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FMGE pathology questions

50 original FMGE-style questions on pathology, each with the correct answer, an explanation, why the other options are wrong and the educational objective. Solve them in the quiz or read them below, grouped by section.

Questions50 with answers
Sections10
Options per question4
Time≈ 75 min
FMGE Pathology: practice quizPick an answer to see the correct option and the explanation at once. Your best score is saved in this browser.

Cell Injury & Adaptation

8 questions
1

A 50-year-old man suffers an episode of transient coronary artery occlusion lasting 10 minutes, followed by reperfusion. Electron microscopy of the affected myocardial cells performed immediately after the ischemic insult is most likely to show which of the following changes?

  1. AKaryolysis of the nucleus
  2. BRupture of lysosomal membranes
  3. CBreakdown of the plasma membrane
  4. DSwelling of mitochondria with loss of cristae
Show answer
Answer: D. Swelling of mitochondria with loss of cristae

The earliest ultrastructural response to reversible cell injury is mitochondrial swelling due to loss of ion homeostasis and influx of calcium and water, seen within minutes of ischemia. This is accompanied by cellular and organellar swelling from failure of the Na+/K+ ATPase pump. Plasma membrane rupture and lysosomal breakdown are features of irreversible injury occurring later. Karyolysis is a nuclear change of necrosis appearing hours after the insult.

  • A. This is a delayed nuclear change seen in established necrosis, not the earliest change.
  • B. This occurs later and marks the transition to irreversible injury.
  • C. This is a late, irreversible change leading to cell death.
Educational objective: Mitochondrial swelling is the earliest ultrastructural change in reversible cell injury.
2

A 62-year-old man dies of acute chest pain. Autopsy reveals a pale, well-demarcated area in the left ventricular wall. Microscopy shows myocardial fibers with preserved cell outlines, hypereosinophilic cytoplasm, and loss of nuclei. Which type of necrosis is depicted?

  1. ACoagulative necrosis
  2. BFat necrosis
  3. CLiquefactive necrosis
  4. DCaseous necrosis
Show answer
Answer: A. Coagulative necrosis

Coagulative necrosis is characteristic of hypoxic death in solid organs such as the heart and kidney, where denaturation of structural proteins and enzymes preserves the basic cell and tissue architecture for several days before macrophages remove the debris. The myocardial infarct here shows ghost outlines of fibers with anucleate, hypereosinophilic cytoplasm, a classic description. Liquefactive necrosis produces a soft, liquefied area typical of brain infarcts or abscesses. Caseous necrosis gives a cheesy appearance seen in tuberculosis, and fat necrosis affects adipose tissue.

  • B. This occurs in adipose tissue and is not the pattern described in myocardium.
  • C. This would show tissue liquefaction, not preserved architecture, as in brain infarcts.
  • D. This shows a granular, cheese-like appearance with no preserved outlines, typical of tuberculosis.
Educational objective: Coagulative necrosis with preserved cell outlines is the hallmark of myocardial infarction.
3

A 70-year-old woman with atrial fibrillation develops sudden right-sided weakness and dies two weeks later. Autopsy of the brain reveals a soft, cystic cavity filled with fluid at the site of the infarct. Which mechanism best explains this pattern of tissue death?

  1. ADenaturation of structural proteins with preservation of cell outlines
  2. BCombination of fat necrosis and saponification by calcium
  3. CDeposition of calcium salts in previously damaged tissue
  4. DDigestion of dead cells by hydrolytic enzymes released from neutrophils and microglia
Show answer
Answer: D. Digestion of dead cells by hydrolytic enzymes released from neutrophils and microglia

Liquefactive necrosis occurs when dead cells are digested by hydrolytic enzymes released from neutrophils and activated microglia, converting the tissue into a liquid viscous mass, classically seen in brain infarcts and bacterial abscesses. This happens because the brain has high lipid content and lacks sufficient supporting stroma to maintain architecture after cell death. Coagulative necrosis, in contrast, preserves tissue architecture due to protein denaturation. Dystrophic calcification and fat necrosis describe different necrosis patterns not relevant to cerebral infarcts.

  • A. This describes coagulative necrosis, which preserves architecture and is not seen in brain infarcts.
  • B. This describes fat necrosis, which occurs in adipose tissue, not brain parenchyma.
  • C. This describes dystrophic calcification, which is unrelated to the softening seen here.
Educational objective: Liquefactive necrosis, caused by enzymatic digestion of dead tissue, is the characteristic pattern in cerebral infarction.
4

A 35-year-old man with chronic cough and low-grade fever undergoes lymph node biopsy. On gross examination, the cut surface shows a soft, friable, yellow-white, cheese-like area. Microscopy shows amorphous granular debris surrounded by epithelioid histiocytes and giant cells, with no visible tissue architecture. Which type of necrosis is seen?

  1. ACoagulative necrosis
  2. BFibrinoid necrosis
  3. CGummatous necrosis
  4. DCaseous necrosis
Show answer
Answer: D. Caseous necrosis

Caseous necrosis is a distinctive combination of coagulative and liquefactive necrosis classically seen in tuberculosis, where the necrotic focus appears grossly as a soft, cheese-like, yellow-white area and microscopically as structureless granular eosinophilic debris surrounded by a granulomatous inflammatory rim of epithelioid cells, lymphocytes, and giant cells. Unlike coagulative necrosis, cellular and tissue outlines are completely lost. Fibrinoid necrosis occurs in blood vessel walls in immune-mediated and hypertensive injury, and gummatous necrosis is seen in tertiary syphilis with a rubbery, gummy appearance.

  • A. This preserves tissue architecture, unlike the structureless debris described here.
  • B. This affects vessel walls and shows fibrin-like deposits, not this cheesy gross appearance.
  • C. This is seen in syphilis and has a rubbery rather than cheesy gross appearance.
Educational objective: Caseous necrosis, with its cheese-like gross appearance and granulomatous rim, is characteristic of tuberculosis.
5

A 45-year-old man with severe epigastric pain and vomiting is found to have a serum lipase of 1200 U/L. CT scan shows peripancreatic fat stranding. Which mechanism best explains the chalky-white deposits seen in the peripancreatic fat in this condition?

  1. ADeposition of calcium in normal tissue due to hypercalcemia
  2. BDenaturation of structural proteins by hydrogen ions released from damaged cells
  3. CRelease of activated lipases causing fatty acid liberation that combines with calcium to form soaps
  4. DDigestion of necrotic tissue by enzymes released from neutrophils
Show answer
Answer: C. Release of activated lipases causing fatty acid liberation that combines with calcium to form soaps

In acute pancreatitis, activated pancreatic lipases are released into the peripancreatic and omental fat, hydrolyzing triglycerides into free fatty acids, which then combine with calcium ions to form chalky-white deposits of calcium soaps, a process called saponification. This explains the grossly visible white, firm foci in the fat and can also contribute to hypocalcemia due to calcium consumption. Protein denaturation by hydrogen ions is unrelated to fat necrosis. Neutrophil-mediated liquefaction describes liquefactive necrosis, and metastatic calcification occurs in normal tissue due to hypercalcemia, not fat necrosis.

  • A. This describes metastatic calcification, which occurs in normal tissue, unlike the peripancreatic fat necrosis described here.
  • B. This describes a different, unrelated injury mechanism, not fat necrosis.
  • D. This describes liquefactive necrosis, not the saponification seen in fat necrosis.
Educational objective: Fat necrosis in pancreatitis results from lipase-mediated fatty acid release that saponifies with calcium to form chalky-white deposits.
6

A 50-year-old man with a blood pressure of 220/140 mmHg is found to have renal biopsy changes showing bright pink, amorphous deposits within the walls of small arterioles, associated with onion-skin thickening of the vessel wall. Which type of necrosis is being described?

  1. AFibrinoid necrosis
  2. BCoagulative necrosis
  3. CLiquefactive necrosis
  4. DCaseous necrosis
Show answer
Answer: A. Fibrinoid necrosis

Fibrinoid necrosis is seen in immune-mediated vascular damage and malignant hypertension, where plasma proteins including fibrin leak into the injured vessel wall, producing a smudgy, bright pink, amorphous appearance on microscopy. It is often accompanied by onion-skin hyperplasia of the arteriolar wall in malignant hypertension and can also be seen in vasculitis. Coagulative and caseous necrosis affect solid organ parenchyma and granulomas respectively, not vessel walls. Liquefactive necrosis produces tissue softening, not the fibrin-rich vascular deposit described here.

  • B. This occurs in solid organ parenchyma with preserved architecture, not in vessel walls as fibrin deposits.
  • C. This produces tissue softening and liquefaction, not fibrin deposition in vessel walls.
  • D. This occurs in granulomas with a cheesy gross appearance, unrelated to vessel wall pathology.
Educational objective: Fibrinoid necrosis in arteriolar walls is the characteristic vascular lesion of malignant hypertension.
7

A pathologist examines a tissue section and identifies individual scattered cells that are smaller than surrounding normal cells, with intensely eosinophilic cytoplasm and condensed, fragmented nuclear chromatin, without any surrounding inflammatory infiltrate. Which process is best represented by these findings?

  1. ALiquefactive necrosis
  2. BAutophagy
  3. CApoptosis
  4. DCoagulative necrosis
Show answer
Answer: C. Apoptosis

Apoptosis is programmed cell death characterized by cell shrinkage, cytoplasmic eosinophilia, and chromatin condensation into dense masses that may fragment, forming apoptotic bodies, all occurring without eliciting an inflammatory response since the cell membrane remains intact and contents are not released. This is in contrast to necrosis, which involves cell swelling, membrane rupture, and release of cellular contents that trigger inflammation. Coagulative and liquefactive necrosis both affect groups of cells and provoke inflammatory reactions. Autophagy refers to self-digestion of cellular components via lysosomes and is a distinct survival mechanism, not a form of cell death with these morphologic features.

  • A. This produces tissue liquefaction with inflammation, not isolated shrunken cells without inflammatory response.
  • B. This is a lysosome-mediated self-digestion process, not a cell death pattern with these features.
  • D. This involves cell swelling and inflammation, unlike the shrinkage and absence of inflammation described here.
Educational objective: Cell shrinkage with chromatin condensation and absence of inflammation is the morphologic hallmark of apoptosis.
8

A 60-year-old woman with primary hyperparathyroidism has a serum calcium of 12.5 mg/dL and serum phosphate of 2.0 mg/dL. Imaging reveals calcium deposits in the renal tubules, gastric mucosa, and lung alveolar septa, all of which are histologically normal apart from the calcification. Which statement best explains this pattern of calcification?

  1. ACalcification is restricted to atherosclerotic plaques with normal serum calcium levels
  2. BCalcification is localized to a single necrotic focus with normal serum calcium levels
  3. CCalcification is occurring in tissue that has undergone prior necrosis despite normal serum calcium levels
  4. DCalcification is occurring in previously normal tissue as a result of elevated serum calcium levels
Show answer
Answer: D. Calcification is occurring in previously normal tissue as a result of elevated serum calcium levels

Metastatic calcification occurs in previously normal tissues as a consequence of hypercalcemia, most commonly from primary hyperparathyroidism, and tends to involve organs that excrete acid such as the kidney, stomach, and lung, which have a relatively alkaline environment favoring calcium salt deposition. In contrast, dystrophic calcification occurs in previously damaged or necrotic tissue with normal serum calcium levels, as seen in atherosclerosis, tuberculous caseous necrosis, or old infarcts. The key distinguishing feature is that metastatic calcification depends on a deranged serum calcium level, whereas dystrophic calcification depends on local tissue damage regardless of serum calcium.

  • A. This describes dystrophic calcification in atherosclerosis, not the widespread normal-tissue pattern described here.
  • B. This describes a single necrotic dystrophic focus, inconsistent with the multi-organ involvement of normal tissue described here.
  • C. This describes dystrophic calcification, which requires prior tissue damage rather than widespread normal-tissue involvement as seen here.
Educational objective: Metastatic calcification occurs in normal tissues due to hypercalcemia, while dystrophic calcification occurs in damaged tissue with normal serum calcium.

Inflammation & Repair

8 questions
9

During acute inflammation, a neutrophil in a post-capillary venule first begins to loosely tether and roll along the endothelial surface before firm adhesion occurs. Which family of adhesion molecules mediates this initial rolling step?

  1. ACadherins
  2. BIntegrins
  3. CImmunoglobulin superfamily (ICAM, VCAM)
  4. DSelectins
Show answer
Answer: D. Selectins

Selectins (E-selectin and P-selectin on endothelium, L-selectin on leukocytes) mediate the initial loose, reversible rolling of leukocytes along the endothelial surface by binding sialylated carbohydrate ligands. This rolling slows the leukocyte enough for chemokine-activated integrins to undergo a conformational change and bind firmly to ICAM-1 and VCAM-1, producing stable adhesion. The leukocyte then transmigrates through the endothelium via diapedesis. This sequence of margination, rolling, adhesion and transmigration is the standard leukocyte recruitment cascade.

  • A. Cadherins mediate cell-cell adhesion in epithelial and endothelial junctions, not leukocyte rolling.
  • B. Integrins mediate firm adhesion after rolling, not the initial rolling step.
  • C. ICAM and VCAM are the endothelial ligands bound by activated integrins during firm adhesion, not rolling.
Educational objective: Selectins mediate rolling of leukocytes, while integrins binding ICAM/VCAM mediate firm adhesion in the leukocyte recruitment cascade.
10

A researcher compares the potency of various endogenous mediators in inducing directed migration of neutrophils toward a site of bacterial invasion. Which of the following is the most potent chemotactic agent for neutrophils?

  1. AProstaglandin E2
  2. BLeukotriene B4
  3. CInterleukin-1
  4. DHistamine
Show answer
Answer: B. Leukotriene B4

Leukotriene B4, along with complement component C5a and bacterial N-formyl-methionine peptides, is among the most potent chemotactic agents for neutrophils. It is produced from arachidonic acid via the 5-lipoxygenase pathway and binds specific G-protein coupled receptors on neutrophils, triggering actin polymerization and directed movement toward the chemical gradient. This chemotactic signaling is essential for recruiting neutrophils from the vasculature to the site of infection or tissue injury. C5a and LTB4 are considered the principal chemoattractants in acute inflammation.

  • A. Prostaglandin E2 mediates vasodilation and pain sensitization rather than acting as a potent neutrophil chemoattractant.
  • C. Interleukin-1 is a pro-inflammatory cytokine that activates endothelium and induces fever, but is not itself chemotactic for neutrophils.
  • D. Histamine primarily increases vascular permeability and causes vasodilation, it is not a major chemotactic agent.
Educational objective: Leukotriene B4 and complement C5a are the most potent chemotactic agents for neutrophils in acute inflammation.
11

A 30-year-old man develops a painful abscess on his forearm six hours after a thorn prick. Histological examination at this stage would most likely show predominance of which cell type, in contrast to a biopsy of a tuberculous lymph node showing chronic inflammation?

  1. APlasma cells
  2. BNeutrophils
  3. CLymphocytes
  4. DMacrophages
Show answer
Answer: B. Neutrophils

Neutrophils are the first cells to arrive at a site of acute inflammation, typically within 6 to 24 hours, recruited by chemoattractants such as C5a, LTB4 and bacterial peptides, and they dominate the early cellular infiltrate. In contrast, chronic inflammation such as tuberculosis is characterized by a predominance of lymphocytes, macrophages, and plasma cells reflecting a sustained immune response. This temporal distinction in cellular infiltrate helps differentiate acute from chronic inflammatory processes on histology. Macrophages typically replace neutrophils as the dominant cell after 24 to 48 hours in acute inflammation.

  • A. Plasma cells are seen in chronic inflammation reflecting ongoing antibody production, not in the earliest phase of acute inflammation.
  • C. Lymphocytes are characteristic of chronic inflammation, not the earliest responders in acute inflammation.
  • D. Macrophages become prominent later in acute inflammation, after neutrophils, and persist in chronic inflammation.
Educational objective: Neutrophils are the first responders in acute inflammation, while lymphocytes and macrophages predominate in chronic inflammation.
12

A 45-year-old man with pulmonary tuberculosis has a lung biopsy showing well-formed granulomas with central caseous necrosis surrounded by epithelioid macrophages and giant cells. Formation and maintenance of these granulomas is critically dependent on which cytokine produced by activated macrophages?

  1. AInterleukin-10
  2. BTumor necrosis factor-alpha
  3. CTransforming growth factor-beta
  4. DInterleukin-4
Show answer
Answer: B. Tumor necrosis factor-alpha

Tumor necrosis factor-alpha, produced by activated macrophages in response to persistent antigens such as mycobacteria, is essential for the formation and maintenance of granulomas by recruiting and activating additional monocytes and promoting their differentiation into epithelioid cells. Anti-TNF therapy in conditions like rheumatoid arthritis is known to reactivate latent tuberculosis because it disrupts granuloma integrity, confirming this cytokine's central role. T-helper 1 cells also contribute by secreting interferon-gamma, which activates macrophages, but TNF-alpha is the key macrophage-derived mediator sustaining the granuloma structure. This mechanism explains why granulomas can wall off but not always eliminate intracellular pathogens.

  • A. Interleukin-10 is an anti-inflammatory cytokine that suppresses macrophage activation rather than sustaining granulomas.
  • C. Transforming growth factor-beta is primarily involved in fibrosis and immune suppression, not the core granuloma-sustaining signal.
  • D. Interleukin-4 promotes a Th2 response and is associated with allergic and parasitic inflammation, not granuloma maintenance.
Educational objective: TNF-alpha from activated macrophages is essential for formation and maintenance of granulomas, as shown by TB reactivation with anti-TNF therapy.
13

A 25-year-old woman develops localized swelling and redness within minutes after an insect bite. The early increase in vascular permeability at this site is mediated by histamine acting primarily on which component of the microvasculature?

  1. ACapillary basement membrane
  2. BArterial endothelial cells
  3. CArteriolar smooth muscle
  4. DVenular endothelial cells
Show answer
Answer: D. Venular endothelial cells

Histamine causes an immediate transient increase in vascular permeability by acting on H1 receptors on venular endothelial cells, causing them to contract and widen the interendothelial junctions. This endothelial gap formation in postcapillary venules allows plasma proteins and fluid to leak into the interstitium, producing the wheal and flare response seen in acute inflammation. Histamine also causes arteriolar vasodilation contributing to redness and warmth, but the permeability change specifically occurs at the venular level. This mechanism explains the rapid, short-lived edema characteristic of immediate hypersensitivity and mild trauma.

  • A. The basement membrane is not directly contracted by histamine; the primary effect is on endothelial cell junctions.
  • B. Permeability changes in acute inflammation occur predominantly in venules, not arteries.
  • C. Arteriolar smooth muscle responds to histamine with vasodilation, contributing to redness, but is not the site of permeability increase.
Educational objective: Histamine increases vascular permeability by causing contraction of venular endothelial cells and widening of interendothelial junctions.
14

A 40-year-old man has a surgical incision that is healing normally. Granulation tissue formed in the first week is composed predominantly of a thinner, more delicate collagen, which is gradually replaced over subsequent weeks by a stronger, more cross-linked collagen that forms the mature scar. Which collagen type predominates in the early granulation tissue?

  1. AType I
  2. BType IV
  3. CType II
  4. DType III
Show answer
Answer: D. Type III

Early granulation tissue is rich in type III collagen, produced rapidly by fibroblasts to provide initial structural support during wound healing. Over the following weeks, type III collagen is progressively degraded by matrix metalloproteinases and replaced by type I collagen, which has greater tensile strength and cross-linking, forming the mature scar. This remodeling phase can continue for months and determines the final strength of the healed wound. Deficient remodeling or excess collagen deposition can lead to complications such as hypertrophic scarring or keloid formation.

  • A. Type I collagen is the predominant mature scar collagen, replacing type III over time, not the initial type laid down.
  • B. Type IV collagen is a component of basement membranes, not the fibrillar collagen of granulation tissue or scar.
  • C. Type II collagen is found in cartilage and is not involved in cutaneous wound healing.
Educational objective: Early granulation tissue contains type III collagen, which is remodeled into stronger type I collagen as the scar matures.
15

A 19-year-old woman of African descent develops a firm, raised, pruritic scar that extends well beyond the margins of a previous ear piercing site, persisting and enlarging over several months. Biopsy shows thick, haphazardly arranged hyalinized collagen bundles. Which complication of wound healing does this represent?

  1. AHypertrophic scar
  2. BIncisional hernia
  3. CDehiscence
  4. DKeloid
Show answer
Answer: D. Keloid

A keloid results from excessive collagen deposition during wound healing that extends beyond the boundaries of the original wound, forming a raised, firm, often pruritic scar; it shows a genetic predisposition and is more common in people of African descent. Histologically, keloids show thick, disorganized, hyalinized collagen bundles, distinguishing them from hypertrophic scars, which remain confined to the wound margins and tend to regress over time. Keloids result from an imbalance favoring collagen synthesis over degradation during the remodeling phase of healing. Management includes intralesional corticosteroids, silicone sheeting, or surgical excision with adjuvant therapy, as recurrence is common.

  • A. Hypertrophic scars remain confined within the original wound margins and often regress, unlike the extension beyond the piercing site described here.
  • B. Incisional hernia is protrusion of abdominal contents through a weakened surgical scar, unrelated to this presentation.
  • C. Dehiscence refers to mechanical separation of a healing wound, not excess collagen deposition.
Educational objective: Keloids are characterized by collagen overgrowth extending beyond the original wound margins, unlike hypertrophic scars which stay confined to the wound.
16

A 34-year-old man has a healing surgical wound on his forearm. Over two weeks, the wound margins progressively draw closer together, reducing the defect size before re-epithelialization is complete. Which cell type present in the healing tissue is primarily responsible for this reduction in wound size?

  1. AEndothelial cell
  2. BMyofibroblast
  3. CFibroblast
  4. DMacrophage
Show answer
Answer: B. Myofibroblast

Myofibroblasts are modified fibroblasts that express alpha-smooth muscle actin, giving them contractile properties similar to smooth muscle cells. They appear in granulation tissue from day 3 onward and align along the wound edges, generating centripetal tension that pulls the wound margins together, a process called wound contraction. This is distinct from scar contracture, which is pathological shortening due to excessive collagen deposition. Wound contraction can reduce the wound area by up to 80% in open wounds.

  • A. Endothelial cells form new capillaries (angiogenesis) but do not contract the wound.
  • C. Fibroblasts synthesize collagen and ground substance but lack the contractile actin filaments needed for contraction.
  • D. Macrophages clear debris and secrete growth factors but have no contractile role in wound closure.
Educational objective: Myofibroblasts, bearing alpha-smooth muscle actin, mediate wound contraction in granulation tissue.
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Hemodynamics & Shock

6 questions
17

A 58-year-old man with decompensated liver cirrhosis undergoes diagnostic paracentesis for ascites. The fluid is clear and straw-colored. Laboratory analysis shows protein content of 1.8 g/dL and specific gravity of 1.012. Based on these findings, this fluid is best classified as which of the following?

  1. ATransudate
  2. BChylous effusion
  3. CHemorrhagic effusion
  4. DExudate
Show answer
Answer: A. Transudate

Transudates result from hydrostatic or oncotic pressure imbalance without increased capillary permeability, typically containing protein below 3 g/dL and specific gravity below 1.015. Exudates arise from increased vascular permeability due to inflammation or malignancy and have protein above 3 g/dL with specific gravity above 1.015, along with higher cell counts. The low protein and low specific gravity here fit cirrhotic ascites from portal hypertension, a classic transudate. Chylous and hemorrhagic effusions are characterized by milky, triglyceride-rich fluid or grossly bloody fluid respectively, neither of which matches this description.

  • B. A chylous effusion is milky white and rich in triglycerides, not clear and straw-colored.
  • C. A hemorrhagic effusion is grossly bloody, not clear and straw-colored.
  • D. An exudate requires protein above 3 g/dL and specific gravity above 1.015, which are not met here.
Educational objective: Transudates have protein below 3 g/dL and specific gravity below 1.015, reflecting pressure imbalance rather than vascular injury.
18

A 62-year-old woman develops deep vein thrombosis in her left calf three days after undergoing total hip replacement surgery. She had been immobile in bed since the operation. Which of the following best describes the three fundamental factors that predispose to thrombus formation in this setting?

  1. AEndothelial injury, stasis of blood flow, hypercoagulability
  2. BHemolysis, vasoconstriction, inflammation
  3. CAtherosclerosis, vasodilation, leukocytosis
  4. DVasospasm, platelet aggregation, fibrinolysis
Show answer
Answer: A. Endothelial injury, stasis of blood flow, hypercoagulability

Virchow's triad describes the three interrelated factors predisposing to intravascular thrombosis: endothelial injury (from surgery or trauma, exposing subendothelial collagen and tissue factor), stasis or turbulent blood flow (from immobilization, preventing dilution of clotting factors and allowing platelet-endothelial contact), and hypercoagulability of blood (from surgery-induced acute phase response and tissue factor release). This patient has postoperative immobilization causing stasis plus surgical trauma causing endothelial injury, a classic combination for postoperative DVT. Understanding this triad explains prophylactic measures such as early mobilization, compression stockings, and anticoagulation.

  • B. Hemolysis and vasoconstriction are not part of Virchow's triad.
  • C. Atherosclerosis and vasodilation are not the classic triad components, though atherosclerosis can cause endothelial injury.
  • D. Vasospasm and fibrinolysis are not components of Virchow's triad; fibrinolysis opposes thrombosis rather than promoting it.
Educational objective: Virchow's triad of endothelial injury, stasis, and hypercoagulability underlies the pathogenesis of thrombosis.
19

During autopsy, a pathologist examines a thrombus found in the femoral vein of a patient who died after prolonged hospitalization. On gross sectioning, the thrombus shows alternating pale and dark laminations. This specific gross feature is most useful for distinguishing which of the following?

  1. AAn arterial thrombus from a venous thrombus
  2. BA mural thrombus from an occlusive thrombus
  3. CAn antemortem thrombus from a postmortem clot
  4. DA thrombus from an embolus
Show answer
Answer: C. An antemortem thrombus from a postmortem clot

Lines of Zahn are alternating pale bands of platelets and fibrin with darker bands of red cells, formed by laminar deposition under flowing blood as the thrombus propagates. Their presence indicates the thrombus formed in flowing blood, that is, during life, distinguishing it from postmortem clots, which are gelatinous, unattached to the vessel wall, and lack lamination because they form after circulation has stopped. This distinction is important forensically to determine whether a thrombus contributed to death or formed after it. Lines of Zahn can occur in both arterial and venous thrombi and do not by themselves differentiate arterial from venous origin.

  • A. Lines of Zahn can be seen in both arterial and venous thrombi and do not differentiate between them.
  • B. Mural versus occlusive refers to the extent of lumen involvement, not to the lamination pattern.
  • D. Lines of Zahn indicate antemortem formation in flowing blood but do not distinguish a thrombus from an embolus, which is a dislodged fragment.
Educational objective: Lines of Zahn, alternating layers of platelets-fibrin and red cells, confirm that a thrombus formed antemortem in flowing blood.
20

A 24-year-old man sustains a closed fracture of the femur in a road traffic accident. Twenty-four hours later, he develops sudden breathlessness with a respiratory rate of 32/min and oxygen saturation of 88% on room air. Examination reveals petechiae over the anterior chest wall and axillae, and he becomes confused and disoriented. Which of the following best describes this classic clinical presentation?

  1. AAir embolism
  2. BFat embolism syndrome
  3. CAcute respiratory distress syndrome
  4. DPulmonary thromboembolism
Show answer
Answer: B. Fat embolism syndrome

Fat embolism syndrome classically presents 24-72 hours after long bone or pelvic fracture with a triad of respiratory distress, neurological symptoms, and petechial rash over the chest, axillae, and conjunctivae. Fat globules released from bone marrow enter the venous circulation, lodge in pulmonary capillaries causing hypoxia, and their fatty acid breakdown products damage capillary endothelium, leading to petechiae and cerebral dysfunction. This temporal relationship with long bone fracture and the triad of findings distinguishes it from pulmonary thromboembolism, which typically lacks petechiae and neurological changes. Management is supportive, with early fracture fixation playing a key preventive role.

  • A. Air embolism is associated with central line procedures or diving injuries, not long bone fractures, and does not classically cause petechiae.
  • C. ARDS can follow trauma but does not specifically present with petechiae and neurological changes in this triad pattern.
  • D. Pulmonary thromboembolism causes dyspnea and hypoxia but does not typically produce petechiae or confusion as part of a triad.
Educational objective: Fat embolism syndrome after long bone fracture presents with a triad of respiratory distress, neurological symptoms, and petechial rash.
21

A 29-year-old woman develops sudden hypotension and profuse vaginal bleeding after a placental abruption during labor. Laboratory tests show platelet count of 45,000/microliter, fibrinogen 80 mg/dL, prothrombin time prolonged, and markedly elevated D-dimer. Which of the following best explains this combination of findings?

  1. AHemolytic uremic syndrome
  2. BIdiopathic thrombocytopenic purpura
  3. CDisseminated intravascular coagulation
  4. DVitamin K deficiency
Show answer
Answer: C. Disseminated intravascular coagulation

Disseminated intravascular coagulation is triggered by release of tissue factor, as occurs in placental abruption, activating widespread coagulation that consumes platelets and clotting factors including fibrinogen, producing thrombocytopenia, hypofibrinogenemia, and prolonged clotting times. The concurrent activation of fibrinolysis to break down the microthrombi generates elevated D-dimer, a specific marker of fibrin degradation. This combination of low platelets, low fibrinogen, prolonged PT, and high D-dimer is the classic laboratory signature of DIC. Obstetric catastrophes such as abruption, amniotic fluid embolism, and retained dead fetus are well-recognized triggers.

  • A. HUS causes thrombocytopenia and hemolysis with schistocytes but fibrinogen and PT are usually normal.
  • B. ITP causes isolated thrombocytopenia without hypofibrinogenemia or elevated D-dimer.
  • D. Vitamin K deficiency prolongs PT and PTT through reduced factors II, VII, IX, X but does not cause thrombocytopenia or elevated D-dimer.
Educational objective: DIC is characterized by thrombocytopenia, hypofibrinogenemia, prolonged PT/aPTT, and elevated D-dimer from consumptive coagulopathy and secondary fibrinolysis.
22

A 70-year-old man with urosepsis is brought to the emergency department. His blood pressure is 78/40 mmHg, heart rate 128/min, and temperature 39.8°C. His skin is warm and flushed, with capillary refill time of less than 2 seconds. Which of the following hemodynamic patterns best fits this presentation in the early phase of this condition?

  1. AHigh systemic vascular resistance with low cardiac output
  2. BLow systemic vascular resistance with low cardiac output
  3. CLow systemic vascular resistance with high cardiac output
  4. DHigh systemic vascular resistance with high cardiac output
Show answer
Answer: C. Low systemic vascular resistance with high cardiac output

Early septic shock is a form of distributive shock in which bacterial toxins trigger massive release of nitric oxide and other vasodilatory mediators, causing profound peripheral vasodilation and a fall in systemic vascular resistance. The heart compensates with tachycardia and increased stroke volume, producing a high cardiac output state, which explains the warm extremities and rapid capillary refill despite hypotension, often called warm shock. This contrasts with cardiogenic or hypovolemic shock, where high systemic vascular resistance and low cardiac output produce cold, clammy extremities. Late or decompensated septic shock may eventually progress to a low cardiac output state as myocardial depression sets in.

  • A. High SVR with low cardiac output describes cardiogenic or hypovolemic shock, which presents with cold, clammy extremities rather than warm skin.
  • B. Low SVR with low cardiac output describes late decompensated septic shock, not the warm early phase described here.
  • D. High SVR with high cardiac output is not a recognized shock pattern and does not match warm, well-perfused skin with hypotension.
Educational objective: Early septic shock produces warm shock with low systemic vascular resistance and high cardiac output due to toxin-mediated vasodilation.

Neoplasia - Basics

2 questions
23

A 62-year-old man, chronic smoker, presents with a central lung mass on chest X-ray and complains of constipation, polyuria and generalized weakness. Serum calcium is 12.8 mg/dL with low serum parathyroid hormone (intact PTH). Biopsy of the mass shows squamous cell carcinoma. Which of the following best explains the hypercalcemia in this patient?

  1. ADiffuse osteolytic skeletal metastases
  2. BTumor production of 1,25-dihydroxyvitamin D
  3. CSecretion of parathyroid hormone-related peptide by tumor cells
  4. DEctopic secretion of parathyroid hormone by the tumor
Show answer
Answer: C. Secretion of parathyroid hormone-related peptide by tumor cells

Squamous cell carcinoma of the lung is the classic cause of humoral hypercalcemia of malignancy through secretion of parathyroid hormone-related peptide (PTHrP). PTHrP binds the PTH receptor in bone and kidney, increasing osteoclastic bone resorption and renal calcium reabsorption, which raises serum calcium while suppressing endogenous PTH. This mechanism does not require bone metastases. The low intact PTH confirms that the hypercalcemia is PTH-independent, pointing away from true ectopic PTH secretion.

  • A. Osteolytic metastases cause local osteolytic hypercalcemia, typically seen with breast cancer or multiple myeloma, not the mechanism here with low PTH and no mention of metastases.
  • B. Ectopic 1,25-(OH)2D production causing hypercalcemia is characteristic of lymphomas, not squamous cell lung cancer.
  • D. True ectopic PTH secretion by tumors is extremely rare; the low intact PTH level argues against this mechanism.
Educational objective: Squamous cell carcinoma of the lung causes humoral hypercalcemia of malignancy via PTHrP secretion, which suppresses endogenous PTH.
24

A 58-year-old woman presents with sudden onset of multiple pigmented, warty, well-demarcated plaques over her trunk over the past two months, along with velvety hyperpigmented thickening of the skin in the axillae and neck folds. On evaluation, she is found to have adenocarcinoma of the stomach. Which paraneoplastic skin finding is most strongly associated with an underlying visceral malignancy in this presentation?

  1. ASudden eruptive seborrheic keratoses (sign of Leser-Trélat)
  2. BErythema gyratum repens
  3. CDermatomyositis-associated rash
  4. DAcquired ichthyosis
Show answer
Answer: A. Sudden eruptive seborrheic keratoses (sign of Leser-Trélat)

The sign of Leser-Trélat refers to the sudden eruptive appearance of multiple seborrheic keratoses, often together with acanthosis nigricans, and is classically associated with an underlying adenocarcinoma, most commonly of the stomach. The exact mechanism is thought to involve tumor-derived growth factors such as transforming growth factor-alpha stimulating epidermal proliferation. Its abrupt onset in an older adult should prompt a search for occult visceral malignancy. Acanthosis nigricans in this setting is a well-known associated paraneoplastic skin marker, reinforcing the diagnosis.

  • B. Erythema gyratum repens is a figurate erythema associated with malignancy, usually lung cancer, presenting as wood-grain patterned erythematous bands, not pigmented warty plaques.
  • C. Dermatomyositis presents with proximal muscle weakness and a heliotrope rash with Gottron's papules, not warty pigmented plaques.
  • D. Acquired ichthyosis presents as dry, scaly skin, classically linked to Hodgkin lymphoma, not warty pigmented lesions.
Educational objective: Sudden eruptive seborrheic keratoses (sign of Leser-Trélat), often with acanthosis nigricans, suggest an underlying internal malignancy, especially gastric adenocarcinoma.

RBC Disorders

6 questions
25

A 30-year-old woman with heavy menstrual bleeding presents with fatigue. Hemoglobin is 8.2 g/dL. Peripheral smear shows microcytic hypochromic red cells with increased central pallor and occasional pencil-shaped cells. Serum iron is 30 µg/dL (low), total iron-binding capacity is 480 µg/dL (high), and serum ferritin is 8 ng/mL (low). Which of the following best fits this laboratory pattern?

  1. AAnemia of chronic disease
  2. BIron deficiency anemia
  3. CSideroblastic anemia
  4. DBeta-thalassemia trait
Show answer
Answer: B. Iron deficiency anemia

Iron deficiency anemia classically shows low serum iron, high total iron-binding capacity (TIBC) due to increased transferrin synthesis, and low serum ferritin reflecting depleted iron stores. The peripheral smear shows microcytic hypochromic cells with increased central pallor, and pencil cells are a characteristic finding. This combination of low iron, high TIBC and low ferritin is diagnostic, distinguishing it from other microcytic anemias. Heavy menstrual blood loss is a common cause in women of reproductive age.

  • A. Anemia of chronic disease typically shows low serum iron with low or normal TIBC and normal or raised ferritin, the opposite TIBC pattern seen here.
  • C. Sideroblastic anemia shows elevated serum iron and ferritin with normal or low TIBC, reflecting iron overload rather than deficiency.
  • D. Beta-thalassemia trait usually shows normal or elevated serum iron and ferritin with normal TIBC, since iron stores are not depleted.
Educational objective: Iron deficiency anemia shows low serum iron, high TIBC, and low serum ferritin with microcytic hypochromic cells and pencil cells on smear.
26

A 55-year-old strict vegetarian presents with progressive fatigue and tingling and numbness in both feet for the past three months. Examination reveals loss of vibration and position sense in the lower limbs, with a positive Romberg sign. Peripheral smear shows macrocytic red cells and hypersegmented neutrophils. Which of the following is the most likely underlying deficiency explaining this clinical picture?

  1. AVitamin B12 deficiency
  2. BVitamin B6 deficiency
  3. CFolate deficiency
  4. DIron deficiency
Show answer
Answer: A. Vitamin B12 deficiency

Vitamin B12 deficiency causes subacute combined degeneration of the spinal cord, affecting the dorsal columns and corticospinal tracts, producing loss of vibration and position sense, sensory ataxia and a positive Romberg sign. Folate deficiency produces an identical megaloblastic blood picture but does not cause neurological demyelination. This neurological distinction is the key clinical clue separating the two, especially important since both will show macrocytic anemia with hypersegmented neutrophils. Strict vegetarians are at risk of B12 deficiency due to the absence of B12 in plant foods.

  • B. Vitamin B6 deficiency classically causes sideroblastic anemia and peripheral neuropathy but not megaloblastic changes with hypersegmented neutrophils.
  • C. Folate deficiency causes megaloblastic anemia identical on smear but does not cause subacute combined degeneration or the described sensory neuropathy.
  • D. Iron deficiency causes microcytic hypochromic anemia, not macrocytosis with hypersegmented neutrophils.
Educational objective: Neurological involvement (subacute combined degeneration) distinguishes vitamin B12 deficiency from folate deficiency, which causes an identical blood picture without neurological disease.
27

A 10-year-old boy presents with recurrent episodes of jaundice and fatigue since early childhood. Examination reveals mild splenomegaly and scleral icterus. Peripheral smear shows numerous small, densely staining red cells lacking central pallor, and reticulocyte count is elevated at 6%. Family history reveals similar symptoms in his father. Which of the following is the most appropriate screening test to confirm the suspected diagnosis?

  1. AHemoglobin electrophoresis
  2. BG6PD enzyme assay
  3. CDirect Coombs test
  4. DOsmotic fragility test
Show answer
Answer: D. Osmotic fragility test

The clinical picture of chronic hemolytic anemia with jaundice, splenomegaly, spherocytes on smear and autosomal dominant inheritance is classic for hereditary spherocytosis, caused by defects in red cell membrane proteins such as spectrin, ankyrin, band 3 or protein 4.2. The osmotic fragility test demonstrates increased fragility of spherocytes when exposed to hypotonic saline, because their reduced surface-area-to-volume ratio limits their ability to swell. This is the traditional screening test for hereditary spherocytosis, though flow cytometric eosin-5-maleimide binding is now also used. The underlying defect disrupts the vertical linkage between the membrane skeleton and the lipid bilayer.

  • A. Hemoglobin electrophoresis is used to diagnose hemoglobinopathies such as thalassemia or sickle cell disease, not membrane defects.
  • B. G6PD enzyme assay is used to diagnose G6PD deficiency, which presents with episodic hemolysis triggered by oxidative stress, not chronic spherocytic hemolysis.
  • C. Direct Coombs test detects antibody-mediated hemolysis as in autoimmune hemolytic anemia, which is not suggested by the family history here.
Educational objective: The osmotic fragility test is the classic screening test for hereditary spherocytosis, which results from defects in membrane proteins like spectrin and ankyrin.
28

A 6-year-old boy of Mediterranean descent develops dark-colored urine, pallor and jaundice two days after eating fava beans. Laboratory evaluation shows hemoglobin of 7.5 g/dL, elevated indirect bilirubin, and peripheral smear showing bite cells and Heinz bodies. Which of the following drugs is most likely to precipitate a similar hemolytic episode in this child?

  1. AMetformin
  2. BPrimaquine
  3. CParacetamol
  4. DAmoxicillin
Show answer
Answer: B. Primaquine

Primaquine is a classic oxidant drug that precipitates acute hemolysis in G6PD-deficient individuals by generating reactive oxygen species that overwhelm the reduced capacity of deficient red cells to regenerate NADPH and glutathione, leading to oxidative damage of hemoglobin and membrane proteins, producing Heinz bodies and bite cells. Other well-known triggers include sulfonamides, dapsone, nitrofurantoin and fava beans (favism). Avoiding these triggers is central to management, since the enzyme defect itself is not treatable. The self-limited nature of most episodes reflects destruction of the older, more deficient red cells followed by survival of younger cells with relatively higher enzyme activity.

  • A. Metformin does not cause oxidative hemolysis and is not associated with G6PD-deficient hemolytic crises.
  • C. Paracetamol in therapeutic doses is not a typical trigger of hemolysis in G6PD deficiency.
  • D. Amoxicillin is not a recognized oxidant trigger for hemolysis in G6PD deficiency.
Educational objective: Oxidant drugs such as primaquine, sulfonamides, and dapsone precipitate acute hemolysis with Heinz bodies and bite cells in G6PD deficiency.
29

A 7-year-old child from a tribal belt of central India presents with recurrent painful episodes in the limbs, pallor and yellowish discoloration of the sclera. Peripheral smear shows crescent-shaped red cells along with target cells and occasional Howell-Jolly bodies. Which of the following best describes the underlying genetic abnormality responsible for this condition?

  1. APoint mutation causing premature stop codon in the beta-globin gene
  2. BPoint mutation causing substitution of valine for glutamic acid at the sixth position of the beta-globin chain
  3. CTrinucleotide repeat expansion in the beta-globin gene promoter
  4. DDeletion of one or more alpha-globin gene copies
Show answer
Answer: B. Point mutation causing substitution of valine for glutamic acid at the sixth position of the beta-globin chain

Sickle cell anemia results from a single point mutation in the beta-globin gene that substitutes valine for glutamic acid at the sixth amino acid position, producing abnormal hemoglobin S. Under conditions of hypoxia or dehydration, deoxygenated HbS polymerizes, distorting red cells into the characteristic sickle (crescent) shape seen on peripheral smear. Target cells and Howell-Jolly bodies reflect accompanying functional hyposplenism from recurrent splenic infarction. This condition is prevalent among certain tribal populations in central India.

  • A. A premature stop codon causing a truncated beta chain is the mechanism of beta-zero thalassemia, not sickle cell disease.
  • C. Trinucleotide repeat expansions are associated with disorders such as Huntington disease, not hemoglobinopathies.
  • D. Deletion of alpha-globin genes causes alpha-thalassemia, not sickle cell disease.
Educational objective: Sickle cell anemia is caused by a point mutation producing a glutamic acid to valine substitution at position six of the beta-globin chain, leading to HbS polymerization and sickling under hypoxic stress.
30

A 2-year-old child presents with severe pallor, failure to thrive, and massive hepatosplenomegaly. Facial examination reveals frontal bossing and maxillary prominence. Hemoglobin is 5.5 g/dL with marked microcytosis. Hemoglobin electrophoresis shows markedly elevated HbF and increased HbA2, with absent or markedly reduced HbA. Which of the following diagnoses best fits this electrophoretic pattern?

  1. AAlpha-thalassemia trait
  2. BHereditary persistence of fetal hemoglobin
  3. CBeta-thalassemia major
  4. DHemoglobin H disease
Show answer
Answer: C. Beta-thalassemia major

Beta-thalassemia major results from absent or severely reduced synthesis of beta-globin chains due to mutations in both beta-globin alleles, leading to compensatory elevation of HbF (alpha2-gamma2) and HbA2 (alpha2-delta2), with little to no HbA (alpha2-beta2) on electrophoresis. The severe anemia, extramedullary hematopoiesis causing hepatosplenomegaly and bony changes like frontal bossing from marrow expansion are classic features presenting in early childhood. This electrophoretic pattern of markedly raised HbF with increased HbA2 and absent HbA confirms the diagnosis. Lifelong transfusion dependence is typical, with iron overload being a major long-term complication.

  • A. Alpha-thalassemia trait shows a normal hemoglobin electrophoresis pattern since alpha-chain deficiency does not alter the relative proportions of HbA, HbA2 and HbF significantly.
  • B. Hereditary persistence of fetal hemoglobin shows elevated HbF but with normal HbA2 and preserved HbA, and affected individuals are typically asymptomatic.
  • D. Hemoglobin H disease, a form of alpha-thalassemia, shows a distinct fast-moving HbH band on electrophoresis, not the HbF and HbA2 elevation pattern seen in beta-thalassemia major.
Educational objective: Beta-thalassemia major shows markedly elevated HbF and HbA2 with absent or reduced HbA on electrophoresis, reflecting absent beta-globin chain synthesis.

WBC & Lymphoid Neoplasms

6 questions
31

A 4-year-old boy presents with fever, bone pain, and easy bruising for 10 days. Examination reveals pallor, generalized lymphadenopathy, and hepatosplenomegaly. Total leukocyte count is 48,000/microL with 70% blast cells having scant cytoplasm, high nuclear-cytoplasmic ratio, and condensed chromatin. Which of the following findings would best support the most likely diagnosis?

  1. ABlasts positive for CD14 and nonspecific esterase
  2. BBlasts negative for myeloperoxidase and positive for terminal deoxynucleotidyl transferase
  3. CBlasts showing Philadelphia chromosome on karyotyping
  4. DBlasts positive for myeloperoxidase with Auer rods in cytoplasm
Show answer
Answer: B. Blasts negative for myeloperoxidase and positive for terminal deoxynucleotidyl transferase

The age, acute presentation, and blast morphology with scant cytoplasm and high nuclear-cytoplasmic ratio point to acute lymphoblastic leukemia, the commonest childhood leukemia. Lymphoblasts are negative for myeloperoxidase (a myeloid marker) and positive for terminal deoxynucleotidyl transferase (TdT), a nuclear enzyme expressed in immature lymphoid precursors. This immunophenotypic profile distinguishes ALL from acute myeloid leukemia, which is myeloperoxidase positive.

  • A. CD14 and nonspecific esterase positivity indicate monocytic differentiation, seen in acute monocytic leukemia.
  • C. The Philadelphia chromosome is the hallmark of chronic myeloid leukemia, though it can rarely occur in some ALL cases, it is not a defining feature here.
  • D. This profile with Auer rods indicates myeloid differentiation and is characteristic of acute myeloid leukemia, not ALL.
Educational objective: Lymphoblasts in ALL are myeloperoxidase-negative and TdT-positive, confirming lymphoid lineage.
32

A 48-year-old man presents with fatigue and early satiety for 4 months. Examination reveals massive splenomegaly extending 10 cm below the left costal margin. Total leukocyte count is 180,000/microL with a full spectrum of granulocytic maturation from myeloblasts to mature neutrophils, and basophilia is noted. Which of the following best explains the underlying molecular mechanism of this disease?

  1. APoint mutation causing constitutive activation of a JAK2 kinase
  2. BTranslocation involving a retinoic acid receptor gene blocking myeloid differentiation
  3. CTranslocation juxtaposing an oncogene next to an immunoglobulin heavy chain enhancer
  4. DReciprocal translocation forming a fusion gene with constitutive tyrosine kinase activity
Show answer
Answer: D. Reciprocal translocation forming a fusion gene with constitutive tyrosine kinase activity

The massive splenomegaly, markedly elevated leukocyte count with a full maturation spectrum of granulocytes, and basophilia are classic for chronic myeloid leukemia. This disease results from the t(9;22) reciprocal translocation, producing the Philadelphia chromosome, in which the BCR gene on chromosome 22 fuses with the ABL gene on chromosome 9. The resulting BCR-ABL fusion protein has constitutive tyrosine kinase activity, driving uncontrolled myeloid proliferation, and is the target of tyrosine kinase inhibitors like imatinib.

  • A. JAK2 V617F mutation is characteristic of other myeloproliferative neoplasms such as polycythemia vera, not CML.
  • B. This describes the t(15;17) translocation of acute promyelocytic leukemia involving the retinoic acid receptor alpha gene.
  • C. This mechanism describes translocations such as t(8;14) in Burkitt lymphoma, where MYC is juxtaposed to the immunoglobulin heavy chain locus.
Educational objective: CML is driven by the t(9;22) Philadelphia chromosome, producing the BCR-ABL fusion protein with constitutive tyrosine kinase activity.
33

A 68-year-old man undergoes a routine health checkup and is found to have painless generalized lymphadenopathy. He is otherwise asymptomatic. Total leukocyte count is 55,000/microL with 80% small, mature-appearing lymphocytes and occasional smudge cells on peripheral smear. Flow cytometry is advised. Which of the following immunophenotypic findings would confirm the most likely diagnosis?

  1. ACo-expression of CD5 and CD23 on monoclonal B cells
  2. BExpression of CD15 and CD30 on large binucleate cells
  3. CExpression of CD10 and surface immunoglobulin with light chain restriction
  4. DExpression of CD25, CD11c, and tartrate-resistant acid phosphatase
Show answer
Answer: A. Co-expression of CD5 and CD23 on monoclonal B cells

The elderly patient with painless lymphadenopathy, marked lymphocytosis, and smudge cells on smear is characteristic of chronic lymphocytic leukemia. The diagnostic immunophenotype is monoclonal B lymphocytes co-expressing CD5, a T-cell marker aberrantly expressed on the neoplastic B cells, along with CD23, confirming the diagnosis. CD5/CD23 co-positivity also helps distinguish CLL from mantle cell lymphoma, which is CD5 positive but CD23 negative.

  • B. CD15 and CD30 positivity on large binucleate cells describes Reed-Sternberg cells in Hodgkin lymphoma, not a leukemic process.
  • C. CD10 positivity is typical of follicular lymphoma and does not fit this clinical and smear picture.
  • D. This combination is characteristic of hairy cell leukemia, which presents with pancytopenia and splenomegaly, not marked lymphocytosis with smudge cells.
Educational objective: CLL is diagnosed by monoclonal B cells co-expressing CD5 and CD23 on flow cytometry.
34

A 24-year-old man presents with a painless, progressively enlarging mass in the neck for 2 months, along with intermittent fever and night sweats. Excisional biopsy of a cervical lymph node shows large binucleate cells with prominent eosinophilic nucleoli set in a background of lymphocytes, eosinophils, and bands of collagen dividing the node into nodules. Which of the following best describes the diagnostic cell type and the subtype carrying the most favorable prognosis?

  1. AReed-Sternberg cell; lymphocyte-depleted subtype
  2. BPopcorn cell; mixed cellularity subtype
  3. CStarry-sky macrophage pattern; lymphocyte-rich subtype
  4. DReed-Sternberg cell; nodular sclerosis subtype
Show answer
Answer: D. Reed-Sternberg cell; nodular sclerosis subtype

The large binucleate cells with prominent eosinophilic nucleoli, described as having an "owl's eye" appearance, are Reed-Sternberg cells, the diagnostic cell of Hodgkin lymphoma. The collagen bands dividing the node into nodules are characteristic of the nodular sclerosis subtype, which is also the most common subtype in young adults and carries an excellent prognosis with current treatment. Among the classic subtypes, nodular sclerosis and lymphocyte-predominant forms generally have the best outcomes, while lymphocyte-depleted has the worst.

  • A. The lymphocyte-depleted subtype carries the worst prognosis among Hodgkin lymphoma subtypes, not the best.
  • B. The popcorn cell is seen in nodular lymphocyte-predominant Hodgkin lymphoma, not the classic Reed-Sternberg-cell type described here with collagen bands.
  • C. A starry-sky pattern is characteristic of Burkitt lymphoma, a non-Hodgkin lymphoma, not Hodgkin disease.
Educational objective: Reed-Sternberg cells are diagnostic of Hodgkin lymphoma, and the nodular sclerosis subtype carries the best prognosis.
35

A 62-year-old man presents with low back pain for 3 months and increasing fatigue. Examination shows pallor and tenderness over the lumbar spine. Laboratory evaluation shows hemoglobin 8.5 g/dL, serum calcium 11.8 mg/dL, and serum creatinine 2.1 mg/dL. Skeletal survey shows multiple punched-out lytic lesions in the skull and pelvis. Serum protein electrophoresis shows a sharp spike in the gamma region. Which of the following urinary findings would further support the most likely diagnosis?

  1. AMicroscopic hematuria with dysmorphic red cells
  2. BGlycosuria with normal blood glucose level
  3. CFree monoclonal immunoglobulin light chains
  4. DNephrotic range proteinuria exceeding 3.5 g/day
Show answer
Answer: C. Free monoclonal immunoglobulin light chains

This patient has the classic triad of multiple myeloma: lytic bone lesions, an M spike on serum protein electrophoresis, and renal impairment with anemia and hypercalcemia. Bence Jones protein, consisting of free monoclonal kappa or lambda light chains, is filtered by the glomerulus and detected in urine, supporting the diagnosis. These light chains are also nephrotoxic and contribute to the renal failure seen in myeloma through cast nephropathy.

  • A. Dysmorphic red cells in urine suggest a glomerulonephritis, not the light chain proteinuria typical of myeloma.
  • B. Glycosuria with normal blood glucose suggests a proximal tubular defect such as Fanconi syndrome, not the classic finding in this triad.
  • D. While proteinuria can occur, myeloma classically causes light chain (Bence Jones) proteinuria rather than nephrotic-range albuminuria from glomerular disease.
Educational objective: Multiple myeloma presents with the triad of lytic bone lesions, serum M spike, and urinary Bence Jones (free light chain) proteinuria.
36

A 7-year-old boy from a malaria-endemic region presents with a rapidly enlarging jaw mass for 3 weeks. Biopsy shows a monotonous population of medium-sized lymphoid cells with high mitotic activity, interspersed with benign macrophages containing ingested apoptotic debris, giving a "starry-sky" appearance. Which of the following chromosomal translocations is most characteristically associated with this disease?

  1. At(11;14) involving the cyclin D1 gene
  2. Bt(8;14) involving the MYC gene
  3. Ct(14;18) involving the BCL2 gene
  4. Dt(2;5) involving the ALK gene
Show answer
Answer: B. t(8;14) involving the MYC gene

The jaw mass in a child from a malaria-endemic region with starry-sky histology on biopsy is classic for Burkitt lymphoma, which is associated with Epstein-Barr virus infection. The hallmark genetic abnormality is the t(8;14) translocation, which juxtaposes the MYC oncogene on chromosome 8 next to the immunoglobulin heavy chain enhancer on chromosome 14, leading to MYC overexpression and uncontrolled cell proliferation. This translocation is detected by cytogenetics or FISH and supports the diagnosis.

  • A. The t(11;14) translocation involving cyclin D1 is characteristic of mantle cell lymphoma.
  • C. The t(14;18) translocation involving BCL2 causing apoptosis inhibition is characteristic of follicular lymphoma, not Burkitt lymphoma.
  • D. The t(2;5) translocation involving ALK is characteristic of anaplastic large cell lymphoma.
Educational objective: Burkitt lymphoma is characterized by the t(8;14) translocation causing MYC overexpression.

Cardiovascular Pathology

5 questions
37

A 25-year-old man dies in a road traffic accident. At autopsy, the intima of the aorta shows multiple flat, yellow, non-raised lesions composed of lipid-laden macrophages beneath an intact endothelium. Which of the following best explains the initial step in the formation of this lesion?

  1. ARupture of the fibrous cap with superimposed thrombosis
  2. BDystrophic calcification of the necrotic lipid core
  3. CMigration of monocytes into the intima and their transformation into foam cells
  4. DSmooth muscle cell migration into the intima with collagen deposition
Show answer
Answer: C. Migration of monocytes into the intima and their transformation into foam cells

Fatty streaks are the earliest grossly visible lesions of atherosclerosis, appearing as flat yellow intimal lesions that do not cause significant luminal narrowing. They begin with endothelial dysfunction leading to monocyte adhesion and migration into the intima, where they differentiate into macrophages and ingest oxidized LDL to become lipid-laden foam cells. Smooth muscle proliferation and fibrous cap formation occur later in the progression to a fibrofatty plaque. Calcification and plaque rupture are features of advanced, complicated atherosclerotic lesions, not the earliest change.

  • A. Plaque rupture and thrombosis occur in advanced, unstable lesions, not fatty streaks.
  • B. Calcification is a feature of advanced complicated plaques.
  • D. This describes fibrous plaque formation, a later stage, not the earliest lesion.
Educational objective: Fatty streaks, the earliest visible atherosclerotic lesions, form through monocyte-derived macrophages accumulating lipid as foam cells in the intima.
38

A 58-year-old man presents to the emergency department 2 hours after the onset of severe retrosternal chest pain. ECG shows ST-segment elevation in leads II, III and aVF. Which serum marker is most likely to already show a rise at this time point?

  1. ATroponin T
  2. BMyoglobin
  3. CCK-MB
  4. DLactate dehydrogenase
Show answer
Answer: B. Myoglobin

Myoglobin is a small cytoplasmic protein released rapidly from damaged myocytes and begins to rise within 1-2 hours of myocardial infarction, making it the earliest detectable marker, though it lacks cardiac specificity and is rarely used clinically now. Troponin T and I rise slightly later, by 2-4 hours, but remain elevated for 7-10 days and are the most specific and preferred markers for diagnosis. CK-MB rises at 4-6 hours and is useful for detecting reinfarction. LDH rises latest, at 24-48 hours, and is now obsolete for MI diagnosis.

  • A. Troponin rises slightly later than myoglobin, around 2-4 hours.
  • C. CK-MB rises later, around 4-6 hours.
  • D. LDH rises latest, at 24-48 hours, and is not used for early diagnosis.
Educational objective: Myoglobin is the earliest-rising marker of myocardial infarction, but troponin remains the preferred diagnostic marker due to its cardiac specificity and prolonged elevation.
39

A 14-year-old girl presents with history of recurrent sore throat and now has fever, migratory polyarthritis and a pansystolic murmur best heard at the apex. Histopathological examination of a cardiac biopsy would most likely reveal which finding, and which valve is most commonly affected in this condition?

  1. AGranulomatous inflammation; pulmonary valve
  2. BAschoff bodies; mitral valve
  3. CVerrucous vegetations; aortic valve
  4. DLibman-Sacks vegetations; tricuspid valve
Show answer
Answer: B. Aschoff bodies; mitral valve

Rheumatic heart disease follows group A streptococcal pharyngitis and is mediated by molecular mimicry between streptococcal M protein and cardiac myosin. The pathognomonic histological finding is the Aschoff body, consisting of fibrinoid necrosis surrounded by lymphocytes, plasma cells and activated macrophages called Anitschkow cells. The mitral valve is the most commonly affected valve, followed by combined mitral and aortic involvement, due to the higher mechanical stress on this valve. Aschoff bodies are found in the myocardium and signify active rheumatic carditis.

  • A. Rheumatic carditis is not a granulomatous disease and the pulmonary valve is rarely involved.
  • C. Verrucous vegetations do occur in rheumatic fever but the aortic valve is affected less often than the mitral valve.
  • D. Libman-Sacks vegetations occur in SLE, not rheumatic fever, and the tricuspid valve is rarely the most commonly affected.
Educational objective: The mitral valve is most commonly affected in rheumatic heart disease, and Aschoff bodies in the myocardium are pathognomonic of active rheumatic carditis.
40

Three patients are diagnosed with infective endocarditis. Patient A has a structurally normal native valve and no risk factors. Patient B is an intravenous drug user with tricuspid valve vegetations. Patient C developed endocarditis 3 weeks after mitral valve replacement. Which organism is most likely responsible in patient C?

  1. AStreptococcus viridans
  2. BStaphylococcus aureus
  3. CCoagulase-negative staphylococci
  4. DHACEK group organisms
Show answer
Answer: C. Coagulase-negative staphylococci

Early prosthetic valve endocarditis, occurring within 60 days of surgery, is most commonly caused by coagulase-negative staphylococci such as Staphylococcus epidermidis, acquired through intraoperative contamination or hematogenous seeding of the prosthetic material in the perioperative period. Streptococcus viridans typically causes subacute endocarditis on previously damaged native valves. Staphylococcus aureus is the most common cause in intravenous drug users, typically affecting the tricuspid valve, and causes acute, aggressive endocarditis. HACEK organisms cause culture-negative endocarditis, usually on native valves, with a more indolent course.

  • A. Viridans streptococci typically infect damaged native valves, not early prosthetic valves.
  • B. Staphylococcus aureus is the classic organism in IV drug users with tricuspid involvement.
  • D. HACEK organisms cause slow-growing culture-negative endocarditis on native valves.
Educational objective: Early prosthetic valve endocarditis within 60 days of surgery is most commonly caused by coagulase-negative staphylococci.
41

A 45-year-old woman presents with progressive breathlessness and bilateral pedal edema. Echocardiography shows a markedly dilated left ventricular cavity with global hypokinesia and an ejection fraction of 25%. The ventricular wall thickness is normal. Which type of cardiomyopathy is most consistent with these findings?

  1. ADilated cardiomyopathy
  2. BRestrictive cardiomyopathy
  3. CArrhythmogenic right ventricular cardiomyopathy
  4. DHypertrophic cardiomyopathy
Show answer
Answer: A. Dilated cardiomyopathy

Dilated cardiomyopathy is characterized echocardiographically by four-chamber dilation, particularly of the left ventricle, with global systolic dysfunction and a markedly reduced ejection fraction, while wall thickness remains normal or is relatively thin for the dilated chamber size. Hypertrophic cardiomyopathy shows asymmetric septal hypertrophy with a small or normal-sized, hypercontractile left ventricular cavity. Restrictive cardiomyopathy shows normal or near-normal systolic function with impaired diastolic filling and normal chamber size, often due to infiltrative disease. ARVC primarily affects the right ventricle with fibrofatty replacement of the myocardium.

  • B. Restrictive cardiomyopathy shows preserved systolic function with diastolic dysfunction, not a dilated hypokinetic ventricle.
  • C. ARVC primarily involves right ventricular fibrofatty replacement, not left ventricular dilation.
  • D. HCM shows a hypertrophied, non-dilated ventricle with preserved or increased ejection fraction.
Educational objective: Dilated cardiomyopathy is distinguished by four-chamber dilation with reduced ejection fraction and normal wall thickness.

Respiratory Pathology

1 questions
42

A 30-year-old non-smoker presents with progressive dyspnea. CT chest shows predominantly basal panacinar emphysema with uniform destruction of the entire acinus. Liver function tests are mildly deranged. Which underlying mechanism best explains this pattern of emphysema?

  1. AChronic exposure to silica dust causing nodular fibrosis
  2. BRecurrent bacterial infections causing bronchiectasis with secondary air trapping
  3. CChronic cigarette smoking causing centriacinar destruction around the respiratory bronchiole
  4. DDeficiency of alpha-1 antitrypsin leading to unopposed neutrophil elastase activity
Show answer
Answer: D. Deficiency of alpha-1 antitrypsin leading to unopposed neutrophil elastase activity

Panacinar emphysema uniformly destroys the entire acinus, including the respiratory bronchiole, alveolar duct and alveoli, and characteristically predominates in the lower lobes and bases. It results from alpha-1 antitrypsin deficiency, a genetic condition in which the lack of this protease inhibitor allows unchecked neutrophil elastase activity to destroy alveolar walls, and the same deficiency can cause associated liver disease due to accumulation of abnormal protein in hepatocytes. Centriacinar emphysema, in contrast, selectively affects the proximal respiratory bronchiole and is strongly associated with smoking, predominantly in the upper lobes. Silicosis and bronchiectasis do not produce panacinar emphysema.

  • A. Silicosis causes nodular fibrosis, not panacinar emphysema.
  • B. Bronchiectasis causes airway dilation with infection, not panacinar emphysema, and does not explain the liver findings.
  • C. Smoking classically causes centriacinar, upper-lobe predominant emphysema, not panacinar.
Educational objective: Panacinar, lower-lobe predominant emphysema with liver disease suggests alpha-1 antitrypsin deficiency, unlike smoking-related centriacinar emphysema.

GI & Liver Pathology

4 questions
43

A 50-year-old woman presents with epigastric discomfort and dyspepsia for 6 months. Upper GI endoscopy shows antral mucosal erythema, and biopsy reveals chronic inflammatory infiltrate in the lamina propria with curved, spiral-shaped organisms identified on Giemsa stain along the gastric surface epithelium. Which of the following is the most likely causative organism?

  1. ACampylobacter jejuni
  2. BEscherichia coli
  3. CHelicobacter pylori
  4. DKlebsiella pneumoniae
Show answer
Answer: C. Helicobacter pylori

Helicobacter pylori is a curved, microaerophilic, flagellated organism that colonizes the gastric mucus layer and is the leading cause of chronic antral gastritis worldwide. It is identified histologically on special stains (Giemsa, Warthin-Starry) as spiral organisms on the surface epithelium, and the chronic inflammation it induces can progress to intestinal metaplasia, atrophy, and increased gastric cancer risk. Diagnosis is confirmed by biopsy with special stains, rapid urease test, or urea breath test. Eradication therapy reduces the risk of peptic ulcer disease and gastric malignancy.

  • A. Campylobacter jejuni causes acute enterocolitis, not chronic gastritis.
  • B. Escherichia coli is not associated with chronic gastritis and does not colonize the gastric mucosa in this pattern.
  • D. Klebsiella pneumoniae is not implicated in chronic gastritis and typically causes respiratory or urinary infections.
Educational objective: Helicobacter pylori is the most common cause of chronic antral gastritis and is identified as spiral organisms on gastric biopsy with special stains.
44

A 55-year-old man with a 15-year history of gastroesophageal reflux disease undergoes upper GI endoscopy, which shows salmon-colored mucosa extending 3 cm above the gastroesophageal junction. Biopsy of this area reveals columnar epithelium with goblet cells replacing the normal stratified squamous epithelium. This histologic change predisposes the patient to which of the following malignancies?

  1. AEsophageal adenocarcinoma
  2. BEsophageal squamous cell carcinoma
  3. CGastric signet ring carcinoma
  4. DEsophageal leiomyosarcoma
Show answer
Answer: A. Esophageal adenocarcinoma

The finding of columnar epithelium with goblet cells (intestinal metaplasia) replacing the normal squamous epithelium of the distal esophagus defines Barrett esophagus, a complication of chronic GERD. This metaplastic epithelium carries an increased risk of progression through dysplasia to esophageal adenocarcinoma, the malignancy most strongly associated with Barrett esophagus. Patients require periodic endoscopic surveillance with biopsy to detect dysplasia early. Squamous cell carcinoma of the esophagus is instead linked to smoking and alcohol use, not Barrett metaplasia.

  • B. Squamous cell carcinoma is associated with smoking, alcohol, and hot beverages, not with columnar metaplasia of Barrett esophagus.
  • C. Signet ring carcinoma arises in the stomach, not from esophageal Barrett metaplasia.
  • D. Leiomyosarcoma is a mesenchymal tumor unrelated to glandular metaplastic change.
Educational objective: Barrett esophagus is intestinal metaplasia of the distal esophagus due to chronic GERD and is the major precursor lesion for esophageal adenocarcinoma.
45

A 48-year-old man with a 20-year history of heavy alcohol consumption undergoes liver biopsy for evaluation of ascites and jaundice. The biopsy shows diffuse fibrous septa dividing the liver parenchyma into nodules that are uniformly less than 3 mm in diameter. Which of the following is the most likely underlying cause of this pattern?

  1. AWilson disease
  2. BAlcoholic liver disease
  3. CChronic viral hepatitis B
  4. DChronic viral hepatitis C
Show answer
Answer: B. Alcoholic liver disease

Micronodular cirrhosis, defined by uniform regenerative nodules smaller than 3 mm, is classically associated with alcoholic liver disease, where the toxic effect of alcohol causes diffuse, relatively uniform hepatocyte injury and regeneration. In contrast, chronic viral hepatitis (B or C) typically produces macronodular cirrhosis with nodules of varying size greater than 3 mm due to patchy, irregular hepatocyte necrosis and regeneration. Wilson disease can cause either pattern but is less classically linked to a pure micronodular pattern than alcohol. Recognizing the nodule pattern helps narrow the differential for the underlying etiology of cirrhosis.

  • A. Wilson disease is not the classic cause of a purely micronodular pattern as seen here.
  • C. Chronic hepatitis B classically produces macronodular cirrhosis with nodules of varying, often larger, size.
  • D. Chronic hepatitis C classically produces macronodular cirrhosis rather than uniform micronodular change.
Educational objective: Micronodular cirrhosis with uniform nodules under 3 mm is classically caused by alcoholic liver disease, while macronodular cirrhosis is typical of chronic viral hepatitis.
46

A 60-year-old man from a region with high dietary aflatoxin exposure and chronic hepatitis B infection presents with right upper quadrant pain, weight loss, and a palpable liver mass. Ultrasound shows a 6 cm hypoechoic mass in the right lobe of the liver. Serum level of which of the following markers is most useful in supporting the diagnosis of the underlying malignancy?

  1. ACA 19-9
  2. BAlpha-fetoprotein
  3. CCarcinoembryonic antigen
  4. DCA 125
Show answer
Answer: B. Alpha-fetoprotein

Alpha-fetoprotein (AFP) is the serum tumor marker most closely associated with hepatocellular carcinoma, which arises in this patient due to the synergistic carcinogenic effects of chronic hepatitis B infection and aflatoxin B1 exposure (a mycotoxin from Aspergillus-contaminated grains that induces TP53 mutations). Elevated AFP above 400 ng/mL in a patient with a liver mass and cirrhosis or chronic hepatitis strongly supports the diagnosis of hepatocellular carcinoma. CEA, CA 19-9, and CA 125 are markers for colorectal, pancreaticobiliary, and ovarian malignancies respectively and are not specific for hepatocellular carcinoma.

  • A. CA 19-9 is associated with pancreatic and biliary tract cancers.
  • C. CEA is elevated in colorectal and some other GI cancers, not specifically hepatocellular carcinoma.
  • D. CA 125 is used primarily as a marker for ovarian cancer.
Educational objective: Alpha-fetoprotein is the key tumor marker for hepatocellular carcinoma, which is strongly associated with chronic hepatitis B infection and aflatoxin exposure.

Renal Pathology

4 questions
47

A 6-year-old boy presents with generalized periorbital and pedal edema over the past week. Urinalysis shows 4+ proteinuria with a 24-hour urine protein of 4.5 g, and urine microscopy shows no red blood cells or casts. Serum albumin is 2.1 g/dL and serum cholesterol is 320 mg/dL. Which of the following best characterizes this clinical presentation?

  1. AAcute tubular necrosis
  2. BNephrotic syndrome
  3. CNephritic syndrome
  4. DRapidly progressive glomerulonephritis
Show answer
Answer: B. Nephrotic syndrome

This presentation of massive proteinuria (over 3.5 g/day), hypoalbuminemia, hypercholesterolemia, and edema without hematuria or red cell casts defines nephrotic syndrome. It reflects a glomerular lesion that primarily damages the filtration barrier without significant inflammatory injury to the capillary wall, so red blood cells are not spilled into the urine. Nephritic syndrome, in contrast, is characterized by hematuria with red cell casts, mild to moderate proteinuria, hypertension, and oliguria due to glomerular inflammation. The absence of hematuria and casts here excludes a nephritic process.

  • A. Acute tubular necrosis presents with oliguria and rising creatinine from tubular injury, not heavy proteinuria with hypoalbuminemia.
  • C. Nephritic syndrome presents with hematuria, red cell casts, and hypertension, none of which are described here.
  • D. Rapidly progressive glomerulonephritis presents with hematuria, red cell casts, and rapid renal function decline.
Educational objective: Nephrotic syndrome is defined by heavy proteinuria, hypoalbuminemia, hypercholesterolemia, and edema, without hematuria or red cell casts.
48

A 4-year-old girl develops sudden-onset generalized edema. Investigations show urine protein of 4+, serum albumin of 1.8 g/dL, and normal renal function. Light microscopy of a renal biopsy appears normal, and immunofluorescence is negative for immune deposits. Which of the following findings on electron microscopy would confirm the most likely diagnosis?

  1. ASplitting of the glomerular basement membrane
  2. BSubepithelial electron-dense humps
  3. CDiffuse effacement of podocyte foot processes
  4. DSubendothelial electron-dense deposits
Show answer
Answer: C. Diffuse effacement of podocyte foot processes

Minimal change disease is the most common cause of nephrotic syndrome in young children and classically shows normal glomeruli on light microscopy and negative immunofluorescence, with the diagnostic finding being diffuse effacement (flattening) of the podocyte foot processes on electron microscopy. This effacement disrupts the normal filtration slit diaphragm, leading to selective proteinuria, predominantly albumin. The disease is notable for its excellent responsiveness to corticosteroid therapy, with most children achieving remission. Subepithelial humps, basement membrane splitting, and subendothelial deposits are features of other glomerulopathies, not minimal change disease.

  • A. Basement membrane splitting is characteristic of Alport syndrome or membranoproliferative glomerulonephritis.
  • B. Subepithelial humps are the classic electron microscopy finding of post-streptococcal glomerulonephritis, not minimal change disease.
  • D. Subendothelial deposits are typical of lupus nephritis (class III/IV) or membranoproliferative glomerulonephritis.
Educational objective: Minimal change disease shows normal light microscopy with diffuse podocyte foot process effacement on electron microscopy and typically responds well to corticosteroids.
49

A 28-year-old woman with a known diagnosis of systemic lupus erythematosus presents with facial puffiness, hypertension, and hematuria. Urinalysis shows red blood cell casts and proteinuria of 3.8 g/day. Renal biopsy shows diffuse endocapillary and mesangial hypercellularity involving more than 50% of glomeruli, with granular deposits of IgG, IgM, and C3 along the capillary walls and mesangium on immunofluorescence. Which of the following best explains the underlying mechanism of glomerular injury in this patient?

  1. AANCA-associated pauci-immune vasculitis
  2. BDeposition of circulating immune complexes containing anti-dsDNA antibodies
  3. CDirect cytotoxic T-cell mediated podocyte injury
  4. DAnti-glomerular basement membrane antibody deposition
Show answer
Answer: B. Deposition of circulating immune complexes containing anti-dsDNA antibodies

Diffuse proliferative glomerulonephritis (lupus nephritis class IV) is caused by deposition of circulating immune complexes, particularly those containing anti-double-stranded DNA antibodies bound to nuclear antigens, within the glomerular capillary walls and mesangium. This triggers complement activation, producing the granular "full-house" immunofluorescence pattern (IgG, IgM, IgA, C3, C1q) and an intense inflammatory response with endocapillary and mesangial proliferation. It is the most common and most severe form of lupus nephritis, often presenting with both nephritic and nephrotic features. Anti-GBM disease, T-cell mediated injury, and ANCA-associated pauci-immune vasculitis are distinct mechanisms seen in other forms of glomerulonephritis, not lupus nephritis.

  • A. ANCA-associated vasculitis produces pauci-immune glomerulonephritis with scanty or absent immune deposits, unlike the granular deposits seen here.
  • C. Cytotoxic T-cell mediated injury is not the primary mechanism in immune complex glomerulonephritis such as lupus nephritis.
  • D. Anti-GBM antibody disease causes linear, not granular, immunofluorescence and is seen in Goodpasture syndrome, not lupus nephritis.
Educational objective: Diffuse proliferative lupus nephritis results from glomerular deposition of circulating immune complexes containing anti-dsDNA antibodies, producing a granular immunofluorescence pattern and complement-mediated injury.
50

A 58-year-old man presents with dull left flank pain and intermittent painless hematuria for 2 months. He reports no fever or weight loss. On examination, a firm, non-tender mass is palpable in the left lumbar region. Blood pressure is 142/88 mmHg. Laboratory studies show hemoglobin 18.6 g/dL, serum creatinine 0.9 mg/dL, and urinalysis with numerous red blood cells but no casts. Contrast CT shows a 6 cm heterogeneously enhancing solid mass in the left kidney with areas of necrosis. Which of the following is the most likely diagnosis?

  1. AAngiomyolipoma
  2. BTransitional cell carcinoma of renal pelvis
  3. CRenal cell carcinoma
  4. DWilms tumor
Show answer
Answer: C. Renal cell carcinoma

The combination of flank pain, hematuria, and a palpable abdominal mass is the classic triad of renal cell carcinoma, though all three occur together in only about 10% of cases. The elevated hemoglobin reflects a paraneoplastic effect from ectopic erythropoietin secretion by tumor cells, a well-recognized feature of clear cell RCC. CT showing a heterogeneously enhancing, necrotic solid renal mass is typical of RCC arising from proximal tubular epithelium. RCC is most common in men over 50 and is strongly associated with smoking and von Hippel-Lindau disease.

  • A. Angiomyolipoma is a benign hamartoma with fat density on CT and does not cause paraneoplastic erythropoietin secretion.
  • B. Transitional cell carcinoma arises from the urothelium of the renal pelvis and typically causes hematuria without a large parenchymal mass or secondary polycythemia.
  • D. Wilms tumor is a pediatric renal malignancy, not seen in a 58-year-old adult.
Educational objective: Renal cell carcinoma classically presents with flank pain, hematuria, and a palpable mass, and may cause secondary polycythemia due to ectopic erythropoietin production.

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