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USMLE Step 1 · United States

USMLE Step 1 biostatistics, epidemiology & ethics questions

40 original USMLE Step 1-style questions on biostatistics, epidemiology & ethics, each with the correct answer, an explanation, why the other options are wrong and the educational objective. Solve them in the quiz or read them below, grouped by section.

Questions40 with answers
Sections10
Options per question5
Time≈ 60 min
USMLE Step 1 Biostatistics, epidemiology & ethics: practice quizPick an answer to see the correct option and the explanation at once. Your best score is saved in this browser.

Study Design

4 questions
1

Investigators conduct a trial of a new antihypertensive drug in 600 adults with stage 2 hypertension. Participants are randomly assigned using a computer-generated sequence to receive either the new drug or a standard ACE inhibitor. Baseline characteristics, including age, body mass index, smoking status, and duration of hypertension, are similar between the two groups. A reviewer asks why randomization was used instead of simply matching patients on known risk factors. Which of the following best explains the primary statistical advantage of randomization in this trial?

  1. AIt distributes both known and unknown confounders evenly between groups
  2. BIt removes the possibility of a type I error
  3. CIt ensures that the outcome assessors are unaware of treatment assignment
  4. DIt eliminates the need for a control group
  5. EIt guarantees that the sample size is adequate to detect a true effect
Show answer
Answer: A. It distributes both known and unknown confounders evenly between groups

Randomization allocates participants to study groups by chance, which tends to balance both measured and unmeasured confounding variables between groups, including factors investigators have not thought to measure. This is distinct from matching, which only balances known, pre-specified variables. Blinding, not randomization, addresses observer and assessment bias. Adequate sample size is determined by power calculations, not randomization itself.

  • B. Randomization does not affect the alpha level or probability of a type I error
  • C. This describes blinding, a separate design feature from randomization
  • D. A control group is still required; randomization only determines how subjects are allocated to groups
  • E. Sample size adequacy depends on power calculations, not on the randomization process
Educational objective: Randomization balances both known and unknown confounders between study groups, which matching cannot achieve for unmeasured variables.
2

A prospective cohort study enrolls 1,000 smokers and 2,000 nonsmokers and follows them for 10 years to determine the incidence of lung cancer. Among the smokers, 80 develop lung cancer. Among the nonsmokers, 20 develop lung cancer. Based on these data, what is the relative risk of lung cancer in smokers compared with nonsmokers?

  1. A1.6
  2. B40.0
  3. C4.0
  4. D0.125
  5. E8.0
Show answer
Answer: E. 8.0

Relative risk is calculated as the incidence of disease in the exposed group divided by the incidence in the unexposed group. Incidence in smokers = 80/1,000 = 0.08 (8%); incidence in nonsmokers = 20/2,000 = 0.01 (1%). Relative risk = 0.08/0.01 = 8.0, meaning smokers have 8 times the risk of developing lung cancer compared with nonsmokers. Relative risk requires a cohort design because the incidence of disease must be known in both exposed and unexposed groups.

  • A. This value does not correspond to any correct ratio of the given incidence proportions
  • B. This results from an arithmetic error in calculating the incidence proportions
  • C. This results from incorrectly dividing the number of cases (80/20) rather than the incidence proportions
  • D. This is the reciprocal of the correct relative risk, representing the risk in nonsmokers relative to smokers
Educational objective: Relative risk, calculated from incidence data in a cohort study, equals the incidence in the exposed group divided by the incidence in the unexposed group.
3

A case-control study is conducted to evaluate the association between consumption of raw shellfish and hepatitis A infection. The investigators identify 100 patients with confirmed hepatitis A (cases) and 100 matched patients without hepatitis A (controls) and ask about shellfish consumption in the preceding month. Of the cases, 60 reported eating raw shellfish and 40 did not. Of the controls, 20 reported eating raw shellfish and 80 did not. What is the odds ratio for the association between raw shellfish consumption and hepatitis A in this study?

  1. A3.0
  2. B12.0
  3. C0.17
  4. D1.5
  5. E6.0
Show answer
Answer: E. 6.0

In a case-control study, the odds ratio is calculated as (a × d)/(b × c), where a = exposed cases, b = unexposed cases, c = exposed controls, and d = unexposed controls. Here, (60 × 80)/(40 × 20) = 4,800/800 = 6.0. This means the odds of raw shellfish consumption are 6 times higher in people with hepatitis A than in those without, supporting an association. Case-control studies cannot directly calculate relative risk because incidence data are not collected, so the odds ratio is used instead.

  • A. This results from an incorrect cross-multiplication of the 2x2 table values
  • B. This results from doubling the correct odds ratio due to a calculation error
  • C. This is the reciprocal of the correct odds ratio
  • D. This results from comparing exposure proportions directly rather than computing the cross-product odds ratio
Educational objective: In a case-control study, the odds ratio is calculated as (a×d)/(b×c) from a 2x2 exposure-outcome table.
4

A public health researcher surveys 5,000 adults in a single county at one point in time, asking each participant whether they currently have diabetes mellitus and whether they currently smoke cigarettes. The researcher calculates the proportion of the surveyed population that has diabetes at the time of the survey and compares this proportion between smokers and nonsmokers. Which of the following best describes the primary epidemiologic measure that this study design is suited to assess?

  1. AIncidence of new diabetes cases over the study period
  2. BRelative risk of developing diabetes among smokers
  3. CPrevalence of diabetes at a single point in time
  4. DCumulative incidence of diabetes over a defined follow-up period
  5. EAttributable risk of smoking on diabetes incidence
Show answer
Answer: C. Prevalence of diabetes at a single point in time

A cross-sectional study collects data on exposure and disease status at a single point in time from a defined population, making it ideal for calculating prevalence, the proportion of a population affected by a condition at that moment. Because there is no follow-up period, cross-sectional studies cannot measure incidence, the rate of new cases arising over time, nor can they calculate relative risk or attributable risk, which require longitudinal data. This design is useful for generating hypotheses about associations but is limited by its inability to establish temporal sequence between exposure and outcome.

  • A. Incidence requires following a population over time to identify new cases, which a cross-sectional study does not do
  • B. Relative risk requires incidence data from exposed and unexposed cohorts followed longitudinally
  • D. Cumulative incidence requires a defined follow-up period, which is absent in a cross-sectional design
  • E. Attributable risk requires incidence data, which is not available from a single-time-point survey
Educational objective: Cross-sectional studies measure prevalence at a single point in time and cannot determine incidence or temporal sequence.

Bias & Confounding

1 questions
5

A researcher wants to determine the average duration of symptoms before diagnosis in patients with pancreatic adenocarcinoma. She recruits patients from an oncology clinic who are currently alive and receiving treatment, and asks them to recall when their symptoms began. Patients who died rapidly after symptom onset, before ever reaching the clinic, are not included in the study. The researcher concludes that pancreatic cancer has a long symptomatic period before diagnosis. Which of the following best explains why this conclusion may be inaccurate?

  1. ARecall bias from patients misremembering symptom onset
  2. BConfounding by indication from treatment selection
  3. CLate-look bias from excluding patients who died early with aggressive disease
  4. DLead-time bias from earlier detection by screening
  5. ELength-time bias from overrepresentation of slowly progressive disease
Show answer
Answer: C. Late-look bias from excluding patients who died early with aggressive disease

Late-look bias occurs when a study samples patients at a point in time that systematically excludes those who died early from rapidly fatal disease, leaving a sample enriched for individuals with a longer, more indolent course. Here, patients who died quickly after symptom onset (likely those with the most aggressive tumors) never reached the oncology clinic and were excluded, biasing the study toward patients with longer survival and more time between symptom onset and diagnosis. This differs from length-time bias, which specifically refers to screening programs preferentially detecting slow-growing tumors. The researcher's conclusion reflects the survivors remaining in the sample, not the true natural history of the disease.

  • A. Recall bias involves differential memory accuracy between groups, not exclusion of a subgroup from the sample.
  • B. Confounding by indication concerns treatment-outcome associations distorted by why treatment was chosen, which is not the issue described.
  • D. Lead-time bias applies to screening-detected cases appearing to survive longer because they are diagnosed earlier in their course, not to exclusion of patients who died before diagnosis.
  • E. Length-time bias is a screening-specific phenomenon where slow-growing tumors are preferentially caught; this study is not a screening program.
Educational objective: Late-look bias arises when individuals who die early with severe disease are systematically excluded from a study sample, skewing results toward a falsely favorable disease course.
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Diagnostic Statistics

8 questions
6

A new serum biomarker assay is evaluated for detection of acute myocardial infarction in 500 patients presenting with chest pain, using cardiac catheterization as the gold standard. Of the 150 patients with confirmed myocardial infarction, 135 test positive on the biomarker assay. Of the 350 patients without myocardial infarction, 70 test positive on the biomarker assay. What is the specificity of this biomarker assay?

  1. A90.0%
  2. B38.6%
  3. C95.8%
  4. D80.0%
  5. E65.7%
Show answer
Answer: D. 80.0%

Specificity is the proportion of patients without disease who correctly test negative, calculated as true negatives divided by all patients without disease (true negatives plus false positives). Here, among the 350 patients without myocardial infarction, 70 tested positive (false positives), so 280 tested negative (true negatives). Specificity = 280 / 350 = 80.0%. Sensitivity, in contrast, is 135/150 = 90.0%, which is the proportion of diseased patients correctly identified as positive. Confusing the denominator (using all patients rather than only those without disease) is a common calculation error for specificity.

  • A. This value equals the sensitivity (135/150), not the specificity.
  • B. This value results from an incorrect denominator (e.g., using true negatives over total positives) rather than the diseased-free population.
  • C. This value does not match the correct calculation of true negatives over total disease-free patients.
  • E. This value does not correspond to true negatives divided by total disease-free patients.
Educational objective: Specificity equals true negatives divided by the total number of patients without disease (true negatives plus false positives).
7

A screening test for hepatitis C virus infection has a sensitivity of 95% and a specificity of 90%. The test is first applied in a population of intravenous drug users, in whom the prevalence of hepatitis C infection is 40%. The same test is then applied in a population of first-time blood donors, in whom the prevalence of hepatitis C infection is 2%. Assuming sensitivity and specificity remain constant, how does the positive predictive value (PPV) of the test change between these two populations?

  1. APPV is higher in the blood donor population because fewer false positives occur in absolute numbers
  2. BPPV cannot be determined without knowing the total sample size in each population
  3. CPPV is higher in the intravenous drug user population because a positive result is more likely to be a true positive at higher prevalence
  4. DPPV is the same in both populations because sensitivity and specificity are intrinsic to the test
  5. EPPV is higher in the blood donor population because specificity is unaffected by prevalence
Show answer
Answer: C. PPV is higher in the intravenous drug user population because a positive result is more likely to be a true positive at higher prevalence

Positive predictive value is directly influenced by disease prevalence in the tested population, even when sensitivity and specificity remain fixed properties of the test. At higher prevalence (40% in intravenous drug users), a larger proportion of positive results are true positives because there are proportionally more diseased individuals to generate true positives relative to the fixed false-positive rate from the smaller disease-free group. At lower prevalence (2% in blood donors), the same specificity yields a relatively larger pool of false positives among the much larger disease-free population, driving PPV down. This is why PPV rises with prevalence and falls with declining prevalence, unlike sensitivity and specificity which are prevalence-independent.

  • A. Absolute false-positive counts depend on sample size, not on the proportional relationship that determines PPV; the directionality stated is also incorrect.
  • B. PPV can be calculated from prevalence, sensitivity, and specificity alone without needing the raw sample size.
  • D. Sensitivity and specificity are intrinsic to the test, but PPV and NPV depend on prevalence and therefore differ between populations.
  • E. Specificity being prevalence-independent does not mean PPV is prevalence-independent; PPV depends directly on prevalence.
Educational objective: Positive predictive value increases as disease prevalence increases, even though sensitivity and specificity remain constant properties of the test.
8

A new urine antigen test for Legionella pneumonia is studied in 1,000 hospitalized patients with community-acquired pneumonia. Chest CT with bronchoalveolar lavage culture (gold standard) confirms Legionella infection in 100 patients. Of these 100 patients, 92 test positive on the urine antigen test. Of the 900 patients without Legionella infection, 54 test positive on the urine antigen test. What is the positive predictive value of this urine antigen test?

  1. A94.0%
  2. B46.0%
  3. C9.2%
  4. D90.4%
  5. E63.0%
Show answer
Answer: E. 63.0%

Positive predictive value is calculated as true positives divided by all patients who test positive (true positives plus false positives). Here, true positives = 92 and false positives = 54, so total positive tests = 146. PPV = 92 / 146 ≈ 63.0%. Negative predictive value, by comparison, uses true negatives (900 − 54 = 846) divided by all negative tests (846 + 8 false negatives = 854), giving NPV ≈ 99.1%. PPV reflects the probability that a patient with a positive test result truly has the disease.

  • A. This value does not correspond to the correct PPV calculation using the given true and false positive counts.
  • B. This value does not match true positives divided by all positive test results.
  • C. This value does not correspond to the correct ratio of true positives to total positive tests.
  • D. This value approximates sensitivity (92/100), not positive predictive value.
Educational objective: Positive predictive value equals true positives divided by the total number of positive test results (true positives plus false positives).
9

A 55-year-old man presents with exertional chest pain. Based on his age, sex, and symptom characteristics, his pretest probability of significant coronary artery disease is estimated at 30% (pretest odds 0.43). He undergoes an exercise stress echocardiogram, which is positive, and the test has a positive likelihood ratio of 6.0. Using the formula posttest odds = pretest odds × likelihood ratio, what is the approximate posttest probability of coronary artery disease following this positive result?

  1. A50%
  2. B30%
  3. C72%
  4. D85%
  5. E95%
Show answer
Answer: C. 72%

The likelihood ratio approach converts pretest probability to odds, multiplies by the likelihood ratio, and converts back to probability. Pretest probability of 30% corresponds to pretest odds of 0.30/0.70 ≈ 0.43. Posttest odds = 0.43 × 6.0 ≈ 2.57. Converting back to probability: posttest probability = odds / (1 + odds) = 2.57 / 3.57 ≈ 72%. A likelihood ratio greater than 1 increases the probability of disease after a positive test, and larger likelihood ratios produce larger shifts in probability, which is why LRs above 10 are considered strong rule-in evidence.

  • A. This value underestimates the increase in probability produced by a likelihood ratio of 6.0.
  • B. This value simply restates the pretest probability and ignores the effect of the positive test result.
  • D. This value overestimates the posttest probability given the calculated posttest odds of approximately 2.57.
  • E. This value substantially overestimates the posttest probability for this likelihood ratio and pretest probability.
Educational objective: Posttest odds are calculated by multiplying pretest odds by the likelihood ratio, and the result is converted back to posttest probability using odds/(1+odds).
10

A 68-year-old woman with a history of smoking presents to the emergency department with acute dyspnea and pleuritic chest pain. Heart rate is 112/min, blood pressure is 128/82 mm Hg, and oxygen saturation is 91% on room air. The clinical team is highly concerned about pulmonary embolism, and missing this diagnosis could be fatal, but unnecessary CT pulmonary angiography carries contrast and radiation risks. Which of the following test characteristics is most important when selecting an initial test to exclude pulmonary embolism in this patient?

  1. AHigh specificity, to minimize false-positive results
  2. BHigh likelihood ratio for a positive result
  3. CHigh sensitivity, to minimize false-negative results
  4. DHigh positive predictive value, to confirm the diagnosis efficiently
  5. EHigh negative predictive value regardless of disease prevalence
Show answer
Answer: C. High sensitivity, to minimize false-negative results

When a missed diagnosis carries severe consequences, as with pulmonary embolism, the priority is a test with high sensitivity, since a highly sensitive test has few false negatives and a negative result can be used to reliably exclude disease (a negative result on a highly sensitive test rules disease out, following the mnemonic SnNout). D-dimer testing is a classic example used for this purpose in low-to-moderate pretest probability patients. Specificity and positive predictive value are more relevant when the goal is confirming disease, which matters when false positives would be costly, but that is not the priority in an urgent rule-out scenario. Negative predictive value is prevalence-dependent and therefore not an intrinsic test characteristic that guides the initial choice of test.

  • A. High specificity minimizes false positives, which is prioritized when confirming disease, not ruling it out.
  • B. A high positive likelihood ratio is relevant to confirming disease after a positive test, not to safely excluding disease.
  • D. High PPV is relevant to confirming disease after a positive result, not excluding disease when a negative result is the goal.
  • E. Negative predictive value depends on prevalence and is not the fixed test property used to select a screening test for ruling out disease.
Educational objective: A highly sensitive test is preferred to rule out disease when false negatives would be dangerous, because a negative result on a sensitive test effectively excludes the diagnosis.
11

A 45-year-old man undergoes a screening enzyme-linked immunosorbent assay (ELISA) for HIV as part of a routine health evaluation and tests positive. He is asymptomatic and has no known risk factors for HIV infection. Before informing the patient of a diagnosis of HIV infection, which of the following is the most appropriate next step?

  1. ARepeat the same ELISA test on a new blood sample
  2. BPerform an HIV antibody differentiation assay or western blot to confirm the diagnosis
  3. CReassure the patient that a single positive screening test confirms the diagnosis
  4. DMeasure the patient's CD4 count to assess disease severity
  5. EBegin empiric antiretroviral therapy while awaiting further testing
Show answer
Answer: B. Perform an HIV antibody differentiation assay or western blot to confirm the diagnosis

Screening tests such as ELISA are designed with high sensitivity to minimize false negatives, which comes at the cost of lower specificity and a higher false-positive rate, especially in low-prevalence populations such as an asymptomatic patient without risk factors. A confirmatory test with high specificity, such as an HIV antibody differentiation assay (or historically, western blot), is then used to minimize false positives and verify that a positive screening result reflects true disease (a positive result on a highly specific test confirms disease, following the mnemonic SpPin). This two-step strategy, highly sensitive screening followed by highly specific confirmation, is a standard approach in diagnostic testing for low-prevalence conditions. Acting on the screening result alone risks a false diagnosis with major psychological and social consequences for the patient.

  • A. Repeating the identical screening assay does not address its lower specificity and would not resolve the risk of a false positive.
  • C. A single positive result on a screening test, particularly in a low-prevalence patient, is not sufficient to confirm the diagnosis without a confirmatory test.
  • D. CD4 count assesses immune status in confirmed HIV infection but does not establish the diagnosis itself.
  • E. Starting antiretroviral therapy before confirming the diagnosis is inappropriate and exposes the patient to unnecessary risk if the screening result is a false positive.
Educational objective: A positive result on a highly sensitive screening test should be confirmed with a highly specific confirmatory test before a diagnosis is established, particularly in low-prevalence populations.
12

A researcher develops a new serum biomarker to detect early pancreatic cancer and compares it to an existing biomarker by plotting the true-positive rate against the false-positive rate across all possible cutoff values for each test. The new biomarker produces a curve that lies consistently above and to the left of the curve for the existing biomarker, and the area under its curve is 0.91 compared with 0.68 for the existing biomarker. Which of the following is the best interpretation of this finding?

  1. AThe new biomarker requires a higher cutoff value to achieve maximum sensitivity
  2. BThe new biomarker has better reliability but not necessarily better validity than the existing biomarker
  3. CThe new biomarker has higher overall diagnostic accuracy across the range of cutoffs than the existing biomarker
  4. DThe new biomarker has a lower likelihood ratio for a positive result than the existing biomarker
  5. EThe new biomarker has a higher positive predictive value in the population regardless of disease prevalence
Show answer
Answer: C. The new biomarker has higher overall diagnostic accuracy across the range of cutoffs than the existing biomarker

The area under the receiver operating characteristic (ROC) curve (AUC) is a summary measure of a test's overall discriminatory ability across all possible cutoff thresholds, with 1.0 representing a perfect test and 0.5 representing no discriminative value (equivalent to chance). An AUC of 0.91 indicates substantially better overall accuracy than an AUC of 0.68. A curve that lies above and to the left of another reflects a better trade-off between sensitivity and specificity at every cutoff. AUC does not by itself determine predictive values, which depend on disease prevalence, nor does it specify a particular optimal cutoff.

  • A. AUC does not indicate the specific cutoff value needed for maximum sensitivity.
  • B. AUC reflects validity (accuracy), not reliability (reproducibility).
  • D. A higher AUC reflects better overall performance, which corresponds to a higher, not lower, likelihood ratio for a positive test at comparable cutoffs.
  • E. Positive predictive value depends on disease prevalence, not solely on AUC.
Educational objective: The area under the ROC curve summarizes a diagnostic test's overall accuracy independent of a specific cutoff, with values closer to 1.0 indicating better discrimination between diseased and non-diseased individuals.
13

A new screening test for hypothyroidism measures serum TSH level and classifies a result above a certain threshold as positive. Investigators decide to lower the TSH threshold required for a positive result in order to screen a population with a high prevalence of subclinical disease. Compared with the original threshold, what is the expected effect of this change on the test's performance characteristics?

  1. ADecreased sensitivity and increased specificity
  2. BIncreased sensitivity and increased specificity
  3. CDecreased sensitivity and decreased specificity
  4. DIncreased sensitivity and decreased specificity
  5. ENo change in sensitivity or specificity, only in prevalence estimates
Show answer
Answer: D. Increased sensitivity and decreased specificity

Lowering the cutoff value for a positive test result makes it easier for individuals to be classified as test-positive, which increases the number of true positives captured (raising sensitivity) but also increases the number of false positives (lowering specificity). This inverse relationship between sensitivity and specificity is intrinsic to any continuous diagnostic test and is graphically represented by moving along a single ROC curve rather than switching to a different curve. The choice of cutoff reflects a trade-off tailored to the clinical goal, such as maximizing sensitivity for a screening test used to rule out disease.

  • A. Lowering the cutoff increases, not decreases, sensitivity.
  • B. Sensitivity and specificity move in opposite directions when the cutoff changes; both cannot increase simultaneously for the same test.
  • C. Lowering the cutoff increases sensitivity, not decreases it.
  • E. Changing the cutoff alters the test's sensitivity and specificity; prevalence is a property of the population, not the test.
Educational objective: Lowering a diagnostic test's cutoff value increases sensitivity while decreasing specificity, reflecting a trade-off along a fixed ROC curve rather than a change in overall test accuracy.

Measures of Disease Frequency & Impact

4 questions
14

A cohort study examines the incidence of deep vein thrombosis (DVT) among women taking a combined oral contraceptive compared with women who do not use hormonal contraception. Over 5 years, the incidence of DVT is 8 cases per 1,000 women among users and 2 cases per 1,000 women among nonusers. What is the attributable risk of DVT due to oral contraceptive use?

  1. A0.75 cases per 1,000 women
  2. B4 cases per 1,000 women
  3. C4-fold increase in risk
  4. D10 cases per 1,000 women
  5. E6 cases per 1,000 women
Show answer
Answer: E. 6 cases per 1,000 women

Attributable risk (risk difference) is calculated as the incidence of disease in the exposed group minus the incidence in the unexposed group: 8 per 1,000 minus 2 per 1,000 equals 6 per 1,000 women. This measure estimates the excess disease incidence that can be directly attributed to the exposure, assuming the association is causal. It is useful for quantifying the absolute impact of removing an exposure from a population, distinguishing it from relative measures such as relative risk.

  • A. This value does not result from the correct risk difference calculation.
  • B. This value does not correspond to the correct subtraction of incidence rates (8 - 2 = 6, not 4).
  • C. This describes the relative risk (8/2 = 4), not the attributable risk, which is an absolute measure.
  • D. This represents the sum, not the difference, of the two incidence rates.
Educational objective: Attributable risk is calculated as the incidence of disease in the exposed group minus the incidence in the unexposed group, representing the absolute excess risk due to the exposure.
15

A randomized controlled trial evaluates a new antihypertensive drug for prevention of stroke in patients with severe hypertension. Over 3 years, the incidence of stroke is 15% in the placebo group and 9% in the treatment group. Based on these results, how many patients would need to be treated with the new drug for 3 years to prevent one additional stroke?

  1. A67
  2. B11
  3. C17
  4. D7
  5. E24
Show answer
Answer: C. 17

The number needed to treat (NNT) is calculated as the reciprocal of the absolute risk reduction (ARR). Here, ARR = 15% - 9% = 6%, or 0.06. NNT = 1/0.06 ≈ 16.7, which rounds to 17 patients. This means that approximately 17 patients must receive the new drug for 3 years to prevent one additional stroke compared with placebo, providing a clinically intuitive measure of treatment benefit at the population level.

  • A. This value appears to come from using relative risk reduction instead of absolute risk reduction.
  • B. This value does not correspond to the reciprocal of the correct absolute risk reduction.
  • D. This value does not correspond to the reciprocal of the correct absolute risk reduction.
  • E. This value does not correspond to the correct calculation of 1/ARR.
Educational objective: Number needed to treat is the reciprocal of the absolute risk reduction (1/ARR) and estimates how many patients must be treated to prevent one additional adverse outcome.
16

A post-marketing surveillance study of a new NSAID used for chronic osteoarthritis pain reports that gastrointestinal bleeding occurs in 12% of patients taking the drug over 1 year, compared with 4% of patients taking acetaminophen over the same period. Based on this absolute risk increase, how many patients would need to take the NSAID for 1 year to cause one additional episode of gastrointestinal bleeding?

  1. A33
  2. B13
  3. C8
  4. D25
  5. E3
Show answer
Answer: B. 13

The number needed to harm (NNH) is the reciprocal of the absolute risk increase (ARI). Here, ARI = 12% - 4% = 8%, or 0.08. NNH = 1/0.08 = 12.5, which rounds to 13 patients. This value indicates that for every 13 patients treated with the NSAID instead of acetaminophen for 1 year, one additional case of gastrointestinal bleeding would be expected to occur, providing a practical measure of a treatment's harm burden.

  • A. This value does not correspond to the correct calculation of 1/ARI.
  • C. This value does not correspond to the reciprocal of the correct absolute risk increase.
  • D. This value does not correspond to the correct calculation of 1/ARI.
  • E. This value represents the relative risk (12/4 = 3), not the number needed to harm.
Educational objective: Number needed to harm is the reciprocal of the absolute risk increase (1/ARI) and estimates how many patients must be exposed to cause one additional adverse event.
17

An epidemiologist compares two diseases in a stable population of 100,000 people. Disease A is an acute viral gastroenteritis that resolves within 3-5 days, while disease B is a chronic autoimmune condition that persists for decades once diagnosed. Both diseases have identical incidence rates of 50 new cases per 100,000 person-years. Which of the following statements best describes the expected prevalence of these two diseases in this population?

  1. AThe prevalence of disease A cannot be determined without knowing its case-fatality rate
  2. BThe prevalence of disease B will decrease over time as incidence remains constant
  3. CThe prevalence of disease A will be substantially higher than the prevalence of disease B
  4. DThe prevalence of disease B will be substantially higher than the prevalence of disease A
  5. EThe prevalence of both diseases will be approximately equal because their incidence rates are identical
Show answer
Answer: D. The prevalence of disease B will be substantially higher than the prevalence of disease A

Prevalence approximates incidence multiplied by average disease duration when the population is stable. Because disease B persists for decades while disease A resolves within days, disease B accumulates many more existing cases at any given point in time despite having the same incidence rate. This illustrates why prevalence is influenced not only by how many new cases occur but also by how long individuals remain affected, which is a key distinction between incidence (new cases over time) and prevalence (existing cases at a point in time).

  • A. Case-fatality rate affects disease duration but is not required to compare the relative prevalence of the two diseases qualitatively.
  • B. With constant incidence and chronic duration, prevalence of disease B would tend to rise toward a steady state, not decrease.
  • C. Disease A has a much shorter duration, so despite equal incidence, its prevalence will be lower, not higher, than disease B's.
  • E. Equal incidence does not translate into equal prevalence when disease durations differ markedly.
Educational objective: Prevalence is proportional to the product of incidence and average disease duration, so chronic diseases have higher prevalence than acute diseases even with identical incidence rates.

Statistical Inference

9 questions
18

A randomized trial compares a new antihypertensive drug with placebo in 400 patients with stage 1 hypertension. The mean reduction in systolic blood pressure is 12 mm Hg greater with the drug than with placebo (95% CI, 8-16 mm Hg; p = 0.001). The prespecified alpha level for this study is 0.05. Which of the following is the most appropriate interpretation of this result?

  1. AThe probability that the alternative hypothesis is true is 99.9%
  2. BThe drug produces a clinically important reduction in blood pressure
  3. CThe probability that the null hypothesis is true is 0.1%
  4. DThe results are not reproducible because the p-value is very small
  5. EThe observed difference in blood pressure reduction is unlikely to be due to chance alone
Show answer
Answer: E. The observed difference in blood pressure reduction is unlikely to be due to chance alone

A p-value of 0.001 that is less than the prespecified alpha of 0.05 means the observed difference between groups is statistically significant, i.e., unlikely to have arisen from chance variation alone if the null hypothesis were true. The p-value is the probability of obtaining a result as extreme as, or more extreme than, the one observed, assuming the null hypothesis is true; it is not the probability that the null or alternative hypothesis is true. Statistical significance also does not automatically equate to clinical significance, which depends on the magnitude of effect and its practical importance.

  • A. The p-value does not give the probability that the alternative hypothesis is true.
  • B. Statistical significance does not necessarily indicate clinical importance; that requires judgment about the magnitude of effect.
  • C. The p-value is not the probability that the null hypothesis is true; this is a common misinterpretation.
  • D. A small p-value reflects the strength of evidence against the null hypothesis in this sample, not reproducibility of results.
Educational objective: A p-value below the prespecified alpha indicates that the observed data are statistically significant, meaning the result is unlikely due to chance, but this does not equal clinical significance or the probability that either hypothesis is true.
19

Investigators conduct a study testing whether a new biomarker predicts recurrence of breast cancer. The null hypothesis states that the biomarker level has no association with recurrence. Based on a p-value of 0.03, the investigators reject the null hypothesis and conclude that the biomarker is associated with recurrence. In reality, the biomarker has no true association with recurrence. Which of the following best describes this scenario?

  1. AType II error
  2. BType I error
  3. CRegression to the mean
  4. DLow statistical power
  5. EConfounding bias
Show answer
Answer: B. Type I error

A type I error occurs when a true null hypothesis is incorrectly rejected, concluding that an association exists when in reality it does not. The probability of making a type I error is denoted by alpha, the significance level set before the study (commonly 0.05). In this scenario, the null hypothesis (no true association) is true, but the investigators rejected it based on a statistically significant p-value, which is the definition of a type I error, often called a false-positive result.

  • A. A type II error is failing to reject a false null hypothesis, which is the opposite of what occurred here.
  • C. Regression to the mean describes extreme values moving toward the average on repeat measurement, unrelated to this scenario.
  • D. Low power relates to the probability of detecting a true effect and would increase type II error, not type I error.
  • E. Confounding bias refers to a third variable distorting the true association, which is not described here.
Educational objective: A type I error (false positive) occurs when a true null hypothesis is incorrectly rejected, with its probability set by the significance level alpha.
20

A pilot study enrolls 20 patients to test whether a new analgesic reduces postoperative pain scores compared with standard therapy. The study finds no statistically significant difference between groups (p = 0.45) and the investigators conclude the analgesic is not effective. In truth, the analgesic does reduce pain scores, but the study was underpowered to detect this difference. Which of the following best describes this outcome?

  1. ARecall bias
  2. BSelection bias
  3. CType I error
  4. DLead-time bias
  5. EType II error
Show answer
Answer: E. Type II error

A type II error occurs when a study fails to reject a false null hypothesis, concluding there is no effect when a true effect actually exists. This is often called a false-negative result and its probability is denoted beta. Small sample sizes, as in this 20-patient pilot study, reduce statistical power (1 - beta) and increase the likelihood of a type II error because the study lacks sufficient ability to detect a true difference.

  • A. Recall bias involves differential memory of past exposures, not applicable to this randomized comparison.
  • B. Selection bias relates to how participants are chosen for a study, not to a statistical conclusion about effect detection.
  • C. A type I error is incorrectly rejecting a true null hypothesis, which is the opposite of what happened here.
  • D. Lead-time bias relates to earlier diagnosis appearing to improve survival in screening studies, unrelated to this scenario.
Educational objective: A type II error (false negative) occurs when a false null hypothesis is not rejected, commonly due to inadequate statistical power from a small sample size.
21

A researcher is designing a trial to compare a new anticoagulant with warfarin for prevention of stroke in patients with atrial fibrillation. A biostatistician recommends increasing the planned sample size from 200 to 800 patients per group while keeping the significance level and expected effect size the same. Which of the following is the most likely effect of this change on the study?

  1. AIncreased power and increased probability of type II error
  2. BDecreased probability of type I error and decreased power
  3. CNo change in power because power depends only on effect size
  4. DIncreased power and decreased probability of type II error
  5. EDecreased power and decreased probability of type I error
Show answer
Answer: D. Increased power and decreased probability of type II error

Increasing the sample size reduces the standard error of the estimated effect, which narrows the confidence interval and increases the ability of the study to detect a true difference between groups if one exists. This increase in statistical power (1 - beta) directly corresponds to a decrease in the probability of a type II error (beta), since power and beta are complementary. Sample size does not directly change the type I error rate (alpha), which is set by the investigator as the significance threshold.

  • A. Power and type II error move in opposite directions, so both cannot increase together.
  • B. Increasing sample size increases power rather than decreasing it, and alpha is unaffected by sample size.
  • C. Power depends on sample size, effect size, variability, and alpha; sample size is a major determinant of power.
  • E. Alpha, the type I error rate, is set by the investigator and is not directly changed by increasing sample size.
Educational objective: Increasing sample size increases statistical power and decreases the probability of a type II error, without directly affecting the type I error rate (alpha).
22

A case-control study examines the association between occupational asbestos exposure and development of mesothelioma. The odds ratio for mesothelioma in exposed workers compared with unexposed workers is 4.2, with a 95% confidence interval of 1.8 to 9.6. Which of the following is the most appropriate conclusion based on this confidence interval?

  1. AThe association between asbestos exposure and mesothelioma is statistically significant
  2. BThe odds ratio is biased toward the null due to confounding
  3. CThe association between asbestos exposure and mesothelioma is not statistically significant
  4. DThe true odds ratio in the population is exactly 4.2
  5. EThe study has insufficient power to detect an association
Show answer
Answer: A. The association between asbestos exposure and mesothelioma is statistically significant

Because the 95% confidence interval for the odds ratio (1.8 to 9.6) does not include the null value of 1, the association between asbestos exposure and mesothelioma is statistically significant at the conventional alpha of 0.05. For ratio measures of association such as odds ratios and relative risks, a value of 1 indicates no association; if the entire confidence interval lies above or below 1, the result is unlikely to be due to chance alone. The width of the interval also reflects the precision of the estimate, with narrower intervals indicating more precise estimates.

  • B. There is no information given about confounding, and the interval itself does not indicate directionality of bias.
  • C. Because the interval excludes 1, the association is in fact statistically significant, not non-significant.
  • D. A confidence interval provides a range of plausible values for the true odds ratio, not certainty about one exact value.
  • E. An interval excluding the null value with a wide range reflects significance, not necessarily low power; low power typically produces wide intervals that include the null.
Educational objective: A 95% confidence interval for an odds ratio or relative risk that excludes the value 1 indicates a statistically significant association at the corresponding alpha level.
23

A researcher wants to compare the mean hemoglobin A1c level in a group of 50 patients treated with a new oral hypoglycemic agent to the mean hemoglobin A1c level in a group of 50 patients treated with metformin after 12 weeks. Hemoglobin A1c values are continuous and approximately normally distributed in both groups. Which of the following statistical tests is most appropriate to compare the two groups?

  1. AStudent's t-test
  2. BKaplan-Meier analysis
  3. CChi-square test
  4. DPearson correlation coefficient
  5. EAnalysis of variance (ANOVA)
Show answer
Answer: A. Student's t-test

The Student's t-test is used to compare the means of a continuous, normally distributed variable between exactly two independent groups, which matches this scenario of comparing mean hemoglobin A1c between two treatment groups. The chi-square test is reserved for categorical data, ANOVA is used when comparing means among three or more groups, Pearson correlation measures the linear relationship between two continuous variables rather than comparing group means, and Kaplan-Meier analysis estimates survival probabilities over time.

  • B. Kaplan-Meier analysis is used to estimate time-to-event probabilities, not to compare mean laboratory values between two groups.
  • C. Chi-square compares proportions of categorical variables between groups, not means of continuous variables.
  • D. Pearson correlation quantifies the strength and direction of a linear association between two continuous variables, not a difference in means between groups.
  • E. ANOVA is used when comparing means among three or more groups, not just two.
Educational objective: The Student's t-test compares the means of a continuous, normally distributed variable between two independent groups.
24

A clinical researcher wants to compare mean fasting glucose levels among four groups of patients receiving different doses of a new diabetes medication: 0 mg, 50 mg, 100 mg, and 200 mg daily, after 8 weeks of treatment. Fasting glucose is a continuous variable that is approximately normally distributed in each group. Which of the following statistical tests is most appropriate to determine whether there is a significant difference in mean fasting glucose among the four dose groups?

  1. AWilcoxon rank-sum test
  2. BChi-square test
  3. CPearson correlation coefficient
  4. DStudent's t-test
  5. EAnalysis of variance (ANOVA)
Show answer
Answer: E. Analysis of variance (ANOVA)

Analysis of variance (ANOVA) is the appropriate test for comparing means of a continuous, normally distributed variable among three or more independent groups, as in this trial comparing fasting glucose across four dose groups. ANOVA tests whether at least one group mean differs from the others by comparing between-group variance to within-group variance, generating a single overall p-value rather than requiring multiple pairwise t-tests, which would otherwise inflate the type I error rate. If the ANOVA result is significant, post hoc tests can then identify which specific group means differ.

  • A. The Wilcoxon rank-sum test is a nonparametric test comparing two groups, not three or more, and is used when data are not normally distributed.
  • B. Chi-square test compares categorical proportions, not means of continuous variables.
  • C. Pearson correlation quantifies association between two continuous variables, not differences in means among groups.
  • D. A Student's t-test compares means between only two groups and would require multiple comparisons here, inflating the type I error rate.
Educational objective: Analysis of variance (ANOVA) is used to compare the means of a continuous variable among three or more independent groups while controlling the overall type I error rate.
25

A researcher studies the relationship between daily sodium intake (mg) and systolic blood pressure (mmHg) in 200 adults. A scatter plot shows that as sodium intake increases, systolic blood pressure tends to increase in a consistent linear pattern. The calculated correlation coefficient is r = 0.82. Which of the following best describes this finding?

  1. AA strong negative linear association between sodium intake and systolic blood pressure
  2. BA causal effect of sodium intake on systolic blood pressure
  3. CA strong positive linear association between sodium intake and systolic blood pressure
  4. DA weak positive linear association between sodium intake and systolic blood pressure
  5. ENo linear association between sodium intake and systolic blood pressure
Show answer
Answer: C. A strong positive linear association between sodium intake and systolic blood pressure

The Pearson correlation coefficient (r) measures the strength and direction of a linear relationship between two continuous variables, ranging from -1 to +1. An r value of 0.82 indicates a strong positive association, meaning both variables increase together. Values closer to +1 or -1 indicate stronger linear relationships, while values near 0 indicate little to no linear relationship. Correlation does not establish causation, as confounding variables or reverse causation may explain the association.

  • A. A negative r value would indicate an inverse relationship, where one variable increases as the other decreases; here r is positive.
  • B. Correlation coefficients describe association, not causation; a controlled experiment would be needed to establish causality.
  • D. An r of 0.82 is close to 1, indicating a strong, not weak, correlation.
  • E. An r value of 0.82 indicates a strong relationship, not an absence of correlation.
Educational objective: The Pearson correlation coefficient (r) quantifies the strength and direction of a linear relationship between two continuous variables but does not imply causation.
26

A meta-analysis pools results from 12 randomized controlled trials evaluating a new antihypertensive drug versus placebo for reducing the risk of stroke. The forest plot shows individual trial point estimates with 95% confidence intervals as horizontal lines, and a diamond at the bottom representing the pooled relative risk. The diamond is centered at a relative risk of 0.65, with its horizontal tips (95% CI) ranging from 0.55 to 0.77, entirely to the left of the line of no effect. The individual trial estimates show substantial overlap with minimal variability beyond that expected by chance. Which of the following statements best describes this result?

  1. AThe drug significantly reduces stroke risk, and heterogeneity among trials is high
  2. BThe drug has no significant effect on stroke risk, and heterogeneity among trials is low
  3. CThe drug significantly increases stroke risk, and heterogeneity among trials is high
  4. DThe results are inconclusive due to high heterogeneity among trials
  5. EThe drug significantly reduces stroke risk, and heterogeneity among trials is low
Show answer
Answer: E. The drug significantly reduces stroke risk, and heterogeneity among trials is low

In a forest plot, the diamond represents the pooled effect estimate, and its position relative to the line of no effect (RR = 1) indicates statistical significance; here, the diamond and its 95% CI lie entirely below 1, indicating a significant reduction in stroke risk. The degree of overlap among individual trial confidence intervals reflects heterogeneity: substantial overlap with variability close to what is expected by chance indicates low heterogeneity (low I² statistic), supporting that pooling the results is statistically appropriate. High heterogeneity would appear as widely scattered point estimates with little overlap, often prompting use of a random-effects model instead of a fixed-effect model.

  • A. The substantial overlap among individual trial estimates indicates low, not high, heterogeneity.
  • B. The pooled confidence interval excludes 1, indicating a statistically significant effect, not a null result.
  • C. The relative risk is less than 1, indicating a reduction, not an increase, in stroke risk.
  • D. The low heterogeneity and significant pooled estimate support a conclusive, not inconclusive, result.
Educational objective: In a forest plot, a pooled diamond with a confidence interval excluding the line of no effect indicates a statistically significant result, while overlapping individual trial estimates indicate low heterogeneity.

Descriptive Statistics

3 questions
27

A study records the hospital length of stay (in days) for 9 patients admitted with community-acquired pneumonia: 3, 4, 4, 5, 5, 5, 6, 6, and 40 days (the last patient required prolonged ICU care for septic shock). Which of the following statements best describes the effect of the 40-day outlier on the measures of central tendency for this data set?

  1. ANeither the mean nor the median is affected by the outlier
  2. BThe median is markedly increased, while the mean changes little
  3. CThe mean decreases while the median increases
  4. DThe mean is markedly increased, while the median changes little
  5. EThe mean and median are both markedly increased by the outlier
Show answer
Answer: D. The mean is markedly increased, while the median changes little

The mean is calculated by summing all values and dividing by the number of observations, so an extreme outlier like 40 days disproportionately pulls the mean upward. The median, defined as the middle value when data are ordered, is resistant to extreme values because it depends only on rank order, not magnitude; here the median remains 5 days regardless of how extreme the ninth value is. This property makes the median a more robust measure of central tendency for skewed data sets, such as hospital length-of-stay data, which commonly has a long right tail.

  • A. The mean is affected by outliers; it increases substantially due to the extreme value.
  • B. The median is unaffected by the magnitude of the outlier, only its rank; it does not increase markedly.
  • C. Both values should increase or stay stable with a high-value outlier; the mean does not decrease.
  • E. The median is resistant to outliers and does not change markedly with a single extreme value.
Educational objective: The mean is sensitive to extreme outliers, while the median is resistant because it depends on rank order rather than magnitude.
28

A biostatistician analyzes the annual household income of 500 families in a community survey. The mean income is $78,000, and the median income is $58,000. A histogram of the data shows most values clustered at the lower end with a long tail extending toward higher values. Which of the following best characterizes this distribution?

  1. AUniform distribution
  2. BNegatively (left) skewed distribution
  3. CNormal distribution
  4. DPositively (right) skewed distribution
  5. EBimodal distribution
Show answer
Answer: D. Positively (right) skewed distribution

In a positively (right) skewed distribution, the tail extends toward higher values, pulling the mean above the median, as seen here with a mean of $78,000 exceeding the median of $58,000. This pattern is typical of income data, where most individuals earn modest amounts but a small number of high earners create a long right tail. In contrast, a negatively (left) skewed distribution has a tail extending toward lower values, causing the mean to fall below the median. Recognizing skew direction is important because it affects which measure of central tendency (mean vs median) best represents the typical value.

  • A. A uniform distribution has roughly equal frequency across all values, which is inconsistent with a long tail and unequal mean/median.
  • B. A left-skewed distribution would show the mean lower than the median, not higher.
  • C. A normal distribution is symmetric, with the mean equal to the median, which is not the case here.
  • E. A bimodal distribution has two distinct peaks, which is not described here.
Educational objective: In a positively (right) skewed distribution, the tail extends toward higher values and the mean exceeds the median.
29

A researcher measures fasting blood glucose levels in a sample of 25 healthy adults and calculates a mean of 92 mg/dL with a standard deviation of 10 mg/dL. The researcher then increases the sample size to 400 healthy adults from the same population and recalculates the mean and variability, obtaining a similar mean with a similar standard deviation. Which of the following statements best describes the expected effect of increasing the sample size from 25 to 400 on the standard error of the mean?

  1. AThe standard error of the mean decreases to one-half of its original value
  2. BThe standard error of the mean increases fourfold
  3. CThe standard error of the mean increases to four times its original value only if the standard deviation also increases
  4. DThe standard error of the mean decreases to one-fourth of its original value
  5. EThe standard error of the mean remains unchanged
Show answer
Answer: D. The standard error of the mean decreases to one-fourth of its original value

The standard error of the mean (SEM) is calculated as the standard deviation divided by the square root of the sample size (SEM = SD/√n). Increasing the sample size from 25 to 400 represents a 16-fold increase in n, and since √16 = 4, the SEM decreases to one-fourth of its original value, assuming the standard deviation remains stable. Unlike the standard deviation, which reflects the inherent variability of individual measurements in the population and does not systematically change with sample size, the SEM reflects the precision of the sample mean as an estimate of the true population mean and improves (decreases) as sample size increases.

  • A. The square root of the 16-fold increase in sample size is 4, so the SEM decreases to one-fourth, not one-half, of its original value.
  • B. The SEM decreases, not increases, as sample size increases.
  • C. The SEM decreases with increasing sample size regardless of whether the standard deviation changes, as long as the standard deviation remains stable, which is the case described.
  • E. The SEM decreases substantially with a 16-fold increase in sample size; it does not remain unchanged.
Educational objective: The standard error of the mean equals the standard deviation divided by the square root of the sample size, so SEM decreases as sample size increases, even when the standard deviation remains constant.

Clinical Trial Phases

2 questions
30

A pharmaceutical company has developed a novel oral anticoagulant and wants to begin human testing after completing successful animal toxicology studies. In the first stage of human testing, the drug is administered to 20 healthy adult volunteers at escalating doses to assess pharmacokinetics, pharmacodynamics, and tolerability, with close monitoring for adverse effects. No patients with the target disease are enrolled at this stage. Which phase of clinical trials does this scenario describe?

  1. APhase III trial
  2. BPhase I trial
  3. CPhase II trial
  4. DPhase IV trial
  5. EPreclinical trial
Show answer
Answer: B. Phase I trial

Phase I trials represent the first stage of human testing for a new drug and are conducted in a small number of healthy volunteers (typically 20-100) to determine safety, tolerability, pharmacokinetics, and an appropriate dosage range. These trials use escalating doses to identify the maximum tolerated dose and to detect dose-limiting toxicities before the drug is tested in patients with the target disease. Only after a drug demonstrates acceptable safety in Phase I does testing proceed to Phase II trials, which involve patients with the disease to assess efficacy.

  • A. Phase III trials involve large numbers of patients to compare the new treatment with standard therapy, not healthy volunteers.
  • C. Phase II trials involve patients with the target disease to assess efficacy, not healthy volunteers assessing safety and dosage.
  • D. Phase IV trials occur after FDA approval to monitor long-term safety and effectiveness in the general population.
  • E. Preclinical trials involve laboratory and animal studies, not human testing, and were already completed in this scenario.
Educational objective: Phase I clinical trials test safety, tolerability, and dosage of a new drug in a small group of healthy volunteers.
31

After a new monoclonal antibody for rheumatoid arthritis successfully completes initial human safety testing in healthy volunteers, the drug moves to the next stage of clinical development. In this stage, 150 patients diagnosed with moderate-to-severe rheumatoid arthritis are enrolled and treated with the drug to assess its ability to reduce joint inflammation and disease activity scores, as well as to further characterize side effects in this patient population. Which phase of clinical trials does this scenario describe?

  1. APreclinical trial
  2. BPhase II trial
  3. CPhase IV trial
  4. DPhase I trial
  5. EPhase III trial
Show answer
Answer: B. Phase II trial

Phase II trials are conducted after Phase I establishes basic safety and involve a relatively small group of patients who actually have the target disease, in this case rheumatoid arthritis. The primary goals of Phase II are to evaluate the drug's efficacy for the intended indication and to further assess short-term side effects in the disease population, often using dose-ranging designs to identify the optimal therapeutic dose. If a drug demonstrates efficacy and an acceptable safety profile in Phase II, it then proceeds to Phase III, which involves larger, randomized trials comparing it with standard treatment.

  • A. Preclinical trials involve laboratory and animal studies, not testing in human patients.
  • C. Phase IV trials occur after FDA approval to monitor long-term outcomes in the general population, not during initial efficacy testing.
  • D. Phase I trials involve healthy volunteers to assess safety and dosage, not patients with the disease assessing efficacy.
  • E. Phase III trials involve much larger patient populations and are designed to confirm efficacy and monitor adverse effects on a broader scale, typically comparing against standard therapy.
Educational objective: Phase II clinical trials assess efficacy and side effects of a new drug in a small group of patients who have the target disease.

Confidentiality & Legal Duties

3 questions
32

A 4-year-old girl is brought to the emergency department by her mother for a swollen left arm after "falling off a chair." Examination shows a spiral fracture of the left humerus, several bruises of different colors over the back and buttocks, and a well-healed circular scar on the thigh. The child avoids eye contact with her mother and flinches when the mother raises her hand. The mother becomes irritated and insists on taking the child home immediately. Which of the following is the most appropriate next step?

  1. ADischarge the child home with close outpatient follow-up in 1 week
  2. BObtain written consent from the mother before contacting child protective services
  3. CAsk the father for permission to report before taking further action
  4. DDocument the findings in the chart and reassess at the next well-child visit
  5. EReport the suspected abuse to child protective services regardless of parental consent
Show answer
Answer: E. Report the suspected abuse to child protective services regardless of parental consent

Physicians are legally mandated to report suspected child abuse to child protective services or law enforcement whenever there is reasonable suspicion, regardless of parental consent or objection. The physical findings here, bruises of varying ages, a spiral fracture inconsistent with the stated mechanism, and behavioral cues, raise reasonable suspicion. Mandatory reporting laws override the usual requirement for parental consent and confidentiality protections because protecting the child from ongoing harm takes priority. The reporting threshold is reasonable suspicion, not certainty.

  • A. Discharging the child without reporting leaves her at risk for further abuse and violates mandatory reporting law.
  • B. Parental consent is not required or legally relevant for mandatory abuse reporting.
  • C. Reporting does not require permission from either parent; the duty is to the state, not the family.
  • D. Documentation alone is insufficient; a report must be filed promptly given reasonable suspicion of abuse.
Educational objective: Physicians must report suspected child abuse to the appropriate authorities whenever there is reasonable suspicion, overriding parental consent and confidentiality.
33

A 29-year-old man is diagnosed with pulmonary tuberculosis after sputum acid-fast smear and culture confirm Mycobacterium tuberculosis. He begins a four-drug regimen but tells his physician that he does not want anyone, including his employer or health department, to know his diagnosis, citing fear of losing his job. Which of the following is the most appropriate next step?

  1. AHonor the patient's request and withhold the diagnosis from public health authorities
  2. BObtain a court order before notifying public health authorities
  3. CReport the case only if the patient fails to complete therapy
  4. DReport the case to the local health department despite the patient's objection
  5. EAsk the patient's employer to decide whether reporting is necessary
Show answer
Answer: D. Report the case to the local health department despite the patient's objection

Active tuberculosis is a legally reportable communicable disease in all U.S. states, and physicians must notify public health authorities regardless of patient objection. This exception to confidentiality exists because uncontrolled transmission poses a direct risk to the community, and public health agencies need this information to perform contact tracing, ensure treatment adherence (including directly observed therapy if needed), and prevent outbreaks. Patient autonomy and confidentiality are outweighed by the duty to protect public health in the case of reportable infectious diseases.

  • A. Withholding a mandatory report violates public health law and places others at risk of infection.
  • B. No court order is needed; mandatory disease reporting is a standing legal requirement.
  • C. Reporting is required at diagnosis, not contingent on treatment failure.
  • E. Reporting decisions are a legal duty of the physician and health department, not the employer.
Educational objective: Physicians must report cases of legally designated communicable diseases, such as active tuberculosis, to public health authorities even without patient consent.
34

A hospitalist notices that a fellow attending physician smells of alcohol, has slurred speech, and makes an incorrect dosing decision during morning rounds. Colleagues mention that this has happened on several previous occasions. The hospitalist is uncertain how to proceed and considers simply talking to the physician privately without further action. Which of the following is the most appropriate ethical course of action?

  1. AWait until a patient is harmed before taking any action
  2. BDiscuss the concern only with nursing staff and let them decide whether to report
  3. CReport the suspected impairment to the hospital's physician health program or relevant authority
  4. DConfront the colleague privately and consider the matter resolved if they deny impairment
  5. ESay nothing because confronting a colleague violates professional courtesy
Show answer
Answer: C. Report the suspected impairment to the hospital's physician health program or relevant authority

Physicians have an ethical and often legal obligation to report colleagues suspected of practicing while impaired, because impaired practice endangers patient safety. The appropriate channel is typically a hospital's physician health program, credentialing committee, or state medical board, which can arrange evaluation and treatment while protecting patients. This duty exists independently of whether harm has already occurred; the goal is prevention. Reporting is considered an act of professional responsibility, not betrayal, and is distinct from simply confronting the colleague informally, which does not ensure patient safety or get the colleague appropriate help.

  • A. Waiting for harm to occur before acting fails the duty to prevent foreseeable patient injury.
  • B. The reporting duty belongs to the physician who witnessed the impairment, not to nursing staff alone.
  • D. An informal denial does not resolve the safety concern or ensure appropriate evaluation and treatment.
  • E. Professional courtesy does not override the ethical duty to protect patients from impaired practice.
Educational objective: Physicians have an ethical duty to report colleagues suspected of impaired practice to appropriate authorities to protect patient safety.

Error, Disclosure & Professionalism

3 questions
35

A 52-year-old woman undergoes laparoscopic cholecystectomy. During the procedure, the surgeon nicks the gallbladder bed but does not injure any major vessel or duct; the bleeding is controlled immediately, and the remainder of the operation proceeds without complication. The patient's postoperative course is unremarkable, and she is expected to have a full recovery with no additional treatment or monitoring required. The surgeon is deciding whether to mention this intraoperative event when discussing the outcome with the patient. Which of the following is the most appropriate action?

  1. ADocument the event in the operative note but avoid discussing it with the patient directly
  2. BDisclose the error to the patient because full recovery is expected
  3. CWithhold the information since the event caused no lasting harm
  4. DDisclose the error only to the hospital's quality improvement committee, not the patient
  5. EMention the event only if the patient specifically asks about complications
Show answer
Answer: B. Disclose the error to the patient because full recovery is expected

Current professional guidelines, including those from the American Medical Association, require full disclosure of medical errors to patients regardless of whether harm resulted. Honest disclosure respects patient autonomy, maintains trust, and allows the patient to make informed decisions about their ongoing care, even when the clinical outcome is favorable. The absence of lasting harm does not eliminate the ethical obligation to be truthful; withholding information because an error was minor is a form of deception that undermines the patient's right to know what happened during their own care.

  • A. Documentation alone does not fulfill the ethical obligation to communicate honestly with the patient.
  • C. Lack of lasting harm does not remove the ethical duty to disclose; nondisclosure is deceptive regardless of outcome.
  • D. Internal quality reporting does not substitute for the physician's direct duty to inform the patient.
  • E. Disclosure should be proactive, not contingent on the patient happening to ask the right question.
Educational objective: Physicians must disclose medical errors to patients even when the error caused minimal or no harm, as a matter of honesty and respect for autonomy.
36

An 80-year-old man who has been a patient of his primary care physician for 15 years brings the physician a $15 box of cookies as a thank-you after a routine annual visit. Two months later, the same patient offers the physician $5,000 in cash, stating he wants to ensure he receives "the best possible care" during an upcoming hospitalization. Which of the following is the most appropriate response to these two situations?

  1. AAccept the cookies as a modest token of appreciation, but decline the cash and explain that care is not influenced by gifts
  2. BAccept the cash but donate it to the patient's hospital account instead of keeping it personally
  3. CAccept both the cookies and the cash to maintain a positive relationship with the patient
  4. DAccept the cash only if the patient's family approves of the gesture
  5. EDecline both gifts to avoid any appearance of impropriety
Show answer
Answer: A. Accept the cookies as a modest token of appreciation, but decline the cash and explain that care is not influenced by gifts

Modest, inexpensive gifts that express gratitude, such as a small box of cookies, are generally acceptable in the physician-patient relationship and do not compromise professional judgment. Large monetary gifts, however, raise concern that they could influence clinical decision-making, create a sense of obligation, or be perceived as paying for preferential treatment, and should be declined. The physician should explain that the quality and attention of care are not contingent on gifts, which preserves trust and avoids any appearance of a conflict of interest.

  • B. Redirecting the cash to the hospital account does not resolve the ethical problem of accepting a disproportionate gift tied to care expectations.
  • C. Accepting a large cash gift risks the appearance that care could be influenced by payment, which is inappropriate.
  • D. Family approval is irrelevant to whether accepting a large monetary gift from a patient is ethically appropriate.
  • E. Declining a token gift like cookies is unnecessarily rigid and can damage rapport without ethical justification.
Educational objective: Physicians may accept modest tokens of gratitude from patients but should decline gifts large enough to risk influencing clinical judgment or creating a conflict of interest.
37

A 26-year-old woman presents with a 2-day history of clear rhinorrhea, mild sore throat, and low-grade fever of 100.2°F (37.9°C). Physical examination shows clear nasal discharge, no tonsillar exudate, and no cervical lymphadenopathy. She asks for an antibiotic prescription, explaining that she has an important work trip in 3 days and cannot afford to be sick. Which of the following is the most appropriate next step?

  1. AExplain that her symptoms are consistent with a viral illness, that antibiotics will not help, and discuss supportive care and expected course
  2. BPrescribe a shorter course of antibiotics as a compromise to partially satisfy the request
  3. COrder a complete blood count and chest radiograph to decide whether an antibiotic is warranted
  4. DPrescribe the antibiotic to meet the patient's expressed wishes and preserve the therapeutic relationship
  5. ERefuse to discuss the request further and end the visit
Show answer
Answer: A. Explain that her symptoms are consistent with a viral illness, that antibiotics will not help, and discuss supportive care and expected course

The clinical picture, clear rhinorrhea, low-grade fever, absence of exudate or lymphadenopathy, is consistent with a viral upper respiratory infection, for which antibiotics provide no benefit and carry risks of adverse effects and antimicrobial resistance. The appropriate approach is shared decision-making: educate the patient on the viral etiology and natural course, address her underlying concern (missing her trip), and offer symptomatic treatment. This respects her autonomy while avoiding inappropriate prescribing driven solely by patient request.

  • B. A shorter antibiotic course is still unnecessary for a viral infection and does not resolve the underlying issue of inappropriate prescribing.
  • C. Imaging and blood tests are not indicated for a straightforward viral upper respiratory infection and would not change management.
  • D. Prescribing antibiotics for a viral illness provides no clinical benefit and promotes resistance; patient request alone does not justify it.
  • E. Dismissing the request without explanation fails to address the patient's concerns or educate her about her condition.
Educational objective: When a treatment request is not clinically indicated, physicians should use shared decision-making to educate the patient and address their underlying concerns rather than simply complying with or dismissing the request.

End-of-Life & Advance Directives

3 questions
38

A 74-year-old man with end-stage chronic obstructive pulmonary disease is admitted with respiratory failure and placed on mechanical ventilation. He is sedated and unable to communicate. His advance directive, signed 2 years ago while he had full decision-making capacity, clearly states that he does not want mechanical ventilation or other life-sustaining treatment if he develops irreversible respiratory failure. His two adult children insist that "everything be done" and ask the physician to disregard the document. Which of the following is the most appropriate next step?

  1. ATransfer decision-making authority to the children since the patient cannot currently communicate
  2. BContinue mechanical ventilation because the children are present and request full treatment
  3. CContinue treatment until a court order specifically authorizes withdrawal
  4. DWithdraw mechanical ventilation in accordance with the advance directive despite the children's objection
  5. EConsult the hospital ethics committee before taking any action on the ventilator
Show answer
Answer: D. Withdraw mechanical ventilation in accordance with the advance directive despite the children's objection

A valid advance directive created while the patient had decision-making capacity reflects the patient's own autonomous wishes and takes legal and ethical precedence over the preferences of family members, even next of kin, once the patient loses capacity. The physician's duty is to honor the previously expressed wishes of the patient rather than defer to surrogates who wish to override them. Ethics consultation can be helpful for support or conflict resolution, but it is not required before honoring an unambiguous, validly executed directive, and a court order is not necessary.

  • A. An advance directive specifically limits surrogate authority when it clearly addresses the situation at hand; it is not superseded by family preference.
  • B. Family wishes cannot override a clear, validly executed advance directive expressing the patient's own wishes.
  • C. No court order is needed to honor a legally valid advance directive.
  • E. While ethics consultation can assist with family conflict, it is not a required prerequisite to honoring a clear advance directive.
Educational objective: A patient's valid advance directive takes precedence over family objections once the patient loses decision-making capacity.
39

A 68-year-old woman with metastatic pancreatic cancer and multiorgan failure is in the intensive care unit on mechanical ventilation and vasopressor support. After discussion with the palliative care team, the patient's healthcare proxy, acting on her previously expressed wishes, requests that the ventilator be discontinued and that comfort-focused care be provided. The physician extubates the patient and initiates a morphine infusion titrated to control dyspnea; the patient dies 6 hours later. Which of the following best characterizes this physician's action?

  1. APhysician-assisted suicide, because the physician directly caused the patient's death
  2. BInvoluntary euthanasia, because the patient could not consent to extubation at the time
  3. CActive euthanasia, because medication was administered with the intent to end life
  4. DAn illegal act requiring judicial review before being performed
  5. EWithdrawal of life-sustaining treatment, which is ethically and legally distinct from assisted suicide or euthanasia
Show answer
Answer: E. Withdrawal of life-sustaining treatment, which is ethically and legally distinct from assisted suicide or euthanasia

Withdrawing life-sustaining treatment, such as mechanical ventilation, at the request of a patient or authorized surrogate is a well-established and legally protected practice, ethically distinct from physician-assisted suicide or euthanasia. The intent is to discontinue treatment that is no longer wanted and allow the underlying disease to take its natural course, not to directly cause death. Administering morphine to relieve dyspnea during this process is palliative symptom management under the principle of double effect, not an act of euthanasia, since the intent is comfort, not death. Physician-assisted suicide requires the physician to provide a lethal means for the patient to self-administer, which did not occur here.

  • A. Assisted suicide requires the patient to self-administer a lethal agent; here the physician withdrew unwanted treatment and provided symptom relief.
  • B. The surrogate validly consented on the patient's behalf based on her previously expressed wishes, so this is not involuntary.
  • C. The intent of the morphine infusion was symptom control for dyspnea, not to actively end life, which distinguishes this from euthanasia.
  • D. Withdrawal of life-sustaining treatment at the request of a patient or valid surrogate is legal and does not require judicial review.
Educational objective: Withdrawing life-sustaining treatment at a patient's or surrogate's request, with palliative symptom management, is ethically and legally distinct from physician-assisted suicide or euthanasia.
40

A 68-year-old man with metastatic pancreatic cancer is admitted to hospice for uncontrolled abdominal pain. He is awake, alert, and able to communicate. His current morphine infusion is not controlling his pain despite appropriate titration. His oxygen saturation is 94% on room air, respiratory rate is 14/min, and blood pressure is 108/68 mm Hg. The physician increases the morphine dose to achieve adequate analgesia, understanding that this may suppress his respiratory drive and potentially hasten death. The patient's wife asks whether this is ethically permissible. Which of the following best justifies the physician's action?

  1. AThe wife's acceptance of the risk transfers decision-making authority to her
  2. BThe intent is to relieve suffering, and the harmful effect is a foreseen but unintended consequence of a proportionate, necessary intervention
  3. CBecause the patient has a terminal illness, standard ethical principles governing treatment no longer apply
  4. DThe patient's prior consent to any treatment overrides concerns about adverse effects
  5. EHospice enrollment legally exempts the physician from liability for hastening death
Show answer
Answer: B. The intent is to relieve suffering, and the harmful effect is a foreseen but unintended consequence of a proportionate, necessary intervention

The principle of double effect permits an action with a foreseeable harmful effect if the intended effect is good (pain relief), the harmful effect is not the means to the good effect, the action itself is not inherently wrong, and the good effect is proportionate to the risk of harm. Appropriately titrated opioids for severe pain in a terminally ill patient meet these criteria even if respiratory depression and hastened death are foreseeable. The physician's intent is analgesia, not euthanasia, and the dose is adjusted based on symptom need rather than an intent to cause death. This distinguishes ethically permissible palliative sedation/analgesia from physician-assisted death.

  • A. Decision-making authority is not simply transferred by a family member's acceptance of risk when the patient himself is competent and present.
  • C. Core ethical principles such as beneficence, nonmaleficence, and intent still apply in terminal illness; they are not suspended.
  • D. General consent to treatment does not by itself justify an action; the ethical justification rests on intent and proportionality, not blanket consent.
  • E. Hospice status does not create a special legal exemption; the ethical analysis is based on intent and proportionality, not setting.
Educational objective: Under the principle of double effect, administering adequate analgesia to relieve suffering is ethically permissible even if it foreseeably hastens death, provided the intent is pain relief and the dose is proportionate to symptom need.

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