I accumulation does not have significant biologic activity causing cough.
  • B. ACE inhibitors reduce angiotensin II production; decreased angiotensin II does not cause cough.
  • C. The cough is not due to an inflammatory infiltrate but a direct effect of bradykinin on sensory nerves.
  • D. Aldosterone levels decrease, not increase, with ACE inhibition, and aldosterone is not linked to cough.
Educational objective: ACE inhibitors cause dry cough and angioedema through decreased bradykinin degradation by kininase II.
18

A 64-year-old woman with hypertension is started on chlorthalidone. Three months later, routine laboratory studies show a fasting glucose of 136 mg/dL (reference range: 70-99 mg/dL) and a serum uric acid of 9.8 mg/dL (reference range: 3.5-7.2 mg/dL). She has no symptoms of gout. Which of the following best describes the mechanism of this drug's antihypertensive action?

  1. ABlockade of epithelial sodium channels in the collecting duct
  2. BInhibition of carbonic anhydrase in the proximal convoluted tubule
  3. CInhibition of the Na+/K+/2Cl- cotransporter in the thick ascending limb
  4. DAntagonism of aldosterone receptors in the collecting duct
  5. EInhibition of the Na+/Cl- cotransporter in the distal convoluted tubule
Show answer
Answer: E. Inhibition of the Na+/Cl- cotransporter in the distal convoluted tubule

Thiazide diuretics such as chlorthalidone inhibit the Na+/Cl- cotransporter (NCC) in the distal convoluted tubule, reducing sodium reabsorption and producing a mild natriuretic and antihypertensive effect, partly through chronic reduction in plasma volume and peripheral vascular resistance. Thiazides commonly cause hyperglycemia by impairing pancreatic insulin release and reducing insulin sensitivity, and hyperuricemia by competing with uric acid for secretion in the proximal tubule, which can precipitate gout. These metabolic effects are dose-related and are important considerations in patients with diabetes or a history of gout.

  • A. This describes the mechanism of potassium-sparing diuretics such as amiloride.
  • B. This describes the mechanism of acetazolamide, used for conditions like glaucoma and altitude sickness.
  • C. This describes the mechanism of loop diuretics such as furosemide, not thiazides.
  • D. This describes the mechanism of aldosterone antagonists such as spironolactone.
Educational objective: Thiazide diuretics inhibit the Na+/Cl- cotransporter in the distal convoluted tubule and can cause hyperglycemia and hyperuricemia as metabolic adverse effects.
19

A 55-year-old man is started on amlodipine for hypertension. Four weeks later, he reports bilateral swelling of his ankles that worsens throughout the day and improves overnight, without shortness of breath or weight gain. His heart rate has increased from 72/min to 88/min since starting the medication. Which of the following best explains both findings in this patient?

  1. ASodium and water retention from increased aldosterone secretion
  2. BIncreased venous capacitance leading to peripheral pooling of blood
  3. CDirect inhibition of cardiac L-type calcium channels reducing myocardial contractility
  4. DReflex sympathetic activation and preferential arteriolar vasodilation causing increased capillary hydrostatic pressure
  5. EDecreased oncotic pressure from reduced hepatic albumin synthesis
Show answer
Answer: D. Reflex sympathetic activation and preferential arteriolar vasodilation causing increased capillary hydrostatic pressure

Dihydropyridine calcium channel blockers like amlodipine preferentially dilate peripheral arterioles, which increases capillary hydrostatic pressure and promotes fluid transudation into the interstitium, causing peripheral edema that is typically worse in the lower extremities and improves with leg elevation. Because arteriolar dilation lowers blood pressure without a compensatory decrease in venous tone, baroreceptor-mediated reflex sympathetic activation occurs, producing mild tachycardia. Unlike non-dihydropyridine CCBs (verapamil, diltiazem), dihydropyridines have minimal direct cardiac depressant effect, which is why reflex tachycardia rather than bradycardia is observed.

  • A. Thiazolidinediones, not CCBs, are classically associated with aldosterone-mediated fluid retention and edema.
  • B. The edema results from arteriolar dilation and increased hydrostatic pressure, not venous pooling.
  • C. Dihydropyridines have minimal effect on cardiac calcium channels compared to vascular smooth muscle; this would cause bradycardia, not tachycardia.
  • E. Amlodipine does not affect hepatic albumin synthesis or plasma oncotic pressure.
Educational objective: Dihydropyridine calcium channel blockers cause peripheral edema from increased capillary hydrostatic pressure due to arteriolar dilation, and reflex tachycardia from baroreceptor-mediated sympathetic activation.
20

A 48-year-old woman with resistant hypertension has been taking hydralazine for 8 months. She now presents with a 3-week history of malar rash, bilateral joint pain in the hands and knees, and low-grade fever. Laboratory studies show a positive antinuclear antibody test and a positive antihistone antibody test, with negative anti-double-stranded DNA antibodies. Which of the following is the most likely explanation for this patient's presentation?

  1. AIdiopathic systemic lupus erythematosus unmasked by hydralazine
  2. BCross-reactivity between hydralazine and nuclear ribonucleoprotein antigens
  3. CDrug-induced lupus from slow acetylation of hydralazine
  4. DDirect complement activation by hydralazine metabolites
  5. EImmune complex deposition from hydralazine-induced membranous nephropathy
Show answer
Answer: C. Drug-induced lupus from slow acetylation of hydralazine

Hydralazine, a direct arteriolar vasodilator used for resistant hypertension, is a classic cause of drug-induced lupus, particularly in slow acetylators who metabolize the drug less efficiently via N-acetyltransferase, leading to accumulation of reactive metabolites that trigger an autoimmune response. Drug-induced lupus characteristically produces antihistone antibodies with typically negative anti-double-stranded DNA antibodies, and commonly presents with arthralgia, rash, and fever but rarely causes renal or CNS involvement, distinguishing it from idiopathic SLE. Symptoms generally resolve after discontinuing the offending drug.

  • A. The antihistone antibody pattern and absence of anti-dsDNA antibodies point to a drug-induced process rather than idiopathic SLE.
  • B. Drug-induced lupus is due to metabolite-driven immune dysregulation, not direct antigenic cross-reactivity.
  • D. The mechanism involves immune activation from drug metabolites, not direct complement activation.
  • E. Hydralazine-induced lupus rarely involves the kidneys, unlike idiopathic SLE.
Educational objective: Hydralazine causes drug-induced lupus, especially in slow acetylators, characterized by antihistone antibodies and typically sparing the kidneys and CNS.
21

A 55-year-old man with mixed dyslipidemia is started on niacin to raise his HDL cholesterol. After the first dose, he develops facial flushing and warmth lasting about 30 minutes. He is advised to take aspirin 30 minutes before each niacin dose to prevent this reaction. Which of the following is the mechanism by which aspirin prevents this adverse effect?

  1. AReduction of niacin absorption in the small intestine
  2. BAntagonism of niacin receptor GPR109A on Langerhans cells
  3. CInhibition of cyclooxygenase-mediated prostaglandin D2 synthesis in the skin
  4. DBlockade of histamine release from cutaneous mast cells
  5. EInhibition of hepatic lipoprotein lipase activation
Show answer
Answer: C. Inhibition of cyclooxygenase-mediated prostaglandin D2 synthesis in the skin

Niacin activates GPR109A receptors on epidermal Langerhans cells and dermal macrophages, triggering the release of prostaglandin D2 (and prostaglandin E2) via cyclooxygenase activity, which causes cutaneous vasodilation and the characteristic flushing sensation. Pretreatment with aspirin (or another NSAID) 30 minutes before niacin inhibits cyclooxygenase, reducing prostaglandin synthesis and thereby attenuating the flushing reaction. Niacin's lipid-lowering mechanism itself involves inhibition of hormone-sensitive lipase in adipocytes, reducing free fatty acid release and hepatic VLDL synthesis, which is unrelated to the flushing pathway.

  • A. Aspirin does not affect intestinal absorption of niacin.
  • B. Aspirin does not act on the GPR109A receptor itself; it acts downstream on cyclooxygenase.
  • D. The flushing reaction is prostaglandin-mediated, not histamine-mediated, so antihistamines are not the standard preventive therapy.
  • E. Niacin's lipid effects involve inhibition of lipolysis in adipose tissue, not lipoprotein lipase activation, and this is unrelated to flushing.
Educational objective: Niacin-induced flushing results from GPR109A-mediated prostaglandin D2 release in the skin, and can be prevented by aspirin pretreatment through cyclooxygenase inhibition.
22

A 9-year-old boy is brought in for evaluation of yellowish nodules over his Achilles tendons and extensor tendons of both hands. His father died of a myocardial infarction at age 38. Fasting lipid panel shows total cholesterol of 410 mg/dL (reference range: less than 200 mg/dL) and LDL cholesterol of 340 mg/dL (reference range: less than 130 mg/dL), with normal triglycerides. Which of the following best explains the underlying pathophysiology of this condition?

  1. AX-linked deficiency of apolipoprotein B-100
  2. BAutosomal dominant deficiency of hepatic lipase
  3. CAutosomal recessive mutation in the ATP-binding cassette transporter A1
  4. DAutosomal dominant mutation causing defective hepatic LDL receptors
  5. EAutosomal recessive deficiency of lipoprotein lipase
Show answer
Answer: D. Autosomal dominant mutation causing defective hepatic LDL receptors

Familial hypercholesterolemia is an autosomal dominant disorder most commonly caused by mutations in the gene encoding the LDL receptor, impairing hepatic clearance of LDL particles from the circulation and resulting in markedly elevated LDL cholesterol from birth. Heterozygotes present with tendon xanthomas (classically Achilles and extensor tendons), corneal arcus, and premature coronary artery disease, as seen in this child's father who died young of myocardial infarction. Homozygotes have even more severe hypercholesterolemia and can develop coronary disease in childhood. Triglycerides are typically normal, distinguishing this from disorders of triglyceride metabolism.

  • A. Familial hypercholesterolemia is autosomal dominant and due to LDL receptor defects, not an X-linked apolipoprotein B deficiency.
  • B. Hepatic lipase deficiency is a rare cause of dyslipidemia but is not the mechanism of familial hypercholesterolemia.
  • C. ABCA1 mutations cause Tangier disease, characterized by low HDL, not elevated LDL.
  • E. Lipoprotein lipase deficiency causes chylomicronemia with markedly elevated triglycerides, not isolated LDL elevation.
Educational objective: Familial hypercholesterolemia is an autosomal dominant disorder caused by defective LDL receptors, leading to markedly elevated LDL cholesterol, tendon xanthomas, and premature atherosclerotic disease.

Ischemic heart disease

8 questions
23

A 61-year-old man comes to the office because of chest discomfort that occurs whenever he climbs two flights of stairs and resolves within 5 minutes of rest. He has had this pattern for the past 4 months without change in frequency or severity. He has hypertension and hyperlipidemia. Vital signs are within normal limits. Cardiac examination is unremarkable. A coronary angiogram shows an 80% fixed stenosis of the left anterior descending artery with a smooth, stable atherosclerotic plaque. Which of the following best explains the mechanism of his chest discomfort?

  1. AEmbolization of thrombus from the left atrial appendage into the coronary circulation
  2. BRupture of an atherosclerotic plaque with superimposed thrombus formation
  3. CFixed reduction in luminal diameter limiting the increase in coronary blood flow needed during exertion
  4. DMicrovascular dysfunction with normal epicardial coronary arteries
  5. ETransient vasospasm of a coronary artery segment at rest
Show answer
Answer: C. Fixed reduction in luminal diameter limiting the increase in coronary blood flow needed during exertion

Stable angina results from a fixed atherosclerotic stenosis, typically greater than 70% luminal narrowing, that limits the ability of the coronary artery to dilate and augment flow when myocardial oxygen demand rises during exertion. At rest, baseline flow is adequate because distal arteriolar autoregulatory vasodilation compensates, but this reserve is exhausted with increased demand, producing ischemia and pain that resolves with rest. The plaque is stable (not ruptured), distinguishing this from acute coronary syndromes. This supply-demand mismatch is the hallmark pathophysiology of exertional (stable) angina.

  • A. Embolic coronary occlusion causes acute, not predictable exertional, symptoms.
  • B. Plaque rupture with thrombosis causes unstable angina or myocardial infarction, not a reproducible exertional pattern over months.
  • D. Microvascular angina occurs with normal or near-normal epicardial arteries, inconsistent with the 80% fixed stenosis described.
  • E. Vasospasm at rest with transient ST elevation describes Prinzmetal angina, not exertional stable angina.
Educational objective: Stable angina is caused by a fixed coronary stenosis (usually >70%) that prevents adequate flow augmentation during increased myocardial oxygen demand.
24

A 38-year-old woman comes to the emergency department because of recurrent episodes of chest pain that occur at rest, often in the early morning, lasting 10-15 minutes and resolving spontaneously. She has no history of hypertension, diabetes, or hyperlipidemia and does not smoke. During an episode, an ECG shows transient ST-segment elevation in the anterior leads that normalizes once the pain resolves. Serum troponin I is within normal limits. Coronary angiography performed between episodes shows no significant atherosclerotic disease. Which of the following is the most appropriate pharmacologic treatment to prevent further episodes?

  1. AAtorvastatin
  2. BMetoprolol
  3. CAmlodipine
  4. DAspirin
  5. ENitroglycerin patch alone
Show answer
Answer: C. Amlodipine

This presentation, rest pain with transient ST elevation that resolves spontaneously, normal troponin, and angiographically normal coronary arteries, is classic for Prinzmetal (variant) angina caused by focal coronary artery vasospasm. Calcium channel blockers such as amlodipine reduce vascular smooth muscle calcium influx, promoting coronary vasodilation and preventing spasm, and are first-line therapy. Nitrates are useful adjuncts for acute relief and prophylaxis but calcium channel blockers are the mainstay of long-term prevention. Beta-blockers can worsen vasospasm by leaving alpha-adrenergic vasoconstriction unopposed and are generally avoided.

  • A. Statins treat atherosclerotic disease, which is absent in this patient with angiographically normal arteries.
  • B. Beta-blockers may unmask unopposed alpha-mediated vasoconstriction and worsen coronary vasospasm.
  • D. Aspirin targets platelet aggregation and atherothrombosis, not vasospasm, and is not the primary preventive therapy here.
  • E. Nitrates alone are less effective than calcium channel blockers for long-term prevention of recurrent vasospasm.
Educational objective: Prinzmetal angina is caused by coronary artery vasospasm producing transient ST elevation at rest; calcium channel blockers are first-line prevention.
25

A 58-year-old man is hospitalized for an ST-elevation myocardial infarction treated successfully with percutaneous coronary intervention. On hospital day 9, he develops recurrent crushing chest pain and diaphoresis. An ECG shows new ST elevation in the same leads as the initial infarction. His cardiac troponin I, which had been elevated since admission, is found to be rising further. Which of the following laboratory markers would be most useful at this time to confirm reinfarction, given its shorter window of elevation compared with troponin I?

  1. AMyoglobin
  2. BLactate dehydrogenase
  3. CAspartate aminotransferase
  4. DCreatine kinase-MB
  5. EB-type natriuretic peptide
Show answer
Answer: D. Creatine kinase-MB

Cardiac troponin I rises about 4 hours after myocardial injury, peaks at 24 hours, and remains elevated for 7-10 days, making it highly sensitive but poorly specific for detecting reinfarction occurring within that window because baseline levels are already elevated. CK-MB rises in a similar timeframe but returns to baseline within 48-72 hours, so a new rise in CK-MB after it has normalized is a reliable indicator of reinfarction in a patient whose troponin is still elevated from the index event. This is why CK-MB retains clinical value specifically for detecting reinfarction within 7-10 days of an initial MI.

  • A. Myoglobin rises and clears very rapidly but is nonspecific and not routinely used to confirm reinfarction in modern practice.
  • B. Lactate dehydrogenase is nonspecific and rises later, offering no advantage for detecting early reinfarction.
  • C. Aspartate aminotransferase is nonspecific for myocardial tissue and is not used to assess reinfarction.
  • E. B-type natriuretic peptide reflects ventricular wall stress and heart failure, not myocardial necrosis timing.
Educational objective: CK-MB normalizes within 48-72 hours after infarction, allowing it to detect reinfarction during the 7-10 day window when troponin I remains persistently elevated.
26

A 70-year-old man died suddenly 36 hours after being admitted for an acute myocardial infarction. At autopsy, histologic examination of the affected myocardium shows eosinophilic, anucleate myocardial fibers with preserved cell outlines and a dense infiltrate of neutrophils between the fibers. Which of the following best describes this histologic finding?

  1. AMacrophage-predominant infiltrate with early fibroblast proliferation
  2. BDense collagenous scar replacing myocardium
  3. CDystrophic calcification of necrotic fibers
  4. DGranulation tissue with new capillary formation
  5. ECoagulative necrosis with neutrophilic infiltration
Show answer
Answer: E. Coagulative necrosis with neutrophilic infiltration

Between 1 and 3 days after myocardial infarction, the infarcted myocardium shows coagulative necrosis, characterized by anucleate, hypereosinophilic fibers that retain their basic cellular outline, along with a prominent neutrophilic infiltrate responding to the tissue injury. This contrasts with granulation tissue, which appears later at 1-2 weeks and features plump fibroblasts, new capillaries, and loose collagen as the infarct begins to organize. By 2 months, a dense collagenous scar replaces the infarcted region. Recognizing this timeline is essential for correlating histologic findings with the time since infarction.

  • A. Macrophage-predominant infiltrate with fibroblast proliferation occurs later, around 1 week, after neutrophils have been cleared.
  • B. Dense collagenous scar formation is a feature of the healed infarct at 2 months or later.
  • C. Dystrophic calcification is not a characteristic early feature of this timeframe.
  • D. Granulation tissue appears later, around 1-2 weeks after infarction, not at 36 hours.
Educational objective: Myocardial infarction shows coagulative necrosis with neutrophilic infiltrate at 1-3 days, progressing to granulation tissue by 1-2 weeks and collagenous scar by 2 months.
27

A 64-year-old woman was admitted 5 days ago for an anterior ST-elevation myocardial infarction. She now develops sudden hypotension, jugular venous distention, and muffled heart sounds. Blood pressure is 78/50 mmHg and heart rate is 118/min. Bedside echocardiography shows a large pericardial effusion with right ventricular diastolic collapse. Which of the following is the most likely cause of her current presentation?

  1. APapillary muscle rupture causing acute mitral regurgitation
  2. BVentricular septal rupture with left-to-right shunt
  3. CDressler syndrome with autoimmune pericarditis
  4. DLeft ventricular free wall rupture with hemopericardium
  5. EExpansion of a chronic left ventricular aneurysm
Show answer
Answer: D. Left ventricular free wall rupture with hemopericardium

Left ventricular free wall rupture classically occurs 3 to 14 days after myocardial infarction, often at the border of necrotic and viable tissue where the wall is weakest, and presents with sudden hemopericardium leading to cardiac tamponade with hypotension, jugular venous distention, and muffled heart sounds, exactly as seen here with echocardiographic evidence of tamponade. Papillary muscle rupture instead causes acute severe mitral regurgitation with a new holosystolic murmur and pulmonary edema, not tamponade physiology. Dressler syndrome is an autoimmune pericarditis occurring weeks to months after infarction, too late for this timeline.

  • A. Papillary muscle rupture causes acute mitral regurgitation with pulmonary edema and a new murmur, not tamponade physiology.
  • B. Ventricular septal rupture causes a new harsh holosystolic murmur with a left-to-right shunt and biventricular failure, not isolated tamponade.
  • C. Dressler syndrome occurs weeks to months after infarction, not at day 5, and presents as pericarditis rather than acute tamponade.
  • E. Chronic ventricular aneurysms develop weeks to months later and typically present with heart failure or arrhythmia, not acute tamponade.
Educational objective: Left ventricular free wall rupture typically occurs 3-14 days post-MI and presents as cardiac tamponade, while Dressler syndrome occurs weeks later as autoimmune pericarditis.
28

A 55-year-old man comes to the emergency department because of crushing substernal chest pain for the past 45 minutes. An ECG shows ST-segment elevation in leads V1 through V4 with reciprocal ST depression in leads II, III, and aVF. Which of the following coronary arteries is most likely occluded?

  1. APosterior descending artery
  2. BRight coronary artery
  3. CLeft circumflex artery
  4. DLeft anterior descending artery
  5. ELeft main coronary artery with isolated distal occlusion
Show answer
Answer: D. Left anterior descending artery

ST-segment elevation in the precordial leads V1 through V4 corresponds to the anteroseptal wall of the left ventricle, which is supplied by the left anterior descending artery. The left anterior descending artery arises from the left main coronary artery and runs along the anterior interventricular groove, supplying the anterior wall, anterior septum, and apex. Reciprocal ST depression in the inferior leads is a common finding with large anterior infarctions and does not indicate separate inferior wall involvement. Recognizing the lead-to-territory correlation allows rapid identification of the culprit vessel before angiography.

  • A. Posterior descending artery occlusion is associated with posterior infarction, showing ST depression in V1-V3 with tall R waves, not ST elevation.
  • B. Right coronary artery occlusion produces ST elevation in the inferior leads II, III, and aVF, not V1-V4.
  • C. Left circumflex artery occlusion produces ST elevation in the lateral leads I, aVL, V5, and V6.
  • E. Left main occlusion typically causes widespread ST elevation or depression with hemodynamic collapse, not an isolated anteroseptal pattern.
Educational objective: ST elevation in leads V1-V4 localizes to the anteroseptal wall and indicates left anterior descending artery occlusion.
29

A 50-year-old man with an acute ST-elevation myocardial infarction receives tissue plasminogen activator within 2 hours of symptom onset, achieving successful recanalization of the occluded artery. Shortly after reperfusion, there is a further burst of myocardial cell injury in the previously ischemic territory. Which of the following best explains the mechanism of this additional injury?

  1. ACoronary vasospasm triggered by circulating catecholamines
  2. BProgressive extension of the original thrombus into adjacent vessels
  3. CEmbolization of atherosclerotic debris into the microvasculature
  4. DIntracellular calcium overload and generation of reactive oxygen species upon restoration of blood flow
  5. ESustained ATP depletion from continued anaerobic glycolysis
Show answer
Answer: D. Intracellular calcium overload and generation of reactive oxygen species upon restoration of blood flow

Reperfusion injury occurs when blood flow is restored to previously ischemic tissue, reintroducing oxygen that is converted into reactive oxygen species by damaged mitochondria and xanthine oxidase, while simultaneous restoration of ion gradients leads to intracellular calcium overload. This calcium overload activates proteases and phospholipases and can trigger mitochondrial permeability transition pore opening, driving additional myocyte death and arrhythmia beyond the injury caused by the ischemia itself. This paradox, where restoring flow causes additional damage, is a well-recognized consequence of thrombolytic or percutaneous reperfusion therapy. Antioxidant and calcium-channel-targeted strategies have been studied to mitigate this injury.

  • A. Catecholamine-induced vasospasm is not the primary mechanism of reperfusion injury following thrombolysis.
  • B. Thrombus extension would worsen ischemia rather than cause injury specifically tied to the moment of reperfusion.
  • C. Microembolization of debris can occur during intervention but does not explain the oxidative and calcium-mediated injury characteristic of reperfusion.
  • E. ATP depletion from anaerobic glycolysis characterizes the ischemic phase itself, not the injury that follows reperfusion.
Educational objective: Reperfusion injury results from intracellular calcium overload and reactive oxygen species generation when blood flow is restored to ischemic myocardium.
30

A 62-year-old man comes to the emergency department because of substernal chest pressure for 1 hour with diaphoresis. He is given chewable aspirin 325 mg immediately upon arrival. Which of the following best describes the mechanism by which this drug provides benefit in this setting?

  1. AReversible competitive inhibition of platelet adenosine diphosphate receptors
  2. BBlockade of platelet glycoprotein IIb/IIIa receptor-mediated fibrinogen cross-linking
  3. CDirect inhibition of thrombin-mediated conversion of fibrinogen to fibrin
  4. DPotentiation of antithrombin III activity against factor Xa and thrombin
  5. EIrreversible inhibition of cyclooxygenase-1, decreasing platelet thromboxane A2 production
Show answer
Answer: E. Irreversible inhibition of cyclooxygenase-1, decreasing platelet thromboxane A2 production

Aspirin irreversibly acetylates a serine residue on cyclooxygenase-1 in platelets, permanently inactivating the enzyme and preventing conversion of arachidonic acid to thromboxane A2, a potent promoter of platelet aggregation and vasoconstriction. Because platelets lack nuclei and cannot synthesize new cyclooxygenase, this inhibition lasts for the entire 7-10 day lifespan of the affected platelets. This antiplatelet effect reduces further thrombus propagation in acute coronary syndrome and has been shown to reduce mortality. The irreversible nature of the inhibition distinguishes aspirin's long duration of action from reversible antiplatelet agents.

  • A. Clopidogrel and related agents, not aspirin, act on platelet ADP receptors, and that mechanism is reversible or irreversible depending on the specific drug, not aspirin's mechanism.
  • B. Glycoprotein IIb/IIIa inhibitors such as abciximab, not aspirin, block this receptor.
  • C. Direct thrombin inhibition describes drugs like dabigatran, not aspirin.
  • D. Heparin, not aspirin, potentiates antithrombin III activity.
Educational objective: Aspirin irreversibly inhibits cyclooxygenase-1, reducing thromboxane A2 production and platelet aggregation for the lifespan of the platelet.

Heart failure

3 questions
31

A 68-year-old woman presents with progressive exertional dyspnea and bilateral ankle swelling for 3 months. She has a history of hypertension treated inconsistently for 20 years. Blood pressure is 158/94 mmHg, heart rate 82/min. Examination shows an S4 gallop, bibasilar crackles, and 2+ pitting edema. Chest x-ray shows cardiomegaly and pulmonary vascular congestion. Echocardiography shows left ventricular wall thickness of 1.4 cm (normal less than 1.1 cm), left ventricular ejection fraction of 60%, and left atrial enlargement with impaired early diastolic filling. Which of the following best describes the underlying mechanism of this patient's heart failure?

  1. AReduced myocardial contractility from loss of functional cardiomyocytes
  2. BImpaired ventricular relaxation due to increased myocardial stiffness
  3. CDilated cardiomyopathy with eccentric ventricular remodeling
  4. DIncreased afterload from fixed aortic valve obstruction
  5. EDecreased ventricular preload due to pericardial constriction
Show answer
Answer: B. Impaired ventricular relaxation due to increased myocardial stiffness

This patient has heart failure with preserved ejection fraction (HFpEF), driven by long-standing hypertension causing concentric left ventricular hypertrophy. The hypertrophied, stiff myocardium impairs active relaxation and passive compliance during diastole, raising filling pressures despite normal systolic function (EF 60%). This is reflected by the S4 gallop (blood filling a stiff, noncompliant ventricle) and echocardiographic evidence of increased wall thickness with impaired diastolic filling. In contrast, HFrEF results from reduced contractility and ventricular dilation with a low ejection fraction.

  • A. This describes systolic dysfunction (HFrEF), which presents with a reduced ejection fraction, not the preserved EF of 60% seen here.
  • C. Dilated cardiomyopathy causes eccentric hypertrophy and a reduced EF, the opposite of the findings here.
  • D. There is no evidence of aortic stenosis such as a systolic ejection murmur or valve findings on echocardiography.
  • E. Constrictive pericarditis is a distinct restrictive process, not suggested by the hypertrophy and wall thickening described.
Educational objective: HFpEF results from diastolic dysfunction due to impaired ventricular relaxation and compliance, typically from concentric hypertrophy, with preserved ejection fraction, whereas HFrEF results from systolic dysfunction with reduced ejection fraction.
32

A 70-year-old man with a history of chronic left-sided heart failure dies from unrelated causes. At autopsy, the lungs are firm and brown in color. Microscopic examination of the alveolar spaces reveals numerous macrophages containing golden-brown, granular cytoplasmic pigment that stains positive with Prussian blue. Which of the following best explains the origin of this pigment?

  1. AAccumulation of undigested lipid within alveolar macrophages from surfactant breakdown
  2. BDeposition of inhaled carbon particles phagocytosed by alveolar macrophages
  3. CGranulomatous reaction to mycobacterial antigens within alveolar macrophages
  4. DPhagocytosis of red blood cells extravasated into alveoli from elevated pulmonary capillary pressure
  5. EIntracellular accumulation of lipofuscin from oxidative damage to alveolar macrophages
Show answer
Answer: D. Phagocytosis of red blood cells extravasated into alveoli from elevated pulmonary capillary pressure

Chronic left heart failure raises pulmonary capillary hydrostatic pressure, causing chronic pulmonary congestion and microhemorrhages into the alveolar spaces. Alveolar macrophages phagocytose the extravasated erythrocytes and break down hemoglobin into hemosiderin, a golden-brown, iron-containing pigment that stains positive with Prussian blue (Perls') stain. These hemosiderin-laden macrophages are called "heart failure cells" and are a classic histologic marker of chronic pulmonary venous congestion. The resulting brown induration of the lungs is termed "brown induration."

  • A. This describes lipid-laden macrophages seen in conditions like exogenous lipoid pneumonia, not Prussian blue-positive pigment.
  • B. Carbon pigment (anthracotic pigment) is black and does not stain with Prussian blue; it is seen with pollution or smoking exposure.
  • C. Granulomas with mycobacteria would show caseating necrosis and acid-fast organisms, not hemosiderin pigment.
  • E. Lipofuscin is a brown "wear-and-tear" pigment but does not stain with Prussian blue and is unrelated to heart failure.
Educational objective: Chronic left heart failure causes pulmonary congestion with alveolar microhemorrhage, producing hemosiderin-laden "heart failure cells" that stain positive with Prussian blue.
33

A 66-year-old man with a 40-pack-year smoking history and chronic obstructive pulmonary disease presents with progressive leg swelling and abdominal distension over 2 months. He denies chest pain or orthopnea. Vital signs show oxygen saturation of 89% on room air. Examination reveals a barrel-shaped chest, jugular venous distension to the angle of the jaw, a palpable right ventricular heave, tender hepatomegaly, and 3+ pitting edema of both lower extremities. Lung fields are hyperresonant with decreased breath sounds. Which of the following is the most likely underlying mechanism of this patient's peripheral edema?

  1. ADecreased plasma oncotic pressure from pulmonary protein loss
  2. BLeft ventricular systolic dysfunction causing retrograde elevation of pulmonary venous pressure
  3. CChronic hypoxemia causing pulmonary arterial vasoconstriction and increased right ventricular afterload
  4. DIncreased pulmonary capillary permeability from chronic alveolar inflammation
  5. EPrimary tricuspid valve stenosis from rheumatic involvement
Show answer
Answer: C. Chronic hypoxemia causing pulmonary arterial vasoconstriction and increased right ventricular afterload

Cor pulmonale is right ventricular failure caused by a primary lung disorder, most commonly COPD. Chronic alveolar hypoxia triggers pulmonary arteriolar vasoconstriction (hypoxic pulmonary vasoconstriction), which over time leads to pulmonary hypertension and increased right ventricular afterload. The right ventricle hypertrophies and eventually fails, producing the classic signs of right heart failure: jugular venous distension, hepatomegaly, and peripheral edema, in the absence of left heart failure findings such as orthopnea or pulmonary edema. This patient's barrel chest, hypoxemia, and hyperresonant lung fields point to COPD as the inciting lung disease.

  • A. Protein-losing conditions would not explain the combination of jugular venous distension and heave specific to right ventricular pressure overload.
  • B. This describes a cause of left heart failure, but this patient has no orthopnea or signs of pulmonary congestion, and the primary pathology is pulmonary.
  • D. Increased capillary permeability would cause pulmonary edema, not the isolated right heart failure pattern seen here.
  • E. There is no murmur or history suggesting rheumatic valve disease described in this vignette.
Educational objective: Cor pulmonale results from chronic lung disease causing hypoxic pulmonary vasoconstriction, pulmonary hypertension, and right ventricular failure, manifesting as jugular venous distension, hepatomegaly, and peripheral edema without left heart failure signs.

Valvular disease

7 questions
34

A 24-year-old man comes to the physician for a routine evaluation before starting a new exercise program. He is asymptomatic. He is tall with long, thin extremities, a wingspan exceeding his height, and a positive wrist sign. On cardiac auscultation, there is a mid-systolic click followed by a late systolic murmur best heard at the apex, which occurs earlier with standing and Valsalva maneuver. Which of the following is the most likely underlying histopathologic abnormality responsible for these auscultatory findings?

  1. AMyxomatous degeneration of the mitral valve leaflets with excess proteoglycan deposition
  2. BDystrophic calcification of the mitral annulus restricting leaflet mobility
  3. CVerrucous vegetations on both surfaces of the mitral valve leaflets
  4. DFibrinous vegetations along the lines of mitral valve leaflet closure
  5. EFibrosis and calcification of the mitral valve leaflets with commissural fusion
Show answer
Answer: A. Myxomatous degeneration of the mitral valve leaflets with excess proteoglycan deposition

This patient's body habitus (tall stature, long extremities, positive wrist sign) suggests Marfan syndrome, caused by mutations in the fibrillin-1 gene, which is associated with mitral valve prolapse. Mitral valve prolapse results from myxomatous degeneration of the valve leaflets, characterized by excess deposition of proteoglycans and fragmented collagen within the spongiosa layer, causing the leaflets and chordae tendineae to become redundant and floppy. This produces a mid-systolic click (sudden tensing of chordae as the leaflet prolapses into the left atrium) followed by a late systolic murmur from mitral regurgitation, which occurs earlier with maneuvers that decrease left ventricular volume such as standing or Valsalva.

  • B. Mitral annular calcification occurs in older adults and restricts rather than produces floppy, prolapsing leaflets.
  • C. This describes verrucous vegetations of Libman-Sacks endocarditis seen in systemic lupus erythematosus, not mitral valve prolapse.
  • D. This describes the vegetations of nonbacterial thrombotic (marantic) endocarditis, not myxomatous prolapse.
  • E. This describes chronic rheumatic mitral stenosis, which produces a diastolic opening snap and murmur, not a systolic click.
Educational objective: Mitral valve prolapse results from myxomatous degeneration of the mitral leaflets, producing a mid-systolic click and late systolic murmur, and is associated with connective tissue disorders such as Marfan syndrome.
35

A 78-year-old man comes to the office because of exertional chest tightness and lightheadedness for 3 months. Blood pressure is 128/78 mm Hg and pulse is 76/min and regular. Cardiac auscultation reveals a harsh systolic murmur at the right second intercostal space that increases in intensity then fades before S2, radiating to the carotid arteries. The murmur is best heard when the patient leans forward and exhales. Carotid pulses are weak and delayed in upswing. An echocardiogram shows a thickened, calcified valve with markedly reduced leaflet mobility and a peak jet velocity of 4.5 m/s. Which of the following is the most likely underlying valvular diagnosis?

  1. AAortic regurgitation
  2. BCalcific aortic stenosis
  3. CRheumatic mitral stenosis
  4. DHypertrophic obstructive cardiomyopathy
  5. EBicuspid aortic valve stenosis
Show answer
Answer: B. Calcific aortic stenosis

Progressive calcific degeneration of a previously normal trileaflet aortic valve is the most common cause of aortic stenosis in elderly patients, producing a crescendo-decrescendo systolic murmur radiating to the carotids with a delayed, weak carotid upstroke (pulsus parvus et tardus). This is distinct from bicuspid valve disease, which typically presents with calcific stenosis at a younger age (50s-60s) due to accelerated mechanical stress on an abnormal two-cusp valve. The patient's age and echocardiographic findings of heavy calcification fit degenerative senile calcific stenosis rather than a congenital bicuspid valve.

  • A. Aortic regurgitation produces a diastolic decrescendo murmur, not a crescendo-decrescendo systolic murmur.
  • C. Rheumatic mitral stenosis produces a diastolic murmur with an opening snap, not a systolic ejection murmur radiating to the carotids.
  • D. Hypertrophic obstructive cardiomyopathy murmur decreases with increased afterload (squatting) rather than depending on leaflet calcification, and carotid upstroke is typically brisk and bifid, not delayed.
  • E. Bicuspid aortic valve stenosis classically presents at a younger age (50s-60s), not in a 78-year-old.
Educational objective: Calcific degeneration of a normal trileaflet valve is the most common cause of aortic stenosis in patients over 70 years, whereas bicuspid aortic valve causes earlier-onset calcific stenosis.
36

A 64-year-old woman is brought to the emergency department 2 days after an episode of severe substernal chest pain that she did not report to a physician. She now has acute dyspnea and bibasilar crackles. Blood pressure is 96/60 mm Hg and pulse is 112/min. Cardiac auscultation reveals a new holosystolic murmur best heard at the apex, radiating to the axilla. Troponin I is elevated at 8.2 ng/mL (reference range: less than 0.04 ng/mL). An echocardiogram shows a flail segment of the mitral valve with severe regurgitant flow into the left atrium throughout systole. Which of the following best explains the mechanism producing this murmur?

  1. AFibrotic fusion of mitral valve leaflets reducing orifice area
  2. BDilation of the aortic root causing leaflet malcoaptation
  3. CPapillary muscle rupture following inferior wall infarction
  4. DVegetation-induced perforation of the aortic valve leaflet
  5. EMyxomatous degeneration of the mitral valve leaflets
Show answer
Answer: C. Papillary muscle rupture following inferior wall infarction

The posteromedial papillary muscle receives blood supply solely from the posterior descending artery, making it vulnerable to rupture after an inferior wall myocardial infarction, typically 2-7 days post-infarct. Papillary muscle rupture causes acute, severe mitral regurgitation with a holosystolic murmur radiating to the axilla, pulmonary edema, and cardiogenic shock. The regurgitant jet occurs because the ruptured papillary muscle can no longer tether the chordae tendineae, producing a flail leaflet that fails to coapt during systole. This is a classic mechanical complication of myocardial infarction and a surgical emergency.

  • A. Fibrotic fusion of leaflets describes mitral stenosis, which produces a diastolic murmur, not acute holosystolic regurgitation.
  • B. Aortic root dilation causes aortic regurgitation, not mitral regurgitation, and does not fit the post-infarct timeline.
  • D. Vegetation-induced perforation would suggest infective endocarditis, not an abrupt presentation 2 days after unreported chest pain with markedly elevated troponin.
  • E. Myxomatous degeneration causes chronic mitral valve prolapse, not an acute flail valve 2 days after an infarction.
Educational objective: Papillary muscle rupture, usually posteromedial following inferior myocardial infarction, causes acute severe mitral regurgitation with a holosystolic apical murmur and pulmonary edema.
37

A 9-year-old boy is brought to the clinic because of fever, migratory joint pain, and a rash for 5 days. He had a sore throat 3 weeks ago that resolved without treatment. Temperature is 101.9°F (38.8°C). Examination shows erythematous, serpiginous, non-pruritic macules on the trunk and swollen, tender knees and ankles. Cardiac auscultation reveals a new apical holosystolic murmur. Antistreptolysin O titer is elevated. Which of the following mechanisms best explains the cardiac valve involvement in this patient?

  1. ADirect bacterial invasion and destruction of valve leaflets by group A Streptococcus
  2. BAntibodies against streptococcal M protein cross-react with cardiac myosin and valve glycoproteins
  3. CStreptococcal exotoxin-mediated superantigen activation of valve-infiltrating T cells
  4. DFormation of sterile fibrin-platelet thrombi on valve leaflets during a hypercoagulable state
  5. EImmune complex deposition in valve tissue causing type III hypersensitivity injury
Show answer
Answer: B. Antibodies against streptococcal M protein cross-react with cardiac myosin and valve glycoproteins

Acute rheumatic fever results from molecular mimicry, in which antibodies generated against the M protein of group A Streptococcus (Streptococcus pyogenes) cross-react with structurally similar self-antigens, including cardiac myosin and valve glycoproteins. This type II hypersensitivity-like mechanism produces inflammation of the myocardium and valves (pancarditis), most commonly affecting the mitral valve. The Jones criteria, including migratory polyarthritis, carditis, erythema marginatum, and subcutaneous nodules, support the diagnosis in the setting of a preceding streptococcal pharyngitis. The disease is an autoimmune, not an infectious, process of the valve itself.

  • A. Rheumatic fever is a post-infectious autoimmune phenomenon; the bacteria do not directly invade or infect the valve leaflets.
  • C. Superantigen-mediated T cell activation describes toxic shock syndrome, not the pathogenesis of rheumatic carditis.
  • D. Sterile fibrin-platelet vegetations describe nonbacterial thrombotic (marantic) endocarditis, not rheumatic valvulitis.
  • E. The mechanism is molecular mimicry producing cross-reactive antibodies, not immune complex deposition.
Educational objective: Acute rheumatic fever is caused by molecular mimicry between group A streptococcal M protein and cardiac self-antigens, producing autoimmune carditis and valvulitis.
38

A 29-year-old man with a history of intravenous heroin use presents with fever and malaise for 1 week. Temperature is 102.6°F (39.2°C). Examination shows track marks on both forearms and a holosystolic murmur at the left lower sternal border that increases with inspiration. Blood cultures drawn on three separate occasions grow a catalase-positive, coagulase-positive, gram-positive coccus in clusters. Transesophageal echocardiogram shows a large vegetation on the tricuspid valve. Which of the following organisms is the most likely cause of this patient's infection?

  1. AStreptococcus gallolyticus (bovis)
  2. BEnterococcus faecalis
  3. CStreptococcus mutans
  4. DCandida albicans
  5. EStaphylococcus aureus
Show answer
Answer: E. Staphylococcus aureus

Staphylococcus aureus is the most common cause of infective endocarditis in intravenous drug users and classically affects the tricuspid valve, producing a murmur that increases with inspiration due to increased right-sided venous return. The organism is catalase-positive (distinguishing it from streptococci) and coagulase-positive (distinguishing it from coagulase-negative staphylococci), and it typically grows in clusters on gram stain. S. aureus is also notable for causing acute, rapidly destructive endocarditis even on previously normal valves, unlike viridans streptococci, which typically require a pre-damaged valve.

  • A. Streptococcus gallolyticus (bovis) is catalase-negative and associated with colorectal malignancy, not IV drug use.
  • B. Enterococcus faecalis is catalase-negative and is more associated with endocarditis following genitourinary procedures.
  • C. Streptococcus mutans (a viridans group organism) is catalase-negative and typically causes subacute endocarditis on previously damaged native valves, not acute tricuspid disease in IV drug users.
  • D. Candida albicans is a fungus, not a gram-positive coccus, and would not appear in clusters on gram stain.
Educational objective: Staphylococcus aureus, a catalase- and coagulase-positive organism, is the leading cause of acute tricuspid valve endocarditis in intravenous drug users.
39

A 54-year-old woman with a history of mitral valve prolapse is hospitalized for fever and a new regurgitant murmur. Examination shows tender, erythematous nodules on the pads of several fingers that are painful to touch, along with non-tender, erythematous macules on the palms. Funduscopic examination reveals retinal hemorrhages with pale centers. Blood cultures grow Streptococcus sanguinis. Which of the following correctly matches each finding described with its underlying cause?

  1. ATender nodules are immune complex deposition; palmar macules are septic microemboli; retinal lesions are immune complex-mediated vasculitis
  2. BTender nodules are septic microemboli; palmar macules are platelet-fibrin thrombi; retinal lesions are immune complex deposition
  3. CTender nodules are septic microemboli; palmar macules are immune complex deposition; retinal lesions are platelet-fibrin thrombi
  4. DTender nodules are platelet-fibrin thrombi; palmar macules are immune complex deposition; retinal lesions are septic microemboli
  5. ETender nodules are immune complex deposition; palmar macules are platelet-fibrin thrombi; retinal lesions are septic microemboli
Show answer
Answer: A. Tender nodules are immune complex deposition; palmar macules are septic microemboli; retinal lesions are immune complex-mediated vasculitis

Osler nodes (tender nodules on finger and toe pads) result from immune complex deposition in small vessels, a type III hypersensitivity reaction. Janeway lesions (non-tender erythematous macules on the palms and soles) result from septic microemboli lodging in cutaneous vessels. Roth spots (retinal hemorrhages with pale centers) are also thought to arise from immune complex-mediated vasculitis causing capillary rupture. Distinguishing tenderness (Osler = immune, tender) from painlessness (Janeway = embolic) is a classic clinical discriminator in infective endocarditis.

  • B. This incorrectly assigns platelet-fibrin thrombi to Janeway lesions and immune complex deposition to Roth spots rather than Osler nodes.
  • C. This reverses the mechanisms: Osler nodes are immune complex-mediated, not embolic, and Janeway lesions are embolic, not immune complex-mediated.
  • D. Osler nodes are not due to platelet-fibrin thrombi, and Roth spots are not due to septic microemboli.
  • E. Janeway lesions are not due to platelet-fibrin thrombi deposition; they are embolic phenomena.
Educational objective: Osler nodes and Roth spots arise from immune complex deposition, whereas Janeway lesions result from septic microembolization, in infective endocarditis.
40

A 32-year-old woman with a 6-year history of a photosensitive facial rash and intermittent joint pain is found to have a new murmur during a routine visit. She takes hydroxychloroquine. Blood pressure is 122/76 mm Hg. Cardiac examination reveals a soft holosystolic murmur at the apex. Echocardiogram shows small, verrucous vegetations on both surfaces of the mitral valve leaflets. Three sets of blood cultures over 48 hours show no growth. Antinuclear antibody titer is 1:640, and anti-double-stranded DNA antibody is elevated. Which of the following is the most likely diagnosis?

  1. ACarcinoid heart disease
  2. BSubacute bacterial endocarditis
  3. CRheumatic mitral valvulitis
  4. DNonbacterial thrombotic endocarditis due to malignancy
  5. ELibman-Sacks endocarditis
Show answer
Answer: E. Libman-Sacks endocarditis

Libman-Sacks endocarditis is a sterile, verrucous valvulopathy associated with systemic lupus erythematosus, classically affecting the mitral valve with small vegetations that can form on either surface of the leaflet. It results from immune complex deposition and is associated with antiphospholipid antibodies. The combination of a photosensitive rash, elevated ANA and anti-dsDNA titers, and negative blood cultures in a patient with new valvular vegetations supports a lupus-associated sterile endocarditis rather than an infectious cause.

  • A. Carcinoid heart disease typically affects right-sided valves (tricuspid and pulmonic) and is associated with flushing and diarrhea, not a lupus serology profile.
  • B. Subacute bacterial endocarditis would typically show positive blood cultures; this patient's cultures are negative.
  • C. Rheumatic mitral valvulitis follows streptococcal pharyngitis and is not associated with ANA or anti-dsDNA positivity.
  • D. Nonbacterial thrombotic (marantic) endocarditis is associated with malignancy and hypercoagulable states, not with the photosensitive rash and positive dsDNA antibodies seen here.
Educational objective: Libman-Sacks endocarditis produces sterile verrucous mitral valve vegetations in patients with systemic lupus erythematosus and is often associated with antiphospholipid antibodies.

Cardiomyopathy & myocarditis

4 questions
41

A 17-year-old boy collapses suddenly while playing basketball and cannot be resuscitated. His father died suddenly at age 40 during physical exertion. Autopsy reveals asymmetric thickening of the interventricular septum with a histologic pattern of disorganized, branching myocardial fibers arranged at oblique angles to one another, along with areas of interstitial fibrosis. Which of the following is the most likely underlying genetic cause of this condition?

  1. AMitochondrial DNA mutation affecting oxidative phosphorylation enzymes
  2. BAutosomal dominant mutation in a gene encoding a sarcomere protein
  3. CAutosomal dominant mutation in a gene encoding a desmosomal protein
  4. DAutosomal recessive mutation in a gene encoding a lysosomal enzyme
  5. EX-linked mutation in the gene encoding dystrophin
Show answer
Answer: B. Autosomal dominant mutation in a gene encoding a sarcomere protein

Hypertrophic cardiomyopathy is most commonly caused by autosomal dominant mutations in genes encoding sarcomere proteins, such as beta-myosin heavy chain or myosin-binding protein C, leading to disorganized hypertrophy of myocardial fibers. The hallmark histologic finding is myocyte disarray, in which hypertrophied fibers branch and align at oblique angles to each other, along with patchy interstitial fibrosis. This produces asymmetric septal hypertrophy that can cause left ventricular outflow obstruction and is a leading cause of sudden cardiac death in young athletes due to ventricular arrhythmias. A family history of sudden death during exertion is classic given the autosomal dominant inheritance pattern.

  • A. Mitochondrial DNA mutations cause mitochondrial myopathies, which typically also involve other mitochondria-rich tissues and not primarily this isolated sarcomere disarray pattern.
  • C. Desmosomal protein mutations cause arrhythmogenic right ventricular cardiomyopathy, characterized by fibrofatty replacement of the right ventricular myocardium, not septal myocyte disarray.
  • D. Autosomal recessive lysosomal enzyme mutations describe a storage disease such as Pompe disease, not the classic sarcomeric hypertrophic cardiomyopathy pattern.
  • E. X-linked dystrophin mutations cause Duchenne or Becker muscular dystrophy, which can lead to a dilated, not primarily hypertrophic, cardiomyopathy.
Educational objective: Hypertrophic cardiomyopathy results from autosomal dominant sarcomere protein gene mutations causing myocyte disarray and is a leading cause of sudden cardiac death in young athletes.
42

A 68-year-old man presents with progressive dyspnea on exertion and bilateral leg swelling over 6 months. Examination shows jugular venous distension, hepatomegaly, and a heart that is not displaced on palpation. Echocardiogram reveals a thickened, non-dilated left ventricle with normal ejection fraction and a granular sparkling appearance of the myocardium. Serum free light chain assay is abnormal. A myocardial biopsy is obtained and stained with a dye that produces a salmon-pink color under normal light.

  1. AElectron microscopy for fibril ultrastructure
  2. BImmunohistochemistry for desmin expression
  3. CPolarized light microscopy after Congo red staining
  4. DPeriodic acid-Schiff stain for glycogen deposits
  5. EMasson trichrome stain for collagen content
Show answer
Answer: C. Polarized light microscopy after Congo red staining

Amyloid deposits bind Congo red dye and, when viewed under polarized light, exhibit characteristic apple-green birefringence due to the beta-pleated sheet structure of the misfolded protein fibrils. This finding is the diagnostic gold standard for confirming amyloid deposition in tissue, including the heart in restrictive cardiomyopathy. The sparkling granular echogenicity on echocardiogram is suggestive but not definitive, making tissue biopsy with polarized Congo red the confirmatory test. Light chain or transthyretin amyloid are the most common cardiac amyloid types in this clinical context.

  • A. Electron microscopy can show fibrils but is not the standard confirmatory test and does not define amyloid as specifically as polarized Congo red.
  • B. Desmin is a muscle intermediate filament marker, unrelated to amyloid fibril detection.
  • D. PAS stains glycogen and is used for glycogen storage diseases, not amyloidosis.
  • E. Masson trichrome stains fibrosis, not amyloid protein, and would not confirm the diagnosis.
Educational objective: Cardiac amyloidosis is confirmed by apple-green birefringence of Congo red-stained tissue under polarized light, reflecting the beta-pleated sheet structure of amyloid fibrils.
43

A 24-year-old man presents with chest pain and fatigue 10 days after a febrile illness with sore throat and myalgias. Temperature is 100.9°F (38.3°C), heart rate is 110/min, and blood pressure is 100/65 mmHg. Cardiac exam reveals a soft S3 gallop. Troponin I is elevated at 2.1 ng/mL (reference range less than 0.04 ng/mL). Echocardiogram shows global hypokinesis with an ejection fraction of 35%. Endomyocardial biopsy is performed.

  1. ALymphocytic infiltrate with myocyte necrosis
  2. BGranulomatous inflammation with multinucleated giant cells
  3. CFibrofatty replacement of right ventricular myocardium
  4. DNon-caseating granulomas with Langhans giant cells
  5. EEosinophilic infiltrate with vasculitis
Show answer
Answer: A. Lymphocytic infiltrate with myocyte necrosis

This patient's presentation of myocarditis following a febrile viral prodrome is most consistent with Coxsackie B virus infection, the most common cause of viral myocarditis in young adults. Biopsy classically shows a lymphocytic infiltrate with associated myocyte necrosis, reflecting direct viral cytopathic injury plus T-cell mediated immune destruction of infected cardiomyocytes. The clinical course of a preceding viral illness followed by heart failure symptoms and elevated troponin supports this diagnosis. Most cases are self-limited, but some progress to dilated cardiomyopathy.

  • B. Granulomatous inflammation with giant cells is characteristic of giant cell myocarditis, a rarer and more fulminant entity.
  • C. Fibrofatty replacement of the right ventricle describes arrhythmogenic right ventricular cardiomyopathy, a genetic condition.
  • D. Non-caseating granulomas with Langhans giant cells suggest cardiac sarcoidosis, not viral myocarditis.
  • E. Eosinophilic infiltrate with vasculitis suggests hypersensitivity myocarditis, typically from a drug reaction.
Educational objective: Coxsackie B virus is the most common cause of viral myocarditis, producing a lymphocytic infiltrate with myocyte necrosis on biopsy.
44

A 52-year-old woman with breast cancer is being treated with a chemotherapy regimen that includes an anthracycline antibiotic. Her oncologist is concerned about cumulative dose-dependent cardiac injury and adds a second agent to her regimen specifically to reduce this risk. Echocardiograms are monitored serially throughout treatment to track left ventricular ejection fraction.

  1. ADexrazoxane
  2. BLeucovorin
  3. CMesna
  4. DAmifostine
  5. EAllopurinol
Show answer
Answer: A. Dexrazoxane

Doxorubicin and other anthracyclines cause dose-dependent cardiotoxicity primarily through generation of free radicals (reactive oxygen species) via iron-mediated redox cycling, leading to lipid peroxidation of cardiomyocyte membranes and progressive dilated cardiomyopathy. Dexrazoxane is an iron-chelating agent that limits free radical formation by preventing iron from participating in redox reactions, thereby reducing cardiotoxicity risk. It is used selectively in patients receiving high cumulative anthracycline doses. Serial echocardiographic monitoring of ejection fraction is standard practice to detect early cardiac dysfunction.

  • B. Leucovorin rescues cells from methotrexate toxicity, not anthracycline cardiotoxicity.
  • C. Mesna protects against hemorrhagic cystitis from cyclophosphamide/ifosfamide, not cardiotoxicity.
  • D. Amifostine protects against cisplatin-induced nephrotoxicity and radiation injury, not cardiotoxicity.
  • E. Allopurinol prevents tumor lysis syndrome-associated hyperuricemia, unrelated to cardiac protection.
Educational objective: Dexrazoxane chelates iron to reduce free radical formation and protects against doxorubicin-induced cardiotoxicity.

Pericardial disease

1 questions
45

A 61-year-old man who immigrated from a country with high tuberculosis prevalence presents with progressive abdominal distension and bilateral leg swelling over several months. He denies fever or chest pain. Jugular venous pressure rises paradoxically with inspiration. Cardiac auscultation reveals an early high-pitched diastolic sound best heard at the left sternal border, distinct from a third heart sound. Echocardiogram shows a thickened, calcified pericardium with normal-sized ventricles and preserved systolic function.

  1. AAcute rheumatic pancarditis
  2. BCardiac tamponade
  3. CRestrictive cardiomyopathy
  4. DConstrictive pericarditis
  5. EHypertrophic cardiomyopathy
Show answer
Answer: D. Constrictive pericarditis

This patient has constrictive pericarditis, most commonly caused by prior tuberculous pericarditis in endemic regions, in which a fibrotic, often calcified pericardium restricts diastolic filling of the heart. The Kussmaul sign, a paradoxical rise in jugular venous pressure with inspiration, occurs because the rigid pericardium prevents increased venous return from being accommodated by the right heart. The pericardial knock is an early diastolic sound caused by sudden cessation of ventricular filling when the expanding ventricle hits the stiff pericardial shell. Calcified, thickened pericardium on imaging with normal ventricular size and systolic function supports this diagnosis over infiltrative restrictive cardiomyopathy.

  • A. Acute rheumatic pancarditis presents with fever, migratory arthritis, and active inflammation, not chronic calcific pericardial thickening.
  • B. Cardiac tamponade presents acutely with pulsus paradoxus and a pericardial effusion, not a chronic calcified pericardium with a knock sound.
  • C. Restrictive cardiomyopathy involves myocardial infiltration or fibrosis rather than pericardial thickening, and would not typically show a calcified pericardium on imaging.
  • E. Hypertrophic cardiomyopathy shows asymmetric septal hypertrophy on echocardiogram, not pericardial thickening or calcification.
Educational objective: Constrictive pericarditis, often from prior tuberculosis, causes Kussmaul sign and a pericardial knock due to a thickened, calcified pericardium restricting diastolic filling.

Arrhythmias & antiarrhythmic pharmacology

4 questions
46

A 74-year-old woman with a history of hypertension and type 2 diabetes mellitus presents for a routine visit. She feels well. Heart rate is 88/min and irregular, and blood pressure is 142/88 mmHg. ECG shows an irregularly irregular rhythm with no discernible P waves and a variable R-R interval. She has no history of stroke, heart failure, or vascular disease.

  1. AStart aspirin alone for stroke prevention
  2. BPerform urgent synchronized cardioversion
  3. CReassure and schedule follow-up in one year with no new therapy
  4. DStart amiodarone for rhythm control
  5. EStart a direct oral anticoagulant
Show answer
Answer: E. Start a direct oral anticoagulant

This patient has atrial fibrillation, identified by an irregularly irregular rhythm without discrete P waves on ECG, which results from chaotic multiple reentrant wavelets in the atria. Her CHA2DS2-VASc score includes points for age 65-74, hypertension, and diabetes, giving a score of at least 3, which indicates a high annual stroke risk and a guideline-based indication for anticoagulation. A direct oral anticoagulant, such as a factor Xa inhibitor, is preferred over aspirin or warfarin for most patients with non-valvular atrial fibrillation due to better efficacy and safety profile. Rate or rhythm control may be pursued separately for symptom management, but stroke prevention is the most immediately important intervention here.

  • A. Aspirin alone is inferior to oral anticoagulation for stroke prevention in patients with a significant CHA2DS2-VASc score.
  • B. Urgent cardioversion is not indicated in a hemodynamically stable, asymptomatic patient with unknown duration of atrial fibrillation, due to thromboembolism risk.
  • C. Reassurance without anticoagulation would leave her at significant unaddressed stroke risk given her CHA2DS2-VASc score.
  • D. Amiodarone addresses rhythm control but does not substitute for anticoagulation in a patient at elevated stroke risk.
Educational objective: Anticoagulation with a direct oral anticoagulant is indicated in atrial fibrillation when the CHA2DS2-VASc score indicates elevated stroke risk, regardless of symptoms.
47

A 22-year-old man presents to the emergency department with palpitations and lightheadedness. Heart rate is 180/min and blood pressure is 100/64 mmHg. His baseline ECG from a prior visit, obtained for an unrelated reason, showed a short PR interval and a slurred upstroke at the beginning of the QRS complex. The emergency physician considers administering an intravenous calcium channel blocker but a cardiology consultant advises against this, citing risk of degeneration into a life-threatening arrhythmia.

  1. AThe drug blocks the slow conduction properties of the atrioventricular node, allowing preferential antegrade conduction through the accessory pathway
  2. BThe drug increases automaticity of the sinoatrial node, triggering a reentrant tachycardia
  3. CThe drug prolongs the QT interval, precipitating torsades de pointes
  4. DThe drug blocks fast sodium channels in the accessory pathway, causing complete heart block
  5. EThe drug increases vagal tone, worsening conduction block within the accessory pathway
Show answer
Answer: A. The drug blocks the slow conduction properties of the atrioventricular node, allowing preferential antegrade conduction through the accessory pathway

This patient has Wolff-Parkinson-White syndrome, indicated by a short PR interval and delta wave (slurred QRS upstroke) from ventricular pre-excitation through an accessory conduction pathway called the bundle of Kent, which bypasses the normal decremental conduction of the AV node. In the setting of atrial fibrillation or flutter with a pre-excitation pathway, AV nodal blocking agents such as verapamil or digoxin suppress conduction through the AV node without affecting the accessory pathway, which lacks the decremental conduction properties of the AV node. This shifts conduction preferentially down the accessory pathway, potentially leading to very rapid ventricular rates and degeneration into ventricular fibrillation. Procainamide or ibutilide, which slow conduction in the accessory pathway itself, are safer choices in this scenario.

  • B. Calcium channel blockers do not increase sinoatrial node automaticity; this is not the mechanism of danger in WPW.
  • C. QT prolongation and torsades de pointes are not the mechanism by which calcium channel blockers are dangerous in WPW.
  • D. Calcium channel blockers do not block fast sodium channels in the accessory pathway; that is a class I antiarrhythmic mechanism.
  • E. Calcium channel blockers do not act primarily through vagal tone to affect the accessory pathway; their danger is from differential AV nodal blockade.
Educational objective: In WPW syndrome, AV nodal blocking agents like verapamil or digoxin are contraindicated because they can promote preferential conduction through the accessory pathway, risking degeneration into ventricular fibrillation.
48

A 68-year-old woman is started on a medication for recurrent symptomatic atrial fibrillation. Three days later she reports several episodes of lightheadedness and palpitations. Her heart rate is 88/min and blood pressure is 108/68 mm Hg. An ECG shows a corrected QT interval of 540 ms (reference range: <450 ms) with a polymorphic wide-complex tachycardia that spontaneously terminates after 15 seconds. Serum potassium is 3.9 mEq/L (reference range: 3.5-5.0 mEq/L) and serum magnesium is 1.9 mg/dL (reference range: 1.7-2.2 mg/dL). Which of the following drugs was most likely prescribed?

  1. ADiltiazem
  2. BFlecainide
  3. CSotalol
  4. DLidocaine
  5. EMetoprolol
Show answer
Answer: C. Sotalol

Sotalol is a class III antiarrhythmic that blocks the rapid component of the delayed rectifier potassium current (IKr), prolonging the action potential duration and the QT interval. Excessive QT prolongation predisposes to early afterdepolarizations and polymorphic ventricular tachycardia (torsades de pointes), exactly as seen in this patient's ECG. Risk is increased by bradycardia, hypokalemia, and hypomagnesemia, though her electrolytes here are within normal limits, showing this is a direct drug effect. QT-prolonging antiarrhythmics require baseline and follow-up ECG monitoring.

  • A. Diltiazem is a calcium channel blocker that slows AV nodal conduction and does not prolong the QT interval.
  • B. Flecainide is a class IC agent that slows conduction velocity (widens QRS) but does not significantly prolong the QT interval or cause torsades.
  • D. Lidocaine is a class IB agent that shortens the action potential duration and is not associated with QT prolongation or torsades.
  • E. Metoprolol is a beta-blocker that slows heart rate and AV conduction but is not associated with QT prolongation or torsades.
Educational objective: Class IA and class III antiarrhythmics prolong the QT interval by blocking potassium efflux, predisposing to torsades de pointes.
49

A 24-year-old woman presents to the emergency department with sudden-onset palpitations and lightheadedness. Heart rate is 180/min and blood pressure is 110/72 mm Hg. An ECG shows a regular narrow-complex tachycardia without discernible P waves. After a rapid intravenous bolus is given, she experiences several seconds of chest tightness and facial flushing, and the rhythm converts to sinus rhythm at 78/min. Which of the following is the primary mechanism by which this drug terminated the arrhythmia?

  1. ABeta-1 adrenergic receptor antagonism at the sinoatrial node
  2. BBlockade of fast sodium channels in atrial myocardium
  3. CActivation of potassium efflux causing hyperpolarization and AV nodal slowing
  4. DProlongation of the action potential by blocking potassium efflux
  5. EBlockade of L-type calcium channels in the AV node
Show answer
Answer: C. Activation of potassium efflux causing hyperpolarization and AV nodal slowing

Adenosine activates A1 receptors on AV nodal cells, coupling through Gi proteins to open potassium channels (IK,Ado). This increases potassium efflux, hyperpolarizing the cell membrane and slowing conduction through the AV node, which transiently interrupts reentry circuits involving the AV node, such as in AV nodal reentrant tachycardia. Its extremely short half-life (seconds) explains the rapid onset and resolution of adverse effects like flushing and chest tightness. Adenosine is the first-line drug for acute termination of stable reentrant supraventricular tachycardia.

  • A. Beta-blockade describes drugs like metoprolol; adenosine does not act on adrenergic receptors.
  • B. Sodium channel blockade describes class I antiarrhythmics, not adenosine's mechanism.
  • D. Potassium channel blockade prolonging the action potential describes class III antiarrhythmics, which is the opposite of adenosine's effect.
  • E. Calcium channel blockade describes the mechanism of verapamil and diltiazem, not adenosine.
Educational objective: Adenosine terminates AV nodal reentrant tachycardia by activating A1 receptors to increase potassium efflux, hyperpolarizing and slowing AV nodal conduction.

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