General & Cell Physiology
5 questionsA physiology student measures the resting membrane potential of a large nerve fiber as -70 mV. The membrane at rest is far more permeable to one ion than to others, and this permeability is the main reason the resting potential lies close to that ion's equilibrium potential rather than at 0 mV. Which ion's gradient is primarily responsible for setting the resting membrane potential?
- AChloride
- BSodium
- CCalcium
- DPotassium
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At rest, the nerve membrane is roughly 50-100 times more permeable to potassium than to sodium because of a large number of open leak potassium channels. According to the Goldman-Donnan principle, the resting membrane potential is weighted heavily toward the equilibrium potential of the ion to which the membrane is most permeable. The Nernst potential for potassium (about -94 mV) is therefore the dominant determinant, while the small sodium permeability shifts the actual resting potential slightly less negative (around -70 to -90 mV). This is why the resting potential sits much closer to the potassium equilibrium potential than to the sodium equilibrium potential.
- A. Chloride distributes passively in many cells and does not primarily set the resting potential.
- B. Sodium permeability at rest is low, so it contributes only a small depolarizing influence.
- C. Calcium does not significantly determine the resting membrane potential of nerve or skeletal muscle.
A biochemistry experiment studies an enzyme embedded in the neuronal membrane that hydrolyzes ATP to actively transport ions against their concentration gradients, maintaining the ionic gradients required for excitability. For every molecule of ATP hydrolyzed, this enzyme transports a fixed number of sodium ions out of the cell and potassium ions into the cell. What is the correct ratio of ions transported by this pump per ATP molecule hydrolyzed?
- A3 Na+ out, 3 K+ in
- B2 Na+ out, 3 K+ in
- C3 Na+ out, 2 K+ in
- D2 Na+ out, 2 K+ in
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The Na+-K+ ATPase is a primary active transporter that uses the energy from hydrolysis of one ATP molecule to pump 3 sodium ions out of the cell and 2 potassium ions into the cell against their respective electrochemical gradients. This unequal exchange makes the pump electrogenic, contributing a small additional negativity to the inside of the cell. The pump is essential for maintaining the steep sodium and potassium gradients that underlie the resting membrane potential and action potential generation, and it is inhibited by cardiac glycosides such as digoxin.
- A. Equal transport of 3 ions each is not the actual stoichiometry of this pump.
- B. This reversed ratio is incorrect; potassium influx is less than sodium efflux, not more.
- D. This ratio underestimates the actual number of sodium ions extruded per ATP.
A renal physiologist studies glucose reabsorption in the proximal convoluted tubule. Glucose enters the tubular cell from the lumen along with sodium through a membrane carrier, with the energy for glucose movement derived entirely from the sodium gradient rather than from direct ATP hydrolysis by the carrier itself. This type of transport is best classified as:
- AFacilitated diffusion
- BSimple diffusion
- CPrimary active transport
- DSecondary active transport
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In secondary active transport, movement of a solute against its concentration gradient is coupled to the movement of another ion (usually sodium) down its own electrochemical gradient, which was itself established by a primary active pump such as the Na+-K+ ATPase. The sodium-glucose cotransporter (SGLT) in the proximal tubule uses the energy stored in the sodium gradient to move glucose into the cell even when intracellular glucose concentration is higher than luminal concentration. No ATP is hydrolyzed directly by the SGLT carrier itself. This mechanism is distinguished from primary active transport, where the transporter itself hydrolyzes ATP to move a substance against its gradient.
- A. Facilitated diffusion moves a substance down its own concentration gradient without using a sodium gradient for energy.
- B. Simple diffusion does not require a carrier protein and cannot move a solute against its concentration gradient.
- C. Primary active transport requires direct ATP hydrolysis by the transporter, which does not occur with SGLT.
An intracellular microelectrode records the membrane potential of a squid giant axon during stimulation. The trace shows a rapid upstroke from -70 mV to +30 mV, followed by a brief plateau and then a rapid fall back toward baseline, with a transient dip below the original resting level before recovery. The rapid upstroke phase of this recording is primarily caused by:
- AOpening of voltage-gated calcium channels causing calcium influx
- BOpening of voltage-gated sodium channels causing sodium influx
- COpening of voltage-gated potassium channels causing potassium efflux
- DClosure of sodium channels and opening of potassium channels
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The rapid depolarizing upstroke of the action potential results from the opening of voltage-gated sodium channels once the membrane reaches threshold, allowing a large influx of sodium ions down their steep electrochemical gradient. This sodium influx rapidly drives the membrane potential toward the sodium equilibrium potential of about +60 mV, producing the overshoot above 0 mV. Repolarization that follows is caused by inactivation of sodium channels combined with delayed opening of voltage-gated potassium channels, which allows potassium efflux to restore the negative resting potential. The transient dip below resting potential, called after-hyperpolarization, results from potassium channels remaining open slightly longer than needed.
- A. Calcium channels contribute to the plateau of cardiac action potentials, not the upstroke of a nerve action potential.
- C. Potassium channel opening and efflux cause repolarization, not the initial upstroke.
- D. This combination describes the repolarization phase, not the rapid upstroke.
A nerve fiber is stimulated with a series of electrical pulses of increasing strength while a second test stimulus is applied at varying intervals after the first. During a certain interval after the first stimulus, no test stimulus, regardless of how strong, is able to generate a second action potential. This finding indicates that the test stimulus was delivered during which period relative to the first action potential?
- ARelative refractory period
- BSubnormal period
- CAbsolute refractory period
- DSupernormal period
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The absolute refractory period corresponds to the time during which sodium channels are inactivated following an action potential and cannot be reopened regardless of stimulus strength, making the nerve fiber completely inexcitable. This period approximately coincides with the depolarization phase and the early part of repolarization. The all-or-none law states that once threshold is reached, the action potential generated is of fixed amplitude independent of stimulus strength, but during the absolute refractory period no stimulus, however strong, can trigger a new action potential because the sodium channels have not yet recovered from inactivation.
- A. During the relative refractory period a stronger-than-normal stimulus can still generate an action potential.
- B. The subnormal period shows reduced but not absent excitability, so a sufficiently strong stimulus can still evoke a response.
- D. In the supernormal period excitability is actually increased, allowing a weaker stimulus to trigger a response.
Nerve & Muscle Physiology
5 questionsAn action potential arrives at the terminal of a motor neuron innervating a skeletal muscle fiber. Depolarization of the terminal membrane opens voltage-gated calcium channels, allowing calcium influx that triggers fusion of synaptic vesicles with the presynaptic membrane and release of neurotransmitter into the synaptic cleft. The released neurotransmitter then binds to receptors on the muscle end-plate, causing which immediate ionic event?
- AOpening of ligand-gated channels permitting sodium influx and potassium efflux, net depolarization
- BOpening of ligand-gated calcium channels causing calcium influx that directly triggers muscle contraction
- CClosure of chloride channels causing membrane depolarization
- DOpening of voltage-gated sodium channels causing a propagated action potential directly at the receptor
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Acetylcholine released from the motor nerve terminal binds to nicotinic receptors on the muscle end-plate, which are ligand-gated ion channels permeable to both sodium and potassium. Because the electrochemical driving force for sodium influx exceeds that for potassium efflux at resting potential, the net effect is depolarization, producing the end-plate potential. If this end-plate potential is large enough, it triggers a propagated action potential in the adjacent muscle membrane via separate voltage-gated sodium channels, not directly at the receptor itself. This end-plate potential is a graded, non-propagated local response, unlike the subsequent all-or-none action potential in the muscle fiber.
- B. The nicotinic receptor is permeable mainly to sodium and potassium, not primarily calcium, at the end-plate.
- C. Chloride channels are not the primary receptor-linked channels at the neuromuscular end-plate.
- D. The nicotinic receptor itself is a ligand-gated, not voltage-gated, channel, and the propagated action potential occurs in adjacent membrane, not at the receptor.
A 32-year-old woman presents with drooping of both eyelids that worsens by evening and difficulty chewing food after prolonged meals. On examination, ptosis increases after sustained upward gaze for two minutes. Repetitive nerve stimulation shows a decremental response. Which of the following best explains the underlying defect in this patient?
- AAutoantibodies against postsynaptic acetylcholine receptors at the neuromuscular junction
- BDemyelination of peripheral motor nerve axons
- CReduced synthesis of acetylcholine in presynaptic vesicles
- DAutoantibodies against presynaptic voltage-gated calcium channels
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Myasthenia gravis is an autoimmune disorder in which antibodies target nicotinic acetylcholine receptors on the postsynaptic membrane of the neuromuscular junction, reducing the number of functional receptors. This impairs neuromuscular transmission, producing fatigable weakness that worsens with repeated activity, classically affecting ocular, bulbar, and limb muscles. Repetitive nerve stimulation shows a decremental muscle response because fewer receptors are available to generate an end-plate potential above threshold with successive stimuli. Edrophonium (acetylcholinesterase inhibitor) transiently improves strength by prolonging acetylcholine action at the junction.
- B. Demyelination describes conditions like Guillain-Barre syndrome, not a neuromuscular junction disorder.
- C. Botulinum toxin blocks acetylcholine release, not autoimmune receptor loss as seen here.
- D. This describes Lambert-Eaton myasthenic syndrome, which shows incremental response on repetitive stimulation and is often paraneoplastic.
During contraction of a skeletal muscle fiber, the myosin cross-bridges pull the thin filaments toward the center of the sarcomere. Which of the following best describes the structural change that occurs in the sarcomere during this process?
- AThe H zone widens while the A band shortens
- BThe A band remains constant in length while the I band and H zone shorten
- CBoth the A band and I band lengthen equally
- DThe A band shortens while the I band remains constant in length
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According to the sliding filament theory, contraction occurs when actin (thin) filaments slide over myosin (thick) filaments without any change in the length of either filament itself. The A band, which corresponds to the length of the myosin filaments, therefore stays constant. As the actin filaments are pulled further into the A band, the I band (region of actin alone) and the H zone (region of myosin alone) both shorten, while the sarcomere as a whole shortens.
- A. The H zone shortens, not widens, as actin filaments slide further into the A band.
- C. Both bands shorten during contraction, they do not lengthen.
- D. The A band length is fixed by myosin filament length and does not shorten during contraction.
When an action potential travels down the T tubule of a skeletal muscle fiber, calcium ions are released from the sarcoplasmic reticulum into the sarcoplasm. Binding of calcium to which protein directly triggers the molecular events leading to cross-bridge formation?
- AMyosin light chain kinase
- BTropomyosin
- CTroponin C
- DCalmodulin
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Calcium released from the sarcoplasmic reticulum binds to troponin C, a subunit of the troponin complex located on the thin filament. This binding causes a conformational change in troponin that shifts tropomyosin away from the myosin-binding sites on actin, exposing them. Myosin heads can then bind actin and undergo the cross-bridge cycle powered by ATP hydrolysis, producing contraction. This is the basis of excitation-contraction coupling in skeletal muscle.
- A. Myosin light chain kinase mediates calcium-calmodulin regulation in smooth muscle, not the primary mechanism in skeletal muscle.
- B. Tropomyosin is moved as a consequence of calcium binding to troponin C; it does not bind calcium directly in skeletal muscle.
- D. Calmodulin is the calcium-sensing protein in smooth muscle contraction, not skeletal muscle excitation-contraction coupling.
A sports physiologist is comparing two types of skeletal muscle fibers. One type has abundant mitochondria, high myoglobin content, and relies predominantly on oxidative phosphorylation, fatiguing slowly during sustained low-intensity activity such as long-distance running. This fiber type is best classified as which of the following?
- AType IIa (fast oxidative-glycolytic) fibers
- BType I (slow oxidative) fibers
- CType IIb (fast glycolytic) fibers
- DIntrafusal fibers
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Type I (slow oxidative, red) fibers contain abundant mitochondria and myoglobin and depend mainly on aerobic metabolism, making them highly resistant to fatigue and suited for sustained activities like marathon running and postural maintenance. Type IIb (fast glycolytic, white) fibers rely on anaerobic glycolysis, contract rapidly, and fatigue quickly, suited for short bursts of intense activity such as sprinting. Type IIa fibers are intermediate, using both oxidative and glycolytic metabolism. The high mitochondrial and myoglobin content described is characteristic of Type I fibers.
- A. Type IIa fibers have intermediate, not predominantly oxidative, metabolism and fatigue faster than Type I fibers.
- C. Type IIb fibers rely on glycolysis, have few mitochondria, and fatigue rapidly, the opposite of what is described.
- D. Intrafusal fibers are specialized fibers within the muscle spindle involved in proprioception, not force-generating extrafusal fibers.
Blood Physiology
5 questionsA 55-year-old man with chronic kidney disease has a hemoglobin of 8.2 g/dL. His serum erythropoietin level is found to be inappropriately low for the degree of anemia. Which of the following best describes the primary site of production and the main stimulus for secretion of this hormone under normal physiological conditions?
- AProduced by peritubular fibroblast-like cells in the kidney, stimulated by tissue hypoxia
- BProduced by the anterior pituitary, stimulated by low hemoglobin concentration directly sensed by pituitary cells
- CProduced by hepatocytes in the liver, stimulated by low serum iron levels
- DProduced by the bone marrow stroma, stimulated by increased red cell destruction
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Erythropoietin is produced mainly by peritubular interstitial fibroblast-like cells in the renal cortex, with a smaller contribution from the liver, particularly in fetal life and in chronic kidney disease. Tissue hypoxia, sensed through hypoxia-inducible factor pathways, is the principal stimulus for erythropoietin secretion. Erythropoietin then acts on erythroid progenitor cells in the bone marrow to stimulate their proliferation and differentiation into mature red blood cells. In chronic kidney disease, destruction of peritubular cells leads to inappropriately low erythropoietin production relative to the degree of anemia, explaining the anemia of chronic kidney disease.
- B. The anterior pituitary does not produce erythropoietin or directly sense hemoglobin levels for this purpose.
- C. The liver contributes only a minor amount of erythropoietin in adults, and iron levels are not the main trigger; hypoxia is.
- D. Bone marrow stroma is the target tissue for erythropoietin action, not its primary production site.
A 24-year-old woman presents with fatigue and pallor. Her laboratory results show hemoglobin 8.5 g/dL, mean corpuscular volume 68 fL, mean corpuscular hemoglobin concentration 26 g/dL, serum ferritin 8 ng/mL, and serum iron with increased total iron-binding capacity. Peripheral blood smear is most likely to show which of the following findings?
- AMicrocytic, hypochromic red cells with increased central pallor and anisopoikilocytosis
- BNormocytic normochromic red cells with target cells and schistocytes
- CMicrocytic red cells with basophilic stippling and ringed sideroblasts
- DMacrocytic red cells with hypersegmented neutrophils
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The low mean corpuscular volume and mean corpuscular hemoglobin concentration, combined with low ferritin and high total iron-binding capacity, confirm iron deficiency anemia. On peripheral smear, iron deficiency anemia classically shows microcytic, hypochromic red cells with an increased area of central pallor due to reduced hemoglobin content, along with anisocytosis (variation in size) and poikilocytosis (variation in shape), including pencil-shaped cells. Low ferritin reflects depleted iron stores, and raised total iron-binding capacity reflects increased transferrin synthesis in response to iron deficiency.
- B. Normocytic cells with target cells and schistocytes suggest hemolytic processes or liver disease, inconsistent with the low MCV here.
- C. Basophilic stippling and ringed sideroblasts suggest sideroblastic anemia or lead poisoning, not simple iron deficiency.
- D. Macrocytic cells with hypersegmented neutrophils are seen in megaloblastic anemia from vitamin B12 or folate deficiency, not iron deficiency.
A healthy 24-year-old man is tested at sea level. At a partial pressure of oxygen of 40 mm Hg, his hemoglobin is 75% saturated with oxygen, matching the standard oxygen-hemoglobin dissociation curve. Which statement best explains the shape of this curve at this point?
- AOxygen binding to hemoglobin follows simple first-order kinetics similar to enzyme-substrate binding
- BHemoglobin behaves as four independent myoglobin-like units with no interaction between subunits
- CBinding of the first oxygen molecule increases the affinity of hemoglobin for subsequent oxygen molecules
- DThe steep part of the curve reflects the point of maximum oxygen affinity of hemoglobin
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The oxygen-hemoglobin dissociation curve is sigmoid because hemoglobin shows positive cooperativity: binding of oxygen to one of the four heme sites induces a conformational change (T to R state) that increases the affinity of the remaining subunits for oxygen. This cooperative behavior produces the steep middle portion of the curve, around a PO2 of 20-60 mm Hg, which allows large changes in oxygen loading and unloading over a small range of PO2. Myoglobin, in contrast, has a hyperbolic curve because it is a single-subunit protein without cooperativity. This mechanism is essential for efficient oxygen uptake in the lungs and release in the tissues.
- A. Hemoglobin's sigmoid curve specifically reflects cooperative, not simple first-order, binding kinetics.
- B. This describes myoglobin, which lacks cooperativity and shows a hyperbolic curve, not hemoglobin.
- D. The steep part reflects the region of changing affinity due to cooperativity, not maximum affinity, which occurs at high PO2 on the flat upper part of the curve.
A 30-year-old man ascends to a high-altitude base camp. After two weeks of acclimatization, his red cell 2,3-bisphosphoglycerate (2,3-BPG) level rises. What is the expected effect on the oxygen-hemoglobin dissociation curve and its physiological consequence?
- ANo shift, since 2,3-BPG only affects fetal hemoglobin oxygen binding
- BRightward shift, increasing hemoglobin's oxygen affinity and impairing oxygen delivery to tissues
- CLeftward shift, increasing hemoglobin's oxygen affinity and facilitating oxygen uptake in lungs
- DRightward shift, reducing hemoglobin's oxygen affinity and facilitating oxygen unloading at tissues
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2,3-BPG is an organic phosphate that binds preferentially to deoxyhemoglobin, stabilizing the low-affinity T state. Increased 2,3-BPG, as occurs during chronic hypoxia or high-altitude acclimatization, shifts the oxygen-hemoglobin dissociation curve to the right, lowering hemoglobin's affinity for oxygen. This facilitates oxygen unloading at the tissue level despite a lower arterial PO2, an adaptive mechanism to maintain tissue oxygenation. Other factors causing a rightward shift include increased temperature, increased PCO2, and decreased pH (Bohr effect).
- A. 2,3-BPG binds adult deoxyhemoglobin far more avidly than fetal hemoglobin, and it does shift the curve.
- B. A rightward shift decreases, not increases, hemoglobin's oxygen affinity.
- C. A leftward shift would increase hemoglobin's affinity for oxygen and impair, not facilitate, oxygen unloading at tissues, which is the opposite adaptive response needed at altitude.
A medical student is studying the coagulation cascade using the classic classification based on the site of initiation. Which clotting factor is classically activated by tissue factor exposed from damaged subendothelial cells, marking the start of one of the two pathways?
- AFactor XI
- BFactor IX
- CFactor VII
- DFactor XII
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The extrinsic pathway is triggered when tissue factor (factor III), released from damaged vessel wall or subendothelial tissue, forms a complex with circulating factor VII, activating it to factor VIIa. This tissue factor-factor VIIa complex then activates factor X, linking to the common pathway. The intrinsic pathway, in contrast, begins within the blood vessel itself when factor XII is activated by contact with exposed collagen or a negatively charged surface, triggering a cascade through factors XI, IX, and VIII. The extrinsic pathway is faster and is the main pathway tested by prothrombin time (PT).
- A. Factor XI belongs to the intrinsic pathway, activated by factor XIIa, not by tissue factor.
- B. Factor IX is an intrinsic pathway factor, activated later in that cascade by factor XIa, not by tissue factor directly.
- D. Factor XII is activated by contact with exposed subendothelial collagen as the first step of the intrinsic pathway, not by tissue factor.
Cardiovascular Physiology
5 questionsA physiology student records action potentials from two different cardiac cell types. Cell A shows a slow spontaneous depolarization to threshold driven mainly by a gradually increasing inward current carried through funny channels, followed by a slow upstroke mediated by calcium entry. Cell B shows a stable resting potential of about -90 mV with a rapid upstroke due to fast sodium channel opening. Which ionic current is primarily responsible for the slow spontaneous depolarization seen in cell A?
- AINa (fast sodium current)
- BIf (funny current, HCN channels)
- CIK1 (inward rectifier potassium current)
- DICa-L (L-type calcium current)
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SA nodal pacemaker cells lack a true stable resting potential; after maximum diastolic potential, the funny current (If), carried by HCN channels permeable to Na+ and K+, activates and causes slow spontaneous depolarization (phase 4) toward threshold. As depolarization proceeds, T-type and then L-type calcium channels open to produce the slow upstroke (phase 0) of the pacemaker potential. This contrasts with ventricular myocytes, which have a stable resting potential maintained by IK1 and a rapid upstroke due to fast Na+ channels.
- A. Fast sodium current produces the rapid upstroke of ventricular (non-pacemaker) action potentials, not the slow pacemaker depolarization.
- C. IK1 stabilizes the resting membrane potential in ventricular cells and is largely absent in SA nodal cells.
- D. L-type calcium current contributes to the upstroke (phase 0) of the pacemaker potential, but the initial slow depolarization is driven by the funny current.
A 24-year-old healthy volunteer undergoes a 12-lead ECG as part of a physiology demonstration. The examiner points to the interval between the end of the QRS complex and the beginning of the T wave and asks which phase of the cardiac cycle this corresponds to.
- AIsovolumetric ventricular relaxation
- BPlateau phase of ventricular action potential during ventricular systole
- CRapid ventricular filling
- DAtrial depolarization
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The ST segment lies between the end of the QRS complex (ventricular depolarization) and the start of the T wave (ventricular repolarization). Electrically, it corresponds to the plateau phase (phase 2) of the ventricular action potential, during which calcium influx balances potassium efflux and the entire ventricle remains depolarized. Mechanically, this period coincides with the early part of ventricular systole after ejection has begun. A normal ST segment is isoelectric because there is no net potential difference across the ventricular wall during this plateau.
- A. Isovolumetric relaxation occurs after the T wave, between aortic valve closure and mitral valve opening.
- C. Rapid ventricular filling occurs after the T wave, following isovolumetric relaxation and the opening of the AV valves.
- D. Atrial depolarization produces the P wave, which precedes the QRS complex, not the ST segment.
In an isolated heart preparation, increasing the volume of venous return progressively stretches the ventricular myocardium before contraction. Over a physiological range, this increased stretch results in a greater force of ventricular contraction without any change in heart rate or contractility. Which mechanism best explains this intrinsic response?
- AActivation of the baroreceptor reflex increasing contractility
- BIncreased length-dependent sensitivity of myofilaments to calcium with greater overlap of actin-myosin
- CIncreased heart rate leading to greater calcium entry per unit time
- DIncreased sympathetic stimulation of the ventricle
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The Frank-Starling law states that, within physiological limits, the force of ventricular contraction increases with increasing end-diastolic volume (preload). The underlying mechanism is length-dependent activation: stretching the sarcomere increases the sensitivity of troponin C for calcium and optimizes the overlap between actin and myosin filaments, producing greater cross-bridge formation and tension for the same calcium influx. This is an intrinsic property of cardiac muscle and does not require changes in heart rate or autonomic input.
- A. The baroreceptor reflex regulates blood pressure via autonomic changes in heart rate and contractility, not the length-tension relationship described here.
- C. Heart rate is stated to be unchanged in this scenario, and the Frank-Starling response is independent of rate.
- D. The Frank-Starling mechanism is intrinsic to the myocardium and does not depend on sympathetic stimulation, which affects contractility (inotropy) separately.
A 45-year-old man undergoes cardiac catheterization to measure cardiac output directly. Oxygen consumption is measured at 250 mL/min. Arterial blood oxygen content is 20 mL/dL, and mixed venous blood sampled from the pulmonary artery has an oxygen content of 15 mL/dL. Which method is being used to calculate his cardiac output from these values?
- AEchocardiographic Doppler method
- BThermodilution technique
- CFick principle
- DDye dilution technique
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The Fick principle calculates cardiac output as oxygen consumption divided by the arteriovenous oxygen content difference: CO = VO2 / (arterial O2 content - mixed venous O2 content). Here, CO = 250 / (20-15) x 100 = 5000 mL/min = 5 L/min. This method requires sampling of mixed venous blood from the pulmonary artery and measurement of whole-body oxygen consumption, and it remains a reference standard for measuring cardiac output.
- A. Doppler echocardiography estimates cardiac output from blood flow velocity and vessel cross-sectional area, not oxygen consumption.
- B. Thermodilution uses temperature change of injected cold saline detected downstream, not oxygen content measurements.
- D. Dye dilution uses an indicator dye concentration curve over time, not oxygen content difference.
A 30-year-old healthy man stands up suddenly from a supine position. His carotid sinus baroreceptors sense the transient fall in arterial pressure and send decreased afferent signals via the glossopharyngeal nerve to the nucleus tractus solitarius. Which immediate autonomic response restores his blood pressure toward normal?
- AIncreased atrial natriuretic peptide release from the atria
- BDecreased renin release from the juxtaglomerular cells
- CIncreased vagal tone and decreased sympathetic outflow, decreasing heart rate
- DDecreased vagal tone and increased sympathetic outflow, increasing heart rate and vascular resistance
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A fall in arterial pressure reduces baroreceptor firing, which decreases inhibitory input to the vasomotor center. This leads to decreased parasympathetic (vagal) tone and increased sympathetic outflow to the heart and blood vessels, producing tachycardia, increased myocardial contractility, and vasoconstriction, all of which rapidly raise blood pressure back toward normal. This reflex operates within seconds and is the first line of defense against orthostatic hypotension.
- A. ANP release increases with atrial stretch from volume overload, which is unrelated to the rapid baroreceptor response to postural hypotension.
- B. A fall in blood pressure stimulates, not decreases, renin release as part of a slower compensatory mechanism via the renin-angiotensin-aldosterone system.
- C. Increased vagal tone and decreased sympathetic outflow would further lower blood pressure, the opposite of the required compensatory response.
Respiratory Physiology
4 questionsA 30-year-old healthy man undergoes spirometry. His tidal volume is 500 mL, inspiratory reserve volume is 2500 mL, and expiratory reserve volume is 1000 mL. His residual volume, measured separately by helium dilution, is 1200 mL. What is his functional residual capacity?
- A2200 mL
- B3700 mL
- C1200 mL
- D1700 mL
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Functional residual capacity (FRC) is the volume of air remaining in the lungs at the end of a normal passive expiration, and it equals the sum of expiratory reserve volume (ERV) and residual volume (RV). Here, ERV is 1000 mL and RV is 1200 mL, giving FRC = 1000 + 1200 = 2200 mL. FRC cannot be measured by spirometry alone because it includes residual volume, which requires techniques such as helium dilution or body plethysmography. This distinguishes it from vital capacity, which spirometry can measure directly.
- B. This is the vital capacity (tidal volume plus inspiratory reserve volume plus expiratory reserve volume), not functional residual capacity.
- C. This is the residual volume alone, not functional residual capacity.
- D. This equals tidal volume plus expiratory reserve volume, which is not a standard named capacity.
A 55-year-old man with a 30-pack-year smoking history undergoes spirometry for progressive breathlessness. His FEV1 is 1.4 L (55% of predicted), FVC is 2.8 L (78% of predicted), and FEV1/FVC ratio is 0.50. Which of the following best characterizes this spirometric pattern?
- ANormal pattern with age-related decline
- BObstructive pattern with reduced FEV1/FVC ratio
- CRestrictive pattern with reduced total lung capacity
- DMixed pattern with proportionate reduction in both values
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An obstructive ventilatory defect is defined by a disproportionately reduced FEV1 relative to FVC, giving a reduced FEV1/FVC ratio, typically below 0.70, as seen in chronic obstructive pulmonary disease and asthma. In this patient, the ratio of 0.50 confirms airflow obstruction, consistent with his smoking history suggesting COPD. In contrast, a restrictive pattern shows reduced FVC with a preserved or increased FEV1/FVC ratio. Total lung capacity is not given here and is typically increased, not reduced, in obstructive disease due to air trapping.
- A. An FEV1/FVC ratio of 0.50 is markedly abnormal and not consistent with normal aging.
- C. Restrictive disease shows reduced FVC with a preserved or elevated FEV1/FVC ratio, and total lung capacity data is not given here to support this.
- D. A mixed pattern would show both reduced FVC and reduced FEV1/FVC ratio with features of each, which requires lung volume confirmation; the ratio here is clearly obstructive.
A trekker ascends rapidly to an altitude of 4500 meters. After 48 hours of acclimatization, his arterial oxygen saturation improves compared to the first few hours at altitude, partly due to a rightward shift of the oxygen-hemoglobin dissociation curve. Which of the following mechanisms is primarily responsible for this adaptive rightward shift?
- ARespiratory acidosis from hypoventilation
- BIncreased carboxyhemoglobin formation
- CDecreased body temperature at high altitude
- DIncreased 2,3-diphosphoglycerate in red blood cells
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At high altitude, hypoxia stimulates increased production of 2,3-diphosphoglycerate (2,3-DPG) in red blood cells, which binds to deoxyhemoglobin and reduces its affinity for oxygen. This shifts the oxygen-hemoglobin dissociation curve to the right, facilitating unloading of oxygen to the tissues despite a lower arterial oxygen tension, an important acclimatization mechanism over 24-48 hours. Although hyperventilation at altitude causes respiratory alkalosis, which would shift the curve leftward, the compensatory rise in 2,3-DPG dominates and promotes peripheral oxygen delivery. This is a key adaptive feature distinct from the acute hypoxic response.
- A. Altitude hypoxia causes hyperventilation with respiratory alkalosis (not acidosis), which would shift the curve leftward.
- B. Carboxyhemoglobin formation is not increased by altitude exposure and is unrelated to this adaptive mechanism.
- C. Decreased temperature shifts the curve leftward, increasing hemoglobin oxygen affinity, which is the opposite of the adaptive change described.
A physiology student is studying the control of ventilation. A rise in arterial PCO2 is noted to cause a greater increase in ventilation than an equivalent fall in arterial PO2 under normal conditions. Which of the following best explains the primary site and mechanism responsible for the dominant ventilatory drive from carbon dioxide?
- APeripheral chemoreceptors in aortic bodies responding to blood pH only
- BPeripheral chemoreceptors in carotid bodies directly sensing PCO2
- CCentral chemoreceptors in the medulla responding to hydrogen ions generated from CO2 crossing the blood-brain barrier
- DCentral chemoreceptors directly sensing arterial PO2 changes
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Central chemoreceptors located near the ventral surface of the medulla are the dominant drivers of the ventilatory response to CO2. Carbon dioxide diffuses freely across the blood-brain barrier into the cerebrospinal fluid, where it combines with water to form carbonic acid, which dissociates into hydrogen ions and bicarbonate; these hydrogen ions directly stimulate the central chemoreceptors to increase ventilation. In contrast, peripheral chemoreceptors in the carotid bodies are the primary sensors for hypoxia (low PO2) and contribute only a smaller fraction of the CO2-driven response. This explains why the ventilatory response to rising CO2 is quantitatively greater than the response to an equivalent fall in PO2.
- A. Aortic bodies have little role in respiratory chemoreception in humans, and peripheral chemoreceptors respond to PCO2, PO2, and pH, not pH alone.
- B. Peripheral chemoreceptors contribute only a minor part of the CO2 response; CO2 does not directly stimulate them as its main action.
- D. Central chemoreceptors do not directly sense PO2; hypoxia is primarily detected by peripheral chemoreceptors.
Renal Physiology
2 questionsA 55-year-old man with chronic diarrhea for 10 days presents with weakness. Arterial blood gas shows pH 7.30, PaCO2 28 mm Hg, HCO3- 14 mEq/L. What is the acid-base disorder?
- AMetabolic alkalosis with respiratory compensation
- BMixed metabolic and respiratory acidosis
- CRespiratory acidosis with renal compensation
- DMetabolic acidosis with appropriate respiratory compensation
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The low pH confirms acidosis, and the low HCO3- identifies it as metabolic in origin, consistent with bicarbonate loss from diarrhea. Using Winter's formula, expected PaCO2 = 1.5 x HCO3- + 8 ± 2 = 1.5(14) + 8 = 29 ± 2 mm Hg, which matches the measured PaCO2 of 28 mm Hg. This confirms appropriate respiratory (hyperventilation) compensation rather than a second primary disorder. Compensation never fully normalizes pH, consistent with the persistently low pH here.
- A. Metabolic alkalosis would present with an elevated pH and elevated HCO3-, not low values of both.
- B. The PaCO2 falls within the calculated expected compensatory range, so a second primary respiratory disorder is not present.
- C. Respiratory acidosis would show a primary elevation in PaCO2, not a reduction.
During bladder filling, stretch receptors in the bladder wall send afferent signals to the sacral spinal cord, initiating a reflex that is normally suppressed by descending inhibition until voiding is appropriate. Which nerve carries the parasympathetic efferent output responsible for detrusor muscle contraction during voiding?
- AGenitofemoral nerve (L1-L2)
- BPelvic nerve (S2-S4)
- CPudendal nerve (S2-S4)
- DHypogastric nerve (T10-L2)
Show answer
The pelvic nerve carries parasympathetic preganglionic fibers from the S2-S4 spinal segments to the bladder wall, where they synapse on ganglia that release acetylcholine, causing detrusor muscle contraction and bladder emptying. The pudendal nerve supplies somatic motor fibers to the external urethral sphincter, allowing voluntary control over voiding. The hypogastric nerve provides sympathetic innervation that promotes urine storage by relaxing the detrusor and contracting the internal sphincter. Voluntary relaxation of the pudendal-innervated external sphincter together with pelvic nerve-mediated detrusor contraction allows coordinated voiding.
- A. The genitofemoral nerve has no role in bladder innervation.
- C. The pudendal nerve is somatic and controls the external urethral sphincter, not detrusor contraction.
- D. The hypogastric nerve is sympathetic and promotes bladder filling by inhibiting detrusor contraction.
Gastrointestinal Physiology
4 questionsA researcher studies parietal cell function in isolated gastric glands. Addition of a substance directly stimulates histamine release from enterochromaffin-like cells, which then acts on parietal cells to increase acid secretion. Which substance was most likely added?
- ACholecystokinin
- BGastrin
- CGastric inhibitory peptide
- DSecretin
Show answer
Gastrin, released from G cells in the gastric antrum in response to peptides and vagal stimulation, acts on CCK-B receptors on enterochromaffin-like (ECL) cells to trigger histamine release. Histamine then binds H2 receptors on parietal cells, activating adenylyl cyclase and increasing cAMP, which stimulates the H+/K+-ATPase to secrete acid. Gastrin also has a direct but weaker effect on parietal cells; its main amplification of acid secretion is through this histamine-mediated paracrine pathway. This explains why H2 blockers effectively reduce acid secretion even when gastrin levels remain elevated.
- A. Cholecystokinin primarily stimulates pancreatic enzyme secretion and gallbladder contraction, not ECL cell histamine release.
- C. Gastric inhibitory peptide (GIP) inhibits gastric acid secretion and stimulates insulin release.
- D. Secretin inhibits gastric acid secretion and stimulates pancreatic bicarbonate release, it does not stimulate ECL cells.
A 60-year-old woman presents with fatigue, glossitis, and paresthesias. Investigations show megaloblastic anemia and low serum vitamin B12. Anti-parietal cell antibodies are positive. At which site is vitamin B12 absorbed, given the deficiency of the carrier protein produced by parietal cells?
- AStomach
- BJejunum
- CDuodenum
- DTerminal ileum
Show answer
Vitamin B12 absorption occurs in the terminal ileum, where the vitamin B12-intrinsic factor complex binds to cubam receptors on enterocytes and is taken up by endocytosis. Intrinsic factor is secreted by gastric parietal cells, and in pernicious anemia, autoimmune destruction of parietal cells leads to intrinsic factor deficiency, preventing B12 from being protected from gastric and pancreatic proteolysis and from binding ileal receptors. This results in B12 malabsorption despite a structurally normal terminal ileum. Without intrinsic factor, free B12 cannot be efficiently absorbed, leading to megaloblastic anemia and neurological symptoms from demyelination.
- A. The stomach is where intrinsic factor is secreted and where B12 is released from food, not where absorption occurs.
- B. The jejunum absorbs most other nutrients but not vitamin B12.
- C. The duodenum is the site of intrinsic factor-B12 complex formation but not the primary absorption site.
Pancreatic acinar cells secrete proteolytic enzymes as inactive zymogens into the duodenum to prevent autodigestion of the pancreas. Which brush border enzyme initiates the activation cascade by converting trypsinogen into its active form?
- AChymotrypsin
- BCarboxypeptidase
- CEnteropeptidase inhibitor
- DEnterokinase
Show answer
Enterokinase (enteropeptidase), located on the duodenal brush border, cleaves trypsinogen to form active trypsin. Trypsin then autocatalytically activates more trypsinogen and also activates other pancreatic zymogens including chymotrypsinogen, procarboxypeptidase, and proelastase. This cascade ensures that pancreatic enzymes remain inactive within the pancreas and pancreatic duct, becoming active only within the intestinal lumen, protecting pancreatic tissue from autodigestion. A deficiency or dysfunction of enterokinase impairs protein digestion despite normal pancreatic enzyme secretion.
- A. Chymotrypsin is itself activated by trypsin and does not initiate the activation cascade.
- B. Carboxypeptidase is activated downstream by trypsin and plays no role in initiating trypsinogen activation.
- C. There is no physiological entity called an enteropeptidase inhibitor involved in this cascade.
A patient with terminal ileal resection develops steatorrhea and fat-soluble vitamin deficiency. Which physiological process explains why bile salt loss from ileal resection impairs fat digestion despite normal hepatic bile salt synthesis?
- ABile salt malabsorption increases cholecystokinin release and gallbladder contraction
- BInterruption of enterohepatic circulation reduces the bile salt pool available for micelle formation
- CLoss of ileal mucosa prevents emulsification of dietary triglycerides
- DReduced bile salt synthesis directly impairs pancreatic lipase secretion
Show answer
Bile salts are normally reabsorbed in the terminal ileum via sodium-dependent active transport and recycled through the enterohepatic circulation, allowing the small bile salt pool to be reused many times per meal. Terminal ileal resection interrupts this recycling, causing excessive fecal bile salt loss that exceeds the liver's capacity to synthesize new bile salts to compensate. The resulting depletion of the bile salt pool impairs micelle formation, which is required to solubilize monoglycerides, fatty acids, and fat-soluble vitamins for absorption. This leads to steatorrhea and deficiencies of vitamins A, D, E, and K.
- A. Bile salt malabsorption does not directly stimulate CCK release; CCK release is triggered by fatty acids and amino acids in the duodenum.
- C. Emulsification occurs in the duodenum via bile salts and mechanical mixing, not via ileal mucosal function.
- D. Bile salts do not regulate pancreatic lipase secretion, which is primarily controlled by CCK and secretin.
Endocrine Physiology
4 questionsA researcher studies a hormone axis in which the pituitary hormone stimulates a peripheral endocrine gland to secrete its product, and rising levels of that peripheral hormone act back on the hypothalamus and anterior pituitary to reduce further hormone release. Which mechanism best describes this regulatory loop?
- ANegative feedback inhibition by the peripheral hormone on the hypothalamic-pituitary axis
- BAutocrine feedback of the releasing hormone on the same hypothalamic neuron
- CShort-loop feedback of the anterior pituitary hormone on the hypothalamus only
- DPositive feedback stimulation by the peripheral hormone on the hypothalamic-pituitary axis
Show answer
In most hypothalamic-pituitary-target gland axes (e.g., HPA, HPT, HPG axes), the peripheral hormone circulates back to suppress hypothalamic releasing hormone and pituitary trophic hormone secretion, forming a long-loop negative feedback system. This keeps circulating hormone levels within a narrow physiological range. Positive feedback is the exception, seen physiologically only with the LH surge induced by rising estrogen at mid-cycle. Short-loop feedback refers to a pituitary hormone feeding back on the hypothalamus, which is a separate, less prominent feedback path.
- B. Autocrine feedback on the same neuron is not the mechanism operating in classic endocrine axes.
- C. Short-loop feedback describes pituitary hormone acting on the hypothalamus, not the peripheral hormone acting on both hypothalamus and pituitary as described.
- D. Positive feedback is the exception, limited to the pre-ovulatory estrogen-induced LH surge, not the general axis pattern described.
A 35-year-old woman has fatigue and weight gain. Her serum free T4 is 0.4 ng/dL (normal 0.8-1.8) and serum TSH is 45 mIU/L (normal 0.4-4.0). Which site of dysfunction best explains these findings?
- APeripheral resistance to thyroid hormone action
- BPrimary failure of the thyroid gland itself
- CFailure of the anterior pituitary to secrete TSH
- DFailure of the hypothalamus to secrete TRH
Show answer
A low free T4 with an appropriately elevated TSH indicates that the thyroid gland cannot respond to pituitary stimulation, so the pituitary increases TSH output through loss of negative feedback inhibition. This pattern is classic for primary hypothyroidism, commonly due to autoimmune thyroiditis (Hashimoto's) in India. Pituitary or hypothalamic failure (secondary or tertiary hypothyroidism) would show a low or inappropriately normal TSH alongside low T4. Peripheral resistance to thyroid hormone typically shows elevated T4 with normal or high TSH, not low T4.
- A. Thyroid hormone resistance classically presents with high T4 and normal or elevated TSH, not low T4.
- C. Pituitary failure would cause low or inappropriately normal TSH, not a markedly elevated TSH of 45 mIU/L.
- D. Hypothalamic TRH deficiency also produces low or normal TSH, inconsistent with the high TSH seen here.
After a carbohydrate-rich meal, insulin promotes glucose entry into skeletal muscle and adipose tissue cells. Which mechanism underlies this action?
- AIncreased expression of sodium-glucose cotransporters on the apical membrane
- BDirect phosphorylation of glucose within the cell membrane
- CConversion of intracellular glycogen to free glucose for diffusion
- DTranslocation of GLUT-4 transporters from intracellular vesicles to the cell membrane
Show answer
Insulin binds its receptor tyrosine kinase, triggering a signaling cascade that causes GLUT-4 transporter vesicles stored in the cytoplasm to fuse with the plasma membrane of skeletal muscle and adipose cells, increasing glucose uptake by facilitated diffusion. This is the principal mechanism by which insulin lowers blood glucose after meals. Sodium-glucose cotransporters (SGLT) mediate active glucose absorption in the intestine and kidney, not insulin-dependent muscle or fat uptake. Glucose cannot be phosphorylated at the membrane, and glycogen breakdown would raise, not clear, blood glucose.
- A. SGLT transporters mediate sodium-coupled active transport in intestinal and renal epithelium, not insulin-mediated muscle/fat glucose uptake.
- B. Glucose phosphorylation (by hexokinase) occurs inside the cytoplasm after entry, not at the membrane, and is not the entry mechanism.
- C. Glycogenolysis releases glucose from stores and would not explain glucose entering cells from the blood.
A blood sample drawn from a healthy adult at 8:00 AM shows a higher serum cortisol level than a sample drawn from the same person at 11:00 PM. During an episode of acute physical stress, cortisol further increases and promotes survival primarily through which action?
- AStimulating hepatic gluconeogenesis to maintain blood glucose supply
- BDirectly increasing cardiac contractility by acting on beta-1 receptors
- CSuppressing glucagon secretion from pancreatic alpha cells
- DPromoting renal retention of potassium to maintain membrane excitability
Show answer
Cortisol secretion follows a diurnal rhythm driven by ACTH pulses, peaking in the early morning and reaching its lowest point around midnight. During stress, cortisol is a key component of the response because it stimulates hepatic gluconeogenesis and mobilizes amino acids and fatty acids as substrates, ensuring a steady glucose supply to the brain and tissues under threat. Cortisol does not act directly on cardiac beta-1 receptors; that is a catecholamine effect. Cortisol actually promotes renal potassium excretion (mild mineralocorticoid activity) rather than retention, and it does not suppress glucagon secretion.
- B. Direct beta-1 adrenergic stimulation of the heart is a catecholamine (epinephrine) action, not a direct cortisol effect.
- C. Cortisol does not suppress glucagon; both hormones act together to raise blood glucose during stress.
- D. Cortisol has mild mineralocorticoid activity that promotes potassium excretion, not retention.
Nervous System & Special Senses
4 questionsA doctor taps the patellar tendon with a reflex hammer and observes contraction of the quadriceps muscle. Which sequence of events best describes the mechanism of this reflex?
- AJoint capsule receptors activate gamma motor neurons directly, causing extrafusal fiber contraction
- BGolgi tendon organ activation sends inhibitory signals to the same muscle, producing reflex relaxation
- CMuscle spindle stretch activates Ia afferent fibers, which synapse on alpha motor neurons in the spinal cord, causing reflex contraction of the same muscle
- DNociceptors in the tendon activate a polysynaptic withdrawal reflex causing muscle contraction
Show answer
The knee jerk is a monosynaptic stretch reflex: tapping the patellar tendon stretches the quadriceps muscle, stimulating muscle spindles within the muscle. This activates Ia afferent nerve fibers that travel to the spinal cord and synapse directly onto alpha motor neurons supplying the same muscle, producing a rapid reflex contraction. The Golgi tendon organ reflex is an inverse stretch reflex that causes relaxation, not the mechanism of the knee jerk. Nociceptor-mediated withdrawal reflexes are polysynaptic and involve pain fibers, not muscle spindle stretch, and gamma motor neurons innervate intrafusal fibers to set spindle sensitivity, not extrafusal fibers that cause contraction.
- A. Gamma motor neurons innervate intrafusal spindle fibers to adjust spindle sensitivity, not extrafusal fibers that generate the contractile force.
- B. Golgi tendon organ activation produces an inhibitory, relaxing effect on the same muscle, the opposite of the knee jerk response.
- D. Withdrawal reflexes are polysynaptic and pain-mediated, unlike the monosynaptic, proprioceptive knee jerk.
A 50-year-old man develops sudden weakness of the right arm and leg after a stroke. On examination, there is increased muscle tone, exaggerated deep tendon reflexes, and an extensor plantar response on the right side, with no muscle wasting or fasciculations. Which type of lesion best explains these findings?
- ANeuromuscular junction disorder affecting acetylcholine receptors
- BLower motor neuron lesion affecting the peripheral nerve
- CUpper motor neuron lesion affecting the corticospinal tract
- DLower motor neuron lesion affecting the anterior horn cells
Show answer
Increased tone (spasticity), exaggerated deep tendon reflexes, and an extensor plantar response (Babinski sign) without wasting or fasciculations are hallmark features of an upper motor neuron lesion, typically from damage to the corticospinal tract as seen after a stroke. Loss of descending inhibitory control leads to hyperreflexia and spasticity below the lesion. Lower motor neuron lesions, whether at the anterior horn cell or peripheral nerve level, instead cause hypotonia, diminished or absent reflexes, muscle wasting, and fasciculations. Neuromuscular junction disorders cause fatigable weakness without reflex changes or an extensor plantar response.
- A. Neuromuscular junction disorders cause fatigable weakness without changes in deep tendon reflexes or a Babinski sign.
- B. Peripheral nerve lesions also cause lower motor neuron signs with reduced tone and reflexes, not hyperreflexia and an extensor plantar response.
- D. Anterior horn cell lesions produce lower motor neuron signs: hypotonia, wasting, fasciculations, and reduced reflexes, not spasticity with Babinski sign.
A 50-year-old man presents with inability to see objects approaching from either side while walking, though he can clearly see objects directly in front of him. On perimetry, the temporal half of the visual field is lost in both eyes, while the nasal fields are preserved. Which site of lesion best explains this finding?
- ALeft optic nerve
- BOccipital cortex (left side)
- COptic chiasma
- DRight optic tract
Show answer
Fibers from the nasal retina of each eye (which perceive the temporal visual field) decussate at the optic chiasma. A midline lesion compressing the chiasma, classically a pituitary adenoma, damages these crossing fibers from both eyes, producing bitemporal hemianopia. The nasal visual fields, carried by uncrossed temporal retinal fibers, are spared. This pattern is pathognomonic for chiasmal compression.
- A. A lesion of one optic nerve causes monocular blindness, not bilateral temporal field loss.
- B. Occipital cortex lesions cause homonymous hemianopia with macular sparing, affecting one side of the visual field in both eyes.
- D. A lesion of one optic tract causes a homonymous hemianopia, not bitemporal loss.
During a sleep study, an EEG recording shows low-amplitude, high-frequency desynchronized waves resembling the awake state, associated with rapid conjugate eye movements and loss of skeletal muscle tone. Which stage of sleep does this recording represent?
- ANREM stage 2
- BNREM stage 3 (slow wave sleep)
- CREM sleep
- DNREM stage 1
Show answer
REM sleep is characterized by an EEG pattern similar to the awake, alert state, with low-voltage, high-frequency desynchronized activity, despite the person being deeply asleep. It is accompanied by rapid eye movements, vivid dreaming, and profound atonia of postural muscles due to active inhibition of spinal motor neurons. This paradoxical combination of cortical activation and muscular paralysis gives REM sleep its alternate name, paradoxical sleep. NREM slow wave sleep, in contrast, shows high-amplitude, low-frequency delta waves.
- A. NREM stage 2 shows sleep spindles and K-complexes on a background of theta activity, without muscle atonia or rapid eye movements.
- B. NREM stage 3 shows high-amplitude, low-frequency delta waves, the opposite of the described pattern.
- D. NREM stage 1 shows low-voltage theta activity but lacks rapid eye movements and muscle atonia.
Reproductive Physiology
4 questionsA 28-year-old woman with a regular 28-day menstrual cycle is being monitored for ovulation timing using daily serum hormone levels. A sharp rise in one hormone is detected on day 14, followed by ovulation approximately 36 hours later. Which hormonal change triggers this ovulation?
- ASustained rise in estrogen alone
- BProgressive rise in progesterone
- CFollicle-stimulating hormone surge
- DLuteinizing hormone surge
Show answer
Ovulation is triggered by a surge in luteinizing hormone (LH), which occurs approximately 24-36 hours before the release of the ovum. This surge is itself induced by the sustained high estrogen level from the dominant follicle, which switches from negative to positive feedback on the hypothalamic-pituitary axis at the mid-cycle. The LH surge causes final maturation of the oocyte, rupture of the follicular wall, and luteinization of the granulosa cells to form the corpus luteum. Measuring urinary LH surge is the basis of home ovulation prediction kits.
- A. Rising estrogen is the stimulus that induces the LH surge, but it is the LH surge itself that directly triggers ovulation.
- B. Progesterone rises after ovulation due to corpus luteum formation; it does not trigger ovulation.
- C. FSH also shows a smaller mid-cycle surge, but it is the LH surge that is the direct trigger for ovulation.
A 24-year-old man undergoes evaluation for infertility. Testicular biopsy shows normal seminiferous tubules with active spermatogenesis. Sertoli cells in these tubules respond to a pituitary hormone that stimulates production of androgen-binding protein, which maintains high local testosterone levels necessary for sperm maturation. Which hormone acts primarily on Sertoli cells in this manner?
- AProlactin
- BGrowth hormone
- CLuteinizing hormone
- DFollicle-stimulating hormone
Show answer
FSH acts on Sertoli cells within the seminiferous tubules, stimulating secretion of androgen-binding protein, which concentrates testosterone locally to support spermatogenesis. FSH also promotes the maturation and proliferation of Sertoli cells and induces the conversion of spermatids to mature sperm. LH, by contrast, acts on Leydig cells located in the interstitium to stimulate testosterone synthesis. Both FSH and LH secretion are controlled by hypothalamic GnRH pulses.
- A. Prolactin excess actually suppresses GnRH and impairs spermatogenesis; it is not the physiological stimulus for Sertoli cell function.
- B. Growth hormone has a permissive role in testicular growth but is not the primary regulator of Sertoli cell androgen-binding protein secretion.
- C. LH acts on Leydig cells to stimulate testosterone production, not directly on Sertoli cells for androgen-binding protein secretion.
A 26-year-old woman misses her menstrual period and suspects pregnancy. A urine sample is tested using a rapid immunoassay kit that becomes positive within days of implantation. Detection of which hormone forms the basis of this test?
- AHuman placental lactogen
- BProgesterone
- CHuman chorionic gonadotropin
- DEstrogen
Show answer
Human chorionic gonadotropin (hCG) is secreted by the syncytiotrophoblast of the developing placenta almost immediately after implantation and is detectable in maternal urine and blood within about a week of conception. hCG maintains the corpus luteum, preventing its regression and ensuring continued progesterone secretion to sustain the early pregnancy until the placenta takes over steroidogenesis. Its rapid rise and early appearance in urine make it the ideal marker for immunological pregnancy tests, which use antibodies against its beta subunit for specificity. Levels of hCG roughly double every 48-72 hours in early normal pregnancy.
- A. Human placental lactogen rises later in pregnancy and is not used for early pregnancy detection.
- B. Progesterone also rises in the luteal phase of a non-pregnant cycle, making it nonspecific for confirming pregnancy.
- D. Estrogen rises gradually throughout pregnancy and is not specific or early enough for pregnancy testing.
A breastfeeding mother notices that her milk begins to flow suddenly when she hears her baby cry, even before the baby latches onto the breast. This milk ejection occurs due to contraction of myoepithelial cells surrounding the alveoli of the mammary gland. Which hormone mediates this response?
- AEstrogen
- BOxytocin
- CProlactin
- DProgesterone
Show answer
Oxytocin, released from the posterior pituitary, mediates the milk ejection reflex by causing contraction of myoepithelial cells surrounding the mammary alveoli, forcing milk into the ducts for expulsion. This neuroendocrine reflex can be triggered by suckling or by conditioned stimuli such as the sound or sight of the infant, acting through afferent pathways to the hypothalamus. Prolactin, in contrast, stimulates the actual synthesis of milk by alveolar epithelial cells but does not cause its ejection. Both reflexes are initiated by sensory stimulation but act through different hormones and different cellular mechanisms.
- A. Estrogen promotes ductal development of the breast but is not responsible for the milk ejection reflex.
- C. Prolactin stimulates milk synthesis by alveolar cells but does not cause the contraction responsible for milk ejection.
- D. Progesterone promotes lobuloalveolar development during pregnancy but does not mediate milk ejection.
[Respiratory Physiology] Oxygen transport - forms of CO2 transport in blood — an
1 questionsA 24-year-old medical student is studying gas transport in blood. Which form carries the largest percentage of carbon dioxide from tissues to the lungs?
- ABicarbonate ion in plasma
- BCarbonic acid in plasma
- CDissolved CO2 in plasma
- DCarbamino compounds with hemoglobin
Show answer
About 70% of CO2 is transported as bicarbonate ion in plasma, formed when CO2 combines with water inside red blood cells under the action of carbonic anhydrase to form carbonic acid, which dissociates into H+ and HCO3-. The HCO3- then diffuses into plasma in exchange for chloride (chloride shift). Carbamino compounds account for about 20-23%, and dissolved CO2 for about 7%. This bicarbonate buffering also links CO2 transport to acid-base balance.
- B. Carbonic acid is an unstable intermediate present only in trace amounts, not a major transport form.
- C. Only about 7% of CO2 is carried dissolved in plasma.
- D. Carbamino compounds account for roughly 20-23% of CO2 transport, less than bicarbonate.
[Respiratory Physiology] Hypoxia types - hypoxic vs anemic vs stagnant vs histot
1 questionsA 45-year-old man ingests a large quantity of cyanide-containing pesticide. His arterial PaO2 and hemoglobin concentration are normal, and skin color remains pink, but his tissues are unable to utilize oxygen. Which type of hypoxia does this represent?
- AHypoxic hypoxia
- BHistotoxic hypoxia
- CAnemic hypoxia
- DStagnant hypoxia
Show answer
Cyanide poisons cytochrome oxidase in the mitochondrial electron transport chain, blocking cellular utilization of oxygen despite normal oxygen delivery to tissues. This is called histotoxic hypoxia, and arterial oxygen content and saturation remain normal, often with pink skin color because tissues cannot extract oxygen. Hypoxic hypoxia results from low PaO2, anemic hypoxia from reduced hemoglobin or its oxygen-carrying capacity, and stagnant hypoxia from reduced blood flow. Treatment includes sodium thiosulfate and hydroxocobalamin to detoxify cyanide.
- A. Hypoxic hypoxia is due to low arterial PaO2, which is normal in this patient.
- C. Anemic hypoxia results from decreased hemoglobin or abnormal hemoglobin, not present here.
- D. Stagnant hypoxia is due to reduced blood flow or circulatory failure, not a feature of cyanide toxicity.
[Renal Physiology] Glomerular filtration rate - determinants and measurement by
1 questionsA 50-year-old woman with suspected chronic kidney disease undergoes renal function testing. Her serum creatinine is 1.8 mg/dL, and a 24-hour urine sample is collected along with a blood sample. Which substance's clearance is most commonly used in routine clinical practice to estimate glomerular filtration rate?
- AUrea
- BInulin
- CPara-aminohippuric acid
- DCreatinine
Show answer
Creatinine clearance is the most widely used clinical test to estimate GFR because creatinine is an endogenous substance produced at a constant rate from muscle metabolism, requires no exogenous infusion, and is freely filtered at the glomerulus with only minimal tubular secretion. Inulin clearance is the gold standard for GFR measurement but requires continuous intravenous infusion, making it impractical for routine use. Para-aminohippuric acid clearance measures renal plasma flow, not GFR. Urea clearance underestimates GFR because urea undergoes significant tubular reabsorption.
- A. Urea clearance underestimates true GFR due to significant tubular reabsorption of urea.
- B. Inulin is the gold standard but requires intravenous infusion, making it impractical for routine clinical use.
- C. Para-aminohippuric acid is used to measure renal plasma flow, not GFR.
[Renal Physiology] Renal clearance concept - substance used to measure renal pla
1 questionsA physiology researcher wants to measure effective renal plasma flow in a healthy volunteer. He selects a substance that is both filtered at the glomerulus and almost completely secreted by the renal tubules during a single pass through the kidney. Which substance is he most likely using?
- APara-aminohippuric acid
- BInulin
- CCreatinine
- DGlucose
Show answer
Para-aminohippuric acid (PAH) is used to measure effective renal plasma flow because, at low plasma concentrations, it is almost completely cleared from the plasma in a single pass through the kidney by a combination of glomerular filtration and active tubular secretion. Its clearance approximates renal plasma flow rather than GFR. Inulin is filtered but not secreted or reabsorbed, so it measures GFR. Creatinine is filtered with minimal secretion and approximates GFR, while glucose is filtered and almost completely reabsorbed, giving essentially zero clearance at normal plasma levels.
- B. Inulin is filtered but not secreted, so its clearance reflects GFR, not renal plasma flow.
- C. Creatinine clearance primarily reflects GFR with only minimal tubular secretion.
- D. Glucose is almost completely reabsorbed by the tubules and has negligible clearance under normal conditions.
[Renal Physiology] Countercurrent mechanism in loop of Henle - urine concentrati
1 questionsA physiology student is studying how the kidney produces concentrated urine. Which mechanism in the loop of Henle is primarily responsible for establishing the hypertonic medullary interstitial gradient necessary for urine concentration?
- AActive reabsorption of sodium chloride by the thick ascending limb without water
- BActive secretion of urea by the thin descending limb into the interstitium
- CFacilitated reabsorption of glucose and amino acids in the thin segments
- DPassive reabsorption of water by the descending limb exceeding solute reabsorption
Show answer
The thick ascending limb of the loop of Henle actively transports sodium, potassium, and chloride out of the tubular lumen into the medullary interstitium via the Na-K-2Cl cotransporter, but this segment is impermeable to water. This single effect creates a hypertonic interstitium and a hypotonic tubular fluid, which, through the countercurrent multiplication of flow in the descending and ascending limbs, establishes the corticomedullary osmotic gradient. This gradient allows water reabsorption from the collecting duct under ADH influence, concentrating the urine. The thin descending limb is permeable to water but does not actively transport urea or solutes.
- B. The thin descending limb does not actively secrete urea; urea recycling occurs mainly via the inner medullary collecting duct and thin ascending limb.
- C. Glucose and amino acid reabsorption occurs in the proximal tubule, not in the thin segments of the loop of Henle.
- D. The descending limb is permeable to water, which leaves the tubule passively, but this alone does not create the gradient; it depends on active transport in the ascending limb.
[Renal Physiology] Action and site of action of diuretics on nephron segments —
1 questionsA 60-year-old man with acute pulmonary edema is given intravenous furosemide, which produces rapid and potent diuresis. At which nephron segment does this drug primarily act to produce its diuretic effect?
- AEarly distal convoluted tubule
- BPrincipal cells of collecting duct
- CThick ascending limb of loop of Henle
- DProximal convoluted tubule
Show answer
Furosemide is a loop diuretic that inhibits the Na-K-2Cl cotransporter in the luminal membrane of the thick ascending limb of the loop of Henle. This blocks active sodium chloride reabsorption, disrupts the countercurrent multiplication mechanism, and reduces the medullary osmotic gradient, resulting in a large increase in sodium and water excretion. Because the thick ascending limb normally reabsorbs about 25% of filtered sodium, loop diuretics are the most potent class of diuretics. Thiazides act on the distal convoluted tubule, while potassium-sparing diuretics act on principal cells of the collecting duct.
- A. Thiazide diuretics inhibit the Na-Cl cotransporter at the early distal convoluted tubule, not loop diuretics.
- B. Potassium-sparing diuretics such as amiloride and spironolactone act on principal cells of the collecting duct.
- D. Carbonic anhydrase inhibitors like acetazolamide act on the proximal convoluted tubule, not loop diuretics.
[Renal Physiology] Renin-angiotensin-aldosterone system regulation of blood pres
1 questionsA 55-year-old man has an episode of significant hemorrhage, leading to a fall in renal perfusion pressure. The juxtaglomerular cells respond by increasing renin secretion. Which of the following is the direct action of renin in the resulting hormonal cascade?
- ADirect vasoconstriction of the afferent arteriole
- BConversion of angiotensin I to angiotensin II
- CConversion of angiotensinogen to angiotensin I
- DDirect stimulation of aldosterone secretion from the adrenal cortex
Show answer
Renin is a proteolytic enzyme released from the juxtaglomerular cells of the afferent arteriole in response to decreased renal perfusion pressure, decreased sodium delivery to the macula densa, or increased sympathetic activity. Its direct action is to cleave circulating angiotensinogen, produced by the liver, into angiotensin I. Angiotensin I is then converted to angiotensin II by angiotensin-converting enzyme, mainly in the pulmonary vasculature. Angiotensin II subsequently stimulates aldosterone secretion and causes vasoconstriction, but these are downstream effects, not direct actions of renin itself.
- A. Vasoconstriction is a direct effect of angiotensin II, not of renin.
- B. This conversion is carried out by angiotensin-converting enzyme, not renin itself.
- D. Aldosterone secretion is stimulated by angiotensin II, which is formed downstream of renin's action.
[Renal Physiology] ADH (vasopressin) action and diabetes insipidus differentiati
1 questionsA 30-year-old woman presents with polyuria of 7 liters per day and excessive thirst. Her serum sodium is 148 mEq/L, and urine osmolality is 95 mOsm/kg despite water deprivation. After administration of desmopressin, her urine osmolality rises to 450 mOsm/kg within two hours. Which is the most likely diagnosis?
- ACentral diabetes insipidus
- BNephrogenic diabetes insipidus
- CPrimary polydipsia
- DOsmotic diuresis due to uncontrolled diabetes mellitus
Show answer
In central diabetes insipidus, there is deficient secretion of antidiuretic hormone from the posterior pituitary, so the kidneys fail to concentrate urine during water deprivation, but they respond appropriately with a significant rise in urine osmolality when exogenous desmopressin is given, because the renal tubular receptors are intact. In nephrogenic diabetes insipidus, the collecting duct is unresponsive to ADH, so urine osmolality fails to rise significantly even after desmopressin administration. Primary polydipsia is excluded by the elevated serum sodium and failure to concentrate urine on water deprivation alone. Osmotic diuresis from hyperglycemia would show glucosuria and would not respond this way to desmopressin.
- B. In nephrogenic diabetes insipidus, urine osmolality would remain low even after desmopressin due to renal tubular unresponsiveness to ADH.
- C. Primary polydipsia typically presents with low-normal serum sodium and dilute urine that concentrates with water deprivation, unlike this case.
- D. Osmotic diuresis from diabetes mellitus would show hyperglycemia and glucosuria, not corrected by desmopressin.
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